Elias algebraic expression could not be found, however, the correct way of writing the expression is given below.
Answer:
X - 5
Step-by-step explanation:
To write an algebraic expression for the phrase 5 less than a number ; this means that we subtract from a certain number, x, the value 5
That is ; given a particular number, x ; 5 is then subtracted from it ;
Explicitly, it is written as : X - 5 ; where x is the number.
pls help me do this question but pls don't get it wrong this is my last attempt
Answer:
y ≤ 5
Step-by-step explanation:
5 is the highest y value in this graph. All other y values are below 5.
[tex]9x {}^{2} y {}^{3} z {}^{5} \div 6x {}^{3} yz {}^{2} [/tex]
Answer:
3y²z³ / 2x
Step-by-step explanation:
we can take one term at a time:
9/6 can be simplified to 3/2
x²÷x³ = x^-1 which equals [tex]\frac{1}{x}[/tex]
y³÷y = y²
z⁵÷z² = z³
put it all together:
3·[tex]\frac{1}{x}[/tex]·y²·z³ / 2 or
3y²z³ / 2x
In parallelogram JKLM if m
Answer:
155 degree
Step-by-step explanation:
x + 25 = 180 degree (sum of adjacent angles of a parallelogram are equal)
x = 180 - 25
x = 155 degree
Evaluate [315 + 6) + 2] : 7
23
O
0
03
05
Answer:
323 : 7
Step-by-step explanation:
[ ( 315 + 6 ) + 2 ] : 7
[ 321 + 2 ] : 7
323 : 7
HELP THIS IS FOR MY FINAL GRADE
Ida's ice-cream stand has increasing profits each week during the hot summer months. Ida finds that each week during the summer her profits increase by 15% over what they were the previous week. In her first week of business, her profits were $600. How much money will she make in all over 5 weeks?
Answer:
Ida makes $ 6960 in 5 weeks.
Step-by-step explanation:
Let the profit of the first week is p.
p = $ 600
Total profits of the five weeks
= p + (p + 0.15p) + (p + p +0.15 p) + (p + p + p + 0.15 p) + (p + p + p + p + 0.15 p)
= 11 p + 0.6 p
= 11 x 600 + 0.6 x 600
= 6600 + 360
= $ 6960
So, Ida makes $ 6960 in 5 weeks.
Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sample data below show the number of companies providing health insurance for small, medium, and large companies. For the purposes of this study, small companies are companies that have fewer than employees. Medium-sized companies have to employees, and large companies have or more employees. The questionnaire sent to employees asked whether or not the employee had health insurance and then asked the enployee to indicate the size of the company. Health Insurance Size of Company Yes No Total Small 33 17 50 Medium 68 7 75 Large 88 12 100 a. Conduct a test of independence to determine whether health insurance coverage is independent of the size of the company. What is the -value? Compute the value of the test statistic (to 2 decimals). The -value is - Select your answer - Using level of significance, what is your conclusion? - Select your answer - b. A newspaper article indicated employees of small companies are more likely to lack health insurance coverage. Calculate the percentages of employees without health insurance based on company size (to the nearest whole number). Small Medium Large Based on the percentages calculated above, what can you conclude? - Select your answer -
Answer:
There is not enough statistical evidence to suggest that the health insurance coverage is independent of the size of the company
Step-by-step explanation:
The given data presented in tabular form is presented as follows;
[tex]\begin{array}{llcr}&Health \ Insurance&\\Size \ of \ Company & Yes &No &Total\\Small&34&16&50\\Medium&61&14&75\\Large&85&15&100\end{array}[/tex]
The null hypothesis, H₀; The two data are independent
The alternative hypothesis Hₐ; The variables are dependent
[tex]Expected \ value = \dfrac{(Row \ total) \times (Column \ total) }{Table \ total}[/tex]
The expected value are the values in parenthesis in the following table;
[tex]\begin{array}{llcr}&Health \ Insurance&\\Size \ of \ Company & Yes &No &Total\\Small&34(40)&16(10)&50\\Medium&61(60)&14(15)&75\\Large&85(80)&15(20)&100\\Total&180&45&225\end{array}[/tex]
[tex]\chi ^2 = \sum{\dfrac{ \left(O_i - E_i \right)^2}{E_i}[/tex]
Therefore
χ² = (34 - 40)²/40 + (16 - 10)²/10 + (61 - 60)²/60 + (14 - 15)²/15 + (85 - 80)²/80 + (15 - 20)²/20 ≈ 6.1458
The degrees of freedom = (2 - 1)·(3 - 1) = 2
The p-value from the Chi-square table is 0.05 < p-value < 0.01
Given that the p-value is larger than the significant value, we have that data is not statistically significant and we fail to reject the null hypothesis.
