Define a relation Ron R by for a,beR (a,b) e Rif and only if a-bez Which of the following properties does have? Reflexive Symmetric Antisymmetric Transitive

Answer:

A. They will pay more with the new price plan.

B. The new price plan would be cheaper.

Step-by-step explanation:

A. They will pay more with the new price plan.

For the current price plan, you would add the $3 rent to the two games (which are $4 each). This basically means:

$3 + $4 + $4 = $11

For the new price plan, you would add the $11 rent to the two games (which are $2 each). This basically means:

$11 + $2 + $2 = $15

Therefore, you pay more for the new price plan.

B. Using similar logic as part A, the current price plan 7 games would cost:

$3 + [7 x ($4)] = $31    (multiply by 7 since they play 7 games)

For the newprice plan, 7 games would cost:

$11 +  [7 x ($2)] = $25    (multiply by 7 since they play 7 games)

Therefore, the new price plan would be cheaper.

Hope this helps :)

Answer:

(a) His speed when he runs from C to A is [tex]4.\overline {285714}[/tex] m/s

(i) The bearing of B from A is approximately 127.18°

(ii) The bearing of A from B is approximately 307.18°

Step-by-step explanation:

(a) The given parameters are;

The distance from A to B = 120 m

The speed with which Olay runs from A to B, v₁ = 4 m/s

The distance from B to C = 180 m

The speed with which Olay runs from B to C, v₂ = 3 m/s

The distance from C to A = 150 m

His average speed for the whole journey = 3.6 m/s

We find

The total distance of running from A back to A, d = 120 m + 180 m + 150 m = 450 m

The time it takes to run from A to B, t₁ = 120 m/(4m/s) = 30 seconds

The time it takes to run from B to C, t₂ = 180 m/(3m/s) = 60 seconds

Let t₃ represent the time it takes Olay to run from C to A

We have;

The total time it takes to run from A back to A = t₁ + t₂ + t₃

Therefore;

[tex]Average \ velocity = \dfrac{Total \ distance }{Total \ time} = \dfrac{d}{t_1 + t_2 + t_3}[/tex]

Substituting the known values for the average velocity, 'd', 't₁' and 't₂'  gives;

[tex]Average \ velocity = 3.6 \, m/s = \dfrac{450 \, m}{30 \, s + 60 \, s + t_3}[/tex]

3.6 m/s × (30 s + 60 s + t₃) = 450 m

3.6 m/s × 30 s + 3.6 m/s × 60 s + 3.6 m/s × t₃ = 450 m

108 m + 216 m + 3.6 m/s × t₃ = 450 m

∴ 3.6 m/s × t₃ = 450 m - (108 m + 216 m) = 126 m

t₃ = 126 m/(3.6 m/s) = 35 s

The speed with which Olay runs from C to A, v₃ = Distance from C to A/t₃

The speed with which he runs from C to A = 150 m/(35 s) = 30/7 m/s =[tex]4.\overline {285714}[/tex] m/s

(i) The given bearing of C from A = 210°

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

∴ cos(A) = (b² + c² - a²)/(2·b·c)

Where;

a = The distance from B to C = 180 m

b = The distance from C to A = 150 m

c = The distance from A to B = 120 m

We find;

cos(A) = (150² + 120² - 180²)/(2 × 150 × 120) = 0.125

A = arccos(0.125) ≈ 82.82°

The bearing of B from A ≈ 210° - 82.82° ≈ 127.18°

The bearing of B from A ≈ 127.18°

(ii) The angle, θ, formed by the path of the bearing of A from B is an alternate to the supplementary angle of the bearing of B from A

Therefore, we have;

θ ≈ 180°- 127.18° ≈ 52.82°

The bearing of A from B = The sum of angle at a point less θ

∴ The bearing of A from B = 360° - 52.82° ≈ 307.18°

The bearing of A from B ≈ 307.18°.

The answers are =

1) The board is now 1.26 meters long.

2) Olivia's recipe calls for approximately 113 grams of rice and a baking temperature of approximately 176.67 degrees Celsius.

