(a) The complete graph [tex]K_n[/tex] has an Euler cycle if and only if n is an even number greater than or equal to 2.
(b) There are no complete graphs [tex]K_n[/tex] that have Euler trails but not Euler cycles. A complete graph always has an Euler cycle if it has an Euler trail.
(c) The bipartite graph [tex]K_r[/tex],s has an Euler cycle if and only if both r and s are even numbers greater than or equal to 2.
(a) To determine the values of n for which the complete graph [tex]K_n[/tex] has an Euler cycle, we need to understand the conditions for an Euler cycle to exist in a graph.
An Euler cycle is a closed walk in a graph that visits every edge exactly once and starts and ends at the same vertex. In order for a graph to have an Euler cycle, it must satisfy the following conditions:
All vertices in the graph have even degrees (an even number of edges incident to them).
The graph is connected, meaning there is a path between any two vertices.
Now let's apply these conditions to the complete graph [tex]K_n[/tex].
Degree of Vertices: In a complete graph [tex]K_n[/tex], each vertex is connected to every other vertex. Therefore, each vertex has a degree of n-1, as it is connected to n-1 other vertices. Since n-1 is always an odd number, it means that all vertices in [tex]K_n[/tex] have odd degrees. Hence, [tex]K_n[/tex] does not have an Euler cycle for any value of n.
Connectivity: A complete graph [tex]K_n[/tex] is always fully connected, meaning there is a direct edge between every pair of vertices. Therefore, the connectivity condition is satisfied for any value of n.
Based on these conditions, we can conclude that the complete graph [tex]K_n[/tex] does not have an Euler cycle for any value of n.
(b) since [tex]K_n[/tex] does not have an Euler cycle for any value of n, it also implies that there are no [tex]K_n[/tex] graphs that have Euler trails but not Euler cycles.
(c) The bipartite graph [tex]K_r[/tex],s is a complete bipartite graph with two sets of vertices, one with r vertices and the other with s vertices. To have an Euler cycle in this bipartite graph, the following conditions must be met:
All vertices in each set have even degrees.
The number of vertices in each set must be equal.
Since the complete bipartite graph [tex]K_r[/tex],s has all vertices with degree s in one set and degree r in the other set, it means that both r and s must be even numbers for all vertices to have even degrees. Additionally, the number of vertices in each set must be equal for the graph to be bipartite. Therefore, an Euler cycle exists in the bipartite graph [tex]K_r[/tex],s if and only if both r and s are even numbers.
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HELPPPPPO
In a school of 500 students, a random sample of 60
students are asked what
their favorite subject is. The
results are in the table. Based on this sample, how
many students in the school would we predict have
math as a favorite subject?
Answer:
150
Step-by-step explanation:
'x' = number of students out of 500 who selected math
18/60 = x/500
cross-multiply:
60x = 9000
x = 150
C. Question 2 of Online Tutorial 5 Test at 20% significance level whether one of the drugs is more effective than the other.
(a) The absolute value of the critical value of this test is type your answer...
(b) The absolute value of the calculated test statistic is type your answer...
(c) The p-value of this test is type your answer....
The p-value of this test is 0.0294.
a) The absolute value of the critical value of this test is "1.645".
The critical value for the given test can be calculated using the following formula;`
Critical value =
± z_(α/2)`
Where,`α` is the level of significance of the test.
`z_(α/2)`
is the critical value from the standard normal distribution table.
Since, the significance level of the test is 20%,
α = 0.2 or 0.20
Level of Significance = 0.20α/2 = 0.20/2α/2 = 0.10
Now, the critical value of the test can be found from the standard normal distribution table at 0.10 level of significance.
It comes out to be 1.645.
So, the absolute value of the critical value of this test is 1.645.
b) The absolute value of the calculated test statistic is "2.23".
The test statistic for the given test is the t-value calculated using the sample data.
It can be calculated using the following formula;
`t = (x¯1 - x¯2) / [ s_p * √(1/n1 + 1/n2) ]`
Where,`x¯1 and x¯2` are the sample means.
`s_p` is the pooled standard deviation.
`n1 and n2` are the sample sizes.
So, the test statistic of the given test comes out to be 2.23.So, the absolute value of the calculated test statistic is 2.23.
c) The p-value of this test is "0.0294".
The p-value for the given test is the probability of getting a t-value more extreme than the calculated t-value, assuming the null hypothesis is true.
The p-value can be calculated using the t-distribution table.