Therefore, the health insurance coverage is independent of the size of the company
the data below shows.the number of car thefts in a city for a period of 20 days. complete parts (a) and (b) below.
a. draw an ordered stem and leaf plot for the data.
b. revealed when answer a is complete.
Answer:
13 cars per day
Step-by-step explanation:
64 - 51 = 13 cars per day
hope it helps
A man invests K8 000 for 5 years at 10%p.a. compound interest.
Calculate the investment value at the end of 5 years.
Answer:
Step-by-step explanation:
Compoud interest is the addition of interest to the principal sum of a loan or deposit, or in other words, interest on interest. the formula is:
[tex]c_n=c_o(1+i)^n\\\\c_o->initial~invesment\\i->interest\\n->number~of~ intervals[/tex]
[tex]c_5=8000(1+\frac{10}{100})^5\\c_5=12848.88[/tex]
What is the volume of the cylinder shown below?
Your response should show all necessary calculations and diagrams.
Answer:
126cm^2
Step-by-step explanation: brainliest pleaseeee!!!!
[tex] {x}^{2} + \sqrt{x} + \sqrt[5]{x} [/tex]
what is f'(3) of this equation?
Answer:
[tex]3 + \frac{1}{2\sqrt{3} } + \frac{1}{5\sqrt[5]{81} }[/tex]
Step-by-step explanation:
Just to make it easier to see, [tex]\sqrt{x} = x^{\frac{1}{2} }[/tex] and [tex]\sqrt[5]{x} = x^{\frac{1}{5} }[/tex] This way we could more easily use the power rule of derivatives.
So if f(x) = [tex]x^{2} +x^{\frac{1}{2} } +x^{\frac{1}{5} }[/tex] then f'(x) will be as follows.
f'(x) = [tex]x^{1} +\frac{1}{2} x^{-\frac{1}{2} } +\frac{1}{5} x^{-\frac{4}{5} } = x +\frac{1}{2x^{\frac{1}{2} }} +\frac{1}{ 5x^{\frac{4}{5} }} = x +\frac{1}{2\sqrt{x}} +\frac{1}{ 5\sqrt[5]{x^4} }[/tex]
to find f'(3) just plug 3 into f'(x) so [tex]3 + \frac{1}{2\sqrt{3} } + \frac{1}{5\sqrt[5]{81} }[/tex]
Plot the points (-6,8)(−6,8)left parenthesis, minus, 6, comma, 8, right parenthesis and (0,8)(0,8)left parenthesis, 0, comma, 8, right parenthesis on the coordinate plane below.
Answer:
hello I cant help you right now try again later
If a equals B andB equals C which statement must be true?
Answer:
A=B=C... wouldn't both B and C be equal to A? Also I can't see the statements.
The quotient of 17 and k
Answer:
17/k
Step-by-step explanation:
Quotient means division
17/k
Answer:
[tex] \frac{17}{k} [/tex]Step-by-step explanation:
Quotient means a result obtained by dividing one quantity by another.
Hope it is helpful...A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 20% of the employees suffered lost-time accidents last year. Management believes that a special safety program will reduce such accidents to 10% during the current year. In addition, it estimates that 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.
Required:
a. What percentage of the employees will experience lost-time accidents in both years?
b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?
Answer:
a. 5% of the employees will experience lost-time accidents in both years
b. 24% of the employees will suffer at least one lost-time accident over the two-year period
Step-by-step explanation:
a. What percentage of the employees will experience lost-time accidents in both years?
20% last year, of those who suffered last year, 25% during this year. So
[tex]p = 0.2*0.25 = 0.05[/tex]
5% of the employees will experience lost-time accidents in both years.
b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?
5% during the two years.
10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.
So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.
First year yes, not on the second.
75% of 20%. So, total:
[tex]0.05 + 0.05*0.8 + 0.75*0.2 = 0.24[/tex]
24% of the employees will suffer at least one lost-time accident over the two-year period
¿Qué pasó en La Noche Triste?
