Find the area of the credit card:


2 1/4 inch, 3 1/3 inch.

Answer:

24 minutes

Step-by-step explanation:

The Dimensions of the wall are given as:

8ft × 5ft = 40ft² or 40 square feet

Step-by-step explanation:

Answer:

24 minutes

Step-by-step explanation:

8 * 5 = 40 ft²

---------------------------

Method I: Use a proportion

x/40 = 45/75

multiply both sides by 40

x = 45/75 * 40

x = 24

24 minutes

---------------------------

Method II: Use the rate

45/75 = 0.6min/ft²

40 * 0.6 = 24

24 minutes

Answer:

24 (x + 2)

24x + 48

these are two ways to rewrite the expression

Answer:

24x+48

Step-by-step explanation:

Answer:

Can't help you on an ASIT

Step-by-step explanation:

Answer:

Fish tanks come in all different sizes. I can't answer unless you tell me the dimensions (Length, width, height)

Step-by-step explanation:

Answer:

Hope this helps

Step-by-step explanation:

MRK ME BRAINLIEST PLZZZZZZZZZZZZZZ

Answer:

y = x - 10

Step-by-step explanation:

slope intercept form is

y = mx + b

m is the slope = 1

b is the y intercept = -10

Therefor

y = x - 10

Answer:

88

A:J

8:3

a - 40 = j

8y - 40 = 3y

5y = 40

y = 8

8 *11 = 88

Step-by-step explanation:

Hope i helped!  have a nice day

Answer:

88

Step-by-step explanation:

I know this because I used a secret method my parents told me that I can't tell anyone.

Answer:

First box: 15 * 10^10.

Second box: 300,000,000 meters per second.

Third box: 48 * 10^-13 meters.

Fourth box: 167 * 10^-29 meters.

Step-by-step explanation:

These should be correct! I put them in order from the top empty box to the bottom empty box!!!

Please mark brainliest if correct!!!

Answer:

329.5ft

Step-by-step explanation:

First one: ((4+18+26)x10)/2

Second: +(18x4)

Third: (7x5)/2

=240+72+17.5

=329.5

Answer:

a. H0: p1=p2 versus Ha: p1>p2

Step-by-step explanation:

Given that

p1 represent the proportion of the population for young allots 20-39

And, p2 denotes the proportion of the population for all older adults that are above 60

So,

We need to find out the hypotheses

The null & alternative hypothesis is

H_o: P_1 = P_2

H_a: P_1>P_2

This shows the right tailed test

Answer:

D. Removeable

Step-by-step explanation:

ed2021

Answer:

It's actually C, infinite!

Step-by-step explanation:

Answer:

FV= $6,750

Step-by-step explanation:

Giving the following information:

Initial investment (P)= $5,000

Interest rate (r)= 5% simple interest

Number of periods (t)= 7 years

To calculate the future value of the investment, we need to use the following formula:

FV= (P*r*t) + P

FV= (5,000*0.05*7) + 5,000

FV= 1,750 + 5,000

FV= $6,750

Lidal's price is better

Step-by-step explanation:

Lidal

4 for £2.04

1 for £2.04/4= £0.51= 51 p

Oldi

9 for £4.68

1 for £4.68/9= £0.52= 51 p

Lidal offers better price per roll

Answer:

58

Step-by-step explanation:

There would be 58 nickels and 42 dimes. This can be found out by

1. 100 - 16 = 84

2. 84/2 = 42

3. 42 + 16 = 58

making 42 dimes and 58 nickels.

Answer:

23

Step-by-step explanation:

6x3=18

18+5=23

Answer

this is wrong

Step-by-step explanation:

this is an equation not an expression. Equations have = and expressions dont. Please rewrite this and I will help.

The percentage equivalent is 20.

Given,

Percentage .

Now,

Firstly calculate the fractional form,

193/965 = .2

Now to convert fraction into percentage , multiply by 100.

So,

0.2 * 100

= 20%

Thus 193 is 20% of 965 .

Know more about percentage,

https://brainly.com/question/23418123

#SPJ6

Answer:

1024

Step-by-step explanation:

4^8/4^3=4^8-3=4^5=1024

Answer:

40 mi

Step-by-step explanation:

a² + b² = c²

24² + 32² = c²

1600 = c²

√1600 = c

c = 40

Answer:

E) 6

Step-by-step explanation:

a/b = 6

36/b = 6

6b = 36

b = 36/6 = 6

b/x = 36

6/x = 36

36x = 6

x = 6/36 = 1/6

hence 1/x = 6

Answer:

E) 6

Step-by-step explanation:

a/b=6, b/x=36, and a=36

=>a = 6b

36 = 6b => b =6

b/x = 36 => x = b/36 = 6/36

so, 1/x = 36/6 = 6

Answer:

j

Step-by-step explanation:

h

Answer:

1cm:20cm

Step-by-step explanation:

10cm:2m

1m=100cm

10cm:200cm

÷10

1cm:20cm

Answer:

