en un rectnagulo de 17 cm de ancho y su diagonal mide 26 cm ¿cuanto mide el rectangulo de largo?

Answers

Answer 1

Answer:

[tex]x=19.67[/tex]cm

Step-by-step explanation:

Por Pitágoras,

[tex]x^{2} = 26^{2} - 17^{2} \\\\x^{2} = 676 - 289\\\\x^{2} =387\\\\x=\sqrt{387} \\\\x=19.67[/tex]


Related Questions

Answer for brainlest

Answers

Answer:

∠1 = ∠8

Step-by-step explanation:

Because they are ALTERNATE EXTERIOR ANGLE

Answer:

∠1 = ∠8

Step-by-step explanation:

Because alternate exterior angles are equal.

Also there is no angle given so you cant work them out.

simply put:

∠1 = ∠8

∠1 = ∠4

∠3 = ∠2

∠1 = ∠5

∠2 = ∠6

∠2 = ∠7

∠5 = ∠8

∠4 = ∠8

∠7 = ∠6

∠7 = ∠3

Let me know if I missed out on anymore! It was long that's why.

Hope this kind of explained it :)

This is a 4th grade level
Ethan puts $1200 into a Certificate of Deposit (CD) account that earns 2.1% interest each year. What will be the interest of the CD account earned after 5 years? Round to the nearest cent (hundredths place).

Answers

Answer:

126

Step-by-step explanation:

1200 x .021=25.20 interest per year

25.20x5=126

assumes no compounding

For an angle to be in standard position, its vertex is at the origin and the initial side lies on the

A) positive y-axis. B) positive x-axis. C) negative x-axis. D) negative x-axis.

Answers

Answer:

B) positive x-axis.

Step-by-step explanation:

angle to be in standard position, its vertex is at the origin and the initial side lies along the positive x axis

Answer:

Positive x axis

Step-by-step explanation:

The angle lies in standard position means it begins from Q1

The first side must be x axis

Then in Q1 x>0 so it's positive x axis

Anyone know this answer

Answers

Answer:

Step-by-step explanation:

1 is 60 2 i 60 and 3 is 61 ;)

The answer should be 61, goodluck ;)

Cindy has a chocolate box whose length is 12 cm, height of 8 cm, and width of 6 cm. Find the volume of the box?

WITH SOLUTION PLEASE​

Answers

Hello there I hope you are having a great day :) Cindy has a chocolate box whose length is 12 cm, height of 8 cm, and width of 6 cm. Find the volume of the box?

V = L x W x H

Volume = length x Width x Height.

12cm x 6cm x 8cm = V = 576cm^3

so the answer is 576cm^3

Hopefully that helps you :)

ANSWER the volume of the box is 576 CM³

Step-by-step explanation:

VOLUME : is the quality of three deamination place enclosed by a closed surface it is the space that substance or shape or keep use or contains it is measured in cubic units

A RACTANGULAR :is a three dimensional figure it has length wind and height

to find the value of the box we need to multiply length buy it wide and by its height

v=l x w x h

let us analysis the problem above

GIVEN :

length =12 cm

height = 8 cm

width=6 cm

SOLUTION :

v=1 x w x h

=(12 CM) x (8 CM) x (6 CM)

=576 cm³

FINAL ANSWER(:

the value of the box is 576 CM ³

Please help with this question

Answers

9514 1404 393

Answer:

  4. (d) 4.38 in³

  5. (b) 19 gallons

  6. (a) 6.4 yd³

Step-by-step explanation:

4. The equation can be rearranged to find the compressed volume.

Multiply both sides by the compressed volume:

  (compression ratio)×(compressed volume) = (expanded volume)

Divide both sides by the compression ratio:

  (compressed volume) = (expanded volume)/(compression ratio)

Fill in the numbers and do the arithmetic.

  compressed volume = 46.0 in³/(10.5/1) = 4.38 in³

The compressed volume is about 4.38 in³.

__

5. The area to be covered is 3170 ft². We want to cover it twice, so the total area we want to cover is 2×3170 ft² = 6340 ft². One gallon of paint covers 350 ft². We want to find the smallest integer number of gallons n such that ...

  n×(350 ft²) ≥ 6340 ft²

Dividing by the coefficient of n, we have ...

  n ≥ 6340/350 ≈ 18.11

The smallest integer value of n is 19. 19 gallons of paint will be needed.

