Evidence of liquid water in mars' distant past suggests that it had a substantial atmosphere compared to what it has presently. What happened to its water vapor?.

Answers

Answer 1

Answer:

The atmosphere has frozen out into the polar ice caps and permafrost as Mars has cooled.

Explanation: Good luck box BrokenTag27


Related Questions

. Which of the following are forces that push upward on an indoor skydiver? Choose all that apply. *
gravity
acceleration
air resistance
lift


WILL GIVE BRAINLIST

Answers

The forces that push upward on an indoor skydiver are lift force and air resistance.

The forces that act on a skydiver moving downwards includes, gravity due to his weight, air resistance and lift force.

The downward forces on the indoor skydiver include the following;

gravity due to its weightdownward force due its acceleration

The upward force on the indoor skydiver include the following;

lift forceair resistance

Thus, we can conclude that the forces that push upward on an indoor skydiver are lift force and air resistance.

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Tall trees collapse in stoms, why?​

Answers

Answer: One main reason, all three experts agree, is the phenomenon known as “windthrow” which uproots a tree. “The tree trunk acts as a lever and so the force applied to the roots and trunk increases with height,” says Foster. “Taller trees are more susceptible to windthrow.”

A transformer is being built to triple the voltage produced. Which data are collected to investigate whether the transformer can achieve the goal? (1 point)

A) the ratio of the number of turns in the primary and secondary coils

B) only the number of turns in the secondary coil and the magnetic field of the core

C) only the number of turns in the primary coil and the magnetic field of the core

D) the ratio of the number of turns in the primary and secondary coils and the magnetic field of the core

Answers

Answer:

the ratio of the number of turns in the primary and secondary coils.

Explanation:

hope i'm not too late!!

If the depth of water in a well is 10m, what is the pressure exerted by it the bottom of the well ? ( Use g = 10 m/s2)
show the process as well​

Answers

Answer:

The precise answer depends on the density and therefore the temperature of the water, but we can obtain a reasonable approximation by assuming that the density of the water is 1000 kilograms per cubic meter (kg/m³).

Since the depth of the water in the well is 10 m, the volume of water directly above an area A of a square meters (m²) at the bottom of the well is 10×a m³.

Since the density of the water is 1,000 kg/m³, the mass of water directly above area A is (1,000 kg/m³) × (10×a m³) = (1000×10×a kg) = 10,000×a kg.

Since g = 9.8 m/s², the force of gravity acting on the water directly above area A is (9.8 m/s²) × (10,000×a kg) = 9.8×10,000×a N (newtons) = 98,000×a N.

So the pressure of water acting on area A is (98,000×a N)/(a m²) = (98,000×a)/a N/m² = 98,000 pascals (pa). And since A could be any given area at the bottom of the well, this is the pressure at any point at the bottom of the well.

So the pressure at the bottom of the well is 98,000 pascals (or 98,000/101,325 standard atmospheres = 560/579 atmospheres ~ 0.967 standard atmospheres).

Please comment below if you have any questions.

Describe the steps in solving the problem below.
A red cart of mass 4 kg slides to the right on a frictionless track with a velocity of +4 m/s. It collides with the stationary blue cart of mass 1 kg. After the collision, the blue cart has a velocity of +8 m/s. Calculate the velocity of the red cart after the collision. ;)


Answers

The velocity of the red cart after the collision is 2 m/s

From the law of conservation of momentum, initial momentum of system = final momentum of system.

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.

Substituting the values of the variables into the equation, we have,

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄

4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s

16 kgm/s + 0 kgm/s =  4v₃ + 8 kgm/s

16 kgm/s =  4v₃ + 8 kgm/s

16 kgm/s - 8 kgm/s =  (4 kg)v₃

(4 kg)v₃ = 8 kgm/s

Divide both sides by 4 kg, we have

v₃ = 8 kgm/s ÷ 4 kg

v₃ = 2 m/s

The velocity of the red cart after the collision is 2 m/s.

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A particular roller coaster has a mass of 3500 kg, a height of 4.0 m, and a velocity of 12 m/s. What is the kinetic energy? If needed, use g= 10. m/s^2

Answers

Explanation:

given

m=3500kg,h=4.0m,v=12m/s

ke=½mv²

½×3500×12²=3500×144÷2

=252,000j or 252j

what is the direction of the rotational velocity vector of the jar lid when you open a jar of pickles?

Answers

Answer:

Explanation:

The rotational velocity vector is directed away from the jar

What does negative acceleration mean.

Answers

When an object is slowing down, the acceleration is in the opposite direction as the velocity.