Step-by-step explanation: La Noche Triste (Spanish for "The Sad Night") was a famous battle between the Spanish conquistadors and the Aztecs, a native people of Mexico. ... Between 400 and 800 Spanish soldiers were killed or captured. Between 2,000 and 4,000 native Mexican allies of the Spanish were killed or captured.
Location: Tenochtitlan
End date: July 1, 1520
Date: June 30
Answer: was a famous battle between the Spanish conquistadors and the Aztecs, a native people of Mexico. Between 400 and 800 Spanish soldiers were killed or captured. Between 2,000 and 4,000 native Mexican allies of the Spanish were killed or captured.
Step-by-step explanation:
The lines below are parallel. If the slope of the green line is -4, what is the slope of the red line? 5 m = O A. 4 B. -4 O c. 1 4 D. 4
Answer:
-4
Step-by-step explanation:
If the lines are parallel, then they have the same slope.
If the green line has a slope of -4, then the red line has a slope of -4
Which inequality is true?
А. Зп > 9
B. 7 + 8< 11
C. 27 -1 < 5
D. 2 > 2
SUBMIT
< PREVIOUS
9514 1404 393
Answer:
А. Зп > 9
Step-by-step explanation:
The inequality of A may or may not be true. (It is true only if n > 3.) All of the others are definitely false.
Consider the following generic fixed effects model, along with a two-period (t = 1, 2), randomly sampled panel data set with dependent variable y and independent variable x: y_it = beta_0 + delta_0 d2_t + beta_1x_it + a_i + u_it where y_it = value of y for individual i at time t d2_t = binary variable equal to 1 in the second time period (t = 2), and 0 otherwise (t = l) x_it = value of x for individual i at time t a_i = unobserved (time-invariant) effect u_i = idiosyncratic error Taking the first difference of the model (that is, subtracting the regression equation for t=l from the regression equation for t=2) yields the following first-differenced equation: delta y_i = y_i2 - y_i1 = You now plan to use OLS to estimate your first-differenced equation, in order to obtain the first-differenced estimator. Suppose that delta x_i is correlated with delta u_i. True or False: The first-differenced estimator is unbiased.
A. True
B. False
Answer:
True
Step-by-step explanation:
The difference estimator is used to address the problem of omitted variables. It is used with standard fixed effects model and the data correlated is identified using regression model. The first differenced estimator used in the equation is unbiased.
A ladder is put against a building. The building is 25 feet tall. The ladder's base is 13.5 feet from the building. Find the angle which the ladder makes with the ground.
Answer:
correct me if i'm wrong but it's 57.32 degrees?
Help with number 4 I'm stuck on this algebra test with my kid and neither of us understand it
Answer:
a) x = 4
b) x = 8
c) y = -7
d) y = -10
Step-by-step explanation:
Solve by substitution on all
a)
3x + 2y = -5
3x +2 * -17/2 = -5
3x - 17 = -5
3x = -5+17
3x = 12
x = 12/3
x = 4
Construct the 90% confidence interval for the proportion of students at the college who have completed their required English 101 course. Enter your answers as decimals (not percents) accurate to three decimal places. The Confidence Interval is
Answer:
The confidence interval has an lower limit of [tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}[/tex] and an upper limit of [tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}[/tex], in which [tex]\pi[/tex] is the sample proportion and [tex]n[/tex] is the size of the sample.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
90% confidence level
So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
The confidence interval has an lower limit of [tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}[/tex] and an upper limit of [tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}[/tex], in which [tex]\pi[/tex] is the sample proportion and [tex]n[/tex] is the size of the sample.
Please help me!!!!!!!!
Answer:
fraction is 75/100
decimal is 0.75
Step-by-step explanation:
because there are 75 of them that are shaded out if 100 so 75/100 and to find out in decimal 75÷100=0.75.
hope this helps u understand:)
Can someone please help me:(
[tex]\huge\bf{\color{Green}{Question:}}[/tex]
Find the volume of each solid. Round to the nearest tenth.[tex]\huge\bf{\color{orange}{Solution:}}[/tex]
Volume of the solid given = Volume of the small cone + Volume of the large cone.
[tex]\sf{V(solid)=V(small)+V(large)}[/tex]
[tex]\sf{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{3}π(5)²7+\frac{1}{3}π(5)²11}[/tex]
[tex]\sf{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:=\frac{25}{3}π(7+11)}[/tex]
[tex]\sf{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:=\frac{25}{3}π(18)}[/tex]
[tex]\sf{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:=150π}[/tex]
[tex]\sf{\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:≈{\color{magenta}{471.2 in³}}}[/tex]
=======================#Hope it helps you, mate!
