Find the exact value, without a
calculator.
710
6
sin
2
tan
12
6
2
7Tt/6
COS

Find The Exact Value, Without Acalculator.7106sin2tan12627Tt/6COS

Answers

Answer 1

Answer:

[tex]-2 -\sqrt{3}[/tex]

Step-by-step explanation:

First consider numerator

[tex]sin \frac{\frac{7\pi}{6}}{2} = sin \frac{7\pi}{12}= sin (\frac{\pi}{4} + \frac{\pi}{3})[/tex]

Using the formula : sin (A + B) = sin A cos B + cos A sin B

[tex]sin \frac{\pi}{4} = \frac{\sqrt{2} }{2}, \ cos \frac{\pi}{4} = \frac{\sqrt{2} }{2}\\\\sin \frac{\pi}{3} = \frac{\sqrt{2} }{2}, \ cos \frac{\pi}{3} = \frac{1}{2}[/tex]

[tex]sin(\frac{\pi}{4} + \frac{\pi}{3}) = sin \frac{\pi}{4} \cdot cos \frac{\pi}{3} + cos \frac{\pi}{4} \cdot sin \frac{\pi}{3}[/tex]

                [tex]=\frac{\sqrt{2} }{2} \cdot \frac{1}{2} + \frac{\sqrt{2} }{2} \cdot \frac{\sqrt{3} }{2} \\\\= \frac{\sqrt{2} }{4} + \frac{\sqrt{6} }{4}\\\\=\frac{\sqrt{2} +\sqrt{6} }{4}[/tex]

Second consider denominator

[tex]cos \frac{\frac{7\pi}{6}}{2} = cos \frac{7\pi}{12}= cos (\frac{\pi}{4} + \frac{\pi}{3})[/tex]

Using the formula : cos (A + B) = cos A cos B - sin A sin B

[tex]sin \frac{\pi}{4} = \frac{\sqrt{2} }{2}, \ cos \frac{\pi}{4} = \frac{\sqrt{2} }{2}\\\\sin \frac{\pi}{3} = \frac{\sqrt{2} }{2}, \ cos \frac{\pi}{3} = \frac{1}{2}[/tex]

[tex]cos(\frac{\pi}{4} + \frac{\pi}{3}) = cos \frac{\pi}{4} \cdot cos \frac{\pi}{3} -sin \frac{\pi}{4} \cdot sin \frac{\pi}{3}[/tex]

[tex]=\frac{\sqrt{2} }{2} \cdot \frac{1}{2} - \frac{\sqrt{2} }{2} \cdot \frac{\sqrt{3} }{2}\\\\=\frac{\sqrt{2}}{4} - \frac{\sqrt{6}}{4}\\\\= \frac{\sqrt{2} -\sqrt{6} }{4}[/tex]

Therefore,

           [tex]tan \frac{7\pi}{12} = \frac{sin \frac{7\pi}{12}}{cos\frac{7\pi}{12}}[/tex]

                     [tex]= \frac{\frac{\sqrt{2} +\sqrt{6} }{4}} {\frac{\sqrt{2} -\sqrt{6} }{4} }\\\\=\frac{\sqrt{2} +\sqrt{6} }{4} \times \frac{4 }{\sqrt{2} -\sqrt{6}}\\\\=\frac{\sqrt{2} +\sqrt{6} }{\sqrt{2} -\sqrt{6}}[/tex]

Either we can stop here or Rationalize the denominator:

[tex]\frac{\sqrt{2} +\sqrt{6} }{\sqrt{2} -\sqrt{6}} \times \frac{\sqrt{2} +\sqrt{6} }{\sqrt{2} +\sqrt{6}} = \frac{(\sqrt{2} +\sqrt{6})^{2} }{(\sqrt{2})^2 -(\sqrt{6})^2} = \frac{2 + 6 +2\sqrt{12} }{2-6} = \frac{8+2\sqrt{12} }{-4} = \frac{8+ 4\sqrt{3} }{-4} = -2-\sqrt{3}[/tex]


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Answer:

4

Step-by-step explanation:

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Answers

Answer:

This inscribed angle is half of the intercepted arc JL, so 2(83)= 9x +40.

166 -40 = 9x, x=14.

Step-by-step explanation:

The value of x in the given figure is 14 which we obtain by  inscribed angle is half of the intercepted arc.

The inscribed angle is half of the intercepted arc.

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Subtract 20 from both sides to isolate the x variable

83-20=9/2x

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Divide both sides by 9

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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At his new job, Jeremiah can choose an hourly rate of $9 plus a $50 weekly bonus for opening the store, or an hourly rate of $10 per hour with no opening bonus. The equations model his salary options.

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Answer:

angle 1=127 degree

angle 3=127 degree

angle 2=53 degree

angle 4=53 degree

angle 5=37 degree

angle 6=90 degree

angle 7=53 degree

angle 8=37 degree

angle 9=37 degree

angle 10=143 degree

angle 11=37 degree

angle 12=143 degree

Step-by-step explanation:

pupils are required to spend 3/8 of the day at school and 2/3 of that time in class. How much time do they spend doing Mathematics? Give your answer in minutes.​

Answers

Answer:

[tex]Time \ in\ school = \frac{3}{8} \ of \ the \ day[/tex]

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Answers

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Answer:

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Step-by-step explanation:

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Answer:

7

Step-by-step explanation:

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Every value that falls under a range of values, such as 15-30, is counted as a freqeuncy of 1.

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In 45-60 we have a frequency of 2.

In 60-75 we have a frequency of 2.

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answer:

Our two selected points:

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I made some brownies and cookies to sell for a local fundraiser. The cookies sold for $0.75 each and the brownies sold for $1.25 each. If I sold 51 baked goods and made $53.25 from the bake sale, which item’s sales made the most money? Cookies Brownies

Answers

Answer:

Brownies made the most money

Step-by-step explanation:

Let c = cookies

b = brownies

We sold 51 items  so c+b = 51

Cookies are .75  and brownies are 1.25

.75c + 1.25 b = 53.25

We have 2 equations and 2 unknowns

c = 51-b

Substituting into the second equation

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Answers

Answer:

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Step-by-step explanation:

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Answers

Solution :

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