Edwin raps for 10 minutes on Monday. On Tuesday he raps for an
hour. Find out how many minutes he has practiced so far this week.

Answers

Answer 1

Answer:1 hour and 10 mins

Step-by-step explanation: on Monday he raps for 10

Tuesday he raps for 1 hour

1 h +10m =1 h and 10 min


Related Questions

Write 40/64 in simplest

Answers

5/8 is the simplified fraction for 40/64

Suppose f has absolute minimum value m and absolute maximum value M. Between what two values must 7 f(x) dx 4 lie?Which property of integrals allows you to make your conclusion?

Answers

Answer:

3m ≤ ∫ f(x) dx ≤ 3M, at limit of b, a

Step-by-step explanation:

Like the question asked, which property of integral was used.

Property 8 of integrals was the basis upon which the question was solved.

The property of the integral is used to solve the problem. The function is given below.

[tex]3m & \leq \int_a^b f(x)dx \leq 3M \end{aligned}[/tex]

What is a function?

The function is an expression, rule, or law that defines the relationship between one variable to another variable. Functions are ubiquitous in mathematics and are essential for formulating physical relationships.

Suppose f has absolute minimum value m and absolute maximum value M.

We know that the property of the integral can be used.

If m ≤ f(x) ≤ M ∀ a ≤ x ≤ b. Then we have

[tex]m (b-a) \leq \int_a^b f(x) dx \leq M(b-a)\\[/tex]

Then we have

[tex]m \leq f(x) \leq M \ \ and \ \ 4 \leq x \leq 7[/tex]

This means that

[tex]\begin{aligned} m(7-4) & \leq \int_a^b f(x)dx \leq M(7-4)\\\\3m & \leq \int_a^b f(x)dx \leq 3M \end{aligned}[/tex]

More about the function link is given below.

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a medical transcriptionist has a four drawer cabinet. one drawer is 4/5 full and one is 1/2 full and one drawer is 3/4 full. can the contents be combined into 3 drawers why or why not

Answers

Answer:

Yes, provided they are all the same size.

Step-by-step explanation:

4/5=0.8

1/2=0.5

3/4=0.75

0.8+0.5+0.75=n

8+5=13

0.8+0.5=1.3

1.3+0.75=2.05

Without suffering of.....

Write the following words as an algebraic expression. The sum of the quotient of a number x and 5 and the product of 6 and a number y

Answers

Answer:

[tex]\frac{x}{5} + 6y[/tex]

Step-by-step explanation:

what is the average of the following numbers 66.9,5.6,70.1​

Answers

Answer:

47.53

Step-by-step explanation:

First you add all of the numbers together.

66.9+5.6+70.1=142.6

Then you divide the sum of numbers by how many number there are.

142.6/3=47.53

-6mn + 5mn - 3x2 - 4x2
Help

Answers

Answer:

Step-by-step explanation:

3x^2 - 4x^2 - 6mn + 5mn

-x^2 - mn

the perimeter of the isosceles triangle with base length y-2 and legs of length y

Answers

Answer:

3y-2

Step-by-step explanation:

y+y+y-2

3y-2

The perimeter of the isosceles triangle with base length y - 2 and length of legs y is 3y - 2. legs.

Here,

Base length of triangle is y - 2.

Length of legs of triangle is y.

What is Perimeter of triangle?

Perimeter of triangle is sum of all three sides of a triangle.

Now,

Base length of triangle is y - 2.

Length of legs of triangle is y.

Perimeter = y - 2 + y + y

               = 3y - 2

Hence, The perimeter of the isosceles triangle with base length y - 2 and legs of length y is 3y - 2.

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The length of a toucan is about two thirds the length of a macaw. Toucans are about 24 in. long. What is the length of macaw

Answers

Answer:

12, 12 and 12 so 36

Step-by-step explanation:

1. The point A(-4,6) is rotated 90 degrees counterclockwise and then translated 3 units up.
What is the point A'?
A
(-6, -7)
B. (-6, -1)
C. (6.7)
D. (9.7)

Answers

Answer:

Step-by-step explanation:

Adam built a tree house with a rectangular base. The length of the base is 7 inches more than its width.
Ifw represents the width of the tree house, which inequality could be used to determine what lengths would make the area of the base
of the tree house greater than 293 square Inches?
W + 7 > 293
202 + 286 > 2,051
w2 + 7w > 293
12 + 293 > 293
Submit

Answers

w²+7w>293 is the inequality which we use to determine what lengths would make the area of the base of the tree house greater than 293 square Inches

What is Area of Rectangle?

The area of Rectangle is length times of width.

Given that Adam built a tree house with a rectangular base.

The length of the base is 7 inches more than its width.