The degrees of freedom for the given test is
`df = n1 + n2 - 2`.
Substituting the values in the formula, the p-value for the given test comes out to be 0.0294.
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PLEASE HURRY 12 POINTS PLEASE HELPPPPPP
Step-by-step explanation:
to find the area of a circle, it is pi times radius squared. so 1 times pi squared is pi^2 the area is 4 plus 2pi^2
PLEASE HELP ASAP ILL AWARD BRAINIEST
Answer:
Сен қазақ сыңба?
Step-by-step explanation:
қазашшаайтшыааа
Someone help me please! With 3 and 4
Determine whether each quadrilateral is a parallelogram. Write yes or no. If yes, give a reason for your answer.
Answer:
yes
Step-by-step explanation:
All of the opposite sides are parallel to each other.
Which of the following systems of inequalities has point D as a solution?
Two linear functions f of x equals 3 times x plus 4 and g of x equals negative one half times x minus 5 intersecting at one point, forming an X on the page. A point above the intersection is labeled A. A point to the left of the intersection is labeled B. A point below the intersection is labeled C. A point to the right of the intersections is labeled D.
A. f(x) ≤ 3x + 4
g of x is less than or equal to negative one half times x minus 5
B. f(x) ≥ 3x + 4
g of x is less than or equal to negative one half times x minus 5
C. f(x) ≤ 3x + 4
g of x is greater than or equal to negative one half times x minus 5
D. f(x) ≥ 3x + 4
g of x is greater than or equal to negative one half times x minus 5
The point labeled D is to the right of the intersection of the two linear functions. This means that its x-coordinate is greater than the x-coordinate of the point of intersection.
We can find the point of intersection by setting the two functions equal to each other:
3x + 4 = (-1/2)x - 5
Solving for x, we get:
(7/2)x = -9
x = -18/7
So the point of intersection is (-18/7, -29/7).
Since the x-coordinate of point D is greater than -18/7, we can eliminate options A and C.
Now we need to check whether option B or option D includes point D as a solution. To do this, we can simply plug in the coordinates of D into the two inequalities and see which one holds true.
Option B:
f(x) ≥ 3x + 4
2 ≥ 3(D) + 4
2 ≥ 3D + 4
-2 ≥ 3D
D ≤ -2/3
g(x) ≤ (-1/2)x - 5
2 ≤ (-1/2)(D) - 5
7 ≤ -D
D ≥ -7
Since -2/3 is less than -7, option B does not include point D as a solution.
Option D:
f(x) ≥ 3x + 4
2 ≥ 3(D) + 42 ≥ 3D + 4
-2 ≥ 3D
D ≤ -2/3
g(x) ≥ (-1/2)x - 5
2 ≥ (-1/2)(D) - 5
7 ≥ -D
D ≤ -7
Since -2/3 is less than -7, option D does not include point D as a solution either.
Therefore, neither option B nor option D includes point D as a solution. The correct answer is that neither system of inequalities has point D as a solution.
hey hottie !
Which of the following situations does Mrs. Ji Woo's hourly wage change by a constant percent?
A)Mrs. Ji Woo's starting hourly wage is $30.00 per hour the first year, and it increases by $2.50 each year.
B)Mrs. Ji Woo's hourly wage is $20 per hour in the first year, $22 per hour the second year, $24.20 per hour the third year, and so on.
C)Mrs. Ji Woo's starting hourly wage is $15.00 per hour. Her hourly wage is $15.75 after one year, $17.00 after two years, $18.75 after three years, and so on.
D)Mrs. Ji Woo's starting hourly wage is $28.00 per hour. She receives a $0.75 per hour raise after one year, a $1.00 per hour raise after the second year, a $1.25 raise after the third year, and so on.
Answer:
B I think
Step-by-step explanation:
I think it's B because in b it says so on which means his raise keeps going up each year
Find the Errors: A student multiplied the two polynomials below.
(a) Clearly state the two errors that the student made in their multiplication table. (4 points)
(b) State what the correct answer should be. (2 points)
help i need the answer
Answer:
NO
Step-by-step explanation:
If the diameter of the circle is doubled the area will be increased 4 times
What is the answer to the question
Someone please help me I’ll give out brainliest please dont answer if you don’t know
Answer:
-5 + 4n
Step-by-step explanation:
-1/2(10 - 8n)
-5 + 4n
Help ! I’m stuck. Any help would be gladly appreciated
Answer:
The answer is D
hope this helps
Given that z is a standard normal random variable, find z for each situation (to 2 decimals). Enter negative values as negative numbers. The area to the left of z is .2119. The area between -z and z is .9030. The area between -z and z is .2052. The area to the left of z is .9948. The area to the right of z is .6915.
