Find with proof the minimum possible k such that every subset of f1; 2; : : : ; 2022g of size k must contain at least two elements a; b such that a < b and b is a multiple of a.

Answer:

The answers are B, D, and E

Step-by-step explanation:

Answer:

I think B, D, E! Sorry if it's wrong!

Step-by-step explanation:

Only ones that fits the plot!

Answer:

Solution given:

1.

L.h.s.

cscx+cotx

[tex] \frac{1}{cosx}+\frac{cosx}{sinx}[/tex]

[tex]\frac{1+cosx}{sinx}[/tex]

multiplying and dividing by (1-cosx)

[tex]\frac{(1+cosx)(1-cosx)}{sinx(1-cosx)}[/tex]

[tex]\frac{1-cos²x}{sinx(1-cosx)}[/tex]

we have

1-cos²x=sin²x

[tex]\frac{sin²x}{sinx(1-cosx)}[/tex]

[tex]\frac{sinx}{1-cosx}[/tex]

=R.h.s.

proved.

2.

l.h.s

[tex]\frac{tan y}{1-cot y}+\frac{cot y}{1-tany}[/tex]

[tex]\frac{\frac{sin y}{cos y}}{1-\frac{cos x}{siny}}+\frac{\frac{cos y}{sin y}}{1-\frac{siny}{cos y}}[/tex]

[tex]\frac{\frac{sin y}{cos y}}{\frac{siny -cos y}{siny}}+\frac{\frac{cos y}{sin y}}{\frac{cos y-siny}{cos y}}[/tex]

[tex]\frac{sin²y}{cos y(siny-cosy)}+\frac{cos ² y}{sin y(cos y-siny)}[/tex]

[tex]\frac{sin²y}{cos y(siny-cosy)}- \frac{cos ² y}{sin y(-cos y+siny)}[/tex]

[tex] \frac{sin³y -cos³y}{sinycosy(siny -cosy)}[/tex]

[tex] \frac{(sin y- cos y)(sin²y+sinycosy+cos²y)}{sinycosy(siny -cosy)}[/tex]

[tex] \frac{sin²y+cos²y +siny cosy}{sinxcosy}[/tex]

[tex] \frac{1+sinxcosy}{sinycosy}[/tex]

[tex]\frac{1}{sinycosy}+1[/tex]

1+cscysecy

R.h.s.

proved.

Answer:

12x - 6y + 2

Step-by-step explanation:

Answer:

[tex](7m^2+10)^2[/tex]

Step-by-step explanation:

This is a quadratic in disguise. To visualize this better, let [tex]x=m^2[/tex]. We have:

[tex]49x^2+140x+100[/tex]

To factor, we can write out the format [tex](ax+y)(bx+z)[/tex]. We're looking for numbers [tex]a[/tex], [tex]b[/tex], [tex]y[/tex], and [tex]z[/tex] such that the following is true:

We find the following numbers:

[tex]a=7,\\y=10, \\b=7, \\z=10[/tex]

Thus, we have:

[tex](7x+10)(7x+10)[/tex]

Substitute back [tex]x=m^2[/tex] to get your final answer:

[tex](7m^2+10)(7m^2+10)=\boxed{(7m^2+10)^2}[/tex]

(x – 3)² – 10 = 15

↓

[tex] {x}^{2} - 6x + 9 - 10 = 15[/tex]

[tex] {x}^{2} - 6x - 1 = 15[/tex]

[tex] {x}^{2} - 6x - 15 = 0[/tex]

[tex] {x}^{2} + 2x - 8x - 1 - 15 = 0[/tex]

[tex] {x}^{2} + 2x - 8x - 16 = 0[/tex]

[tex]x \times (x + 2) - 8x - 16 = 0[/tex]

[tex]x \times (x + 2) - 8(x + 2) = 0[/tex]

[tex](x + 2) \times (x - 8) = 0[/tex]

[tex]x + 2 = 0[/tex]

[tex]x - 8 = 0[/tex]

so,

[tex]x1 = - 2[/tex]

[tex]x2 = 8[/tex]

Step-by-step explanation:

hope it helps you see the attachment for further information

Answer:

A. 0.75

B. Elsa can expect to gain 0.75 dollars

Step-by-step explanation:

We have six outcomes

Using the table in the attachment, the expected value was calculated.

Expected value = 0.166667+0.3333+0.5-0.083333-0.083333-0.083333

= 0.75

B. From the answer in part A , we can conclude that Elsa can expect to gain money. She can expect to win 0.75 dollars per roll.

