convert the model below to a skeletal drawing

Answer:

2.7 mL

Explanation:

The equation of the reaction is;

2AlBr3 + 3Cl2 -----> 2AlCl3 + 3Br2

Number of moles in 2.12 x 1022 formula units of aluminum bromide

1 mole of AlBr3 = 6.02 * 10^23 formula units

x moles = 2.12 x 1022 formula units

x = 2.12 x 1022 formula units  * 1 mole/ 6.02 * 10^23 formula units

x = 0.0352 moles of AlBr3

According to the reaction equation;

2 moles of AlBr3 produces 3 moles of Br2

0.0352 moles of AlBr3 produces 0.0352 moles  *  3 moles /2 moles

= 0.0528 moles of Br2

Mass of Br2 produced = 0.0528 moles of Br2 * 159.808 g/mol

Mass of Br2 produced = 8.44g

But density = mass/volume

volume = mass/density

volume of Br2 = 8.44 g/ 3.12 g/mL

volume of Br2 =  2.7 mL

Answer:

30.0ml

Explanation:

Half of fifty is 25 and 25 represents 15.0ml so 15.0ml×2=30.0ml there for 25+25 is 50

Answer:

The conduction was made by the foil which was touching the chocolate made the chocolate slowly melt because of the tea light giving heat to the foil the foil conducted it to the chocolate causing it to melt.

Explanation:

Conduction is the transfer of heat through touch.

Convection is the transfer of heat through liquid or gas.

Radiation is how heat/energy travels through space.

Hope this helped!

Answer:

Thymus. This gland makes white blood cells called T-lymphocytes that fight infection and are crucial as a child's immune system develops

Answer:

3

Explanation:

The plates are moving away from each other

Answer: The percent yield of zinc carbonate is 5.91 %

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]

 [tex]\text{Moles of} ZnCO_3=\frac{12.6 g}{125.4g/mol}=0.100moles[/tex]

[tex]ZnI_2[/tex] is the limiting reagent as it limits the formation of product and [tex]Na_2CO_3[/tex] is the excess reagent.  

[tex]Na_2CO_3+ZnI_2\rightarrow 2NaI+ZnCO_3[/tex]  

According to stoichiometry :

1 mole of produce =  1 mole of

Thus 1.7 moles of [tex]ZnI_2[/tex] will produce=[tex]\frac{1}{1}\times 1.7=1.7moles[/tex]  of [tex]ZnCO_3[/tex]

Theoretical yield of [tex]ZnCO_3=moles\times {\text {Molar mass}}=1.7moles\times 125.4g/mol=213.2g[/tex]

percentage yield = [tex]\frac{\text {Experimental yield}}{\text {Theoretical yield}}\times 100=\frac{12.6g}{213.2g}\times 100=5.91\%[/tex]

Answer:

the other person was right EXCEPT it says in 2 significant numbers so the answer is 5.9

Explanation:

i hope this helps. have a wonderful day :))

Genetic engineering improved the lives if individuals with insulin because it helps the body use and store sugar, since people with diabetes can't produce insulin.

Solution :

For the real gas following Vander Waals equation, reversible isothermal work done is given by :

[tex]$W= \int P \ dV$[/tex]

[tex]$W= \int \left(\frac{nR}{V-nb}-\frac{an^2}{V^2}\right) dV$[/tex]

[tex]$W_{real}=-nRT \ln \left[\frac{V_2-b}{V_1-b}\right]-an^2\left[\frac{1}{V_2}-\frac{1}{V_1}\right]$[/tex]

Given : [tex]$V_1=0.1 \ dm^3$[/tex], [tex]$$V_2 =100 \ dm^3[/tex]  

[tex]$a=359 \ atm \ L^2/ mol^2, \ \ b = 0.0427 \ L/mol$[/tex]

As T is not given, assuming T = 290 K

[tex]$W_{real} = 0.0823 \times 240 \left[ \ln \left(\frac{100-0.042}{0.1-0.0427}\right)\right]-3.59\left[\frac{1}{100}-\frac{1}{0.1}\right]$[/tex]

[tex]$W_{real}= -183.06+35.864$[/tex]

[tex]$W_{real}=-147.196$[/tex]

For the perfect gas,

[tex]$W=nRT \ln\left[\frac{V_2}{V_1}\right] =(1)(0.0823)(290) \ln \left[\frac{100}{0.1}\right]$[/tex]

[tex]$W_{ideal}=169.415$[/tex] kJ

Answer:

the answer is B

Explanation:

Answer:

1. Mass of KCl produced = 774.8 g of KCl

2. Mass of KNO₃ produced = 13.837g

3. Moles of NaOH made = 0.846 moles

4. Moles of LiCl produced = 0.846 moles

5. Moles of CO₂ produced = 207.6 moles

Explanation:

