Find the volume of this sphere.Use 3 for TT..V ?20 ftV ==Tr3Hint: The radius (r) is1/2 of the diameter.

Find The Volume Of This Sphere.Use 3 For TT..V ?20 FtV ==Tr3Hint: The Radius (r) Is1/2 Of The Diameter.

Answers

Answer 1

From the problem, the diameter of the sphere is 20 ft.

Note that radius is half of diameter, so the radius will be r = 20/2 = 10 ft

Using the volume formula of a sphere.

[tex]V=\frac{4}{3}\pi r^3[/tex]

where π = 3

[tex]\begin{gathered} V=\frac{4}{3}(3)(10)^3 \\ V=4000 \end{gathered}[/tex]

The answer is 4000 ft^3


Related Questions

PLEASE HURRY IM SO CONFUSED

What is the product of (−4)(23)(−7)?

Answers

Answer:

644

Step-by-step explanation:

-4x23=-92

-92x-7=644

i hope this helped :)

PLS HELP ME WITH THIS

you need to use the y=mx+b

Answers

Hello!

What is a slope-intercept line:

 [tex]y = mx + b[/tex]

m: slope

            [tex]slope = \dfrac{y_2-y_1}{x_2-x_1} =\frac{-4--2}{3-0} =-\dfrac{2}{3}[/tex]

y-intercept or point whose x-coordinate is '0'

           ==> value of y-intercept is '-2'

Thus the equation is [tex]y=-\dfrac{2}{3}x-2[/tex]

Hope that helps!

Answer: y=-2/3x-2

Step-by-step explanation:

1) Draw a triangle from one point to the next point.

For this example, I will use (-3,0) and (0,-2).

You can see that the number goes down 2 and right 3. From this, you can conclude that the rate is -2/3 using the equation rise/run.

2) Find the y-intercept

Looking at the graph, you can find that the y-intercept is (0,-2).

3) Fill in the y=mx+b

y=-2/3x-2

What value is equivalent to (8+2)2 + (6 − 4) × 3?

Answers

Answer:

26

Step-by-step explanation:

PEMDAS

8 + 2 = 10

6 - 4 = 2

10 x 2 = 20

2 x 3 = 6

20 + 6 = 26

Mary's dog weighs 25 pounds. How many ounces does the dog weigh? Remember, there are 16 ounces in a pound.

Answers

Answer:

400

Step-by-step explanation:

4 x 10^, 20^2

Answer:

25 pounds  16 ounces = 6400

Step-by-step explanation:

how many ways can nine trophies be arranged on a shelf

Answers

we know that

There are: 9 ways to put the first trophy.

8 ways to put the second trophy after putting the first one.

7 ways to put the third trophy after putting the second one.

6 ways .............the third one

5 ways --------> the fourth

4 ways------> 5

3 ways -----> 6

2 ways ----> 7

1 ways-----> 8

therefore

n!

where n=9

9!=9*8*7*6*5*4*4*2*1

9!=362,880

the answer is

362,880 ways

Precalc please help Answers:A. 5 sin 60°/sin 70°B. 5/sin 50° sin 70°C. 5/sin 50°D. 5 sin 50°/sin 70°

Answers

step 1

Find out the measure of angle P

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

P+Q+R=180 degrees

substitute given values

P+70+60=180

P=180-130

P=50 degrees

step 2

Applying the law of sines

QR/sin P=PR/sin 70

substitute given values

QR/ sin 50=5/sin 70

QR=(5/sin 70)*sin 50

the answer is option D

Which of the following expressions is equivalent to 3x(2+5y)

Answers

Answer:

[tex]15xy+6x[/tex]

Simplify the expression.Can you help me with this one. I'm stuck at 12^x4 - 15x^2

Answers

Simplify the given expression as shown below

[tex]\begin{gathered} 3x(4x^4-5x)=3x*4x^4+3x(-5x)=12x^5+(-15x^2) \\ =12x^5-15x^2 \end{gathered}[/tex]Therefore, the answer is 12x^5-15x^2

find the X and the Y intercepts of the graph of the equation below 8x + 2y equals negative 16

Answers

The expresion is:

[tex]8x+2y=-16[/tex]

to find the intercepts with the x axis we have to rplace in the equation y = 0, so:

