Find the measure of side b. (Round the answer to the nearest whole number)

Answer:

I can't see the picture, sorry. :(

Step-by-step explanation:

Answer:

y=3/4x-5.5

Step-by-step explanation:

y=mx+b

B=starting point 5.5

x= variable

M=slope 3/4

Answer:

s ∈ ( − ∞ , 1 )

Step-by-step explanation:

-2(s-7)>4s+8

-2s+14>4s+8

14>6s+8

6>6s

1>s

Answer:

(-inf, 1)

Step-by-step explanation:

Answer:

IT'S A. HEHEHEHEHEHEHE

Answer:

30

Step-by-step explanation:

(3x12)-(4+2)

36-6

30

Answer:

150 miles

Step-by-step explanation:

use the pythagoerean theorem

42^2 + 144^2 = c^2

1764+20736=c^2

22500 = c^2

c= 150 miles

Answer:

Set A: mean = 79.6, standard deviation = 9.8

Step-by-step explanation:

Set A has a larger spread of data.

If Set A: mean = 79.6, standard deviation = 9.8 and Set B: mean = 79.6, standard deviation = 2.3 then set A has  larger spread of data compared to set A.

Statistics is the study and manipulation of data, including ways to gather, review, analyze, and draw conclusions from data.

Given,

Set A:

mean = 79.6,

standard deviation = 9.8

Set B:

mean = 79.6,

standard deviation = 2.3

As we compare both set A and set B the mean of set A and set B are same whereas set A has more standard deviation than set B.

As Standard deviation is an important measure of spread or dispersion.

if the standard deviation is small, then this tells us that the results are close to the mean, whereas if the standard deviation is large, then the results are more spread out.

Set A has a larger spread of data.

Hence Set A has larger spread of data compared to set A.

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Answer:

(-7, -2)

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define systems

x - 7y = 7

6x - 7y = -28

Step 2: Rewrite systems

x = 7y + 7

6x - 7y = -28

Step 3: Solve for y

Step 4: Solve for x

And we have our answer!

Answer:

yeah for sure

Step-by-step explanation:

Answer:

24 pennies

Step-by-step explanation:

120 x 0.2 go get 24 and other will get 48

work it out

Step-by-step explanation:

Answer:

s = 6, r = 8 or s = 4, r = 7

Step-by-step explanation:

2r - s = 10

2r = 10 + s

r = 5 + s/2 --(1)

rs - s^2 = 12 --(2)

sub (1) into (2):

(5 + s/2)s - s^2 = 12

5s + 0.5s^2 - s^2 = 12

-0.5s^2 + 5s - 12 = 0

s^2 - 10s + 24 = 0

(s - 6)(s - 4) = 0

therefore s = 6 or s = 4

when s = 6, r = 8 and when s = 4, r = 7

if you would like to discover more about simultaneous equations, you can have a look at my Instagram page (learntionary). I'll be posting mathematics related stuff there and some of my notes (simultaneous enq notes are already posted!)

Answer:

1) -9.3465 × 10^8

2) 1.6214 × 10^-1

3) 1.33 × 10^-11

Explanation:

When solving arithmetic operations of numbers in scientific notation, there is a strategy that can be used.

First recognize the quotient(division) between the size of the numbers indicated by a multiple of 10 to a certain power. Remember, taking the quotients of like numbers with different powers is the subtraction of powers.

For example, to solve the first expression (problem one):

7.35 x 10^6 – 9.42 x 10^8

Divide 10^8 by 10^6 to get 10^2

So

it is like subtracting 7.35 and 9.42 × 10^2 which is 7.35 - 942, then once this expression is solved, multiply by the lowest multiple of 10 which is 10^6.

7.35 - 942 = -934.65 → -934.65 × 10^6 = (-9.3465 × 10^2) × 10^6 = -9.3465 × 10^8.

Long subtraction may need to be used when dealing with numbers that are far apart. Likewise long addition multiplication or division is used for very big or small numbers.

Anyway for the second expression (problem 2)

Addition in my opinion is much easier because it is really just adding on the bigger number. Subtraction may take a little longer but both processes are all based on the bigger number or the number with the greatest power of the multiple 10.

So 3.14 × 10^-3 + 1.59 × 10^-1

The quotient between 10^-1 and 10^-3 is the the difference between -3 and -1 which is 10^2

So again it is like adding 3.14 and 1.59 × 10^2 which is 3.14 + 159 = 162.14 = 1.6214 × 10^2. Now use the multiple of 10 with the largest contrast which is 10^-3 so 1.6214 × 10^2 × 10^-3 = 1.6214 × 10^(2-3) = 1.6214 × 10^-1.

Answer:

Step-by-step explanation:

4 + 6z - 15 = 6z - 11

2(3z -4) = 6z - 8

Here's the tricky part. You are only taking 8 away from 6z

The result is going to be larger than when you take away 11 from 6x

Try it

suppose z = 7

6*7 - 8 = 42 - 8 = 34

6*7 - 11 = 42 - 11 = 31

34>31

Answer:

i believe 40.88

Step-by-step explanation:

2.34 + 3.5 x 7 = 40.88

Answer:

1. Given

2. Given

3. Vertical Angles prop

4. SSS

Step-by-step explanation:

Hope this helps ya!

