Find the cosecant for the angle whose measure is 7pi/4....7pi divided by 4.

Answers

Answer 1

cosecant = hypotenuse / opposite side

Angle = 7pi/4

I suggest to convert radians into angles

180° ------------------------- pi rad

x ------------------------ 7pi/4

x = 315°

Use the calculator to find this value

Cosecant 315° = -1.41

This is the answer

[tex]-\frac{\sqrt[]{2}}{2}[/tex]


Related Questions

convert these measurements to centimeters : (a)73.1 cm and (b) 0,0012km​

Answers

Answer:

(a) 73.1 cm (b) 120 cm

Step-by-step explanation:

Step-by-step explanation:

Part (a)

73.1 cm                 [It remains the same as it is already given in cms]

Part (b)  

To convert 0.0012km to cm we multiply x 100000

=> 0.0012 x 100000

=> 120 cm

I need questions 10 , 13 , 15 , and 16 solved with steps and graph

Answers

10. |x - 4| - 4 = 1/2x

⇒ Multiplying by 2,

2 |x - 4| - 8 = x

So, x - 4 = (x + 8)/2

             = -(x + 8)/2

When,

x - 4 = (x + 8)/2

2x - 8 = x + 8 (Multiplying by 2)

2x - x = 8 + 8 (Adding 8 and subtracting x to both sides)

x = 16

When,

x - 4 = - (x + 8)/2

2x - 8 = -x - 8 (Multiplying by 2)

2x + x = -8 + 8 (Adding 8 and x to both sides)

3x = 0

x = 0

Hence, the solution is x = 16 and x = 0.

13. (3/4)x = 2x - 10

⇒ Subtract 2x from both sides.

-5x/4 = -10

Multiply both sides by 4/(-5).

(-5x/4)×4/(-5) = -10 × 4/(-5).

x = 8 is the solution of the equation.

15. x² - 7x - 8 > 0

⇒ Solve the quadratic equation by splitting the middle term,

x² - 8x + x - 8 > 0

x(x - 8) + 1(x -8) > 0

(x + 1)(x- 8) > 0

-1 and 8 are the critical points of the inequality.

x < -1 and x > 8 are the solutions of the inequality which are represented by the shaded red region in the graph.

16. x - 5 > - 2x + 4

⇒ Adding 2x to both sides.

3x - 5 > 4

Adding 5 to both sides.

3x > 9

Divide both sides by 3.

x > 3 is the required solution represented by blue shade region in the graph.

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Solve for x
12x-6 need answer please

Answers

Answer:

-72

Step-by-step explanation:

Answer:

Step-by-step explanation:

12x-6 = 90 because opposite angles are equal if intercepted in parallel lines

12x=96

x= 8

which number is the closest approximation to the value of 3/94?

Answers

Answer:

[tex] \frac{1}{3} [/tex]

Step-by-step explanation:

[tex] \frac{3}{94} = 0.31 \\ \\ \frac{1}{3} = 0.33[/tex]

Find X.

Cirucumscribed angles

Answers

Answer:

x = 64

Step-by-step explanation:

to find x add make an equation to solve for x. the equation is 90+90+44+2x+8=360. after solving for x, x will equal 64.

To rent a certain meeting room, a college charges a reservation fee of $46 and an additional fee of $6.70 per hour. The math club wants to spend less than$106.30 on renting the meeting room.What are the possible amounts of time for which they could rent the meeting room?Use t for the number of hours the meeting room is rented, and solve your inequality for t.

Answers

As given by the question

There are given that the college charges a reservation fee of $46.

Now,

According to the question, the inequality is:

[tex]46+6.70t<106.30[/tex]

Then,

To solve the above inequality, collect the constant terms on the right side

So,

[tex]\begin{gathered} 46+6.70t<106.30 \\ 6.70t<106.30-46 \\ 6.70t<60.3 \\ t<\frac{60.3}{6.70} \\ t<9 \end{gathered}[/tex]

Hence, the room could be rented for up to 9 hours less than the stated amount.