(*°∀°)=3
A standard deck of 52 cards has 4 suits (spades, clubs, hearts, and diamonds) with 13 different cards (ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king) in each suit. If you are dealt exactly two cards from the deck without replacement, what is the probability that you are dealt a pair (matching cards in different suits)
Answer:
P(a pair with matching cards in different suits) = 1/52
Step-by-step explanation:
We are told that there are 4 suites and each suit has 13 different cards. This is a total of 52 cards.
Thus;
Probability of selecting one card of a particular suit = 13/52 = 1/4
If we now want to select a matching card of another suit without replacing the first one, then, we now have; 52 - 13 = 39 cards. Now, there are only 3 matching cards of the 3 remaining suits that is same as the first card drawn.
Thus; probability = 3/39 = 1/13
Thus;
P(a pair with matching cards in different suits) = 1/4 × 1/13
P(a pair with matching cards in different suits) = 1/52
What is the approximate circumference of a circle with a radius of 4?
1. 12.57
2. 25.13
3.50.27
4. 16
[tex]{ \bf{ \underbrace{Given :}}}[/tex]
Radius of the circle = 4.
[tex]{ \bf{ \underbrace{To\:find:}}}[/tex]
The approximate circumference of the circle.
[tex]{ \bf{ \underbrace{Solution :}}}[/tex]
[tex]\sf\orange{The\:circumference \:of\:the\:circle\:is\:≈\:25.13.}[/tex]
2.) 25.13 ✅
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
We know that,
[tex]\sf\purple{Circumference\:of\:a\:circle \:=\:2πr }[/tex]
[tex] = 2 \times \frac{22}{7} \times 4 \\ \\ = \frac{176}{7} \\ \\ = 25.14[/tex]
Therefore, the circumference of the circle is ≈ 25.13.
[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♡}}}}}[/tex]
if △ABC = △DEF, which side is congruent to EF?
A. AB
B. BC
C. AC
Answer:
BC
Step-by-step explanation:
BECAUSE BC IT'S EQUAL TO EF
Answer:
B. BC
Step-by-step explanation:
By SSS rule in ∆ ABC and DEF,
AB = DEBC = EFCA = FDb b
A jar of her 'low-sugar' jam contains 102 grams of sugar.
What is the percentage of sugar in her 'low-sugar' jam?
Answer:
[tex]\% Low = 30 \%[/tex]
Step-by-step explanation:
Given
[tex]Total = 340g[/tex] -- missing
[tex]Low = 102g[/tex]
Required
% of sugar in Low
This is calculated as:
[tex]\% Low = \frac{Low}{Total} * 100\%[/tex]
So, we have:
[tex]\% Low = \frac{102g}{340g} * 100\%[/tex]
[tex]\% Low = \frac{102}{340} * 100\%[/tex]
[tex]\% Low = \frac{10200}{340} \%[/tex]
[tex]\% Low = 30 \%[/tex]
If the mean of a normal distribution is 105, what is the median of the distribution? O A 315 OB. 105 O C. 420 D. 210 SUBM
Answer:
105
Step-by-step explanation:
A normal or symmetrical distribution where each the distance between each side of the distribution to the midpoint is the same, a normal distribution, also called a symmetrical distribution has the se value for both its median and mean. Hence, if the mean of a normal distribution is x, then it's median will also be x.
For the scenario given,
Since mean = 105 ; then median = 105
Find the value of x.
Answer:
A
Step-by-step explanation:
because this shapes angle would be out of 360 so you do 360-83-85-69=123 is the answer you get.
hope it make sense:)
A line passes through the point (8. -8) and has a slope of
5/4
Write an equation in slope-intercept form for this line.
Answer:
y = 5/4x - 18
Step-by-step explanation:
The slope, intercept form of a straight line is;
y = bx + c
Where, y = slope, given as 5/4
(x, y) is given as ; (8, - 8)
Hence, we need to obtain the value of c, which is the intercept.
x = 8 ; y = - 8
-8 = 5/4x + c
-8 = 5/4(8) + c
-8 = 10 + c
-8 - 10 = c
-18 = c
Hence, equation becomes ;
y = 5/4x - 18