__

6. The quantity of sand needed (q) is proportional to the area to be covered, so we have ...

  q/(400 yd²) = (1.6 yd³)/(100 yd²)

Multiplying both sides of this equation by 400 yd² gives ...

  q = (1.6 yd³)(400/100) = 6.4 yd³

6.4 yd³ of sand will be needed.

what could the expression below represent? please help

Answers

Answer:

third

Step-by-step explanation:

arctan of ( opp/adj) = arctan( 10/15 )

the shadow is 15 so 10 must be the height of the streetlight and

arctan (10/15) is the angle between the ground and the line from the edge of the shadow to the top of the streetlight

The equation $x + {y = 2 can be rewritten in a form that reveals the y-intercept of the graph of the equatior
Drag numbers to complete the equation that is equivalent to $x + žy = 2 and show the value of the y-intercept

Answers

Answer:

[tex]y = \frac{2}{z} - \frac{x}{z}[/tex]

Step-by-step explanation:

Given

[tex]x + zy = 2[/tex]

Required

Rewrite to show y-intercept

We have: [tex]x + zy = 2[/tex]

Subtract x from both sides

[tex]zy = 2-x[/tex]

Divide both sides by z

[tex]y = \frac{2}{z} - \frac{x}{z}[/tex]

The y intercet is: [tex]\frac{2}{z}[/tex]

You fllp a fair coln 7 times in a row. Let X be the number of heads that come up. Which of the following cannot be a
possible value of X?
2
0
7
16

Answers

Answer:

16

Step-by-step explanation:

Given

A coin

[tex]n = 7[/tex] --- Number of flips

[tex]x \to heads[/tex]

Required

Which can't be the value of x

From the question, we understand that the coin was flipped 7 times.

This means that, the highest occurrence of head is:

[tex]x = 7[/tex]

And the list is:

[tex]x = 0[/tex]

So, the range of x is:

[tex]x = \{0,1,2,....,7\}[/tex]

In the above range, only (16) is out of range.

Hence:

[tex]x \ne 16[/tex] --- Number of heads can't be 16

can someone help me with this math problem please? One hundred ten students are assigned to four classrooms as equally as possible. How many students are in each classroom? (Write four numbers in all show how many students are in each room?​

Answers

Answer:

27.5

Step-by-step explanation:

Answer:

27.5

Step-by-step explanation:

110/4 is 27.5

Twice a number is 14. What is the number

Answers

Answer:

7

Step-by-step explanation:

Divide 14 by 2

Which of the following CANNOT be true for a triangle?

A. A triangle can be equilateral and obtuse at the same time.
B. A triangle can be equilateral and equiangular at the same time.
C. A triangle can be isosceles and right at the same time.
D. A triangle can be scalene and obtuse at the same time.

Answers

Answer:

A. A triangle can be equilateral and obtuse at the same time

Step-by-step explanation:

All angles in an equilateral triangle are 60° therefore they cannot be above 90° and less than 180°

Anybody know this one? I’m set that it is B but I am not too sure

Answers

Answer:

D

Step-by-step explanation:

It is D because there are only 3 sides given. I understand where you were going with B, but there is no angle given, (and you cannot prove one either), so the answer is simply D.

A - There is no angle, triangle does not matter

B - There is no angle, triangle is correct

C - It is similar, they have the same scale factor

D - There are 3 sides, and the triangle is correct

VALUE OF X PLEASE ASAP

Answers

Answer:

Hello! answer: x = 40

Step-by-step explanation:

These are vertical angles meaning they will have the same measure.

40 × 3 = 120 120 - 16 = 104 therefore x = 40 hope that helps!

Product of 32.56 and 1.4

Answers

Answer:

45.584

;)

Have a nice day

Brianne earns $20 for 4 hours of babysitting. Which graph shows the relationship between the number of hours and the total amount she earns?

Answers

Answer:

Can you insert a picture?  and then I could help you.

Step-by-step explanation:

Answer:

Brianne would earn 5 dollars an hour so the graph should look something like this.

PLease help!! Will mark brainliest for right answer!! NO LINKS

Let f(x)=10/x−4 . What is the average rate of change of f(x) from 2 to 8 ?
Enter your response as a decimal.

Answers

Answer:

[tex]f(x) = \frac{10}{x} - 4 \\ \delta \: f(x) = \frac{f(8) - f(2)}{2} \\ = \frac{(\frac{10}{8} - 4) - ( \frac{10}{2} - 4)}{2} \\ = \frac{ \frac{ - 11}{4} - 1}{2} \\ = \frac{ \frac{ - 15}{4} }{2} \\ = - \frac{15}{8} [/tex]

what is the solution set for this inequalty? -8x + 40> -16

Answers

Answer:

x < 7

Step-by-step explanation:

-8x + 40> -16

Subtract 40 from each side

-8x + 40-40> -16-40

-8x >-56

Divide each side by -8, remembering to flip the inequality

-8x/-8 < -56/-8

x < 7

The moving company
charges extra money to move boxes weighing more than
25 pounds. Circle the packages that weigh less than 25 pounds.
Put an X on the packages that weigh more than 25 pounds.
320 ounces
480 ounces
288 ounces
368 ounces
352 ounces
432 ounces

Answers

480 ounces and 432 ounces exceed the 25 pound limit.

the rest are under 25 pounds.

what is the value of x?

