The car’s velocity as a function of time is b + 2ct and the car’s average velocity during this interval is 0.9 m/s.
Average velocity of the carThe average velocity of the car is calculated as follows;
x(t) = a + bt + ct2
v = dx/dt
v(t) = b + 2ct
v(0) = -10.1 m/s + 2(1.1)(0) = -10.1 m/s
v(10) = -10.1 + 2(1.1)(10) = 11.9 m/s
Average velocityV = ¹/₂[v(0) + v(10)]
V = ¹/₂ (-10.1 + 11.9 )
V = 0.9 m/s
Thus, the car’s velocity as a function of time is b + 2ct and the car’s average velocity during this interval is 0.9 m/s.
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Within the visible spectrum, our experience of red is associated with ________ waves of light.
Within the visible spectrum, our experience of red is associated with a longer wavelength of light.
What is the electromagnetic spectrum?The electromagnetic spectrum is seen as colors: violet, indigo, blue, green, yellow, orange, and red. Blue light has a very short wavelength, and so produces a higher amount of energy.
In the visible spectrum, the longer wavelengths that we perceive as red are followed by intermediate wavelengths for green and shorter wavelengths for blue and violet.
Our perception of red is connected to a longer wavelength of light within the visible spectrum.
Hence longer wavelength is the correct answer for blanks.
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The atmospheric pressure at the surface of titan is.
Answer:
about 1.5 bars
Titan's atmosphere is similar to Earth's both in the predominance of nitrogen gas and in surface pressure, which is about 1.5 bars, or 50 percent higher than sea-level pressure on Earth.
Explanation:
Which piece of furniture will have the most inertia and give the furniture movers the most difficulty in moving?
a 50kg couch
a 5kg dining chair
a 75kg dining table
an 10kg end table
Answer:
75kg dining table
Explanation:
its the heaviest
more force would be required to push it
so it has greater inertia
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Answer:
C.
Explanation:
EDGE 2023
Find the potential energy of a 40kg cart that is on a hill that is 10 meters high
Explanation:
P.E. = mgh
PE = 40 × 10 × 10
PE = 4000 Joule
can you guys help me please
brainliest if correct answer
when a metal sphere is dropped in to a tall cylinder containing liquid its acceleration is g÷2 (gravity over 2) show that : density of metal =2density of liquid
The density of the metal sphere is 2 times the density of the liquid as proved.
Net upward force acting on the metal sphere
The net upward force acting on the sphere as it is dropped into the liquid is calculated as follows;
F = σVg - ρVg
ma = σVg - ρVg
where;
ρ is density of the liquidσ is the density of the metala is acceleration of the metalσV(a) = σVg - ρVg
σ(a) = σg - ρg
σ(g/2) = σg - ρg
g(σ/2) = g(σ - ρ)
σ/2 = σ - ρ
σ/2 - σ = - ρ
-σ/2 = - ρ
σ = 2ρ
Thus, the density of the metal sphere is 2 times the density of the liquid as proved.
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A train traveled 250 km from its starting point in 5 hours. If the train continues at the same average speed for another 4 hours, what is the total distance traveled from its starting point?
Answer:
200
Explanatio
sample ananswer
A pile of 60 sheet’s of paper is 6mm high. Calculate the average thickness of a sheet of the paper
Answer:
0.1 mm
Explanation:
60 sheets = 6 mm
We want 1 sheet so we divide both sides by 60 :
1 sheet = 6/60 mm
1 sheet = 1/10 mm
1 sheet is 0.1 mm
Hope this helped and brainliest please
If a lever has an input arm of 80 cm and an output arm of 20 cm, what is its ideal mechanical advantage?
Answer:
16
Explanation:
explain the law of conservation of energy in your own words
Answer:
The law of conservation of mass states that the total energy of an isolated system remains constant over time.