Length=W+7

W is the width

The area of the base of the tree house greater than 293

We need to find the inequality to represent the area of the base of tree

Area of rectangle=Length×width

293=(w+7)w

293=w²+7w

As area is greater we have

w²+7w>293

Hence, w²+7w>293 is the inequality which we use to determine what lengths would make the area of the base of the tree house greater than 293 square Inches

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6) 6a + 34 = -3(-2a + 8)​

Answers

step 1: open up the brackets ( rmb to flip the signs )

step 2: bring 'a' to one side and the numbers to the other

6a + 34 = -3(-2a + 8)

6a + 34 = 6a - 24

6a - 6a = -24 - 34

0 = - 58

the final ans is kind of weird but here's my solution :))

what Is the area of the trapezoid​

Answers

18m

Step-by-step explanation:

5x3=15 +3 =18

how does "money breeds money" apply to simple interest

Answers

Answer:

The saying money breeds money means that with money, you have the possibility to create more money. Simple interest is the idea that you have something, and you obtain a percentage of that every designated time period. That being said, simple interest = money breeds money

What is the missing value A=3 b=5 c=?

Answers

Answer:

4

Step-by-step explanation:

Please answer I will make you Brainliest if it's right How do I do this step by step??

Answers

Answer:

[tex] \sqrt{2 \times 2 \times 2 \times 3 } = \sqrt{24} = \sqrt{4 \times 6} = 2 \sqrt{6} [/tex]

Answer:

Step-by-step explanation:

Divide $70 in the ratio 1:2:4

Answers

Answer:

Here Ratio=1:2:4

total money =$70

Step-by-step explanation:

let the ratio number be 1x,2x and4x

Now,

1x+2x+4x =$70

or, 7x. =$70

or, x. =$70÷7=$10

again,

1x=1×$10=$10,

2x=2×$10=$20 and

4x=4×$10=$40

Question 1 (1 point)
What is the slope of the line that passes through the points
(8,-15) and (-12,25)?
A No answer provided
a 2
6.-2
c15
D-1/2

Answers

Answer:

B) -2

Step-by-step explanation:

[tex]\frac{25-(-15)}{-12-8} =\frac{40}{-20} =-2[/tex]

17. Write a quadratic equation to find two consecutive odd natural numbers whose
product is 63. Then find the numbers

Answers

Answer:

7 and 9

Step-by-step explanation:

So we want two consecutive odd numbers whose product is 63.

Let's write an equation.

Let's let n be a random integer: doesn't matter what it is. Therefore, the first integer must be 2n+1.

This is because we're letting n be whatever it wants to be. If we multiply that whatever number by 2, then it will turn even. If we add 1 to an even number, it becomes odd.

Therefore, our first odd number is (2n+1). Our second, then, must be (2n+3).

Multiply them together. They equal 63. Thus:

[tex](2n+1)(2n+3)=63[/tex]

Expand:

[tex]4n^2+6n+2n+3=63[/tex]

Combine like terms:

[tex]4n^2+8n+3=63[/tex]

Subtract 63 from both sides:

[tex]4n^2+8n-60=0[/tex]

Divide both sides by 4:

[tex]n^2+2n-15=0[/tex]

And now, factor:

[tex](n+5)(n-3)=0[/tex]

Zero Product Property:

[tex]n+5=0\text{ or } x-3=0[/tex]

Find n:

[tex]n=-5\text{ or } n=3[/tex]

So, we've found n.

Then the first integer is either:

[tex]2(-5)+1 \text{ or } 2(3)+1[/tex]

Evaluate:

[tex]-9 \text{ or } 7[/tex]

However, we want two consecutive odd natural numbers. So, ignore the -9.

Therefore, our first odd integer is 7.

And our second one would be 9.

So, our answer is 7 and 9.

And we're done!

Polygon QQQ is a scaled copy of Polygon PPP using a scale factor of \dfrac1221​start fraction, 1, divided by, 2, end fraction. Polygon QQQ's area is what fraction of Polygon PPP's area?

Answers

Answer: Area of Polygon Q is  [tex]\dfrac14[/tex]  of  Area of Polygon

Step-by-step explanation:

Given: Polygon Q is a scaled copy of Polygon P using a scale factor of [tex]\dfrac12[/tex] .

According to the property of scale factor ,

Area of the image = (scale factor )²x (Area of the original figure)

So, Area of Polygon Q = [tex](\dfrac12)^2[/tex]  x (Area of Polygon P)

⇒ Area of Polygon Q = [tex]\dfrac14[/tex]  x (Area of Polygon P)

Hence,  Area of Polygon Q is   [tex]\dfrac14[/tex]  of  Area of Polygon P.

Answer:

1/4

I did on khan

Step-by-step explanation:

Choose the function to match the graph.