5 tons of rocks cost $7,000.00. What is the price per pound ??

Answers

Answer: Per rock or pound?

can you help me factor the expression x^2+4x-21

Answers

To factor this expression we need to find two numbers which sum is 4 and the product is -21.

Now, 21 has only 2 factors (besides 1 and 21), 7 and 3, se we need to write them in a way such that they sum 4, so

[tex]x^2+4x-21=(x+7)(x-3)[/tex]

we see that 7-3=4 and 7(-3)=-21, so the factorization is correct.

Rajan climbed to a height of 15 ft from the bottom of a climbing wall. He then climbed up an additional 10 ft.

What must he do to return to the bottom of the climbing wall?

In the first blank, say whether Rajan must climb up or down. In the second blank, state the number of feet Rajan must travel up or down.

Rajan must climb_____ft to return to the bottom of the climbing wall.

Answers

Rajan must climb down 25 ft to return to the bottom of the climbing wall

Height climbed from the bottom of the wall = 15ft

Height: The measurement of an object's height from the base to the top is known as height. It is sometimes referred to as altitude in geometry. The vertical distance between the lowest and highest point is measured. In coordinate geometry, it is often the measurement along the y-axis of an object.

Additional height climbed = 10ft

Total height climbed = 25ft

He should climb down the distance, as climbing up will further move him away from the bottom of the wall

Distance to climb down to the bottom of the wall = 25ft

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If you spend 1 hours a week studying for English and 3.5 hours studying for math what is the ratio of time spent studying in math to studying for English?

Answers

The ratio of time spent studying math to studying English is 7:2.

According to the question,

We have the following information:

One spends 1 hour a week to study English and 3.5 hours to study math.

Now, we know that the ratio can be simply understood as the division.

So, we will divide the number of hours devoted to math by the number of hours devoted to English.

Ratio of time spent studying math to studying English = 3.5/1

Ratio of time spent studying math to studying English = 35/10

(Now, we will convert this fraction into the simplest form by dividing both the numerator and denominator of the fraction by 5.)

Ratio of time spent studying math to studying English = 7/2

Ratio of time spent studying math to studying English = 7:2

Hence, the ratio of time spent studying math to studying English is 7:2.

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Premises:
If you have a cat, then it will chase mice.
You have a cat.
Conclusion:
Your cat will chase mice.
The Law of _____ makes this
argument true.

Answers

A premise or premiss is a true or false statement that helps form the body of an argument, By law of syllogism the statement is true. Your cat will chase mice.

What are premises?

A premise or premiss is a true or false statement that helps form the body of an argument, which logically leads to a true or false conclusion.

If the following two statements are true: (1) If p , then q . (2) If q , then r . Then we can derive a third true statement: (3) If p , then r .

If you have a cat, then it will chase mice.

is the given statement.

Let p is you have a cat

q is chase mice.

r is cat will chase mice.

iby the law of syllogism Your cat will chase mice. because  (1) If p , then q . (2) If q , then r . Then we can derive a third true statement: (3) If p , then r .

Hence by law of syllogism the statement "if you have a cat, then it will chase mice" is true.

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Question 10The table below shows the amount of water that is in a bathtub that is being filled.Minutes1234Gallons ofWater12172227Which of the following functions could model the amount of gallons of water, f(x), that the bathtub will contain after x minutes of being filled?Аf(x) = 5x + 7Bf(x) = 5x + 12сf(x) = 7x + 5Df%) = 12x + 5No

Answers

[tex]\begin{gathered} x=\text{ number of minutes} \\ f(x)=\text{amount of gallons of water the bathtub will contain} \\ \text{The function that fit the table is } \\ f(x)=5x+7 \end{gathered}[/tex]

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Find the difference. Write your answer in simplest form.

Answers

The mixed fraction 11 [tex]\frac{7}{16}[/tex] - 4[tex]\frac{7}{12}[/tex]  is equivalent to the fraction to 6 41/48

How to solve an equation?