Explanation: Hope it helps you :))))
Have a good day
[tex] \textbf{Can someone help me with this question ? } [/tex]
[tex] \textsf{I need proper Explanation} [/tex] ~
Recall the formula of refractive index
[tex]\sf \mu =\dfrac{sini}{sinr}[/tex]
i is angle of incidencer is angle of refractionAs per the diagram
At AD angle of incidence i is
[tex]\\ \rm\Rrightarrow \gamma=sin^{-1}\left(\dfrac{1}{\dfrac{n_1}{n_2}}\right)[/tex]
[tex]\\ \rm\Rrightarrow \gamma=sin^{-1}\left(\dfrac{n_2}{n_1}\right)[/tex]
That's reverse for BC tooAt AB's imaginary boundary line
Use snell's law
[tex]\\ \rm\Rrightarrow \dfrac{\mu_1}{\mu_2}=\dfrac{sin\alpha}{sin\beta}[/tex]
[tex]\\ \rm\Rrightarrow \mu_1sin\alpha=\mu_2sin\beta[/tex]
[tex]\\ \rm\Rrightarrow n_2sin\alpha=n_1sin\left(\dfrac{\pi}{2}-\gamma\right)[/tex]
[tex]\\ \rm\Rrightarrow n_2sin\alpha=n_1cos\left(sin^{-1}\left(\dfrac{n_2}{n_1}\right)\right)[/tex]
we need [tex]\sf \alpha[/tex][tex]\\ \rm\Rrightarrow sin\alpha=\dfrac{n_1}{n_2}cos\left(sin^{-1}\dfrac{n_2}{n_1}\right)[/tex]
[tex]\\ \rm\Rrightarrow \underline{\boxed{\bf{\alpha=sin^{-1}\left[\dfrac{n_1}{n_2}cos\left(sin^{-1}\dfrac{n_2}{n_1}\right)\right]}}}[/tex]
Option A
3) A photon is emitted as the electron in a hydrogen
atom drops from the n = 5 energy level directly to
the n = 3 energy level. What is the energy of the
emitted photon?
(1) 0.85 eV
(2) 0.97 eV
(3) 1.51 eV
(4) 2.05 eV
From the information provided and the calculations, the energy of the drop is 1.51 eV
What is the Rydberg formula?The Rydberg formula is used to obtain the energy of a photon or the wavelength of a photon.
Thus;
1/λ = 1.097 * 10^7 (1/3^2 - 1/5^2)
1/λ = 1.097 * 10^7(0.11 - 0.04)
λ = 1.3 * 10^-6 m
Since;
E = hc/λ
E = 6.6 * 10^-34 * 3 * 10^8/1.3 * 10^-6
E = 1.51 * 10^-19 J or 1.51 eV
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Answer:
0.97eV
Explanation:
The energy emitted during n=5 is 0.54 eV
The energy emitted during n=3 is 1.51 eV
(This information is on the Physics Reference Table 2006 edition)
We find the change in the energy level which is:
1.51eV-0.54eV = 0.97eV
Therefore the energy emitted by the photon is 0.97eV.
which is heavier a pound of bricks or a pound of feather
Answer:
pound of bricks
meh wrong ? XD
Answer:
neither is heavier.both are equal
Explanation:
since 1 pound equals 16 oz.(1 pound=16 oz.).,both are equal too!
Who produces more work? Which one produces more power?
Person A pushes a box with 100 N of force for 3 meters in 6 seconds
Person B pushes a box with 100 N of force for 5 meters in 20 seconds
The person that produces more power is Person A because its power is 50watts.
Calculation of powerFor person A = Power= ,work done/ time
But work done = force × distance
person A = 100×3/6
= 300/6
= 50watts
For person B = 100×5/20
= 500/20
= 25watts
Therefore, the person that produces more power is Person A because its power is 50watts.
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What are 2 factors affecting friction?
Answer:
xhxzguztyayrayhNzxlhhlिगजि
When a positively charged body touches a neutral body, the neutral body will
label the diagram Please
The earth tilt about 23 degrees which leads to the formation of seasons on earth.
At what degree the earth tilt?This is tilted at 23 degrees from the vertical. The northern hemisphere is in the winter season.
This is the path as the earth revolves around the sun. It takes 1 year to complete this path.
This is the path as the earth rotates around its.
So we can conclude that the earth tilt about 23 degrees which leads to the formation of seasons on earth.
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A man pushes a shopping cart full of groceries at a constant velocity. What happens if the man DECREASES the force of his push on the cart?
A. The cart slows down.
B. The cart speeds up.
C. The cart moves at the same speed.
D. The cart becomes less massive.
If the man DECREASES the force of his push on the cart, the cart slows down.
Force acting on bodyThe force applied to an object is determined by applying Newton's second law of motion.
F = ma
where;
m is mass of the bodya is acceleration of the bodya = Δv/t
F = (mΔv)/t
mΔv = Ft
Δv = Ft/m
From the equation above, when the applied force decreases, the change in velocity decreases.
Thus, if the man DECREASES the force of his push on the cart, the cart slows down.