[tex]\begin{gathered} 8x+2(0)=-16 \\ 8x=-16 \end{gathered}[/tex]

and we solve for x

[tex]x=-\frac{16}{8}=-2[/tex]

the intersection with the x axis is -2

And for the itercepts with the y axis we replace x = 0

[tex]\begin{gathered} 8(0)+2y=-16 \\ 2y=-16 \end{gathered}[/tex]

and we solve for y

[tex]y=-\frac{16}{2}=-8[/tex]

This means that the intersepts with the y axis is -8

Find the area of a square with a diagonal that measures 4 square root of 2

Answers

Let's draw the figure to better understand the scenario:

Let,

s = the measure of the sides of the square

For us to be able to determine the area, let's first find out the measure of its side.

We will be using the Pythagorean Theorem:

[tex]\text{ a}^2+b^2=c^2[/tex][tex]\text{ s}^2+\text{ s}^2=(4\sqrt[]{2})^2[/tex][tex]\text{ 2s}^2=32[/tex][tex]\text{ }\frac{\text{2s}^2}{2}=\frac{32}{2}[/tex][tex]\text{ }\sqrt{\text{s}^2}=\sqrt{16}[/tex][tex]\text{ s = 16}[/tex]

Let's now determine the area of the square:

[tex]\text{ Area = s}^2[/tex][tex]\text{ = 4}^2[/tex][tex]\text{Area = 16}[/tex]

Therefore, the area of the square is 16.

=
If P = 3+5+7+9+...+99 and Q = 7+9+11+13+...+101 are sums of arithmetic sequences, determine which is
greater, P or Q, and by how much.

Answers

Answer:

Q is greater than P by 291

Step-by-step explanation:

The terms of these Arithmetic Sequences are odd natural numbers, because their common difference is 2

And, sum of 'n' odd natural numbers starting from 1 = n²

P = 99² - (1) = 9800

Q = 101² - (1 + 3 + 5) = 10192

Q - P = 291

Questlon 14 of 25 What is the slope of the line containing (-3, 1) and (1, -2)? O A. A - 3 O B. 4 O c. - 3 4 O D. SUBMIT

Answers

Answer:

C - 3/4

Step-by-step explanation:

In the expression 7^4 = 2,401, the value of the____ is 7.A. BaseB. PowerC. exponent

Answers

Answer:

The value of the base is 7 (option A)

Explanation:

Given:

[tex]7^4\text{ = 2401}[/tex]

To find:

To complefe the sentence by ill ingthe blanks

In powers and exponents:

[tex]For\text{ }a^b:\text{ a = base, b = exponent}[/tex][tex]\begin{gathered} Applying\text{ same principle:} \\ 7^4:\text{ Base = 7, exponent = 4} \end{gathered}[/tex]

The value of the base is 7 (option A)

12–23. Tony Ring wants to attend Northeast College. He will need $60,000 4 years from today. Assume Tony’s bank pays 12% interest compounded semiannually. What must Tony deposit today so he will have $60,000 in4 years?

Answers

Answer:

See below

Step-by-step explanation:

Period = 1/2 year    total 4years = 8 periods

i = interest per period in decimal form = .12/2 = .06

initial deposit = ?

Final value = 60 000

60 000 = ? ( 1 + .06)^8

? = 37644.74

Please help!!!!!!!!!!!

Answers

They are similar because they share one same angle and both have a angle with the same degree

Divide and simplify 7/8 ÷ -13/7

Answers

7/8x-7/13 = -49/104 and that is its simplest form

Hi, I need help differentiating using the product rule, thanks

Answers

Differentiate using the product rule:

g. We take out the constant:

[tex]4\frac{dy}{dx}\left(x\left(3x-2\right)^5\right)[/tex]

So:

[tex]=4\left(\frac{d}{dx}\left(x\right)\left(3x-2\right)^5+\frac{d}{dx}\left(\left(3x-2\right)^5\right)x\right)[/tex]

Now

[tex]\begin{gathered} \frac{d}{dx}\left(x\right)=1 \\ \frac{d}{dx}\left(\left(3x-2\right)^5\right)=5(3x-2)^4\cdot\frac{d}{dx}\left(\left(3x-2\right)^5\right)=5\left(3x-2\right)^4\cdot\:3=15\left(3x-2\right)^4 \end{gathered}[/tex]