An equation shows the relationship between two or more numbers and variables.The mixed fraction 11 7/16 is equivalent to the fraction (11 * 16 + 7)/16 = 183/16

The mixed fraction 4 7/12 is equivalent to the fraction (4 * 12 + 7)/12 = 55/12

Substituting:= 18 [tex]\frac{3}{16}[/tex] - 5 [tex]\frac{5}{12}[/tex]

Simplifying:= 329/48

= 6 41/48

11 [tex]\frac{7}{16}[/tex] - 4 [tex]\frac{7}{12}[/tex] is equal to 6 [tex]\frac{41}{48}[/tex]

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If f (x) = x


2 − 2 x , g (x) = x − 2


1) prove that : f(2) = g(2)

2) If g (K) = 7 , find : the value of k

Answers

1. The value of f(2) = 0 and g(2) = 0

2. The value of k is 9

What is a function?

A function can simply be described as a law, rule, theorem or expression that explains the relationship between two terms.

These terms are known as;

The dependent variableThe independent variable

Given the functions;

f(x) = x^2 - 2xg(x) = x - 21

To prove that f(2) = g(2)

Substitute the value of x as 2 in the functions, we have;

f(2) = 2^2 - 2(2)

expand the bracket

f(2) = 4 - 4

f(2) = 0

Then for g(2), we have;

g(2) = 2 - 2

g(2) = 0

Then, f(2) = g(2) = 0

If g(k) = 7

Then, we have;

k - 2 = 7

collect like terms to determine the value of k

k = 7 + 2

k = 9

Hence, the value is 9

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A person tosses a coin 14 times. In how many ways can he get 10 heads?

Answers

probability 50% for each side
14 times 14 =196 divided by 2 = 98
10 times 10 = 100 divided by 2 = 50
He can get 10 heads 50 different ways

PLS HELP WILL MARK YOU BRAINLIEST!!

Point B is the midpoint of AC. AB=2x and AC=3x+20.
What is the value of x?
x=-20
x=20
x=4
x=6

Answers

Answer:

X=4

Step-by-step explanation:

i got the answer on a different app

Answer: The correct answer is 20 or -20

Step-by-step explanation:

its between 20 and -20 since i selected x=6 and x=4 and they were both wrong lol

I just need to know how to work it out for future problems. (Business Calc)
Find the price elasticity of the demand function as a function of p.
1. q=D(p)=600-3p
A)E(p)= p/p-200
B)E(p)= p/600-3p
C)E(p)= p/200-p
D)E(p)= p(200-p)

Answers

The price elasticity of the demand function as a function of p is C. E(p)= p/200-p

How to illustrate the information?

It should be noted that the price elasticity of demand simply means the ratio of the percentage change in quantity demanded to the percentage change in price.

In this case, the function is given as:

q = D(p) = 600-3p

Differentiate with respect to p

D'(p) = 3

The elasticity of demand will be:

= (P / 600 - 3p) × (-3)

= P / (200 - P)

In conclusion, the correct option is C.

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Helping my son with homework.. I have no clue what this is

Answers

Answer:

45 times

Step-by-step explanation:

it is 45 times because it can land on blue or green 5 out of 8 times so u do 72 divided by 8 and u get 9 so I do 9 times 5 and u get 45

Four of the twelve members of the panel were late for
the meeting. What fraction of the members were on
time?

Answers

Answer:

2/3

Step-by-step explanation:

If 4 were late, then 8 were on time.

8/12  Divide the top and bottom by 4

2/3

What is the exact decimal equivalent of 7/12​

Answers

Answer:


0.58333333333

HELP ASAP HELP ASAP PLEASEEEEE

Answers

The distance between the parallel lines measured in the y direction is 3 units.