A girl pushes her little brother on his sled with a force of 300 N for 750 m.
How much work is this? _______________
How much energy is used?__________
How much power does she use if it takes her 25s?_________
How much power does she use if she runs and complete the 750m in 10s?________

Answers

Answer:

W = F× d

= 300×750

= 225000

E = 225000

P = 300×750/25 = 9000

P = 300× 750/10 = 22500

The 5.0-m-long rope in (Figure 1) hangs vertically from a tree right at the edge of a ravine. A woman wants to use the rope to swing to the other side of the ravine. She runs as fast as she can, grabs the rope, and swings out over the ravine.
When she's directly over the far edge of the ravine, how much higher is she than when she started?
Given your answer to Part A, how fast must she be running when she grabs the rope in order to swing all the way across the ravine?

Answers

She is 1.0 m higher than she is when she started. The speed at which the woman must be running when she grabs the rope is 4.427 m/s

Suppose we consider the Figure 1 to be a right-angle triangle;

where;

the hypotenuse is the rope = (5.0 m),the opposite side is the ravine = (3.0 cm) and;the adjacent is the slant imaginary distance = (x)

Using Pythagoras rule;

(hyp)² = opp² + adj²

5.0² = 3.0² + x²

x² = 25 - 9

x² = 16

x = √16

x = 4 m.

When she is directly over the far edge of the ravine, the height at which she is far higher than where she started is:

= 5cm - 4cm

= 1 cm

The speed at which the woman must be running when she grabs the rope can be determined by taking both the potential energy and kinetic energy of the system, which can be computed as:

mgh = 1/2 mv²

Making the speed the subject of the formula, we have:

[tex]\mathbf{v = \sqrt{2gh}}[/tex]

[tex]\mathbf{v = \sqrt{2\times 9.8 \times 1.0}}[/tex]

v = 4.427 m/s

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Which of the following statements about lipids and carbohydrates is true?

Answers

Answer : Lipids and carbohydrates are both made from carbon, hydrogen, and oxygen, but lipids have less oxygen (Option B)

Carbohydrates are biomolecules composed of carbon (C), hydrogen (H), and oxygen (O) in a 1:2:1 ratio, respectively.

Carbohydrates can be divided regarding the number of monomers in the biomolecule into monosaccharides, disaccharides, and polysaccharides.

Explanation:

hope this answer will helps you !

Train car A is at rest when it is hit by train car B. The two cars, which have the same mass, stick together and move off after the collision. How does the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision?.

Answers

The value of the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision is [tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex].

According to the principle of conservation of linear momentum, the total momentum before and after collision is conversed.

[tex]m_av_a_1 + m_bv_b_1 = v(m_a + m_b)[/tex]

where;

[tex]v_a_1 \ \ and \ \ v_b_1[/tex] are the initial velocity of the cars before collisionv is the final velocity of the cars after collision

since the train car A is at rest, [tex]v_a _1 = 0[/tex]

[tex]m_bv_b_1 = v(m_a + m_b)[/tex]

The relationship between the final velocity and initial velocity of the cars is given as;

[tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex]

Thus, the value of the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision is [tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex].

Learn more about conservation of linear momentum here: https://brainly.com/question/22698801

Answer: the answer is the third option. Edge 2021

Explanation: i just answered the problem

Hello guys! Can u please help me with physics. I translated it in English. Can yall help me please how much u can!!

A body 60 m above the ground shall be thrown vertically upwards at an initial speed of 20 m / s. Air resistance can be ignored!
1. How high will the body fly from the point of ejection?
2. What is the maximum height it will reach above the ground?
3. How long does it take for the body to reach its highest point from the moment of expulsion?
4. After how long after the expulsion will the body fall to the ground?
5. What is the speed of the body at the moment of falling to the ground?​

Answers

1. Since the body is thrown vertically upward, the only force acting on it as it rises and falls is gravity, which causes a constant downward acceleration with magnitude g = 9.8 m/s². Because this acceleration is constant, we can use the formula

v² - u² = 2a ∆x

where

u = initial speed

v = final speed

a = acceleration

∆x = displacement

At its maximum height, some distance y above the point where the body is launched, the body has zero velocity, so

0² - (20 m/s)² = 2 (-9.8 m/s²) y

Solve for y :

y = (20 m/s)² / (2 (9.8 m/s²)) ≈ 20.4 m

2. Relative to the ground, the body's maximum height is 60 m + 20.4 m ≈ 80.4 m.

3. At any time t ≥ 0, the body's vertical velocity is given by

v = 20 m/s - gt

At the highest point, we have

0 = 20 m/s - (9.8 m/s²) t

and solving for t gives

t = (20 m/s) / (9.8 m/s²) ≈ 2.04 s

4. The body's height y above the ground at any time t ≥ 0 is given by

y = 60 m + (20 m/s) t - 1/2 gt²

Solve for t when y = 0 :

