F is inversely proportional to d 2 . When F = 8 , d = 6 Work out d (positive value rounded to 2 DP) when F = 7

Answers

Answer 1

Answer:

d ≈ 6.41

Step-by-step explanation:

Given that F is inversely proportional to d² then the equation relating them is

F = [tex]\frac{k}{d^2}[/tex] ← k is the constant of proportion

To find k use the condition when F = 8, d = 6 , then

8 = [tex]\frac{k}{6^2}[/tex] = [tex]\frac{k}{36}[/tex] ( multiply both sides by 36 )

288 = k

F = [tex]\frac{288}{d^2}[/tex] ← equation of proportion

When F = 7 , then

7 = [tex]\frac{288}{d^2}[/tex] ( multiply both sides by d² )

d² × 7 = 288 ( divide both sides by 7 )

d² = [tex]\frac{288}{7}[/tex] ( take the square root of both sides )

d = ± [tex]\sqrt{\frac{288}{7} }[/tex] ≈ ± 6.41

The positive value of d is 6.41 ( to 2 dec. places )

Answer 2

Answer:

when F = 7, d = 6.41

Step-by-step explanation:

We know that when 'y' varies inversely with 'x', we get the equation

y ∝ 1/x

y = k/x

where 'k' is called the constant of proportionality

Given that F is inversely proportional to d.

F ∝ 1/d

F = k /d²

When F = 8, d = 6, we need to find k

k = Fd²

k = 8×(6)²=288

Now, we need to find d when F = 7

so substitute k = 288, F = 7 in the equation

F = k /d²

d² = k/F

d² = 288/7

[tex]\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]d=\sqrt{\frac{288}{7}},\:d=-\sqrt{\frac{288}{7}}[/tex]

but, we need to take the positive value of d, so

[tex]d=\sqrt{\frac{288}{7}}[/tex]

[tex]d=6.41[/tex]

Therefore,

when F = 7, d = 6.41


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hello your question is incomplete attached below is the missing diagram

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Step-by-step explanation:

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Answers


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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step 2 - Find New Numerator

Multiply the answer from Step 1 by the denominator and deduct that from the original numerator.

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