3) The cost of a piece measuring 3.70 meters is 3.70 × $12.99 = $48.03. Rounded to the nearest cent, the cost is $48.03.

4) Jalo's weight in pounds is approximately 80.9 × 2.20462 ≈ 178.6 pounds.

5) Approximately 13.5 liters of punch are needed for 75 people.

Peggy's cutting board initially measured 2 meters 4 centimeters, which is equivalent to 204 centimeters.

After cutting off 78 centimeters, the board's new length is 204 - 78 = 126 centimeters.

To convert this to meters, divide by 100: 126 cm ÷ 100 = 1.26 meters. Therefore, the board is now 1.26 meters long.

2) To convert 4 ounces of rice to grams, we need to know the conversion factor.

1 ounce is approximately equal to 28.35 grams.

Therefore, 4 ounces of rice is approximately equal to 4 × 28.35 = 113.4 grams.

To convert 350 degrees Fahrenheit to Celsius, we use the formula: Celsius = (Fahrenheit - 32) × 5/9.

Celsius = (350 - 32) × 5/9 = 318 × 5/9 ≈ 176.67 degrees Celsius.

Therefore, Olivia's recipe calls for approximately 113 grams of rice and a baking temperature of approximately 176.67 degrees Celsius.

3) The length of the fabric is 3 meters 70 centimeters, which is equivalent to 3.70 meters.

The cost of the fabric per meter is $12.99.

Therefore, the cost of a piece measuring 3.70 meters is 3.70 × $12.99 = $48.03. Rounded to the nearest cent, the cost is $48.03.

4) Jalo's weight is given as 80.9 kilograms.

To convert this to pounds, we need to know the conversion factor. 1 kilogram is approximately equal to 2.20462 pounds.

Therefore, Jalo's weight in pounds is approximately 80.9 × 2.20462 ≈ 178.6 pounds.

Jalo's height is given as 1.83 meters.

To convert this to feet, we need to know the conversion factor. 1 meter is approximately equal to 3.28084 feet.

Therefore, Jalo's height in feet is approximately 1.83 × 3.28084 ≈ 6.003 feet, which can be rounded to 6 feet.

Therefore, Jalo weighs approximately 178.6 pounds and is approximately 6 feet tall.

5) Each serving of punch is 180 mL.

To find the total amount of punch needed for 75 people, we multiply the serving size by the number of people: 180 mL × 75 = 13,500 mL.

Since 1 liter is equal to 1,000 mL, we can convert the amount of punch to liters by dividing by 1,000: 13,500 mL ÷ 1,000 = 13.5 liters.

Therefore, approximately 13.5 liters of punch are needed for 75 people.

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Answer:

[tex]\sqrt{53}[/tex]

Step-by-step explanation:

To maintain the same exposure of 100mR with a new technique of 20 mAs, the new kV value should be increased to approximately 120 kV.
The exposure received by a patient during an X-ray examination is determined by the product of milliamperes-seconds (mAs) and kilovolts (kV).

In this case, the initial technique of 40 mAs with 60 kV resulted in an exposure of 100mR.

To calculate the new kV value, we can use the mAs reciprocity law, which states that if the mAs is halved, the kV should be doubled to maintain the same exposure. In other words, the product of mAs and kV should remain constant.

In the initial technique, the product of mAs (40) and kV (60) is 2400. When the mAs value is reduced to 20, we need to find the new kV value that, when multiplied by 20, gives the same product of 2400.

By rearranging the equation, we find that the new kV value should be approximately 120, obtained by dividing the constant (2400) by the new mAs value (20).

To maintain the same exposure of 100mR with a reduced mAs value of 20, the new kV value should be increased to approximately 120 kV. This adjustment ensures that the product of mAs and kV remains constant, as dictated by the mAs reciprocity law.

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Answer:

Step-by-step explanation:

In this scenario, You've asked about the Chutney (Sauce/Raita).

Ok, So let's suppose you are making a "Chutney"

The amount of milliliters (Weight measurement) depends upon the amount of usage/intake that one is taking.

It could be a few hundred (gms. or some Kg's).