How to find the distance between the two given lines

given data

y = - 3x + 4

y = - 3x + 1

let line 1 be y = - 3x + 4 and line two be y = -3x + 1

Analyzing the two lines show that the slope is equal hence parallel

slope = -3

The y intercept of the line or just the intercept is what varied

line 1 = 4line 2 = 1

The difference between these two pints represents the distance between them measured in the y direction.

The difference is solved as

4 - 1 = 3 units

The distance is 3 units

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The number of hours it takes for ice to melt varies inversely with the air temperature. A block of ice melts in 2.5 hours whenthe temperature is 54 degrees.How long would it take for the same block of ice to melt if the temperature was 45 degrees?

Answers

Let t be the time in hours it takes a block of ice to melt at T degrees.

Since both variables have an inverse relation, we can say that:

[tex]t=\alpha\cdot\frac{1}{T}[/tex]

Where alpha is a constant value.

Since we know that a block of ice melts in 2.5 hours when the temperature is 54 degrees, we can plug in such data and find alpha as following:

[tex]\begin{gathered} 2.5=\alpha\cdot\frac{1}{54}\rightarrow2.5\cdot54=\alpha \\ \Rightarrow\alpha=135 \end{gathered}[/tex]

Therefore, our expression would be:

[tex]t=\frac{135}{T}[/tex]

For T = 45,

[tex]\begin{gathered} t=\frac{135}{45} \\ \\ \Rightarrow t=3 \end{gathered}[/tex]

We can conclude that it would take 3 hours for the block of ice to melt.

Graph the following inequalities.4x + y ≥ 0I need TWO COORDINATES

Answers

We need to graph the following inequality:

[tex]4x+y\ge0[/tex]

First, let's apply the same operations on both sides of the inequality to isolate the variable y on the left side of the inequality. We obtain:

[tex]\begin{gathered} 4x+y-4x\ge0-4x \\ \\ y\ge-4x \end{gathered}[/tex]

Now, notice that:

[tex]y=-4x[/tex]

represents a line containing all points with coordinates (x,y) such that y=-4x.

The solution to the inequality includes those points, and also the points for which y is greater than -4x.

Thus, the solution to this inequality consists of all the points on that line (solid line) and the whole region above that line:

Notice that, to graph the solid line, we can choose two points on the line, and then join them. We can use the points:

[tex]\begin{gathered} x=0\Rightarrow y=0\text{ point }(0,0) \\ \\ x=1\Rightarrow y=-4\text{ point }(1,-4) \end{gathered}[/tex]

IXL Transversals of parallel lines: prove angle relationships 6QF for geometry, please help

Answers

4) [tex]m\angle XWY=m\angle HGY[/tex] (definition of congruent angles)

5) [tex]\angle HGY \cong \angle GTU[/tex] (corresponding angles theorem)

6) [tex]m\angle HGY=m\angle GTU[/tex] (definition of congruent angles)

7) [tex]\angle GTU[/tex] and [tex]\angle UTR[/tex] are supplementary (linear pair)

8) [tex]m\angle GTU+m\angle UTR=180^{\circ}[/tex] (definition of supplementary angles)

9) [tex]m\angle HGY+m\angle UTR=180^{\circ}[/tex] (substitution)

10) [tex]m\angle RTU+m\angle XWY=180^{\circ}[/tex] (substitution)

it says on top that the image is not drawn to scale.

Answers

D; Both statements are correct

Here, we want to check the correct statement

Basically from the diagram, it is confirmed that what we have is a 30-60-90 triangle

Now, for a 30-60-90 degrees triangle, the side lengths are in a particular ratio

From the diagram, MO faces the right angle and thus, it is the longest side and the hypotenuse

Now, let us take a look at the ratio of the sides in both submissions

For a 30-60-90 degrees triangle, the ratio of the sides is;

[tex]1\colon\sqrt[]{3}\text{ :2}[/tex]

Hence, one side must be twice the length of the other

From Kellie's statement we can see MO is twice NO

From Eddie's statement, we can also see that MO is twice NO

Lastly, we can also see in both that dividing MN by NO yields the root of 3 in both statemets which confirms the existence of the theoretical ratio

So the conclusion here is that;

Both students are correct

Can you please help me solve this questions. I want a clear explanation thank you.