Answers

Answer:

your pics a little blurry but if i am reading it right

the first one

f(x)=log x+5

What function do you know from calculus is such that its first derivative is itself?The above function is a solution of which of the following differential equations?a. y = ey.b. y = 1.c. y = y.d. y = y2.e. y = 2y.What function do you know from calculus is such that its first derivative is a constant multiple k of itself? The above function is a solution of which of the following differential equations?a. y = ky.b. y = yk.c. y = eky.d. y = k.e. y = y + k.

Answers

Answer:

a.  y= e raise to power y

c. y = e^ky

Step-by-step explanation:

The first derivative is obtained by making the exponent the coefficient and decreasing the exponent by 1 . In simple form the first derivative of

x³ would be 2x³-² or 2x².

But when we take the first derivative of  y= e raise to power y

we get y= e raise to power y. This is because the derivative of e raise to power is equal to e raise to power y.

On simplification

y= e^y

Applying ln to both sides

lny= ln (e^y)

lny= 1

Now we can apply chain rule to solve ln of y

lny = 1

1/y y~= 1

y`= y

therefore

derivative of e^y = e^y

The chain rule states that when we have a function having one variable and one exponent then we first take the derivative w.r.t to the exponent and then with respect to the function.

Similarly when we take the first derivative of  y= e raise to power ky

we get y=k multiplied with e raise to power ky. This is because the derivative of e raise to a  constant and power is equal to constant multiplied  with e raise to power y.

On simplification

y= k e^ky

Applying ln to both sides

lny=k ln (e^y)

lny=ln k

Now we can apply chain rule to solve ln of y ( ln of constant would give a constant)

lny = ln k

1/y y~= k

y`=k y

therefore

derivative of e^ky = ke^ky

Simplify the expression using
order of operations
12 (10-5) - 40 + (4+1)

Answers

ans is 25

Step-by-step explanation:

12(10-5)-40+(4+1)

=12 of 5 - 40 + 5

= 60 - 40 +5

=60 +5 - 40

=65-40

=25

Answer:

-25

Step-by-step explanation:

We start off by using PEMDAS. 10-5 then 4+1.

12(5)-40+5

we multiply, then add and subtract giving us -25

Write a rule to describe each transformation.
11. P (3,4), Q (3,5), R (4,5), S (5,0)

to

P’ (0,3), Q’ (0,4), R’ (1,4), S’ (2,-1) 12.

F (-4,1), E (-4,3), D (-1,3) to

F’ (1,4), E’ (3,4), D’ (3,1)

B (-3, -5), C (-2,-2), D (-1,-2) to

B’ (3,-5), C’ (2,-2), D’ (1,-2)

Answers

I need points lol so I’m just doing stuff

At noon, the temperature in Ebonsville, Texas was 29℉. By midnight, the temperature had fallen to −10℉. What was the change in temperature over the 12-hour period?

Answers

Answer:

i believe it's 39

Step-by-step explanation:

29 -39 = -10

What is equivalent to 6/25. A.0.20 B.0.22 C. 0.24 D. None

Answers

Answer:

C. .024

Step-by-step explanation:

You multiply 25 by 4 to get 100 and then you multiply 6 by 4 to get twenty four. After that you divide both numbers by one hundred and you get C

Combine like terms: A. 7a + 7b - 13a - 11b B. -5a - 12a + 2b - 3b Explain

Answers

A. 7a i have done this before

laws of Sines. Find each measurement indicated. Round your answers to nearest tenth​. Part 1

Answers

Answer:

1) 19.0km

2) 23.9mi

3) 53.9yd

4) 30.0mi

(all answers rounded off to the nearest tenth)

Step-by-step explanation:

Please see the attached pictures for full solution.

-1
The distance AB
rounded to the
nearest tenth = [?]
Help Resources
-2
-1
0
Skip
B
Hint: Use the distance formula:
d = (x2 – X1)2 + (y2 - yı)?
Enter

Answers

Answer:

AB = 4.5

Step-by-step explanation:

Distance between A(-1, 2) and B(1, -2):

[tex] AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Let,

[tex] A(-1, 2) = (x_1, y_1) [/tex]

[tex] B(1, -2) = (x_2, y_2) [/tex]

[tex] AB = \sqrt{(1 - (-1))^2 + (-2 - 2)^2} [/tex]

[tex] AB = \sqrt{(2)^2 + (-4)^2} [/tex]

[tex] AB = \sqrt{4 + 16} = \sqrt{20} [/tex]

[tex] AB = 4.5 [/tex] (nearest tenth)

In a hockey game, Seth took 12 shots and scored 3 times.
Zak took 10 shots and scored twice. Who scored on a
greater fraction of his shots?