That totally depends up on your choice

Answer:

25.5 / 3 = 8.5

8.5 times more student prefer basketball over soccer

Step-by-step explanation:

Answer:

C: Half the people surveyed liked baseball or football

Step-by-step explanation:

25% + 25% = 50% which is 1/2 of the surveyed population

Answer: 1/2(16p+8)(p+2)

Explanation: There is a lot to do, but basically you must simplify the equation and then multiply by 4 on both sides

Without specific alternative hypotheses and distribution parameters, it is not possible to determine the type I error rate.

a) The type I error rate of this test is 0.01, which is the significance level chosen for the test. It represents the probability of rejecting the null hypothesis when it is actually true. In this case, if the data is indeed normally distributed with a mean of 10 and variance of 4, there is a 1% chance of incorrectly rejecting the null hypothesis.

b) To determine the type II error rate, we need to know the specific alternative hypothesis and the distribution parameters under that hypothesis. Without this information, we cannot calculate the type II error rate.

c) Similarly, without knowing the specific alternative hypothesis and the distribution parameters under that hypothesis (mean and variance), we cannot calculate the type II error rate for the scenario where the data is normally distributed with a mean of 9 and a variance of 16.

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The mean of the data set is -6.

The median of the data set is - 9.

The mode of the data set, is - 11.

The mean of the data set is calculated by applying the following formula as follows;

mean = total number of data sample /number of data sample

mean = ( -11 - 11 - 9 - 11 + 0 + 0 + 0 ) / 7

mean = ( -42 ) /7

mean = -6

The median of the data set is calculated as follows;

-11, - 11, - 11, - 9, 0, 0, 0

The median number = - 9

The mode of the data set, is the most occurring number or the number with the highest occurrence.

mode = - 11

The data sample is unimodal because it has only one mode.

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Answer:

49

Step-by-step explanation:

7^2 mean 7x7 which is 49

Answer:

nosee

Step-by-step explanation:

At α = 0.10, 0.05,0.01, and   0.001, we reject the null hypothesis and conclude that there is sufficient evidence to suggest that the population proportion is not equal to 0.3.

Given

H₀: p = 0.3 (null hypothesis)

Hₐ: p ≠ 0.3 (alternative hypothesis)

Sample size (n) = 100

Sample   proportion (p)= 0.2

To calculate the p-value, we can follow these steps  -

Calculate the test statistic z -

z = (pa   - p₀) /√(p₀ * (1 -  p₀) / n)

where pa is the sample proportion,   p₀ is the hypothesized population proportion,and n is the sample size.

Calculate the p-value -

For a two-tailed test, the p-value is calculated as:

p-value =2 * P(Z ≤ -|z  |), where Z is the standard normal distribution.

Now let's calculate the test statistic and p-value for each level of significance α

For α = 0.10:

p₀ = 0.3

The test statistic is

z =(0.2 - 0.3) / √(0.3   * (1 - 0.3) / 100)

z ≈ -4.714

The p-value for a two-tailed test is calculated like this

p-value = 2 * P(Z ≤ -|z|)

≈ 2 * P(Z ≤ -4.714)

Using a standard   normal distribution table or calculator,the p-value is approximately < 0.001

At α = 0.10  - We reject the null hypothesis and conclude that there is sufficient evidence to suggest that the population proportion is not equal to 0.3.

At α = 0.05  - We reject the null hypothesis and conclude that there is sufficient evidence to suggest that the population proportion is not equal to 0.3.

At α = 0.01  - We reject the null hypothesis and conclude that there is sufficient evidence to suggest that the population proportion is not equal to 0.3.

At α = 0.001  - We reject the null hypothesis and conclude that there is sufficient evidence to suggest that the population proportion is not equal to 0.3.

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To calculate the minimum, score a person must have to qualify for the society catering to highly intelligent individuals, given that test scores are normally distributed with a mean of 140 and a standard deviation of 5, you may need to use the appropriate appendix table to answer this question.

The Z-score formula is useful for calculating the minimum score a person must have to qualify for the society catering to highly intelligent individuals. The formula for Z-score is given below: Z = (X - μ) / σwhere, X is the minimum scoreμ is the mean σ is the standard deviation Z is the z-score

From the given data, we can find the Z-score as follows: Z = (X - μ) / σZ = (X - 140) / 5

Given that the person must score in the upper 2% of the population, the area under the normal curve is 0.02.

