draw a rough sketch of india to show the densely populated states any two​

Answer:

400N is applied to the rope

Answer:

300N

Explanation:

Assuming his friend didn't throw the box, they would need a total of 1,500N to lift it, if the first person is already applying 1,200N, the only other amount of force needed is 300N to make a total of 1,500N! Simple math problem :)

Hope this helps! <3

Answer:

El delfín nada a una profundidad de 22 m

Explanation:

El principio fundamental de la hidrostática establece que la presión en un punto del interior de un fluido (presión hidrostática) es directamente proporcional a su densidad, a la profundidad que se encuentre dicho punto y a la gravedad del sitio en el que se encuentre el fluido.

Esto se expresa como:

P=ρ⋅g⋅h

donde:

En este caso:

Reemplazando:

2.22*10⁵ Pa= 1,030 [tex]\frac{kg}{m^{3} }[/tex] * 9.8 [tex]\frac{m}{s^{2} }[/tex] * h

Resolviendo:

[tex]h=\frac{2.22*10^{5} Pa}{1,030\frac{kg}{m^{3} }*9.8 \frac{m}{s^{2} }}[/tex]

h= 21.993 m ≅ 22 m

El delfín nada a una profundidad de 22 m

Answer:

The surface closest to the balloon becomes positively charged, while the far side of the can becomes negatively charged. This results in an attractive force that draws the can to the balloon.

Explanation:

Answer:

The balloon is negatively charged.

Explanation:

hope it helps

Answer:

Explanation:

Strain of a material is the ratio of its extension to its original length.

strain = e/lo

e is the extension

lo is the original length

For a copper rod;

e = 2.00 * 10^-2mm

lo = 1.00m

convert 1.00m to mm

1.00m = 1*10^-3mm

get the strain

Strain = 2.00 * 10^-2mm/1*10^-3mm

Strain = 2 * 10^{-2+3}

Strain = 2*10^1 = 20

For the steel

e = 2.00 * 10^-3mm

lo = 0.100m

convert 0.100m to mm

0.1m = 0.1*10^-3mm

0.1m = 10^-4mm

get the strain

Strain = 2.00 * 10^-3mm/10^-4mm

Strain = 2 * 10^{-3+4}

Strain = 2*10^1 = 20

Since the value of their strain are the same, this means that they a re under the SAME tensile strain. No one is greater that the other.

The rod under greater tensile strain is ; Neither of them i.e. They both have the same tensile strain

Given data :

Cross sectional area of copper rod = 0.5 cm²

Length of copper rod  = 1.0 m  = 1 * 10³ mm

Elongation of copper rod ( Ec )  = 2.0 * 10⁻² mm

For Steel

Cross sectional area of steel = 0.5 cm²

Length of steel rod = 0.1 m  = 1 * 10² mm

Elongation of steel rod  ( Es )=  2.0 * 10⁻³ mm

Determine the Tensile strain of each rod

i) For copper rod

Tensile strain = Ec / Length of copper rod

                       = ( 2.0 * 10⁻² ) /  ( 1 * 10³ )

                       = 2.0 * 10⁻⁵

ii) For the steel rod

Tensile strain = Es / Length of steel rod

                       = ( 2.0 * 10⁻³ ) / ( 1 * 10² )

                        = 2.0 * 10⁻⁵

The Tensile strain for the copper rod and the steel rod is the same ( 2.0 * 10⁻⁵ ) This means that both rods are under the same tensile strain

Learn more : https://brainly.com/question/24024159

Answer:

i would be that annoying child lol

Explanation:

but i just needed this for points sorry :>

Answer:

Correlation

Explanation: Answer for Ap3x

V = I • R

V = (0.054 A) • (152 ohms)

V = 8.208 volts

None of the listed choices is correct.

Answer:

melanie ran 8.3 meters per second

Explanation:

I think thats right, hope it helps.

Answer:

erosion

Explanation:

Answer:

b 43 kg

Explanation:

mass doesn't differ from place to place.

but the weight may

Answer:

Abdul has an apparent weight of 600 newtons.

Explanation:

The statement is incorrectly written. Its correct form is:

Abdul of mass 50 kg is standing in an elevator of his building. The elevator is moving upwards and is slowing down at a rate of 2.0 m/s2. What is Abdul's apparent weight? Use g = 10 m/s2.