Circumference of circle = 31.4 square meter

Step-by-step explanation:

Given:

Radius of a circle = 5 meter

Value of π = 3.14

Find:

Circumference of circle using formula "2πr"

Computation:

Circumference of circle = 2πr

By putting value of 'r' and 'π' in given formula

Circumference of circle = 2(3.14)(5)

Circumference of circle = (6.28)(5)

Circumference of circle = 31.4 square meter

Answer:

since you are helping me with my answer on my other account, cutiepatato about the discrimination

imma try my best to help answer yours <3

the picture is in the box

Step-by-step explanation:

Step-by-step explanation:

sorry I don't know the answer

Answer: 3 Pounds

Step-by-step explanation: Limit = 30 - 6.50 / 2 = 3.25. Limit = 30, she wouldn't be able to go over 6.50 so it would be 3.

Answer:

https://youtu.be/wmQMBJ_ce3k see this video

Answer:

4 children

Step-by-step explanation:

Let the number of children = c.

The cost of the pizza place for c children (without the fee) = 8c

The cost of the pizza place for c children (with the fee) = 8c+30

The cost of the taco place for c children (without the fee) = 12c

The cost of the taco place for c children (with the fee) = 12c+14

To find c when the totals are equal, set 8c+30 equal to 12c+14 and solve:

8c+30=12c+14

8c-12c=14-30

-4c=-16

c=4

Answer:

Base is 21

Step-by-step explanation:

I'm gonna be honest, just divide 336 by 16.

However just in case you meant volume instead of area because you said (bases), they would be 5 and 4.2

Answer:

Step-by-step explanation:

Group 1 Information:

sample size  :  n₁  =  200

individuals with stomach as a side effect  x₁  = 45

p₁ =  45 / 200   p₁ = 0,225   then  q₁  =  1  -  p₁   q₁ =  0,775

Group 2 Information:

sample size  :  n₂ =  150

individuals with stomach as a side effect  x₂  = 33

p₂  =  33/150  p₂ = 0,22   q₂   =  0,78

Hypothesis Test:

Null Hypothesis:                             H₀         p₁   =  p₂

Alternative Hypothesis                  Hₐ         p₁   >   p₂

The alternative hypothesis indicates that the test is a one-tail test  to the right

Significance level is   α = 0,01   ( confidence interval  99%)

From  z-table we get z(c) for that α     z(c) =  2,32

To calculate z(s)

z(s)  =  (  p₁  -  p₂ ) / EED

EED =  √ ( p₁*q₁)/n₁  +  ( p₂*q₂)/n₂

EED =  √ ( 0,225*0,775)/200   + (0,22*0,78)/150

EED =  √ 0,0008718  + 0,001144

EED =  0,045

z(s)  =  ( 0,225  -  0,22 ) / 0,045

z(s)  =  0,005 / 0,045

z(s)  =  0,11

Comparing z(s)  and  z(c)

z(s)  <  z(c)        0.11 < 2.32

Then z(s) is in the acceptance region. We accept  H₀ . We don´t have evidence to support differences between the two groups.

Question:

Two rectangular picture frames have the same area of 45 square inches but have different side lengths. Frame A has a length of 6 3/4 inches, and Frame B has a length of 7 1/2 inches.

Answer:

 1. the longer frame (B) has the shorter width

 2. the shorter width is 6 3/7 inches, area divided by length

Step-by-step explanation:

The relation between area, length, and width is ...

 A = LW

Then the width is ...

 W = A/L . . . . .  inversely proportional to length

1. Since length and width are inversely proportional (when area is constant), the shorter width will be associated with the longer length. Frame B will have the shorter width.__

2. The width of frame B is ...

 W = A/L = (45 in²)/(7 in) = 45/7 in = 6 3/7 in

-Alan Becker

Answer:

[tex]\displaystyle 2[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{2} \hookrightarrow \frac{\frac{2}{3}\pi}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle \boxed{y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{1}{2}} \hookrightarrow \frac{\frac{\pi}{6}}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2cos\:\frac{\pi}{3}x + \frac{1}{2},[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will horisontally shift and map the graph onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between the two photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle 2\:units[/tex]to the left, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph FORWARD [tex]\displaystyle 2\:units,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{2} = \frac{\frac{2}{3}\pi}{\frac{\pi}{3}}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}.[/tex]Intermediate, we have two sine graphs to deal with [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2sin\:\frac{\pi}{3}x + \frac{1}{2}.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle \frac{1}{2}\:unit[/tex]to the left, which means that in order to match the leftward sine graph, we need to shift the graph FORWARD [tex]\displaystyle \frac{1}{2}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{\frac{1}{2}} = \frac{\frac{\pi}{6}}{\frac{\pi}{3}}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [-2\frac{1}{2}, \frac{1}{2}],[/tex]from there to [tex]\displaystyle [3\frac{1}{2}, \frac{1}{2}],[/tex]they are obviously [tex]\displaystyle 6\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 6.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = \frac{1}{2},[/tex]in which each crest is extended two units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.