Since the curve is symmetric, the area under the curve to the right of the mean will be 0.5 - 0.02/2 = 0.49. Since we need to find the minimum score, we can use the inverse normal distribution table or appendix table. From the inverse normal distribution table, the Z-score for 0.49 is 2.06. Now we can substitute the Z-score in the above formula and find the minimum score: X = Zσ + μX = (2.06) (5) + 140X = 151.3The minimum score a person must have to qualify for the society catering to highly intelligent individuals are 151 (rounded to the nearest integer).

Therefore, the correct answer is 151.

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Answer:

234

Step-by-step explanation:

x=2+3

suppose that number is ( x ).

three time of it means : 3 × x

six more means : + 6

So;

Six more three times a number means :

3x + 6

Thus, f ( x ) = 3x + 6

The cross product of the current vector (1 = 2i + 3j – 4k) and the magnetic field vector (B = 3i - 2j + 6k) is obtained by calculating the determinant of a 3x3 matrix formed by the coefficients of i, j, and k. The resulting cross product is 26i + 18j + 13k.

To find the cross product (I x B), we can calculate the determinant of the following matrix:

|i j k |

|2 3 -4 |

|3 -2 6 |

Expanding the determinant, we have:

(i * (3 * 6 - (-2) * (-4))) - (j * (2 * 6 - 3 * (-4))) + (k * (2 * (-2) - 3 * 3))

Simplifying the expression, we get:

(26i) + (18j) + (13k)

Therefore, the cross product of the current vector (1 = 2i + 3j – 4k) and the magnetic field vector (B = 3i - 2j + 6k) is 26i + 18j + 13k. This cross product represents the force on the conductor within the electric motor housing. The resulting force has components in the i, j, and k directions, indicating both the magnitude and direction of the force acting on the conductor.

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Answer: First one is 140, second one is 70

Step-by-step explanation: They’re corresponding angles

A) The approximation of the definite integral ∫₀³ (2x - 1) dx using a right-endpoint approximation with four subintervals is 8.25.

B) The total area between f(x) = 2x and the x-axis over the interval [-5, 5] is 0.

C) The approximation of the definite integral ∫₋₂² (1/(x^2 + 1)) dx using a right-endpoint approximation with four subintervals is approximately 2.2

D) The derivative of s(x) is 0, which means the function s(x) is constant; s'(5) is also equal to 0.

A) To evaluate the definite integral ∫₀³ (2x - 1) dx using a right-endpoint approximation, we divide the interval [0, 3] into subintervals and approximate the area under the curve using rectangles. Let's use four subintervals:

Δx = (3 - 0) / 4 = 0.75

The right endpoints of the subintervals are: 0.75, 1.5, 2.25, 3.0

For each subinterval, we evaluate the function at the right endpoint and multiply it by the width Δx:

f(0.75) = 2(0.75) - 1 = 1.5 - 1 = 0.5

f(1.5) = 2(1.5) - 1 = 3 - 1 = 2

f(2.25) = 2(2.25) - 1 = 4.5 - 1 = 3.5

f(3.0) = 2(3.0) - 1 = 6 - 1 = 5

The Riemann sum is the sum of these areas:

R4 = Δx * [f(0.75) + f(1.5) + f(2.25) + f(3.0)]

= 0.75 * [0.5 + 2 + 3.5 + 5]

= 0.75 * 11

= 8.25

Therefore, the approximation of the definite integral ∫₀³ (2x - 1) dx using a right-endpoint approximation with four subintervals is 8.25.

B) The total area between the function f(x) = 2x and the x-axis over the interval [-5, 5] can be found by evaluating the definite integral ∫₋₅⁵ (2x) dx.

Since the function f(x) = 2x is a linear function, the area between the function and the x-axis is the area of a trapezoid. The base of the trapezoid is the interval [-5, 5], and the height is the maximum value of the function within that interval.