After considering the given data we conclude that the z-score for each situation is
The area concerning left of z is .2119: z = -0.81
The area amongst -z and z is .9030: z = 1.44
The area amongst -z and z is .2052: z = 0.84
The area concerning left of z is .9948: z = 2.59
The area concerning right of z is .6915: z = 0.48
To evaluate the z-score for each situation, we can apply the z-table . Here are the steps to find the z-score for every situation:
The area concerning left of z is .2119:
Applying the z-table, we can evaluate that the z-score is -0.81.
The area amongst -z and z is .9030:
Applying the z-table, we can evaluate that the z-score is 1.44.
The area amongst -z and z is .2052:
Utilising the z-table, we can express that the z-score is 0.84.
The area concerning left of z is .9948:
Applying the z-table, we can calculate that the z-score is 2.59.
The area concerning right of z is .6915:
We need to evaluate the area concerning left of z first, which is
1 - 0.6915 = 0.3085.
Applying the z-table, we can compound that the z-score is 0.48.
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In a basketball game, Elena scores twice as many points as Tyler. Tyler scores four points fewer
than Noah, and Noah scores three times as many points as Mai. If Mai
scores 5 points, how many
points did Elena score? Explain your reasoning.
Answer:
22
Step-by-step explanation:
if mai scores 5 points and noah scores 3 times that then noah scored 15 points, and if tyler scores four less than noah than he scored 11 points, which you multiply by 2 to get elena's score which is 22
Got It? Do this problem to find out.
y
K
b. The plans for a teeter-totter
are shown at the right. Using
points G and L, find the slope
of the teeter-totter. Then verify
that the slope is the same at
a different location by choosing
a different set of points.
Н.
G
O
х
AN
Check
2
Answer:
2/3
Step-by-step explanation:
rise over run
up and over
Each person is dealt 5 cards, show the total number of cards dealt for each players from 3 to 6 write the ratio of cards dealt
Answer:
Following are the responses to these question:
Step-by-step explanation:
Because every player has 5 cards handed
The card ratio is 5:1 per player.
So, if there are three teams
5 times 3=15 Cards
Four players=four times five=20 cards
Five players=5 times five=25 cards
6 cards=6 times 5=30 cards
The card ratio is 5:1 per player.
y=x+8
x+y=2
Solving Systems by Substitution
Answer:
{-3, 5}.
Step-by-step explanation:
y = x + 8
x + y = 2
Substitute y = x + 8 in the second equation:
x + x + 8 = 2
2x + 8 = 2
2x = -6
x = -3
Now plug this into the first equation
y = -3 + 8 = 5.
helllllllllllllp me please i just wanna finish this worksheet
Answer:
what
Step-by-step explanation:
Please find the next fraction to this sequence! Right answers only!
Answer:
4/15
Step-by-step explanation:
Each fraction is 1/15 less than the previous.
If we make them all the same denominator,
then it would show as:
8/15
7/15
6/15
5/15
The next fraction would be 5/15 - 1/15
which is
4/15
Answer:
4 1
__ because it goes down by ___
15 15
Step-by-step explanation:
Someone please help
Answer:
The first one
Step-by-step explanation:
Because
$5,000 is deposited in an account that receives 6.1 percent interest compounded continuously. How much money is in the account after six years?
$30500 ..............................................................................................................................
Maria wants to buy a pair of shoes for $32.50 and a shirt for $8.50. If the sales tax rate is 8.5%, what will be the amount of sales tax on Marias purchase?
Answer:
54.25
Step-by-step explanation:
Determine the Y intercept PLEASE HELP!!
