Evaluate the function for the given value of x.

Answer:

answer is c

Step-by-step explanation:

Answer:

3.21869 km

Step-by-step explanation:

Answer:

8 thats how many pies and cakes you can do

Step-by-step explanation:

you have 20 minutes and 10 and the most cakes you can get with left over is 8

The pies and cakes should be made to maximize profits is 8 pies.

Profit is defined as the sum of revenue and income after all costs have been deducted by a business. A function with a business-oriented focus is called a profit function. The main goal of a business is to generate income through the sale of goods and services, minus the costs associated with producing those goods and services, in order to turn a profit.

Revenue minus costs equals profit.

Costs comprise both variable costs and fixed costs, whereas revenue is the total amount of positive cash flow that a business generates.

The maximum number of cakes you can get with leftovers in 20 minutes and 10 is 8.

Thus, the pies and cakes should be made to maximize profits is 8 pies.

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Answer:

Its BELOW sea level

Step-by-step explanation:

Answer:

[tex]F' = (-3,-3)[/tex]

[tex]G' = (-3,3)[/tex]

[tex]H' = (6,-3)[/tex]

Step-by-step explanation:

Given

The attached graph

[tex]Scale\ Factor = 1\frac{1}{2}[/tex]

Required

Determine the coordinates of F'G'H'

First, we need to get the coordinate of F, G and H from the graph

[tex]F = (-2,-2)[/tex]

[tex]G = (-2,2)[/tex]

[tex]H = (4,-2)[/tex]

The dilated coordinate is then calculated as:

[tex](FGH)' = (FGH) * Scale\ Factor[/tex]

This gives:

[tex]F' = (-2,-2) * 1\frac{1}{2}[/tex]

[tex]F' = (-2* 1\frac{1}{2},-2* 1\frac{1}{2})[/tex]

[tex]F' = (-3,-3)[/tex]

[tex]G' = (-2,2) * 1\frac{1}{2}[/tex]

[tex]G' = (-2 * 1\frac{1}{2},2 * 1\frac{1}{2})[/tex]

[tex]G' = (-3,3)[/tex]

[tex]H' = (4,-2) * 1\frac{1}{2}[/tex]

[tex]H' = (4 * 1\frac{1}{2},-2 * 1\frac{1}{2})[/tex]

[tex]H' = (6,-3)[/tex]

Answer:

$66.15

Step-by-step explanation:

(9.95x2)+(6.75x3)+26=66.15

Answer:

The Answer is 66.15 By the person above

The equation that represents the amount in dollars that she must pay for using the parking lot that month is y = 2x +10, the correct option is B.

An equation is a mathematical statement formed when two algebraic expressions are equated using an equal sign.

The equations are useful in determination of unknown parameters.

The equations are of various types, such as Trigonometric equations, quadratic equations.

The amount Tanesha pays to use the parking lot is $10

The daily amount she pays to use the parking is $2

Let x represents the days in one month.

Let y represents the amount in dollars that she must pay for using the parking lot that month.

The unknown parameters are x and y

The equation that can be formed is

y = 2x +10

It seems that your question is incomplete, the complete question is as follows:

A .  y = 2x

B. y = 2x +10

C. y = 10x +2

D. y = 10x

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Answer:

first one

Step-by-step explanation:

Answer:

Any constant that is set to equal x would have an undefined slope.  For example, x=0 is just a horizontal line, so the slope is undefined.  

Step-by-step explanation:

The slope would be undefined because in a horizontal line, the length could be anything, but there is no distance between x-values.

Answer:

X=0

Step-by-step explanation:

Answer:

Step-by-step explanation:

a). Formula to be used,

   A = P(1 + i)ⁿ

       = 100(1 + 0.09)¹

       = $109

b). Formula to be used,

   A = [tex]P(1+\frac{i}{12})^{12n}[/tex]

       = [tex]100(1+\frac{0.09}{12})^{12\times 1}[/tex]

       = [tex]100(1+0.0075)^{12}[/tex]

       = 100 × 1.0938

       = $109.38

(c). Formula to be used,

     A = [tex]Pe^{i\times n}[/tex]

         = [tex]100e^{1\times 0.09}[/tex]

         = [tex]100(e)^{0.09}[/tex]

         = $109.42

Answer:

[tex]\mathbf{((lnx)(2x^2)) -x^2 +39 =(2y^2 +(\dfrac{4}{3})(8+y^2)^{3/2})}[/tex]

Step-by-step explanation:

Given that:

[tex]x In(x) = y( 1+ \sqrt{8+ y^2}) \ } \ \dfrac{dy}{dx}[/tex]

[tex]xln(x) *dx= (y+y \sqrt{(8+y^2}) \ dy[/tex]

[tex]\int xln(x) dx = \int(y+y\sqrt{(8+y^2})) \ dy[/tex]

[tex]\int lnx (x)dx =(\dfrac{y^2}{2} +\dfrac{1}{3}(8+y^2^{)3/2})[/tex]

[tex](lnx \dfrac{x^2}{2})-\int((\dfrac{x^2}{2})\times \dfrac{1}{x} =(\dfrac{y^2}{2} +\dfrac{1}{3}(8+y^2)^{3/2})[/tex]

[tex]((lnx)(\dfrac{x^2}{2}))-\int(\dfrac{x}{2}) =(\dfrac{y^2}{2} +(\dfrac{1}{3})(8+y^2)^{3/2})[/tex]

[tex]((lnx)(\dfrac{x^2}{2}))-(\dfrac{x^2}{4}) +C= (\dfrac{y^2}{2 }+(\dfrac{1}{3})(8+y^2)^{3/2})[/tex]