Answers

Answer:

Seth

Step-by-step explanation:

Seth:

3/12 = 0.25

0.25*100 = 25%

Seth scored at 25%

Zak:

2/10 = 0.2

0.2*100 = 0.2

0.2*100 = 20%

Zak scored at 20%

then:

25>20

then:

Seth scored on a greater fraction of his shots.

Zak scored on a greater fraction of his shots.

Given,

In a hockey game, Seth took 12 shots and scored 3 times.

Zak took 10 shots and scored twice.

We need to find who scored on a greater fraction of his shots.

How do we compare fractions?

We can compare fractions by finding their decimal values a nd comparing them.

Example: 1/2 and 2/5

1/2 = 0.5

2/5 = 0.4

0.5 is greater than 0.4.

Find the number of score Seth shots out of 12 shots.

= 3

We can write in fractions as:

3/12 _____(1)

Find the number of score Zak shots out of 10 shots.

= 2 x 3

= 6

We can write in fractions as:

6/10 _____(2)

Compare (1) and (2)

3/12 = 1/4 = 0.25
6/10 = 3/5 = 0.6

0.25 is less than 0.6

6/10 is a greater fraction than 3/12

Thus Zak scored on a greater fraction of his shots.

Learn more about how to compare fractions here:

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Suppose we are estimating a population proportion by its sample equivalent.
(a) We have a sample of n = 10 units and we find the proportion is p = .4. If the true proportion is p= .3 find PC Ô-p|>.2)
(b) Consider the same problem as in part (a) but now, our sample size is n = 400. Find P( P-p> .001)

Answers

Answer:

(a) 0.16759

(b)  0.9649

Step-by-step explanation:

Given that:

n = 10 , p = 0.3 and  [tex]\hat p = 0.4[/tex]

[tex]P(|\hat p - p| > 0.2 ) = 1 - P ( |\hat p -p| \leq 0.2)[/tex]

= [tex]1 - P(-0.2 \leq \hat p-p \leq 0.2)[/tex]

= [tex]1 - P \begin {pmatrix} \dfrac{-0.2}{\sqrt{\dfrac{pq}{n}}} \leq \dfrac{\hat p -p}{\sqrt{\dfrac{pq}{n}}} \leq \dfrac{0.2}{\sqrt{\dfrac{pq}{n}}} \end {pmatrix}[/tex]

[tex]=1 - P \begin {pmatrix} \dfrac{-0.2}{\sqrt{\dfrac{(0.3)(1-0.3)}{10}}} \leq Z \leq \dfrac{0.2}{\sqrt{\dfrac{(0.3)(1-0.3)}{10}}} \end {pmatrix}[/tex]

[tex]=1 - P \begin {pmatrix} \dfrac{-0.2}{\sqrt{\dfrac{(0.3)(0.7)}{10}}} \leq Z \leq \dfrac{0.2}{\sqrt{\dfrac{(0.3)(0.7)}{10}}} \end {pmatrix}[/tex]

[tex]=1 - P \begin {pmatrix} \dfrac{-0.2}{\sqrt{0.021}} \leq Z \leq \dfrac{0.2}{\sqrt{0.021}} \end {pmatrix}[/tex]

[tex]=1 - P \begin {pmatrix} -1.380 \leq Z \leq 1.380 \end {pmatrix}[/tex]

= 1 - P( Z ≤ 1.380) - P(-1.380)

= 1 - ( 0.91620 - 0.08379 )

= 1 - 0.83241

= 0.16759

b) when n = 400; p =0.3 , q = 1 - p = 1 - 0.3 = 0.7

[tex]P( |\hat p - p | > 0.001) = 1- P ( |\hat p - p | < 0.001 )[/tex]

[tex]= 1- P ( -0.001 < \hat p - p < 0.001 )[/tex]

[tex]= 1- P ( \dfrac{-0.001}{\sqrt{\dfrac{pq}{n}}} < \dfrac{ \hat p - p}{\dfrac{pq}{n}} < \dfrac{0.001}{\sqrt{\dfrac{pq}{n}}} )[/tex]

[tex]= 1- P ( \dfrac{-0.001}{\sqrt{\dfrac{0.3\times 0.7}{400}}} < Z < \dfrac{0.001}{\sqrt{\dfrac{0.3 \times 0.7}{400}}} )[/tex]

[tex]= 1- P ( \dfrac{-0.001}{\sqrt{5.25 \times 10^{-4}}} < Z < \dfrac{0.001}{\sqrt{5.25 \times 10^{-4}}} )[/tex]

[tex]= 1- P ( -0.0436< Z < 0.0436)[/tex]

= 1 - P ( Z < 0.0436) - P ( -0.0436)

= 1 - (0.5176 - 0.4825)

= 1 -  0.0351

= 0.9649

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