Substituting the derivatives found:

[tex]=4\left(1\cdot\left(3x-2\right)^5+15\left(3x-2\right)^4x\right)[/tex]

Simplify:

[tex]=4\left(\left(3x-2\right)^5+15x\left(3x-2\right)^4\right)[/tex]

Answer:

[tex]=4\left(\left(3x-2\right)^5+15x\left(3x-2\right)^4\right)[/tex]

A cone has a radious of 5inches and a height of 10.125inches.What is the volume of the cone in inch rounded to the nearest tenth?

Answers

Answer:

264.9 in³

Explanation:

The volume of a cone can be calculated using the following equation:

[tex]V=\frac{\pi\cdot r^2\cdot h}{3}[/tex]

Where π is approximately 3.14, r is the radius of the cone and h is the height.

So, replacing r by 5 in and h by 10.125 in, we get:

[tex]\begin{gathered} V=\frac{3.14\cdot(5)^2\cdot(10.125)}{3} \\ V=\frac{3.14\cdot25\cdot10.125}{3} \\ V=\frac{794.8}{3} \\ V=264.9 \end{gathered}[/tex]

Therefore, the volume of the cone is 264.9 in³

Simplify (z9z−3)−2.

1 over z raised to the twelfth power

1 over z raised to the sixth power

−z^12

−z^6

Answers

Answer:

A. 1 over z raised to the twelfth power

Step-by-step explanation:

Hope this helps! :))
Please tell me if this is incorrect

Answer:

1 over z raised to the twelfth power

Step-by-step explanation:

A group of 175 college students who took math last term were interviewed. They were asked whether they passed their math course and whether they live on campus. Their responses are summarized in the following table. Passed math Failed math Live on campus 49 21 Live off campus 28 77 Х x $ ? (a) What percentage of the students passed math? [% (b) What percentage of the students live on campus? % (C) What percentage of the students who live on campus passed math? []% (d) Is there evidence that students who live on campus tend to pass math more often than average? O No, because the percentage found in part (c) is about the same as the percentage found in part (a). O No, because the percentage found in part (c) is about the same as the percentage found in part (b). ○Yes, because the percentage found in part (C) is much greater than the percentage found in part (a).○yes because the percentage found in part C is much greater than the percent is found in Part B

Answers

Given the group of 175 college students who took math last term:

(a) You can identify in the table that the total number of students that passed math is:

[tex]49+28=77[/tex]

Therefore, knowing the total number of students that were interviewed, you can determine that the percentage of the students who passed math is:

[tex]\frac{77}{175}\cdot100=44\text{ \%}[/tex]

(b) Based on the data shown in the table, the total number of students who live on campus is:

[tex]49+21=70[/tex]

Therefore, you can determine that the percentage of the students who live on campus is:

[tex]\frac{70}{175}\cdot100=40\text{ \%}[/tex]

(c) You can identify that 49 students live on campus and passed math. Therefore, the percentage of the students who live on campus and passed math is:

[tex]\frac{49}{49+28}\cdot100\approx63.6\text{ \%}[/tex]

(d) Knowing that 63.6% of the students who live on campus passed math, 40% of the student who live on campus, and 44% of the students interviewed passed math, you can identify that students who live on campus tend to pass math more often than average, because:

[tex]63.6\text{ \%}>40\text{ \%}[/tex]

Hence, the answers are:

(a)

[tex]44\text{ \%}[/tex]

(b)

[tex]40\text{ \%}[/tex]

(c)

[tex]63.6\text{ \%}[/tex]

(d) Last option.

Which equation represents a line which is parallel to the line y=8x-4?A x+8y=-16B x-8y=-40C y-8x=-1D 8x+y=3

Answers

Two parallel lines has the same slope.

The given line:

[tex]y=8x-4[/tex]

Is written in the form y=mx+b where m is the slope.