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Express 9.39 x 109 seconds in terms of days.
Answer:
108680.6 days
Explanation:
1 day = 24 hours there is 3600 seconds in 1 hour
so 24 * 3600 = 86400 so there is 86400 second in a day
so the take t = time s = seconds
t = 9.39 * 10^9s * 86400
t = 108680.6 days
Hope This Helped
Maria throws two stones from the top edge of a building with a speed of 20 m/s. She throws one straight down and the other straight up. The first one hits the street in a time t1. How much later is it before the second stone hits
Maria throws two stones from the top edge of a building at a speed of 20 m/s, The time is mathematically given as
t=4.5 sec.
How much later is it before the second stone hits?Generally, the equation for speed is mathematically given as
V = u+at
Therefore
0 = 22-9.8xt.
t = 22 /9.8 sec
t = 2.24489.
The same time will be taken from max^m height to point O
The extra time is taken
t=4.49 sec.
t=4.5 sec.
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It takes 25N or force to drag a box along the floor at a constant speed. If the coefficient of friction is .3, what is the mass of the box?
The mass of the box is 8.5 kg.
What is mass?Mass can be defined as the quantity of matter contained in a body.
To calculate the mass of the box, we use the formula
Formula:
F = mgμ............. Equation 1Where:
F = Forcem = mass of the boxg = acceleration due to gravity μ = coefficient of frictionMake m the subject of the equation
m = F/gμ..................... Equation 2From the question,
Given:
F = 25 Ng = 9.8 m/s²μ = 0.3Substitute these values into equation 2
m = 25/(0.3×9.8)m = 25/2.94m = 8.5 kgHence, the mass of the box is 8.5 kg.
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A 4 kg block is pushed 2m at an acceleration of 0.2 meter per second square up a vertical wall by constant force f applied at an angle of 37 degree with the horizontal if the coefficient of kinetic friction between the block and the wall is 0.30 find the work done by the applied force the frictional force
The work done by the applied force on the block against the frictional force is 15.75 J.
What is work done?Work done is equal to product of force applied and distance moved.
Work = Force x Distance
Given is a 4 kg block is pushed 2m at an acceleration of 0.2 meter per second square up a vertical wall by constant force f applied at an angle of 37 degree with the horizontal if the coefficient of kinetic friction, μ between the block and the wall is 0.30.
From the equilibrium of forces acting on the block, we have
F - f = ma
where, F is applied force, f is frictional force, m is the mass and a is the acceleration.
Frictional force f = μmgsinθ
Substitute the values, we get
Fcos(37) - μmgsin(37) = ma
Fcos(37) - (0.3)(4)(9.8)sin(37) = 4(0.2)
0.799F - 7.077 = 0.8
F = 9.86 N
Work done by the applied force is
W = Fdcosθ
W = 9.86 x 2 x cos(37)
W = 15.75 J
Thus, the work done by the applied force on the block against the frictional force is 15.75 J.
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21. A 1000-kg automobile moving with a speed of 24 m/s relative to the road collides with a 500-kg automobile initially at rest. If the two stick together, what is the velocity in m/s of the two cars after the collision according to an observer in a truck moving 10 m/s in the same direction as the moving cars
A truck is moving with less velocity in the direction in which the truck is moving earlier because the truck has more momentum.
In which direction the truck moves?A truck is moving with the velocity of 10 m/s in the same direction in which the truck is moving earlier because the truck has more mass so it has more momentum. Due to collision, the velocity of the truck is slow down but can't be stopped because of high momentum in the truck.
So we can conclude that a truck is moving with less velocity in the direction in which the truck is moving earlier because the truck has more momentum.
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A bicycle is ridden along a horizontal road with a driving force of 400, n,400n. its speed is constant at 12, m, slash, s,12m/s. what is the magnitude of the sum of the frictional forces acting on the bike and its rider?
The magnitude of the sum of the frictional forces acting on the bike and its rider is 400N.
What is friction force?The friction force is the opposing force which acts on the object which is in relative motion.
The driving force is equal and opposite to the friction force acting between road and bicycle.
Friction force = 400N
The friction force between rider and bike is zero.
So the magnitude of sum of friction force = 400N +0 = 400N
Thus, the magnitude of the sum of the frictional forces acting on the bike and its rider.