Solution :

Avrami relationship

[tex]$1-y=exp(-kt^n)$[/tex]

[tex]$\ln(1-y)=-kt^n$[/tex]

[tex]$-\ln(1-y)=kt^n$[/tex]

[tex]$\ln\left[\ln\left(\frac{1}{1-y}\right)\right]=\ln k + n \ln t$[/tex]

The fraction transformed is 0.2 at 12.6 s,

[tex]$\ln\left[\ln\left(\frac{1}{1-0.2}\right)\right]=\ln k + n \ln (12.6)$[/tex]

[tex]$-1.5 = \ln k + 2.533 n$[/tex]  .........(i)

The fraction transformed is 0.7 at 25.7 s,

[tex]$\ln\left[\ln\left(\frac{1}{1-0.7}\right)\right]=\ln k + n \ln (25.7)$[/tex]

[tex]$0.5 = \ln k + 3.24 n$[/tex]   ..............(ii)

Subtract (ii) from (i),

-2 = -0.71 n

n = 2.81

Therefore, from (i),

[tex]$-1.5 = \ln k + 2.533 (2.81)$[/tex]

k = 0.000181

Now if the fraction transformed is 0.92, then

[tex]$kt^n=-\ln (1-y)$[/tex]

[tex]$t=\left[\frac{-\ln (1-y)}{k}\right]^{\frac{1}{n}}$[/tex]

[tex]$t=\left[\frac{-\ln (1-0.92)}{0.000181}\right]^{\frac{1}{2.81}}$[/tex]

t = 29.8528 s

Answer:

Percentage

Step-by-step explanation:

Answer:80

Step-by-step explanation: I am not 100% sure this is right but what i did was 75 - 15 =60, 60/75 in percentage is 80%

9514 1404 393

Answer:

  p = 6

Step-by-step explanation:

The difference between the first two terms is ...

  5p -p = 4p

Since this is an arithmetic sequence, the next term will be 4p more than the last term:

  5p +4p = 9p

Then the sum of the first three terms is ...

  p + 5p + 9p = 90

  15p = 90 . . . . . . . . . . collect terms

  p = 6 . . . . . . . . . . . . divide by 15

_____

The first three terms are 6, 30, 54.

Answer:

DE

Step-by-step explanation:

You can tell by the markings. Since there are two vertical markings it concludes that those sides are the same length.

Answer:

The answer is "0.00842".

Step-by-step explanation:

Due to these cards, a conventional 52-card set is dealt one at a time.

While the first two cards are spades, then it would be expected that we could find the next three cards tents, too.

Let A draw 2 spade cards out of 52 cards. Let B become the occasion to draw 3 spade cards the remaining 50 end cards [tex](A \cap B)[/tex] was its case where a 52 card spade is chosen [tex](2+3)=5[/tex].

The number of plots drawn first from 13 regular 52-cerd decks equals number of,[tex]n(A)=\binom{13}{2}[/tex]  probability of event [tex]A, PA =\frac{\binom{13}{2}}{\binom{52}{2}}[/tex]

Furthermore, the multitude of possibilities we can pull from of the remaining 11 spades of the previous 3 cards is 50-card decks standard, [tex]n (B) = \binom{11}{3}[/tex]  then, the probability of event, [tex]B, P(B)=\frac{\binom{11}{3}}{\binom{50}{3}}[/tex]

The chances of five cards being drawn (three spades and two spades),

[tex]P(B \cap A)=\frac{\binom{13}{5}}{\binom{52}{5}}[/tex]

Then there is the chance that the next three cards will be picked if the first two are both pads, [tex]P(\frac{B}{A})[/tex]

[tex]\to P(\frac{B}{A}) \\\\ =\frac{P(B\cap A )}{P(A)}\\\\=\frac{\frac{\frac{13}{5}}{\frac{52}{2}}}{\frac{\frac{13}{2}}{\frac{52}{2}}}\\\\= 0.00842[/tex]

Answer:  No, we don't have a right triangle

==========================================================

Explanation:

If a triangle with sides a,b,c makes the equation a^2+b^2 = c^2 true, where c is the longest side, then this triangle is a right triangle. This is the converse of the pythagorean theorem.

Here we have a = 2, b = 5 and c = 7.

So...

a^2+b^2 = c^2

2^2+5^2 = 7^2

4+25 = 49

29 = 49

The last equation is false, so the first equation is false for those a,b,c values. Therefore, we do not have a right triangle.

------------

In contrast, consider the classic 3-4-5 right triangle

a = 3, b = 4 and c = 5 would make a^2+b^2 = c^2 true because 3^2+4^2 = 5^2 is a true equation (both sides lead to 25).

Answer:

Corrie = 5 ft.  2 in.

Jennifer = 4 ft.  6 in.

Step-by-step explanation:

If you convert Jason's height to inches then it would be 57 in.

4 x 12 = 48 in.     48 + 9 = 57 in.

To find Corrie's height you just have to add 5 inches to Jason's height.

57 + 5 = 62 in.

And to find Jennifer's height you just subtract 8 inches from Corrie's height.

62 - 8 =  54 in.

Now all you need to do is convert Corrie and Jennifer's height into feet. You have to divide Corrie and Jennifer's height by 12 inches. And if there are leftover or remaining numbers once you divide, they are just inches that you add on after the feet.

Jennifer's height =  54 / 12 = 4 feet and 6 inches are left over.

Corrie's height = 62 / 12 = 5 feet and 2 inches are left over.

Answer:

The decimal number system comprises digits from 0-9 that are 0, 1, 2, 3, 4, 5, 6, 7, 8 & 9. Some of the decimal number system examples are: ... 34110, 5610, 678910, 7810. Now as we know to write decimal numbers till 10 let us use the 3 rules on a decimal system,to write further numbers.