The slope is 8

To find the parallel line you need to write the given options in the form y=mx+b by solving y, as follow:

[tex]\begin{gathered} A \\ x+8y=-16 \\ 8y=-x-16 \\ y=-\frac{1}{8}x-\frac{16}{8} \\ \\ y=-\frac{1}{8}x-2 \end{gathered}[/tex]

Slope is -1/8 (it is not parallel to given line)

_______________

[tex]\begin{gathered} B \\ x-8y=-40 \\ -8y=-x-40 \\ y=\frac{-x}{-8}-\frac{40}{-8} \\ \\ y=\frac{1}{8}x+5 \end{gathered}[/tex]

Slope is 1/8 (it is not parallel to given line)

________________

[tex]\begin{gathered} C \\ y-8x=-1 \\ y=8x-1 \end{gathered}[/tex]Slope is 8 (It is parallel to given line)___________[tex]\begin{gathered} D \\ 8x+y=3 \\ y=-8x+3 \end{gathered}[/tex]

Slope is -8 (it is not parallel to given line)

Then, as given line and line in option C have the same slope (8) they are parallel lines

The graph shows the mass of the bucket containing liquid depends on the volume of liquid in the bucket. Use the graph to find the range of the function.

Answers

The range of the graph is 0 <= M <= 5.5

How to find the range of the function?

The range of a function is the set of output values of the graph.

This in other words mean the range of a function is the set of y values of the graph.

How to determine the domain and the range?

The domain

On the graph of the function, we can see that:

The x values start from 0 and it ends at 7.5

This means that the domain is 0 <= x <= 7.5

The range

On the graph of the function, we can see that:

The x values start from 0 and it ends at 5.5

This means that the range is 0 <= M <= 5.5

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Answer:

0 <= M <= 5.5

Step-by-step explanation:

Log z 2 + log 2x

pahelp po

Answers

answer is 1.2, log(2) + log(2X)

4x - 2y = 8Solve for yy = 4x + 8y = -2x + 4y = 2x - 4y = -x

Answers

This question has to do with the change in the subject of the formula.

So we will proceed thus:

[tex]\begin{gathered} 4x-2y=8 \\ \text{Making y the subject of formula will give:} \\ \end{gathered}[/tex][tex]\begin{gathered} 4x-8=2y \\ \text{Divide both sides by 2} \\ \frac{4x-8}{2}=\frac{2y}{2} \\ 2x-4=y \end{gathered}[/tex]

The correct answer, therefore, is the third option:

[tex]y=2x-4[/tex]

I only need the answer
THANK YOU!!

Answers

Answers:

[tex]\cos(\theta) = \frac{-3\sqrt{5}}{7}\\\\\tan(\theta) = -\frac{2}{3\sqrt{5}} = -\frac{2\sqrt{5}}{15}\\\\\csc(\theta) = \frac{7}{2}\\\\\sec(\theta) = -\frac{7}{3\sqrt{5}} = -\frac{7\sqrt{5}}{15}\\\\\cot(\theta) = \frac{-3\sqrt{5}}{2}\\\\[/tex]

=================================================

Explanation:

We're given that [tex]\sin(\theta) = \frac{2}{7}\\\\[/tex]

Plug that into the pythagorean trig identity [tex]\sin^2(\theta)+\cos^2(\theta) = 1\\\\[/tex] and solve for cosine to find that [tex]\cos(\theta) = \frac{-3\sqrt{5}}{7}\\\\[/tex]

I skipped steps in solving so let me know if you need to see them.

Keep in mind that cosine is negative in quadrant 2

------------------

Once you've determined cosine, divide sine over cosine to get tangent

[tex]\tan(\theta) = \sin(\theta) \div \cos(\theta)\\\\\tan(\theta) = \frac{2}{7} \div \frac{-3\sqrt{5}}{7}\\\\\tan(\theta) = \frac{2}{7} \times -\frac{7}{3\sqrt{5}}\\\\\tan(\theta) = -\frac{2*7}{7*3\sqrt{5}}\\\\\tan(\theta) = -\frac{2}{3\sqrt{5}}\\\\\tan(\theta) = -\frac{2\sqrt{5}}{3\sqrt{5}*\sqrt{5}}\\\\\tan(\theta) = -\frac{2\sqrt{5}}{3*5}\\\\\tan(\theta) = -\frac{2\sqrt{5}}{15}\\\\[/tex]

------------------

To determine cosecant, we apply the reciprocal to sine.