0 = 60 m + (20 m/s) t - 1/2 (9.8 m/s²) t²

Using the quadratic formula,

t = (-b + √(b² - 4ac)) / (2a)

(and omitting the negative root, which gives a negative solution) where a = -1/2 (9.8 m/s²), b = 20 m/s, and c = 60 m. You should end up with

t ≈ 6.09 s

5. At the time found in (4), the body's velocity is

v = 20 m/s - g (6.09 s) ≈ -39.7 m/s

Speed is the magnitude of velocity, so the speed in question is 39.7 m/s.

10C of charge flow through a resistor in 4 seconds. What is the current?

Answers

Answer:

Very simple. The charge Q= 20 C. the formula for Q= I* t. now I= Q/t = 20/1s = 20 Amps.

Explanation:

The current given that the charge is 10C and the time is 4 seconds is gotten as Current = 2.5 Amps

Given Data

Charge = 10 Columbs

Time = 4 seconds

Current = ?

Current, charge and time Relationship

Electrical current is defined by how much electric charge has been transferred per second, giving the following relationship:

Charge = Current*Time

Rearranging this we get:

Current = Charge/Time

The symbol for charge is Q , it is measured in coulombs (C).

The symbol for current is I , it is measured in amperes (A).

The symbol for time is T, it is measured in seconds (s).

Substituting our given Data into the expression we have

Current = 10/4

Current = 2.5 Amps

Learn more about Charge here:

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PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!


Why are those with low cardiovascular fitness more prone to heart disease than those whose cardiovascular fitness is high?
A.
Exercise decreases the size of arteries, causing heart disease.
B.
Those with lower cardiovascular fitness will have weaker heart muscles.
C.
High cardiovascular fitness means that the heart rate is rarely elevated.
D.
Cardiovascular fitness is the only factor that determines the strength of the heart.


PLEASE NO LINKS OR I WILL REPORT YOU

Answers

People with low cardiovascular fitness are more prone to heart disease than those whose cardiovascular fitness is high because those with lower cardiovascular fitness will have weaker heart muscles. Thus, the correct option is B.

What is Cardiovascular fitness?

Cardiovascular fitness may be defined as the accommodation of the cardiovascular system to furnish oxygenated blood to functioning muscles. It includes the muscles of the heart, lungs, blood vessels, etc.

People with low cardiovascular fitness have lower furnishing of oxygenated blood to various organs like the heart, lungs, etc. Due to this, the muscles of specific body parts or organs may undergo a state of inactivity suddenly for a fraction of seconds.

This activity constantly leads to various heart-related diseases directly or indirectly in the life of an individual.

Therefore, the correct option for this question is B.

To learn more about Cardiovascular fitness, refer to the link:

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#SPJ1

What can we say about energy on
the low end of the
electromagnetic spectrum?

A. They have longer wavelengths and less dangers.

B. They have lower frequencies and more energy.

C. They have shorter wavelengths and less dangers.

D. They have higher frequencies and more energy.

Answers

Answer:

A. Longer wavelengths and less dangers

Explanation:

Radio waves are at the lowest end of the EM spectrum, they have the longest wavelength of any other EM waves, the lowest energy and, accordingly, the lowest frequency;

Their low energy and frequency means they pose little risk of harm or danger as they don't get absorbed by human being.

pls pls pls help i need to know the correct answer and why it’s correct, thanks in advance

What is the relationship between power, work, and time?
A
As the amount of time increases,
power and work both increase.
B
As the amount of time increases,
power and work both decrease.
С
As the amount of time increases,
power increases and work is not affected. D. As the amount of time increases power decreases and work is not affected.

Answers

Answer:

it's ans is D because all three are wrong

You throw a can of cranberry sauce straight up in the air with an initial velocity of 12 m/s. What is the maximum height the baseball reaches above your head.

Answers

Answer:

Δx=7.35m

Explanation:

This is a free fall problem (g= -9.8 m/s²).

Displacement: ? <--- what you're trying to find (max height)

Initial Velocity: 12 m/s

Final Velocity: 0 m/s <-- since the can will land back in your hands

Time: Missing <-- not needed to solve

Acceleration: -9.8 m/s²

The equation that you will use is vf²=vi²+2aΔx

Now plug the information into the equation!