For  y(1) = 1

[tex]((ln(1))(\dfrac{1^2}{2}))-(\dfrac{1^2}{4}) +C= (\dfrac{1^2}{2 }+(\dfrac{1}{3})(8+1^2)^{3/2})[/tex]

[tex](0)-(\dfrac{1}{4}) +C =(\dfrac{1}{2} +(\dfrac{1}{3})(3)^3)[/tex]

[tex]C=(\dfrac{19}{2}) +(\dfrac{1}{4})[/tex]

[tex]C=\dfrac{39}{4}[/tex]

[tex]((lnx)(\dfrac{x^2}{2}))-(\dfrac{x^2}{4}) +(\dfrac{39}{4}) = (\dfrac{y^2}{2} +(\dfrac{1}{3})(8+y^2)^{3/2})[/tex]

[tex]\mathbf{((lnx)(2x^2)) -x^2 +39 =(2y^2 +(\dfrac{4}{3})(8+y^2)^{3/2})}[/tex]

Answer:

270

Step-by-step explanation:

✔️Area of the Patio = bh

b = 12 ft = 144 in.

h = 10 ft = 120 in.

Area of Patio = 144*120 = 17,280 in.²

✔️Area of Brick Paver = bh

b = 8 in

h = 8 in

Area of the Brick Paver = 8*8 = 64 in.²

The number of quaver needed to cover the Patio = area of Patio ÷ area of one brick quaver

= 17,280/64 = 270

Answer:

False

Step-by-step explanation:

Because it is your family, does not mean you should still take it. Yes genes are transmittable and inheritable, but that doesnt mean medication should be shared unless its a guarantee for the same issue. The answer if False.

Answer: 3.498 * 10^26 % ; 16.9% per day

Step-by-step explanation:

Inflation rate = 11,000 per month

Hence, price after a month :

Final price = initial price (1 + rate)

Final price = 1 + 11000/100

Final price = (1 + 110) * initial price

Final price = 111 times the initial price

Hence inflation over the 12 month period :

(111)^12 = 3.498 * 10^24

(3.498 * 10^24) * 100% = 3.498 * 10^26 %

The daily inflation rate :

Number of days = 30

30th root of 3.498 * 10^24 = 1.169

(1.169 - 1) = 0.169

0.169 * 100% = 16.9% per day

Answer:

circumference = pi*diameter

400 = 3.14 * d

d = 400 / 3.14

d = 127.4 yards

Answer:

Step-by-step explanation:

Dimensions of the diagram:

Nadia is correct as the diagram of 27 cm × 20 cm will fit in A4 paper

Answer: 2.5

Step-by-step explanation:

For this problem, we see that 4km is 1/2 of 8km.

So, we will have to find 1/2 of 5km.

1/2 of 5km = 2.5km

Your answer is 2.5km

Answer:

2.48548 Miles or simplified 2.5

Step-by-step explanation:

You Divide by 1.609 to find the answer.  

Answer: 6 square feet

Step-by-step explanation: We simply need to do 1.5 x 4! This shows that the area of the carpet runner is 6 square feet.

Hope this helps :)

Answer:

the is option d cause big number is divided by small ones.

Step-by-step explanation:

hope it's right

Answer:

1. YZX

2. XYZ

3. ZXY

4. EDF

5. MLN

6. FED

7. DFE

8. MNL

9. LMN

1 was flipped (reflected).

2 was slid (translated).

3 was slid (translated).

4 was rotated 180 degrees clockwise.

5 was flipped and rotated.

6 was flipped and rotated.

7, 8, 9 were translated.

Answer:

i  need points

Step-by-step explanation:

i need points ,, hope you find your answer

Answer:

11

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

Answer:

6 cans will be defective

Step-by-step explanation:

do 50x0.12

Answer: a p e x 2, 15, 29.5, 41, 52

Step-by-step explanation:

The required value is [tex]\csc A=\dfrac{5}{4}[/tex].

Important information:

We need to find the exact value of csc A.

Formulae used: If angle A is in Quadrant I.

[tex]\cos A=\dfrac{1}{\sec A}[/tex]

[tex]\sin A=\sqrt{1-\cos^2 A}[/tex]

[tex]\csc A=\dfrac{1}{\sin A}[/tex]

Using these formulae, we get

[tex]\cos A=\dfrac{3}{5}[/tex]

And,

[tex]\sin A=\sqrt{1-\left(\dfrac{3}{5}\right)^2}[/tex]

[tex]\sin A=\sqrt{1-\dfrac{9}{25}}[/tex]

[tex]\sin A=\sqrt{\dfrac{16}{25}}[/tex]

[tex]\sin A=\dfrac{4}{5}[/tex]

Now,

[tex]\csc A=\dfrac{1}{\sin A}[/tex]

[tex]\csc A=\dfrac{1}{\frac{4}{5}}[/tex]

[tex]\csc A=\dfrac{5}{4}[/tex]

Thus, the required value is [tex]\csc A=\dfrac{5}{4}[/tex].

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The required value of cscA is 1.25

Given,

[tex]secA=\frac{5}{3}[/tex]

Trigonometrical ratios:

In the first quadrant, all ratios are positives.

[tex]sin A=\frac{P}{H}[/tex]

And the value of hypotenuse is,

[tex]P=\sqrt{H^2-B^2} \\=\sqrt{5^2-3^2} \\=\sqrt{16}\\ P=4[/tex]

So, the sine A is,

[tex]sinA=\frac{P}{H}\\ =\frac{4}{5}[/tex]

So, the rational denominator is,

[tex]cscA=\frac{H}{P}\\ =\frac{5}{4}\\=1.25[/tex]

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