You are lucky I wish our teacher gave us proofs like this!

Answer:

-17/9

Step-by-step explanation:

You need to add 7 to both sides.

-9x - 7 = 10

-9x -7 + (7) = 10 + 7

-9x             = 17

Then both sides for (-9)

-9x/(-9) = 17/(-9)

          x = -17/9

Answer:

y=-3x+6

Step-by-step explanation:

that might not be fully simplified, but that should be the equation

Answer:

i know the circumference is 1.57 so it is A)

Step-by-step explanation:

Answer:

folding 6 loads of laundry in 3 days i think

Step-by-step explanation:

im pretty sure a rate is something paid/done/etc per one unit if that makes any sense lol

Answer: the answer is folding 6 loads of laundry in 3 days

Answer:

THATS MADDDD CAPPPP U NEED 25 POINTS OF THE QUESTION FOR BRAINLIEST

Answer:

5 gallons

Step-by-step explanation:

there were 5 gallons already in the tank before it started to get filled.

Answer: A. 12 + 12√12

Step-by-step explanation:

The perimeter of a triangle is acquired by adding up all the sides of the triangle.

In this case therefore the perimeter is;

= 2√2 + 2√2 + 4

= 4√4 + 4

There are 3 triangles so the total perimeter is;

= 3 * (4√4 + 4)

= 12√12 + 12

= 12 + 12√12

Answer:

The solution to the system of the equations will be:

[tex]x=3,\:y=1[/tex]

Step-by-step explanation:

Given the system of the equations

[tex]x+y=4[/tex]

[tex]x-y=2[/tex]

solving the system of the equations

[tex]\begin{bmatrix}x+y=4\\ x-y=2\end{bmatrix}[/tex]

[tex]x-y=2[/tex]

[tex]-[/tex]

[tex]\underline{x+y=4}[/tex]

[tex]-2y=-2[/tex]

solving

[tex]-2y=-2[/tex]

Divide both sides by -2

[tex]\frac{-2y}{-2}=\frac{-2}{-2}[/tex]

[tex]y=1[/tex]

[tex]\mathrm{For\:}x+y=4\mathrm{\:plug\:in\:}y=1[/tex]

[tex]x+1=4[/tex]

[tex]x=3[/tex]

Therefore, the solution to the system of the equations will be:

[tex]x=3,\:y=1[/tex]

Answer:

Step-by-step explanation:

Answer is "B"

Answer: 9.1-10=0.2x

Step-by-step explanation:

9.1 = −0.2x + 10

−0.2x + 10 = 9.1

−0.2x + 10 − 10 = 9.1 −10

−0.2x = −0.9

−0.2x / −0.2 = −0.9 / −0.2

x=4.5

10 = 9.1 + 0.2x

10 = 0.2x + 9.1

0.2x + 9.1 = 10

0.2x + 9.1 − 9.1 = 10 − 9.1

0.2x = 0.9

0.2x / 0.2 = 0.9 / 0.2

x=4.5

10 − 0.2x = 9.1

10 + (−0.2x) = 9.1

−0.2x + 10 = 9.1

−0.2x + 10 − 10 = 9.1 − 10

−0.2x = −0.9

−0.2x / −0.2 = −0.9 / −0.2

x=4.5

9.1 - 10 = 0.2x

-0.9 = 0.2x

-0.9 / 0.2 = 0.2x / 0.2

x= -4.5

Answer:

the answer is d/9.1 – 10 = 0.2x

Step-by-step explanation:

Answer:

x=7

Step-by-step explanation:

Answer:

The must have the same dimension

Step-by-step explanation:

Two matrice may be added or subtracted only if they have the same dimension; that is, they must have the same number of rows and columns.

When we add 2 matrices the matrices should be of the same size and same dimension

A matrix is referred to as the collection of numbers or variables arranged in a set of rows and columns, where each number or variable is referred to as an "element".

In order to perform addition or subtraction on matrices, they must be of the same size and dimension ie. two matrices must have an equal number of rows and columns. Simply add or subtract the numbers in each corresponding position of the first matrix with the number in the same position of the second matrix. The sum of two matrices A and B will be a matrix that has the same number of rows and columns as A and B. The sum of A and B denoted A + B, is computed by adding corresponding elements of A and B

A=[tex]\left[\begin{array}{ccc}a1&a2\\a3&a4\end{array}\right][/tex]  B=[tex]\left[\begin{array}{ccc}b1&b2\\b3&b4\end{array}\right][/tex]

A+B=[tex]\left[\begin{array}{ccc}a1+b1&a2+b2\\a3+b3&a4+a5\end{array}\right][/tex]

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Answer:

No they shouldn't.

Step-by-step explanation:

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