Answers

the answer is 35 I did a lot of work I can't show you here


Show that the transformation T defined by
T(x1, x2) = (2x1 - 3x2, X1+4, 5x2) is not linear.

Answers

Let u = (1, 0) and v = (0, 1). Then

T (u) = (2*1 - 3*0, 1 + 4, 5*0) = (2, 5, 0)

T (v) = (2*0 - 3*1, 0 + 4, 5*1) = (-3, 4, 5)

=>   T (u) + T (v) = (-1, 9, 5)

but

T (u + v) = T (1, 1) = (2*1 - 3*1, 1 + 4, 5*1) = (-1, 5, 5)

=>   T (u + v) ≠ T (u) + T (v)

which means T does not preserve addition, so it is not linear.

What function equation for the input/output table

Answers

Answer: The answer would be y = x + 8

Step-by-step explanation:

Suppose a fair six sided die has been relabeled so that the 6 is replaced with another 5,i.e., the sides read 1,2,3,4,5,5. If the die is rolled five times, what is the probability that we roll five distinct values

Answers

Answer:

P(rolling five distinct values) = 1/3888

Step-by-step explanation:

We are told that I the fair sided dice, 6 is replaced with 5.

Thus,the numbers are now;

1,2,3,4,5,5.

This means a total of 6 possible numbers appearing.

Now, in these 6 numbers there are only 5 distinct numbers since 5 occurs twice.

P(1) = 1/6

P(2) = 1/6

P(3) = 1/6

P(4) = 1/6

P(5) = 2/6

Thus,probability of rolling 5 distinct values = 1/6 × 1/6 × 1/6 × 1/6 × 2/6 = 1/3888

use special right triangle:
What is the length of (BD)

What is the length of (BC)

Answers

Answer:

BC = 6.9

Step--step explanation:

Reference angle = 30°

Adjacent = BC

Hypotenuse = 8

Apply trigonometric function, CAH:

Cos 30° = Adj/Hypotenuse

Cos 30° = BC/8

8*Cos 30° = BC

6.92820323 = BC

BC = 6.9 (to the nearest tenth)

Do girls read more than boys during the summer? Serena's class asked
30 parents to estimate how many pages their child read over the summer. They
collected the following data.
Girls: 10 30 230 130 110 240 150 260 60 230 100 20 50 160 90 pages
Boys: 210 100 0 40 260 240 200 220 190 150 50 100 12 140 40 pages
Make parallel box plots and compare the center, shape, spread, and outliers.
b. Do girls read more? How many IQRs more do they read? Use the box
plots to estimate.
a.

Answers

Answer:

Step-by-step explanation:

I dont know how to do the box thing, but I added all the things and boys read more.

girls:1870

boys:1952

The diffrence (when subracting) is 82

Move each fraction to a box to make each comparison true.

Answers

6/5<13/10
6/5=120/100
6/5>11/10
(6/5 =12/10)

Simplify (4a to the fifth power b to the sixth power) to the fourth power

Answers

Answer:

(4a^5b^6)^4 = 256a^20b^24

Step-by-step explanation:

The first person that answered is correct just let you know!

What is the equation of the curve that best fits the data? Round to the nearest hundredths, when appropriate. picture*​

Answers

Answer:

.....

Step-by-step explanation:

Up and down

solve for k. 6 = -3(k - 10)

Answers

Answer: k = 8

Step-by-step explanation:

-3k + 30 = 6

-3k = -24

k = 8

Answer:

k = 8

Step-by-step explanation:

6 = -3(k - 10)

Divide each side by -3

6/-3 = -3/-3 *(k - 10)

-2 = k-10

Add 10 to each side

-2+10 = k-10+10

8 = k

determine the term 6 generated by the rule TN is equals to n squared minus n and over 2​

Answers

Given:

Consider the rule of a sequence is:

[tex]T_n=\dfrac{n^2-n}{2}[/tex]

To find:

The 6th term generated by the given rule.

Solution:

We have,

[tex]T_n=\dfrac{n^2-n}{2}[/tex]

Substituting [tex]n=6[/tex] in the above rule, we get

[tex]T_6=\dfrac{6^2-6}{2}[/tex]

[tex]T_6=\dfrac{36-6}{2}[/tex]

[tex]T_6=\dfrac{30}{2}[/tex]

[tex]T_6=15[/tex]

Therefore, the 6th term generated by the given rule is 15.

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