According to the statement, we know that elevator and Abdul himself are moving upwards and decelerating, which means that Abdul feels a force from elevator is the same direction of his weight. From 2nd Newton's Law we find the following equation of equilibrium:

[tex]\Sigma F = F-m\cdot g = m\cdot a[/tex] (1)

Where:

[tex]F[/tex] - Apparent weight, measured in newtons.

[tex]m[/tex] - Mass of Abdul, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]a[/tex] - Net acceleration of the elevator-Abdul system, measured in meters per square second.

In (1) we clear the apparent weight:

[tex]F = m \cdot (a+g)[/tex]

If we know that [tex]m = 50\,kg[/tex], [tex]a = 2\,\frac{m}{s^{2}}[/tex] and [tex]g = 10\,\frac{m}{s^{2}}[/tex], we find that the apparent weight of Abdul is:

[tex]F = (50\,kg)\cdot \left(2\,\frac{m}{s^{2}}+10\,\frac{m}{s^{2}} \right)[/tex]

[tex]F = 600\,N[/tex]

Abdul has an apparent weight of 600 newtons.

Complete Question

A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the ball's time in the air until it hits the ground to be 4.3 s. How far does the baseball travel horizontally?

Answer:

The distance covered horizontally is  [tex]d = 43 \ m[/tex]

Explanation:

From the question we are told that

     The initial horizontal velocity is  [tex]u = 10 \ m/s[/tex]

     The time taken by the ball in the air is  [tex]t = 4.3 \ s[/tex]

Generally the distance traveled by the ball is  

       [tex]d = u * t[/tex]

=>     [tex]d = 10 * 4.3[/tex]

=>     [tex]d = 43 \ m[/tex]

Answer:

a. TRUE

Explanation:

When a satellite is launched to orbit around earth, it has to produce its own artificial gravity by performing rotations. The frequency of this rotation is given by the following formula:

f = √[ac/4πR²]

where,

f = frequency

ac = centripetal acceleration

R = Radius of the satellite

Therefore, it is clear from this formula that the frequency of rotation of the satellite is independent of its height above the surface of earth. So, the correct option is:

a. TRUE

Answer:

The coefficient of friction in the hall is 0.038

Explanation:

Given;

mass of the Parker, m = 73.2 kg

applied force on the parker, F = 123 N

frictional force, Fs = 27.4 N

the coefficient of friction in the hall = ?

frictional force is given by;

Fs = μN

Where;

μ is the coefficient of friction

N is normal reaction = mg

Fs = μmg

μ = Fs / mg

μ = (27.4) / (73.2 x 9.8)

μ = 0.038

Therefore, the coefficient of friction in the hall is 0.038

Answer:

B. 4 times

Explanation:

Fg'=G(2m1)(2m2)/d²

Fg'=4Gm1m2/r²

Answer:  Kinetic energy is energy that an object has as a result of its motion. Potential energy is stored energy that has not yet been released.

Explanation:  All moving objects possess kinetic energy, which is determined by the mass and speed of the object. Potential energy is the energy an object has as a result of its position.

Answer:

It has potential energy

PE = 15450.75 J

Explanation:

we know its potential energy because the carriage is not moving, although it can

PE = mgh

in this case, m is 75, h is 21, and g is always 9.81

plug these in: PE = (75) (21) (9.81)

your answer: PE = 15450.75 J

Answer:

Can some body plz explain me plzzz

Answer:

1.Your friend says "no thanks" to the dinner your dad cooked and prefers to just hang out with friends instead.

2. Your teammates keep making fun of you for spending so much time studying for Friday's math test.

3. Your coworkers spend every weekend watching movies at Tim's house and invite you to join them.

4. Your friends all sign up for a free class at the gym and suggest you sign up for it, too.

Answer:

B

Explanation:

The pattern that the double slit experiment produces is a diffraction pattern (made as a result of single and double slit interference).

Answer:

B. It is the result of diffraction.

Explanation: a p e x

Answer:

Abstract

A methodology for designing mechanical non-uniform motion generators is presented. The basic requirements for four-bar and six-bar linkages are established and it is shown how the performance can be evaluated by harmonic analysis applied to the output angular velocity function. A means of creating and searching a library of mechanisms based on normalized output functions is presented. B-spline curves are used as a means of defining a desired performance and it is shown how minimum acceleration can be achieved with continuity in the derivatives. Finally, a means of increasing the quality of motion transmission in the selected mechanisms is given. The techniques are used to synthesize a six-bar linkage.