1. From the equation of reaction, 1 mole of ZnCl₂ produces, 2 moles of KCl.

5.02 moles of ZnCl₂ will produce, 2 × 5.02 moles of KCl = 10.4 moles of KCl

Molar mass of KCl = (39 + 35.5) g/mol = 74.5 g/mol

10.4 moles of KCl = 10.4 × 74.5 g

Mass of KCl produced = 774.8 g of KCl

2. Mole ratio of KNO₃ and KOH = 1:1

O.137 moles of KOH will produce 0.137 moles of KNO₃

Molar mass of KNO₃ = 101 g/mol

Mass of KNO₃ produced = 0.137 × 101 g = 13.837g

3. Molar mas of Ca(OH)₂ = 74.0 g

Moles of Ca(OH)₂ in 31.3 g = 31.3/74.0 = 0.423 moles of Ca(OH)₂

Mole ratio of NaOH and Ca(OH)₂ in the reaction = 2 : 1

Moles of NaOH made = 2 × 0.423 = 0.846 moles

4. Molar mass of MgCl₂ = 95.0 g

Moles of MgCl₂ in 40.2 g = 40.2/95.0 = 0.423 moles

From the reaction equation, mole ratio of MgCl₂ and LiCl = 1:2

Moles of LiCl produced = 2 × 0.423 = 0.846 moles

5. From the equation of reaction, 1 mole of C₆H₁₀O₅ produces 6 moles of cO₂

34.6 moles of C₆H₁₀O₅ will produce 34.6 × 6 moles of CO₂

Moles of CO₂ produced = 207.6 moles

Answer:

D

Explanation:

31 / 2.8 = 11.0714286 L per mole of helium

3.5 / 4 = 0.875 moles

2.8 + 0.875 = 3.675 moles

11.0714286 x 3.675 = 40.6875 L

Explanation:

A-Corrosion

B- Magnesium helps ur body regulates its zinc levels and zinc absorbs into absorbs magnesium more efficiently

Answer:

B

Explanation:

Answer:

iron (III) oxide is a gas

Answer:

0.95g of Ag we can produce

Explanation:

To solve this question we have to convert the mass of silver nitrate (AgNO₃) to moles. The moles of silver nitrate = Moles of Ag. Then, with molar mass of Ag we can know the mass of silver:

Moles AgNO₃ -Molar mass: 169.87g/mol-:

1.5g * (1mol / 169.87g) = 0.0088 moles Ag

Mass Ag -Molar mass: 107.87g/mol-:

0.0088 moles Ag * (107.87g / mol) =

Answer:

The answer is B

Explanation:

I'm just big-brained

And because it's hotter than the rest and since all of them are cold "B" is just going to make them warmer.

Answer:

c) %5.68×10²⁴

Explanation:

Number atoms=Avogadro's number ₓ number of moles

N= 6.023ₓ 10²³×9.44

N=5.68×10²⁴

Answer:

Atacama

Explanation:

Answer:

Mass of 1 mole of Aluminium = Mass of 6.02 x 10 23atoms of Aluminium =  26.98 grams.

Explanation:

1 mole of any element or molecule has 6.02 x 10 23atoms or subparts.

Hence 1 mole of aluminum will also have 6.02 x 10 23atoms. Hence, it is clear that mass of 1 mole of Aluminium will be equal to 6.02 x 10 23atoms of Aluminium.

Thus,

Mass of 1 mole of Aluminium = Mass of 6.02 x 10 23atoms of Aluminium =  26.98 grams.

Answer:

5 L

Explanation:

We'll begin by calculating the molarity of the CaCl₂ solution. This can be obtained as follow:

Mole of CaCl₂ = 0.5 mole

Volume = 2 L

Molarity =?

Molarity = mole /Volume

Molarity = 0.5 / 2

Molarity = 0.25 M

Finally, we shall determine the volume of the diluted solution. This can be obtained as follow:

Molarity of stock solution (M₁) = 0.25 M

Volume of stock solution (V₁) = 2 L

Molarity of diluted solution (M₂) = 0.1 M

Volume of diluted solution (V₂) =?

M₁V₁ = M₂V₂

0.25 × 2 = 0.1 × V₂

0.5 = 0.1 × V₂

Divide both side by 0.1

V₂ = 0.5 / 0.1

V₂ = 5 L

Thus the volume of the diluted solution is 5 L

Answer:

1.) b

2.) c

3.) e

4.) g

5.) j

6.) k

HOPE THIS HELPS

-Todo <3

Explanation:

Answer:B, C, F, G, I, L.

Explanation: i think that these are the correct one there was not a whole lot of contects on the question

Answer:

See explanation

Explanation:

When we are writing chemical reaction equations, we must ensure that such equations are balanced. That is, the number of atoms of each element on both sides of the reaction equation are exactly the same.

After we identify the formula of each compound in the reaction, then we proceed the write the balanced reaction equation as follows;

CuCl2 + 2AgNO3 -------> Cu(NO3)2  + 2AgCl

Answer:

3

H+ and OH-

Explanation: