Answer:
Explanation:
Hello!
In this case, since the undergoing chemical reaction is:
[tex]2NO+O_2\rightleftharpoons 2NO_2[/tex]
The equilibrium expression in terms of pressures is:
[tex]Kp=\frac{p_{NO_2}^2}{p_{NO}^2p_{O_2}}[/tex]
Thus, for the initial conditions, we compute the initial pressures of both nitric oxide and oxygen:
[tex]p_{NO}^{0}=\frac{12.0g*0.082\frac{atm*L}{mol*K}*298.15K}{30g/mol*10.0L}=0.978atm\\\\ p_{O_2}^{0}=\frac{12.0g*0.082\frac{atm*L}{mol*K}*298.15K}{32g/mol*10.0L}=0.917atm[/tex]
Next, since the equilibrium pressure is 1148 mmHg or 1.51 atm, we can write:
[tex]p_T=p_{NO_2}+p_{NO}+p_{O_2}\\\\1.51=2x+0.978-2x+0.917-x\\\\1.51=1.90-x\\\\x=0.39atm[/tex]
Thus, the Kp turns out:
[tex]Kp=\frac{(2*0.39)^2}{(0.978-2*0.39)^2(0.917-x)} \\\\Kp=29.4[/tex]
Best regards!
In ionic bonding, atoms__.
A. share electrons
B. are connected by strong electrical forces
C. lose protons and form ions
D. stop moving completely
what is the equation for the esterification of glycerol and three palmitic acid
Answer:
Pentyl Ethanoate, CH3COOC5H11, which smells like bananas, is produced from the esterification reaction: CH3COOH(aq) +C5H11OH(aq) → CH3COOC5H11(aq) + H … 2O(l) A reaction uses 3.58g of CH3COOH and 4.75g of C5H11OH and has a yield of 45.00%. Determine the mass of ester that foorms
PLZ HELP ASAP
Which would increase the reaction rate?
Check all that apply.
A. Stirring the reaction
B. Raising the activation energy
O C. Adding a catalyst
D. Raising the temperature
Answer:
adding a catalyst will increase the reaction rate.
Explanation:
im like 95% sure thats right.
Answer:
A. C. D
Explanation:
ap ex
A student is using colored beads to model 1 molecule of LaTeX: Ca_3\left(PO_4\right)_2C a 3 ( P O 4 ) 2. The student uses blue beads to model Calcium, red beads to model Phosporus, and green beads to model Oxygen. How many of each color will the student need to make their model?
Answer:
3 blue beads
1 red beads
4 green beads
Explanation:
The compound given:
Ca₃PO₄
Elements in the compound are:
Ca
P
O
Number of atoms are :
Ca - 3
P - 1
O - 4
blue beads to model Calcium
red beads to model Phosphorus
green beads to model Oxygen
3 blue beads
1 red beads
4 green beads
A ball was massed in a dish. The total mass was 15.6 grams. Treball was placed in a
cylinder containing 26.7 ml of water. The new water level was 38.9 ml. If the mass of the dish is 1.03 grams, what is the mass of the ball?
Answer:
14.57g
Explanation:
Given parameters:
Mass of dish + ball = 15.6g
Initial volume of water in the cylinder = 26.7mL
Final volume of water in the cylinder = 38.9mL
Mass of dish = ?
Unknown
Mass of the ball = ?
Solution;
Since the mass of ball and dish is 15.6g,
Mass of the ball =Mass of ball + dish - mass of the dish
Insert the parameters and solve;
Mass of the ball = 15.6g - 1.03g = 14.57g
How is filtration done?
What is the difference between residue and filtrate?
Answer:
residue is whatever remains after something else has been removed while filtrate is the liquid or solution that has passed through a filter, and which has been separated from the filtride.
filtration id done by placing a filter paper on the beaker or container then pour the filtride then let it settle and it will pass through and you will have the fitrate and residue
Explanation:
1. The state of Georgia has seen their water table become lower. What does this mean?
The amount of groundwater is increasing.
Their groundwater is being recharged by rain.
The amount of groundwater is decreasing.
Their groundwater is flowing to confined aquifers.
Answer:
The amount of groundwater is decreasing.
Explanation:
In an ecosystem like the state of Georgia where the water table has become lower it means that the amount of groundwater in the ecosystem is decreasing.
What is an ecosystem?Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.
Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.
Learn more about ecosystem,here:
https://brainly.com/question/19267717
#SPJ5
Explain some of the uses of metals based on their properties.
Answer:
Explain some of the uses of metals based on their properties.
Explanation:
Metals have a shiny or metallic luster and are good conductors of heat and electricity, they can be bent and pounded in various shapes, so they can be used on cars, coins, some pipes, keys, and and a flag.
A student writes Ba?- as the symbol for a barium ion. Explain what is incorrect about the symbol.
Answer:
ion is missing
Explanation:
3 Which of the following best represents potential energy? *
A Air leaking rapidly from a car tire.
B A marble sitting at the top of a ramp.
C Heat radiating from a large forest fire.
D Water flowing through a rubber hose.
Answer:
Its B
Explanation:
Determine the vapor pressure of a solution at 25°C that contains 76.6 g of glucose (C6H12O6 ) in 250.0 mL of water. The vapor pressure of pure water at 25°C is 23.8 torr
Answer:
[tex]23.093\ \text{torr}[/tex]
Explanation:
[tex]M_g[/tex] = Molar mass of glucose = 180.2 g/mol
[tex]M_w[/tex] = Molar mass of water = 18 g/mol
[tex]m_g[/tex] = Mass of glucose = 76.6 g
[tex]m_w[/tex] = Mass of water = [tex]250\times 1\ \text{g/mL}=250\text{g}[/tex]
[tex]P_0[/tex] = Vapor pressure of pure water at 25°C = 23.8 torr
The mole fraction of glucose is
[tex]x_g=\dfrac{\dfrac{m_g}{M_g}}{\dfrac{m_g}{M_g}+\dfrac{m_w}{M_w}}=\dfrac{\dfrac{76.6}{180.2}}{\dfrac{76.6}{180.2}+\dfrac{250}{18}}\\\Rightarrow x_g=0.0297[/tex]
Mole fraction of the solute would be
[tex]\dfrac{P_0-P}{P_0}=x_g\\\Rightarrow 0.0297=\dfrac{23.8-P}{23.8}\\\Rightarrow P=23.8-0.0297\times23.8\\\Rightarrow P=23.093\ \text{torr}[/tex]
The vapor pressure of the solution is [tex]23.093\ \text{torr}[/tex].
Calculate the pH during the titration of 20.00 mL of 0.1000 M trimethylamine, (CH3)3N(aq), with 0.2000 M HClO4(aq) after 9.48 mL of the acid have been added.
Complete Question
Calculate the pH during the titration of 20.00 mL of 0.1000 M trimethylamine, (CH3)3N(aq), with 0.2000 M HClO4(aq) after 9.48 mL of the acid have been added.Kb of trimethylamine = 6.5 x 10-5.
Answer:
The pH is [tex]pH = 9.84[/tex]
Explanation:
From the question we are told that
The volume of trimethylamine, (CH3)3N(aq) is [tex]V_{t} = 20.00mL[/tex]
The concentration of trimethylamine is [tex]C_t = 0.1000 \ M[/tex]
The volume of HClO4(aq) is [tex]V_{h} = 9.48 mL[/tex]
The concentration of HClO4(aq) is [tex]C_h = 0.200 M[/tex]
The Kb value is [tex]K_b = 6.5 * 10^{-5}[/tex]
Generally the the pOH of this reaction is mathematically represented as
[tex]pOH = pK_b + log [\frac{N_h}{N_b} ][/tex]
Here [tex]N_h[/tex] is the number of moles of acid which is evaluated as
[tex]N_h = C_h * V_h[/tex]
=> [tex]N_h = 0.200 * 9.48[/tex]
=> [tex]N_h = 1.896[/tex]
Here [tex]N_t[/tex] is the number of moles of acid which is evaluated as
[tex]N_t = C_t * V_t[/tex]
=> [tex]N_t = 0.100 * 20[/tex]
=> [tex]N_t = 2[/tex]
So
[tex]pOH = -log(K_b) + log [\frac{N_h}{N_b} ][/tex]
[tex]pOH = -log(6.5*10^{-5}) + log [\frac{1.896}{2} ][/tex]
=> [tex]pOH = 4.1639[/tex]
Generally the pH is mathematically represented as
[tex]pH = 14 - pOH[/tex]
=> [tex]pH = 14 - 4.1639[/tex]
=> [tex]pH = 9.84[/tex]
The first excited electronic energy level of the helium atom is 3.13 x 10-18 J above the ground level. Estimate the temperature at which the electronic motion will begin to make a significant contribution to the heat capacity. That is, at what temperature will the ratio of the population of the first excited state to the ground state be 5.0%?
Answer:
75603.86473 K
Explanation:
Given that:
The 1st excited electronic energy level of He atom = 3.13 × 10⁻¹⁸ J
The objective of this question is to estimate the temperature at which the ratio of the population will be 5.0 between the first excited state to the ground state.
The formula for estimating the ratio of population in 1st excited state to the ground state can be computed as:
[tex]\dfrac{N_2}{N_1} = e ^{^{-\dfrac{(E_2-E_1)}{KT}}} = e ^{^{-\dfrac{(\Delta E)}{KT}}}[/tex]
From the above equation:
Δ E = energy difference = 3.13 × 10⁻¹⁸ J
k = Boltzmann constant = 1.38 × 10⁻²³ J/K
[tex]\dfrac{N_2}{N_1} = 0.5[/tex]
Thus:
[tex]0.05 =e^{^{ -\dfrac{3.13 \times 10^{-18} \ J}{1.38\times 10^{-23 \ J/K}\times T}}}[/tex]
[tex]In (0.05) = { -\dfrac{3.13 \times 10^{-18} \ J}{1.38\times 10^{-23 \ J/K}\times T}}}[/tex]
[tex]-3.00 = { -\dfrac{3.13 \times 10^{-18} \ J}{1.38\times 10^{-23 \ J/K}\times T}}}[/tex]
[tex]-3.00 = -226811.5942 \times \dfrac{1}{T}[/tex]
[tex]T = \dfrac{-226811.5942}{-3.00 }[/tex]
T = 75603.86473 K
What is the name of the region (on the graph) where the temperature remains constant while heat is being absorbed (or released)?
Answer:
A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. The plateaus on the curve mark the phase changes. The temperature remains constant during these phase transitions.
Please it's due today
Answer:
B
Explanation:
Newton's third law. states that:
Action and reaction are equal and opposite.
What factors affect the speed of a wave? Check all that apply. the amplitude of the wave the energy of the wave the temperature of the medium the type of wave the type of medium
Answer:
I believe its 1,2, and 5
Explanation:
C D E
temperature of medium
type of wave
type of medium
Using the equations
2 Fe (s) + 3 Cl₂ (g) → 2 FeCl₃ (s) ∆H° = -800.0 kJ/mol
Si(s) + 2 Cl₂ (g) → SiCl₄ (s) ∆H° = -640.1 kJ/mol
Determine the enthalpy (in kJ/mol) for the reaction
3 SiCl₄ (s) + 4 Fe (s) → 4 FeCl₃ (s) + 3 Si (s)
The enthalpy : 320.3 kJ/mol
Further explanationThe change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation
The enthalpy of formation measured in standard conditions (25 ° C, 1 atm) is called the standard enthalpy of formation (ΔHf °)
Based on the principle of Hess's Law,
the change in enthalpy of a reaction will be the same even though it is through several stages or ways
Reaction
2Fe (s) + 3Cl₂ (g) → 2FeCl₃ (s) ∆H° = -800.0 kJ/mol x 2
4Fe (s) + 6Cl₂ (g) → 4FeCl₃ (s) ∆H° = -1600.0 kJ/mol
Si(s) + 2 Cl₂ (g) → SiCl₄ (s) ∆H° = -640.1 kJ/mol
Reverse
SiCl₄ (s) → Si(s) + 2 Cl₂ (g) ∆H° = 640.1 kJ/mol x 3
3SiCl₄ (s) → 3Si(s) + 6Cl₂ (g) ∆H° = 1920.3 kJ/mol
------------------------------------------------------------------------ +
3 SiCl₄ (s) + 4 Fe (s) → 4 FeCl₃ (s) + 3 Si (s) ∆H° = 320.3 kJ/mol
The enthalpy for the formation of 4 moles of [tex]\rm FeCl_3[/tex] has been 320.3 kJ/mol.
The enthalpy of formation of 1 mole at standard temperature and pressure has been termed the standard enthalpy of formation.
The reaction enthalpy to be calculated has reactants of 3 moles of [tex]\rm SiCl_4[/tex], and 4 moles of Fe.
The enthalpy for the formation of [tex]\rm SiCl_4[/tex] has been -640.1 kJ/mol.
The enthalpy for the dissociation of [tex]\rm SiCl_4[/tex] has been the reverse of the formation reaction = +640.1 kJ/mol.
The enthalpy for the dissociation of 3 moles of [tex]\rm SiCl_4[/tex] has been = 3 [tex]\times[/tex] 640.1 kJ/mol.
The enthalpy for the dissociation of 3 moles of [tex]\rm SiCl_4[/tex] has been = 1920.3 kJ/mol.
The enthalpy for the formation of 2 moles of [tex]\rm FeCl_3[/tex] = -800 kJ/mol
The enthalpy for the formation of 4 moles of [tex]\rm FeCl_3[/tex] = -1600 kJ/mol.
The final reaction has 3 moles of [tex]\rm SiCl_4[/tex], and 4 moles of [tex]\rm FeCl_3[/tex].
Thus, the final enthalpy of reaction will be: 1920 kJ/mol + (-1600 kJ/mol)
The final enthalpy of reaction will be = 320.3 kJ/mol.
For more information about the enthalpy of reaction, refer to the link:
https://brainly.com/question/20113839
If 0.0806 mol CaCl2 is dissolved in water to make a 0.490 M solution, what is the volume of the solution?
Answer:
0.16 L
Explanation:
From the question given above, the following data were obtained:
Mole = 0.0806 mole
Molarity = 0.490 M
Volume =?
Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:
Molarity = mole /Volume
With the above formula, we can obtain the volume of the solution as illustrated below:
Mole = 0.0806 mole
Molarity = 0.490 M
Volume =?
Molarity = mole /Volume
0.490 = 0.0806/volume
Cross multiply
0.490 × volume = 0.0806
Divide both side by 0.490
Volume = 0.0806 / 0.490
Volume of solution = 0.16 L
Thus, the volume of the solution is 0.16 L.
A solution is a mixture of solute in the solvent. The volume of the solution is 0.16 L.
What is a solution?A solution is a mixture of solute in the solvent.
An example of a solution is a mixture of salt in water.
Given,
Moles = 0.0806 mol [tex]\rm CaCl_2[/tex]
Molarity = 0.490 M
To find: the volume of the solution
[tex]Molarity = \dfrac{n}{V}[/tex]
Putting the values
[tex]0.490 M = \dfrac{ 0.0806}{V}\\\\0.490 M \times V = 0.0806\\\\Divide\; both\;side\; with\; 0.490\\\\V= \dfrac{ 0.0806}{0.490}=0.16 L[/tex]
Thus, the volume so the solution is 0.16 l.
Learn more about the solution, here:
https://brainly.com/question/7932885
Hugh wrote the properties of physical and chemical weathering in the table shown.
Types of Weathering
Physical Weathering
Chemical Weathering
Temperature may break the rocks Can be caused by chemicals in water
Can be caused by snow and pressure Composition of rock remains same
Why is Hugh's table incorrect? (5 points)
a
Chemicals in water cause physical weathering.
b
ос
Temperature is unable to break rocks physically.
Chemical weathering changes the composition of rocks.
Physical weathering is unaffected by snow and pressure.
Od
Answer:
I am sure that the C one is correct
Answer:
how is this college level..im doing this in middle school..
Explanation:
In a vacuum, if a 0.045 kg golf ball is accelerated upward at 2.5 m/s2 by a hair dryer, how much force is required to accelerate the ball?
Answer:
F = 0.553 N
Explanation:
Given that,
Mass of a golf ball, m = 0.045 kg
Acceleration in upward direction, a = 2.5 m/s²
We need to find the force is required to accelerate the ball. Let the force be F. Using the second law of motion as follows :
F = m(a+g)
So,
F = 0.045 (2.5+9.8)
F = 0.553 N
So, the force required to accelerate the ball is 0.553 N.
What shape is the s sublevel? *
sphere
freaky
peanut
daisy
Answer:
Sphere
Explanation:
The shape of the s-sublevel is spherical in shape.
This sublevel has an azimuthal quantum number of 0 and it is spherical in shape;
p - sublevel has a dumb-bell shape d - sublevel has double dumb - bell shape f - sublevel has a complex shapeDescribe the role of chloroplasts in photosynthesis. (ASAP)
Answer:
Chloroplasts absorb sunlight and use it in conjunction with water and carbon dioxide gas to produce food for the plant. Chloroplasts capture light energy from the sun to produce the free energy stored in ATP and NADPH through a process called photosynthesis.
Explanation:
Nitrogen gas at 300 k and 200 kpa is throttled adiabatically to a pressure of 100 kpa if the change in kinetic energy is negligble the temperature of the nitrogen after throttling will be:_________
Answer:
The temperature of the Nitrogen after throttling is [tex]T_2 = 300 \ K[/tex]
Explanation:
From the question we are told that
The temperature is [tex]T_1 = 300 \ K[/tex]
The pressure is [tex]P = 200 \ kPa = 200 * 10^{3} \ Pa[/tex]
The pressure after being [tex]P_1 = 100 \ kPa = 100 * 10^{3} \ Pa[/tex]
Generally from the first law of thermodynamics we have that
[tex]Q - W = \Delta U + \Delta K[/tex]
Here [tex]\Delta U[/tex] is the change internal energy which is mathematically represented as
[tex]\Delta U = C_p (T_2 - T_1)[/tex]
Here [tex]C_p[/tex] is the specific heat of the gas at constant pressure
[tex]\Delta K[/tex] is the change kinetic energy which is negligible
Q is the thermal energy which is Zero for an adiabatic process
W is the work done and the value is zero given that the gas was throttled adiabatically
So
[tex]0= \Delta U +0[/tex]
=> [tex]\Delta U = 0[/tex]
=> [tex](T_2 - 300) = 0[/tex]
=> [tex]T_2 = 300 \ K[/tex]
How is active immunity different from passive immunity? Give examples of both active and passive natural and artificial immunity.
what processes add methane (CH4) to the atmosphere
Answer:
Cultivated rice paddies
Drilling of natural deposits
Fossil fuel use
Burning of biomass
Landfills
Explanation:
The bulk of the methane released into the atmosphere are as a result of various human activities.
Cultivated rice paddies are a known source of methaneThe drilling of natural deposits and their exploration can release some methane into the atmosphereBurning of fossil fuel and biomass is a source of methane Landfills produces methane as organic materials begins to decay.The freezing point of a solution the freezing point of the pure solvent
Answer:
This means that a solution must be cooled to a lower temperature than the pure solvent in order for freezing to occur.
Explanation:
Answer:
Freezing Point Depression. The freezing point of a solution is less than the freezing point of the pure solvent. This means that a solution must be cooled to a lower temperature than the pure solvent in order for freezing to occur
A Beer's Law Plot of sample A gives a slope equal to 1.2 M-1cm-1. Calculate molar concentration of this sample at a wavelength of 420 nm and an absorbance reading of 0.23 in a 1 cm cuvette.
Answer:
[tex]0.192\ \text{M}[/tex]
Explanation:
A = Absorbance of solution
E = Molar absorptivity
l = Length of cuvette = 1 cm
c = Concentration of solution
Beer's law is given by
[tex]A=Elc[/tex]
The equation of a straight line is given by
[tex]y=mx+c[/tex]
Comparing the above equations we get
Value on [tex]y[/tex] axis = A = Absorbance of solution = 0.23
[tex]m[/tex] = Slope of line = El = Molar absorptivity multiplied with length = [tex]1.2\times 1\ \text{M}^{-1}[/tex]
[tex]x[/tex] = Value of x axis = c = Concentration of solution
So we get
[tex]c=\dfrac{A}{El}\\\Rightarrow c=\dfrac{0.23}{1.2\times 1}\\\Rightarrow c=0.192\ \text{M}[/tex]
The molar concentration of the sample is [tex]0.192\ \text{M}[/tex]
Which element is most likely suspected?
iron
Sulfur
Chromium
Nickel
Answer: sulfur
Explanation:
Answer:
its sulfur babes
Explanation:
4 As a boulder rolls from the top of a hill to the bottom, how do its potential and kinetic energy change? *
A Potential and kinetic energy both increase.
B Potential increases and kinetic decreases.
C Potential decreases and kinetic increases.
D Potential and kinetic energy both decrease..
Answer:
c. Potential decreases and kinetic increases.
Explanation:
As the boulder is rolling down the hill, potential energy decreases as kinetic energy increases.
Please Brainliest me
Plate Tectonics Lab Report
Instructions: In the Plate Tectonic lab you will investigate the interactions between continental and oceanic plates at convergent, divergent, and transform boundaries around the globe. Record your observations in the lab report below. You will submit your completed report.
Name and Title:
Include your name, instructor's name, date, and name of lab.
Kaleb, Ms. Young, 11/25/2020, Plate Tectonics Lab Report
Objective(s):
In your own words, what was the purpose of this lab?
To look at interactions between continental and oceanic plates.
Hypothesis:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
Location One: Select three events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Four: Select two events that you predict will be observed. If I explore two oceanic plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Five: Select three events that you predict will be observed. If I explore two oceanic plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Six: Select two events that you predict will be observed. If I explore two oceanic plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Procedure:
The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure to identify the test variable (independent variable), outcome variable (dependent variable).
Reminder: Test variable = the item you are changing or manipulating; Outcome variable = the item you are measuring
Test variable (independent variable):
Outcome variable (dependent variable):
Data:
Record the data from each location below.
Location Name
Boundary Type
(C=Convergent, D=Divergent, or T=Transform)
Year Observed
(5, 10, or 20 million years)
Geologic Events Observed
(earthquakes, faults, ocean formation, mountains, volcanoes, island chains, seafloor spreading)
Location One
Himalayas
5
Event 1-
20
Event 2-
Location Two
East Africa
5
Event 1-
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Five: Select three events that you predict will be observed. If I explore two oceanic plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Six: Select two events that you predict will be observed. If I explore two oceanic plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Procedure:
The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure to identify the test variable (independent variable), outcome variable (dependent variable).
Reminder: Test variable = the item you are changing or manipulating; Outcome variable = the item you are measuring
Test variable (independent variable):
Outcome variable (dependent variable):
Data:
Record the data from each location below.
Location Name
Boundary Type
(C=Convergent, D=Divergent, or T=Transform)
Year Observed
(5, 10, or 20 million years)
Geologic Events Observed
(earthquakes, faults, ocean formation, mountains, volcanoes, island chains, seafloor spreading)
Location One
Himalayas
5
Event 1-
20
Event 2-
Location Two
East Africa
5
Event 1-
Please answer quickly!!!
I will award 50 points!
Answer:
In this section, please include the if/then statements you developed during your lab activity for each location on the map. These statements reflect your predicted outcomes for the experiment.
Location One: Select two events that you predict will be observed. If I explore two continental plates at a convergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Two: Select three events that you predict will be observed. If I explore two continental plates at a divergent boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
Location Three: Select three events that you predict will be observed. If I explore two continental plates at a transform boundary, then I will observe:
earthquakes
faults
ocean formation
mountains
volcanoes
island chains
seafloor spreading
This is all I have for now! Hope this can help! :)