[tex]\sin(\theta) = \frac{2}{7} \to \csc(\theta) = \frac{1}{\sin(\theta)} = \frac{7}{2}\\\\[/tex]

Similarly, secant is the reciprocal of cosine

[tex]\cos(\theta) = \frac{-3\sqrt{5}}{7} \to \sec(\theta) = \frac{1}{\cos(\theta)} = -\frac{7}{3\sqrt{5}} = -\frac{7\sqrt{5}}{15}\\\\[/tex]

Depending on your teacher, rationalizing the denominator may be optional.

Lastly, cotangent is the reciprocal of tangent

[tex]\tan(\theta) = -\frac{2}{3\sqrt{5}}\to \cot(\theta) = \frac{1}{\tan(\theta)} = \frac{-3\sqrt{5}}{2}[/tex]

------------------

Side notes:

Sine and cosecant are the only things positive in Q2

Everything else (cosine, tangent, secant, cotangent) are negative in Q2.

The vertical height in feet of a projectile on a planet in our solar system at a given time t in seconds is represented by the function h(t)=−6t2+24t . Re-write h(t) in the form h(t)=a(t-h)^2+k and determine the maximum height of the projectile. Show all work.

Answers

We are given the following function:

[tex]h(t)=-6t^2+24t[/tex]

We will take "-6" as a common factor:

[tex]h(t)=-6(t^2-4t)[/tex]

Now, we will complete the square in the expression inside the parenthesis by adding and subtracting the following term:

[tex]undefined[/tex]

Danielle earns $36.80 for 4 hours of yardwork. How much does Danielle earn for 10 hours of yardwork?

Answers

first find out what she earns per hour by dividing 36.80 by 4 which is 9.20 then multiply that by 10 and the answer is $92

Select the GCF for each pair of numbers. 9,15 12,18 15,27 30,54

Answers

The Greatest common factors for each pair of numbers are;

1, ( 9 , 15 ) = 3

2. ( 12 , 18 ) = 6

3. ( 15 , 27 ) = 3

4. (30, 54) = 6

What is Greatest common factors?

The highest number that divides exactly into two more numbers, is called  Greatest common factors.

Given that;

The pairs of numbers are;

1, ( 9 , 15 )

2. ( 12 , 18 )

3. ( 15 , 27 )

4. (30, 54)

Now,

Find the Greatest common factors of the pairs of the numbers as;

1, ( 9 , 15 )

LCM of 9 = 3 x 3

LCM of 15 = 3 x 5

So, GCF of 9 and 15 = 3

2. ( 12 , 18 )

LCM of 12 = 2 x 3 x 2

LCM of 18 = 3 x 3 x 2

So, GCF of 12 and 18 = 3 x 2 = 6

3. ( 15 , 27 )

LCM of 15 = 3 x 5

LCM of 27 = 3 x 3 x 3

So, GCF of 15 and 27 = 3

4. (30, 54)

LCM of 30 = 2 x 3 x 5

LCM of 18 = 3 x 3 x 2

So, GCF of 30 and 54 = 3 x 2 = 6

Thus, The Greatest common factors for each pair of numbers are;

1, ( 9 , 15 ) = 3

2. ( 12 , 18 ) = 6

3. ( 15 , 27 ) = 3

4. (30, 54) = 6

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HELP!
For triangle XYZ, m∠X = 38°, m∠Y = (5x − 11)°, and m∠Z = (4x − 45)°. Find m∠Y.

m∠Y = 22°
m∠Y = 43°
m∠Y = 99°
m∠Y = 158°

Answers

The value of m∠Y in triangle XYZ is 99°

How to solve an equation

An equation is used to show the relationship between two or more numbers and variables.

In triangle XYZ, the angles are angle x, y and z. Hence:

∠X + ∠Y + ∠Z = 180° (sum of angles in a triangle)

Substituting:

38 + (5x -11) + (4x -45) = 180

Collecting like terms:

9x - 18 = 180

9x = 198

x = 22

m∠Y = 5(22) - 11 = 99°

m∠Y is 99°

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Write the correct expression for the following statement.
x six times
Use / for division
do not put any spaces

Answers

the expression is x+x+x+x+x+x , but assuming you want the answer simplified, its 6x
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