The maximum value of the function f(x) = 2x occurs at x = 5, where f(5) = 2(5) = 10.

The area of the trapezoid is given by the formula: Area = (base1 + base2) * height / 2.

In this case, base1 = -5 and base2 = 5, and the height = 10.

Area = (base1 + base2) * height / 2

= (-5 + 5) * 10 / 2

= 0

Therefore, the total area between f(x) = 2x and the x-axis over the interval [-5, 5] is 0.

C) To calculate R4 for the function g(x) = 1/(x^2 + 1) over the interval [-2, 2], we'll use a right-endpoint approximation with four subintervals.

Δx = (2 - (-2)) / 4 = 1

The right endpoints of the subintervals are: -1, 0, 1, 2

For each subinterval, we evaluate the function at the right endpoint and multiply it by the width Δx:

g(-1) = 1/((-1)² + 1) = 1/(1 + 1)

g(-1) = 1/(1 + 1) = 1/2

g(0) = 1/(0² + 1) = 1/1 = 1

g(1) = 1/(1² + 1) = 1/2

g(2) = 1/(2² + 1) = 1/5

The Riemann sum is the sum of these areas:

R4 = Δx * [g(-1) + g(0) + g(1) + g(2)]

= 1 * [1/2 + 1 + 1/2 + 1/5]

= 1 * [5/10 + 10/10 + 5/10 + 2/10]

= 1 * [22/10]

= 22/10

= 2.2

Therefore, the approximation of the definite integral ∫₋₂² (1/(x^2 + 1)) dx using a right-endpoint approximation with four subintervals is approximately 2.2.

D) To determine s'(5) for the function s(x) = 9(6x)/(x³), we need to find the derivative of s(x) with respect to x and evaluate it at x = 5.

Let's first find the derivative of s(x):

s(x) = 9(6x)/(x³)

Using the quotient rule to differentiate s(x), we have:

s'(x) = [9(6)(x³) - (9)(6x)(3x²)] / (x³)²

= [54x³ - 54x³] / x⁶

= 0 / x⁶

= 0

Therefore, The derivative of s(x) is 0, which means the function s(x) is constant; s'(5) is also equal to 0.

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The statement that is used to prove that quadrilateral ABCD is a parallelogram is opposite sides are congruent. In a parallelogram, opposite sides are parallel, and their opposite angles are congruent. A quadrilateral is a polygon with four sides. A parallelogram is a quadrilateral with two pairs of opposite and parallel sides, which means that the opposite sides in the parallelogram are congruent.

So, a statement that is used to prove that quadrilateral ABCD is a parallelogram is that opposite sides are congruent. It is one of the necessary and sufficient conditions to prove a quadrilateral as a parallelogram. Therefore, option (b) is the correct answer.Apart from this, the other statements that could have been options are:Option (a) - Opposite angles are congruent. It is a property of a parallelogram but is not sufficient to prove that a quadrilateral is a parallelogram. If only opposite angles are congruent, then it is not necessary that opposite sides are parallel.Option (c) - Diagonals bisect each other. This property is only applicable to a parallelogram, and not to any other quadrilateral. However, it is not sufficient to prove a quadrilateral as a parallelogram because this property is only one of the properties of a parallelogram.Option (d) - Consecutive angles are supplementary. This property is common to all quadrilaterals, not just parallelograms. Therefore, it is not sufficient to prove that a quadrilateral is a parallelogram.

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The statement that is used to prove that quadrilateral ABCD is a parallelogram is "Opposite sides are congruent".

A parallelogram is a quadrilateral with two pairs of parallel sides.

There are some properties of parallelograms which include:

Opposite sides are parallel

Opposite sides are congruent

Opposite angles are congruent

Consecutive angles are supplementary

Diagonals bisect each other

Now let's look at the answer options available:

a) Opposite angles are congruent: This statement is used to prove that a quadrilateral is not necessarily a parallelogram, but it is a kite.

b) Opposite sides are congruent: This statement is used to prove that quadrilateral ABCD is a parallelogram.

c) Diagonals bisect each other: This statement is used to prove that quadrilateral is a parallelogram or rectangle. But it cannot prove that ABCD is a parallelogram.

d) Consecutive angles are supplementary: This statement is used to prove that quadrilateral is a parallelogram or rectangle. But it cannot prove that ABCD is a parallelogram.