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Alllura is running to the blue lion so she can join the others in forming voltron. if allura starts off
running at 2.50m/s and after 3.00s she has reached a velocity of 8.25m/s. what is her acceleration
over this time in meters per second
The acceleration will be 1.9166 m/s². According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
What is acceleration?The rate of change of velocity with respect to time is known as acceleration.
Given data:
u(Initial velocity)=2.50m/s
v(Final velocity)=8.25m/s
t(time period)= 3.00s
The acceleration of the Allura will be :
[tex]\rm a = \frac{v-u}{t} \\\\ a= \frac{8.25-2.50 }{3.00 }\\\\ a= 1.9166 \ m/s^2[/tex]
Hence, the acceleration will be 1.9166 m/s².
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What is the net force needed to lift a full grocery sack (weighing 210 N) uniformly? What is the net force
needed to accelerate the grocery sack upward at 1.5 m/s2 ?
The net force needed to lift a full grocery sack uniformly is 32.115 N.
What is Net force?When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.
Given the weight of sack W = 210N and the acceleration a = 1.5m/s².
The mass of the sack will be
m = Weight / acceleration due to gravity
m = 210 N/9.81 m/s²
m = 21.41 kg
Using Newton's second law, the net force will be
F = mass x acceleration
F= 21.41 x 1.5
F = 32.115 N
Thus, the net force is 32.115 N.
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An object with charge -4.0μC is placed between a positively charged object to the
left and a negatively charged object to the right that exert electric fields with magnitudes of 1.2 N/C and 1.4 N/C respectively.
What is the net force on the -4.0μC object as a result of this net field?
The net force on the -4.0μC object as a result of this net field will be -10.4 N.
What is the charge?
The matter has an electric charge when it is exposed to an electromagnetic field is known as a charge.
The electric field intensity is found as the force per unit charge.
Electric field intensity on the positive charge:
[tex]\rm E_1 = \frac{F_1}{Q} \\\\\ \rm 1.2 N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_1 = - 4.8 \ N[/tex]
Electric field intensity on the negative charge:
[tex]\rm E_2 = \frac{F_2}{Q} \\\\\ \rm 1.4 \ N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_2 = - 5.6 \ N[/tex]
The net charge is the algebraic sum of the two charges;
[tex]\rm F_{net}=F_1+F_2 \\\\ F_{net}= -4.8 -5.6 \\\\ F_{net}=-10.4 \ N[/tex]
Hence, as a result of this net field, the net force on the -4.0C object will be -10.4 N.
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After picking up several staples with the device, what change would enable tony to drop the staples in the scrap metal bin? removing the battery removing the iron nail moving the wire loops closer together spreading the wire loops farther apart
The change that would enable to drop of the staples in the scrap metal bin after picking up several staples with the device is removing the battery.
What is a battery?A battery is a device that helps us to store electricity to be used accordingly when it is required for a machine.
Moreover, a device may be defined as any tool developed to perform a specific type of work.
In conclusion, the change that would enable to drop of the staples in the scrap metal bin after picking up several staples with the device is removing the battery.
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Question 10 of 34
Julia walks from the park 6 blocks east of her house to the store 3 blocks
east of her house. The walk takes Julia 5 minutes. What is her average
velocity on this walk?
OA. 0.6 blocks/min east
OB. 1.2 blocks/min
O C. 1.8 blocks/min
OD. 0.6 blocks/min west
Julia walks from the park, which is six blocks east of her house, to the store, which is three blocks east of her house. Julia walks for 5 minutes. This walk's average speed will be 1.2 blocks per minute. Option B is correct.
What is displacement?Displacement is defined as the shortest distance between the two points. Distance is the horizontal length covered by the body. While displacement is the shortest distance between the two points.
Displacement is a vector quantity .its unit is m.
The average velocity on this walk will be;
[tex]\rm v_{avg}= \frac{d}{t} \\\\ \rm v_{avg}= \frac{6 \ block+ 3 \ block }{5 \ minute } \\\\ v_{avg}=1.4 \ block /min[/tex]
Hence option B is correct.
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A large truck is moving at 22.0 m/s. if its momentum is 125,000 kg • meters per second, what is the truck's mass? 176 kg 2750 kg 5680 kg 11,400 kg
The mass of the large truck is determined as 5680 kg.
Mass of the truck
The mass of the truck is calculated as follows;
P = mv
where;
P is momentumm is massv is velocitym = P/v
m = 125000/22
m = 5680 kg
Thus, the mass of the large truck is determined as 5680 kg.
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Answer:
C. 5680
Explanation:
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