Answers

Given:

[tex]\begin{gathered} \text{Mean}=\mu=21.4 \\ \text{Standard deviation=}\sigma=5.0 \\ \text{Smple size=n=66} \end{gathered}[/tex]

The z-score for 90 percent is 1.64.

To find the 90 percent confidence interval,

[tex]\begin{gathered} \mu+(\frac{\sigma}{\sqrt[]{n}}\times1.64)=21.4+(\frac{5}{\sqrt[]{66}}\times1.64) \\ =21.4+1.0094 \\ =22.4094\ldots\ldots(\text{ upper limit)} \\ \text{And} \\ \mu-(\frac{\sigma}{\sqrt[]{n}}\times1.64)=21.4-(\frac{5}{\sqrt[]{66}}\times1.64) \\ =21.4-1.0094 \\ =20.3906\ldots\ldots\ldots(\text{lower limit)} \end{gathered}[/tex]

Answer: The 90 % confidence interval is ( 20.3906 , 22.4094 )

How many times larger is 8.1 than 2.7

Answers

8.1 is 5.4 more times larger than 2.7

(3ax - n) ÷ 5
Solve for X.

Answers

Answer:

x = 10/a; restrictions a ± 0

Answer:

[tex]x = \cfrac{n+5}{3a}[/tex]

=============================

Given expression

[tex](3ax - n) : 5 = 1[/tex]

Solve it for x in steps below:

[tex]3ax - n = 5[/tex][tex]3ax = n + 5[/tex][tex]x = \cfrac{n+5}{3a}[/tex]

what is 84i?I'm learning about imaginary numbers but I need extra help

Answers

The imaginary number 'i" can be written in another form below:

[tex]i=\sqrt[]{-1}[/tex]

Whenever we have the root of a negative number, we use the imaginary number 'i' to write it in an easier form.

For example:

[tex]\begin{gathered} \sqrt[]{-4}=\sqrt[]{-1\times4} \\ =\sqrt[]{-1}\times\sqrt[]{4} \\ =2\times\sqrt[]{-1} \\ =2\times i \\ =2i \end{gathered}[/tex]

Therefore:

[tex]\begin{gathered} 84i=84\sqrt[]{-1} \\ =\sqrt[]{84^2\times-1} \\ =\sqrt[]{-7056} \end{gathered}[/tex]

Find sinθ, tanθ, and secθ, where θ is the angle shown in the figure. Give exact values, not decimal approximations.sinθ=tanθ=secθ=

Answers

[tex]undefined[/tex]

1) We have here a right triangle, so we can use the Pythagorean Theorem to find the adjacent leg. Note that the hypotenuse is leg opposite to the right angle. In this case, a=4.

a²=b²+c²

4²=b²+3²

16=b²+9

16-9=b²

b=√7

2) Let's find the trigonometric functions. The first one is the sine (θ), which relates the opposite side and the hypotenuse:

[tex]\sin (\theta)\text{ =}\frac{3}{4}[/tex]

2.2)Moving on, we can deal with the tangent of theta, relating the opposite side over the adjacent, for this one we have to rationalize it:

[tex]\begin{gathered} \tan (\theta)\text{ =}\frac{3}{\sqrt[]{7}} \\ \tan (\theta)=\frac{3\sqrt[]{7}}{7} \end{gathered}[/tex]

Finally, let's find the reciprocal function of the cosine function by setting this as the reciprocal of the cosine, and then calculating it:

[tex]\begin{gathered} \sec \text{ (}\theta)=\frac{1}{\cos(\theta)}\Rightarrow\sec (\theta)=\frac{1}{\frac{\sqrt[]{7}}{4}}\Rightarrow\sec (\theta)\text{ =}\frac{4}{\sqrt[]{7}} \\ \sec (\theta)\text{ =}\frac{4\sqrt[]{7}}{7} \end{gathered}[/tex]