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Step-by-step explanation:

Interest=P×R×T/100

= 900×3.5×6/100

= 9×3.5×6. cancelling 900 by 100

= $189 Answer

Answer:

Answer

5.0/5

1

sana112704

Answer:

i think the answer is 10,296

Step-by-step explanation:

The first one is still 13C6

Review the definition of combina

Step-by-step explanation:

Answer:

what is the answer to part one ?

and the answer too part 2 ?

the answers down below wereńt clear enough .

Step-by-step explanation

Answer:

4.8

Step-by-step explanation:

Radius is 1/2 of the diameter so just do 2.4 and multiply it by 2

hope this helps :)

[tex]z=xe^y,\ x=u^2-v^2,\ y=u^2 v^2[/tex]. Using partial differentiation, ∂z/∂u = [tex]2ue^y + 2uv^2xe^y[/tex] and ∂z/∂v = [tex]-2ve^y + 2u^2\ vxe^y[/tex].

How to apply partial differentiation?

To find the partial derivatives ∂z/∂u and ∂z/∂v, we will differentiate the function [tex]z = xe^y[/tex] with respect to u and v while keeping other variables constant.

Given:

[tex]z = xe^y,\\x = u^2 - v^2,\\y = u^2v^2.[/tex]

First, let's express z in terms of u and v by substituting the expressions for x and y into z:

[tex]z = (u^2 - v^2)e^{u^2v^2}[/tex]

Now, we can find the partial derivatives.

Partial derivative ∂z/∂u:

To find ∂z/∂u, we differentiate z with respect to u while treating v as a constant. Applying the chain rule, we have:

∂z/∂u = (∂z/∂x)(∂x/∂u) + (∂z/∂y)(∂y/∂u).

∂z/∂x = [tex]e^y[/tex],

∂x/∂u = 2u,

∂z/∂y =[tex]x * e^y[/tex],

∂y/∂u = [tex]2uv^2[/tex].

Substituting these values, we get:

∂z/∂u = [tex](e^y)(2u) + (x * e^y)(2uv^2)[/tex].

∂z/∂u = [tex]2ue^y + 2uv^2xe^y[/tex].

Partial derivative ∂z/∂v:

To find ∂z/∂v, we differentiate z with respect to v while treating u as a constant. Applying the chain rule, we have:

∂z/∂v = (∂z/∂x)(∂x/∂v) + (∂z/∂y)(∂y/∂v).

∂z/∂x = [tex]e^y[/tex],

∂x/∂v = -2v,

∂z/∂y = [tex]x * e^y[/tex],

∂y/∂v = [tex]2u^2v[/tex].

Substituting these values, we get:

∂z/∂v = [tex](e^y)(-2v) + (x * e^y)(2u^2v)[/tex].

∂z/∂v = [tex]-2ve^y + 2u^2vxe^y[/tex].

Therefore, the partial derivatives are:

∂z/∂u = [tex]2ue^y + 2uv^2xe^y[/tex],

∂z/∂v =[tex]-2ve^y + 2u^2\ vxe^y.[/tex]

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Answer:b

Step-by-step explanation:

The function f(t) = 5sin(3t) + 4 represents the oscillations of the spring it had an amplitude of 5, a frequency of 3/(2pi), and a midline of 4 option second is correct.

It is defined as the number of waves that crosses a fixed point in one second known as frequency. The unit of frequency is per second.

We have amplitude A = 5

Frequency f = 3/(2π)

Midline m = 4

The equation for the simple periodic motion is given by:

f(t) = Asin(wt+∅) + m

Here phase angle ∅ = 0

We know:

w = 2πf

w = 2π(3/2π)

w = 3

Put all the values in the equation:

f(t) = 5sin(3t) + 4

Thus, the function f(t) = 5sin(3t) + 4 represents the oscillations of the spring it had an amplitude of 5, a frequency of 3/(2pi), and a midline of 4

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