(0m/s)²=(12m/s)²+2(-9.8m/s²)Δx

Multiply the 2 with the acceleration (-9.8m/s²)

(0m/s)²=(12m/s)²-19.6m/s²Δx

Now you need to square the final and initial velocity

0m/s=144m/s-19.6m/s²Δx

Move 144 to the other side of the equal sign

-144m/s=-19.6m/s²Δx

Divide both sides by -19.6m/s²

7.346m=Δx

You can round it to the tenth or hundreth place, up to you!

For this example, I'll round to the hundredth...

Δx=7.35m

I would double check this answer or review it yourself to see if it's correct.

Good luck with your studies!

I need 4 answers for Earth's layers and 4 answers for the Descriptions for Earth's layers graphic organizer.

Answers

Ok well have a nice day

Da 6.0 kg wooden crate slides across a wooden floor
at a speed of 2.4 m/s, it it takes an applica force
of 25 N to keep it going at a steady speed. What is the
coe of kinetic friction between the floor and crate?

Answers

Answer:coe?

Explanation:

Which statement is true about the force of gravity?


A. The moon's gravity pulls the oceans to make tides.

B. The sun has the greatest influence on ocean tides.

C. The moon's gravity pulls the Earth to make tides.

D. The moon's gravity has nothing to do with tides.

Answers

Answer:

The moon's gravity pulls the Earth to make tides.

Explanation:

The Moons Gravity Pulls On The Earth With Different  Strenght Making High Tide And Low Tide.

Hope This Helps!

What is carbon dating?

Answers

Answer:

Im pretty sure its number 2

Explanation:

The first one a scientific way of finding the age of something that is very old (such as a dinosaur bone) by measuring the amount of certain forms of carbon in it

Define displacement in your own word

Answers

Answer:

Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Explanation:

Find the displacement in the time interval 3 seconds to 4 seconds
A. 1m
B.3m
C.7m
D.9m

Answers

Answer:

B. 3 m

Explanation:

The position of the line at 3 seconds is 9 m and at 4 seconds is 12m .

Therefore; Displacement = 12 - 9 = 3 m

Different between the Nature of these sound waves and the water waves

Answers

Explanation:

The main difference is frequency, sound waves are in Kilohertz , water waves are of course much slower. There are other differences , sound is longitudinal compression, but if you track motion of a particle in a water wave it moves in elliptic orbit as the wave passes.

Since the coefficient of friction is less than 1, what does that mean about the normal force and the force of friction?

Answers

Answer:

there is friction between the two things

Explanation:

what is refraction?

this my in sta id-:akhilrawat9453​

Answers

Answer:

refers to the bending of light

the fact or phenomenon of light, radio waves, etc. being deflected in passing obliquely through the interface between one medium and another or through a medium of varying density.

plss helpp:((

(i'll mark as brainliest if u answer)

Answers

Answer:

Seriously Your Question Is Kinda Tremendous

Explanation:

I'll Head Is Boiling From Question That Keeps Popping Up My Head, Someone Might Give You A Positive Hand

Without friction, what is the mass of an ball accelerating at 1.8 m/sec2 to which an
an unbalanced force of 42 Newtons has been applied?
A 75.60 kg
B 00.04 kg
C 23.33 kg
D 43.80 kg

Answers

Answer:

23.33 kg

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{42}{1.8} = 23.3333... \\ [/tex]

We have the final answer as

23.33 kg

Hope this helps you

Answer:

[tex]\boxed {\boxed {\sf C. \ 23.33 \ kg}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F=ma[/tex]

The mass of the ball is unknown. The ball is accelerating at 1.8 meters per second squared. An unbalanced force of 42 Newtons is applied to the ball.

Convert the units of force. 1 Newton is equal to 1 kilogram meter per second squared, so our answer of 42 Newtons is equal to 42 kg*m/s².

F= 42 kg*m/s² a= 1.8 m/s²

Substitute the values into the formula.

[tex]42 \ kg*m/s^1 = m * 1.8 \ m/s^2[/tex]

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 1.8 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 1.8 m/s².

[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} = \frac{a*1.8 \ m/s^2}{1.8 \ m/s^2}[/tex]

[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} =m[/tex]

The units of meters per second squared cancel.

[tex]\frac {42 \ kg}{1.8 } =m[/tex]

[tex]23.3333333 \ kg=m[/tex]

Round to the hundredth place. The 3 in the thousandth place tells us to leave the 3 in the hundredth place.

[tex]23.33 \ kg \approx m[/tex]

The mass of the ball is approximately 23.33 kilograms.

helppppp T^T
......
plsssss​

Answers

The ruler's center of mass is located on the vertical line defined by the 50 cm mark.
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