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A) to encourage young people to create a life planB) to encourage young people to create a life plan to argue that medicine is a better career than law to argue that medicine is a better career than law C) to tell an amusing story about how he met his wife to tell an amusing story about how he met his wife D) to share something he has learned about lifePassage:"A Complication or Two"The rejection letter from my Ivy League school of choice was the first major obstacle I encountered in my grand 10-year plan. It was not the last. I was 17, and at the time quite certain that nothing would derail me from my grandiose future. I planned to achieve everything my parents expected, and more. The first step was supposed to have been attending my parents alma mater, graduating with honors, and then moving on to law school without pausing to let my peersor competitorscatch me. To say thats not how it went is a gross understatement.Needing a distraction in my moment of crisis, I decided to pick up another couple of hours of volunteer service. I rode the subway to Tri-Valley Hospital with that rejection letter wrinkled in my right fist. I probably should have left it at home, but I couldnt bring myself to put it down. Id spent so many hours volunteering at Tri-Valley to build my community service rsum that the trek there felt like it was accomplished on auto-pilot rather than through any active involvement on my part.Alma was a new volunteer that morning, and I felt grateful for her presence, though I suppose I really didnt pay much attention to her. Mostly, I was relieved to have something to focus on, other than the big fat rejection letter swelling in my pocket. I showed Alma the volunteer wing, which was really just a room with a few lockers, a microwave, and a lot of large posters with rules and cautionary messages. She shadowed me on that shift, and together we delivered food trays, chatted with bed-ridden patients who didnt have visitors that morning, and carried out a number of fairly tedious tasks. I forgot Almas name three times and had to apologize. It was a unique enough name that I shouldnt have forgotten once, but the rejection letter was burning a hole in my pocket and apparently in my mind.At lunch, Alma sat across from me, even though by then several other regular volunteers had arrived and offered to take her out for real food rather than subjecting her to the cafeteria fare. I cant imagine how far gone I must have seemed to her, but Ill never forget what she said as I prodded the chocolate mass parading as cake on my tray. You must really love what you do here, she said. I can tell you care about this place and the patients we visited.Her words dug into me, primarily because I had never once stopped to consider whether I enjoyed my time at the hospital. Hundreds of food trays served, hundreds of patients visited, and still somehow the whole experience amounted to nothing more than a checkmark on the extensive list of what I needed to accomplish to achieve my goals. I did think about it then, as I finished my dessert. She wasnt incorrect. A lot of people hate hospitalsthe lights, the sterile smell, the undercurrent of urgency, illness, and tragedy. But I didnt hate it at all. The fact that I was there that day proved more than anything else that I saw it as a comfortable place.Alma and I ended up attending the same university. It wasnt Ivy League, and I wasnt pre-law. Freshman year, I decided to complete my undergraduate degree on an accelerated three-year plan. Although that three years stretched to four-and-a-half, when I graduated, my wife of two years, whose name I had not forgotten once since that first day at Tri-Valley, was by my side and expecting our first daughter. Medical school was its own unique challenge, especially after the twins came along halfway through. We purchased our first house the year they turned six, after I landed a residency at Tri-Valley. But we slept in a nearby hotel for the first two months of home ownership because of a burst pipe that flooded our bedrooms the week we moved in.Looking back, I suppose my life started with that letter. I dont think everything necessarily happens for a reasontheres too much tragedy in the world for that. But theres no doubt that some misfortunes turn into pivotal moments that can alter the course of a persons life for the better. Alma and I have been together for 30 years now, and I still wonder what that other lifethe one in which my letter said congratulationsmight look like. I expect it would have been pretty grand, full of its own triumphs and pitfalls. My children are fresh to the adult world, and when I see their tears as plans go sideways, I like to imagine that someday theyll sit where I am with people to love, hobbies to pursue, and maybe even a spare dollar in the bank.