[tex] \bf \pink{Define \: the \: decimal \: number \: system \: in \: your \: own \: words. }[/tex]

Decimal system, also called Hindu-Arabic number system or Arabic number system, in mathematics, positional numeral system employing 10 as the base and requiring 10 different numerals, the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. ... It also requires a dot (decimal point) to represent decimal fractions.

Answer:

15^2+x^2=22^2

225+x^2=484

x^2=259

x=16.09 feet

Step-by-step explanation: 15^2+x^2=22^2

225+x^2=484

x^2=259

x=16.09 feet

Answer:

the answer is one hundred and eight 108

Step-by-step explanation:

108 bro trust me

Answer:

-1.2

Step-by-step explanation:

Answer: D y>2x-1

y<1/3x+1

Step-by-step explanation: I took the test and got it right

The points (0, 0) and (6/5, 7/5) are solutions to the system of inequalities D y>2x-1 and y<1/3x+1 which is correct options (D).

Inequality is the defined as mathematical statements that have a minimum of two terms containing variables or numbers is not equal.

A graph can be defined as a pictorial representation or a diagram that represents data or values.

Given the system of inequalities as

y>2x-1 and y<1/3x+1.

To determine the solutions, you first have to graph both of the lines in the problem.

y = 2x-1 and y = 1/3x+1. Then, to shift them to inequality, you have to shade the half-plane that they represent.

The solution is the space that they have in common. In this case, it will be on the right side of the graph.

The points (0, 0) and (6/5, 7/5) are included in the shaded region they have in common.

Hence, the points (0, 0) and (6/5, 7/5) are solutions to the system of inequalities y>2x-1 and y<1/3x+1.

Learn more about inequalities here:

brainly.com/question/20383699

#SPJ2

Answer:

21.46

Step-by-step explanation:

Start with the square

[tex]A = a^{2} \\100 = a^{2}\\10 = a[/tex]

Each side of the square is 10

This also means the diameter of the circle is 10, with a radius of 5

[tex]A = \pi r^{2} \\A = \pi 5^{2} \\A = 78.54[/tex]

Now substract the area of the circle from the square

x = 100 - 78.54

2.75

Step-by-step explanation:

[tex]\sf\purple{2.75}[/tex] ✅

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex] \frac{11}{4} \\ = 2.75[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.ඞ}}}}}[/tex]

Answer:

Step-by-step explanation:

11.5 is greater than -12.5

Answer: -12.5 is greater

-

Step-by-step explanation:

Answer: D = 4, 4.5

E = 5, 4.75

H = 8, 5.5

I = 9, 5.75

Step-by-step explanation:Gang

The coordinates of the corresponding points are given below.

C ⇒ (3, 4.25)

D ⇒ (4, 4.50)

E ⇒ (5, 4.75)

F ⇒ (6, 5)

G ⇒ (7, 5.25)

H ⇒ (8, 5.50)

I ⇒ (9, 5.75)

Coordinate geometry is the study of geometry using the points in space. Using this, it is possible to find the distance between the points, the dividing line is the m:n ratio, finding the mid-point of the line, etc.

AB is separated into equal sections in the picture. Point A's coordinates are (2, 4), and Point Bare's coordinates are (10,6).

There are eight sections of line AB. Then the rise in abscissa after each segment is calculated as,

⇒ (10 - 2) / 8

⇒ 8 / 8

⇒ 1

Then the rise in ordinate after each segment is calculated as,

⇒ (6 - 4) / 8

⇒ 2 / 8

⇒ 0.25

Then the coordinate of the points is written as,

C ⇒ (3, 4.25)

D ⇒ (4, 4.50)

E ⇒ (5, 4.75)

F ⇒ (6, 5)

G ⇒ (7, 5.25)

H ⇒ (8, 5.50)

I ⇒ (9, 5.75)

More about the coordinate geometry link is given below.

https://brainly.com/question/1601567

#SPJ7

Answer:

(5^2)(5-7)

Step-by-step explanation:

So we know h(x)=x-7.

We also know g(x)=x^2

We need to plug in these values for (g*h)(5)

This would equal:

((x-7)*x^2)(5)

Since parthese can also be considered multipcation symbols, we can think of this as:

(x-7)(x^2)(5)

Lets distrubute the 5 to all the x's:

(5-7)(5^2)

Which is:

([tex]5^{2}[/tex])(5-7)

This looks like answer C.

Hope this helps!

Step-by-step explanation:

6.5+6.5=diameter

Answer:

13 cm

Step-by-step explanation:

The diameter is twice the radius

The radius is 6.5 cm

diameter = 2 * 6.5 = 13 cm

Answer:

4

Step-by-step explanation: 16/4=4

Answer:

q = 3m

Step-by-step explanation:

We know that segment HF is half of IJ, therefore we can say;

IJ / 2 = HF or q

6 / 2 = HF or q

3 = HF or q

Hope this helps!

Answer:

-48

Step-by-step explanation:

4(-4)(3)

-16(3)

-48

Answer:

4(-4) (3)

Step-by-step explanation:

put that in your calccalculator:)