X Y
-3 -3
0 -1
3 1
Consider the following recurrence: an= 8 n = 1 {2an-1 +8 n>1 it a. Give a closed-form expression for the recurrence. b. Prove, using proof by induction, that your answer from part a is equivalent to the recurrence an?
a.The closed-form expression for the given recurrence is: an = 8 * [tex]2^{(n-1)} + 6.[/tex]
b.In the proof by induction, we showed that the closed-form expression for the recurrence, an = 8 * [tex]2^{(n-1)}[/tex] + 6, holds true for both the base case and the inductive step. Thus, confirming its equivalence to the given recurrence.
a.What is the closed-form expression for the given recurrence?The closed-form expression for the given recurrence, an = [tex]2^n[/tex] * 8 - [tex]2^1[/tex] + 6, represents a direct formula to calculate the value of each term in the sequence. It involves exponentiation and arithmetic operations to determine the value based on the position (n) in the sequence.
b.How can we prove the equivalence between the closed-form expression and the recurrence using induction?In the proof by induction, we will first establish the base case, which is n = 1. From the recurrence, we have a1 = 8 * [tex]2^{(1-1)}[/tex] + 6 = 8. Substituting n = 1 into the closed-form expression, we also get a1 = 8 * [tex]2^{(1-1)}[/tex] + 6 = 8. The base case holds.
Next, we assume that the closed-form expression is true for an arbitrary positive integer k, i.e., ak = 8 * [tex]2^{(k-1)}[/tex] + 6.
Now, we will prove that it holds for k + 1, i.e., ak+1 = 8 * [tex]2^k[/tex] + 6.
Using the recurrence, we have ak+1 = 2 * ak-1 + 8 = 2 * (8 * [tex]2^{(k-1)}[/tex] + 6) + 8 = 16 * [tex]2^{(k-1)}[/tex] + 12 + 8 = 8 * [tex]2^k[/tex] + 6.
By comparing this with the closed-form expression, we see that ak+1 = 8 * [tex]2^k[/tex] + 6.
Therefore, the closed-form expression holds for k + 1.
By the principle of mathematical induction, we have proven that the closed-form expression, an = 8 * [tex]2^{(n-1)}[/tex] + 6, is equivalent to the given recurrence.
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The solution to the recurrence relation T(n) = T(n-1) + 2, with T(1) = 0, is T(n) = 2k.
To solve the given recurrence relation T(n) = T(n-1) + 2, for n > 0, with the initial condition T(1) = 0, we can use backward substitution.
1. Start with the base case T(1) = 0.
2. Substitute T(n-1) with T(n-2) + 2 in the original recurrence relation:
T(n) = T(n-1) + 2
= (T(n-2) + 2) + 2
= T(n-2) + 4
3. Repeat the substitution process until we reach the base case:
T(n) = T(n-1) + 2
= (T(n-2) + 2) + 2
= ((T(n-3) + 2) + 2) + 2
= T(n-3) + 6
4. Continue this process until n - k = 1, where k is a positive integer.
5. Finally, substitute n - k with 1:
T(n) = T(n-1) + 2
= (T(n-2) + 2) + 2
= ((T(n-3) + 2) + 2) + 2
= ...
= T(1) + 2k
6. Since T(1) = 0, we have:
T(n) = 0 + 2k
= 2k
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1. El ayuntamiento de un pueblo quiere asfaltar
una plaza circular que tiene en el centro una
fuente, también circular, para celebrar allí con-
ciertos de música a lo largo del año. Si la fuente
tiene un diámetro de 4 m y la plaza, uno de 16
m, ¿cual será el área de la región por asfaltar?
A "pay-what-you-pull" raffle is an alternative to a standard raffle where a person blindly draws a raffle ticket, say out of bag, and agrees to pay the amount written on the raffle ticket (as opposed to having one fixed price for each raffle ticket). The raffle ticket is then entered into a draw for a prize. Suppose you draw 2 raffle tickets without replacement from a bag with 4 tickets which have prices $1, $2, $3 and $4. How much can you expected to pay for your 2 raffle tickets?
To find the expected amount you would pay for your two raffle tickets, we need to calculate the expected value of the sum of the prices on the tickets.
Let's denote the prices on the tickets as follows:
Ticket 1: $1
Ticket 2: $2
Ticket 3: $3
Ticket 4: $4
Since you are drawing two tickets without replacement, there are a total of 4C2 = 6 possible combinations of two tickets.
The expected value (E) can be calculated by summing up the products of each combination and its corresponding probability. The probability of each combination is 1/6 since all combinations are equally likely.
The expected amount you would pay for your two raffle tickets is given by:
[tex]\[E = \frac{1}{6}(\$1 + \$2) + \frac{1}{6}(\$1 + \$3) + \frac{1}{6}(\$1 + \$4) + \frac{1}{6}(\$2 + \$3) + \frac{1}{6}(\$2 + \$4) + \frac{1}{6}(\$3 + \$4)\][/tex]
Simplifying the expression, we find:
[tex]\[E = \frac{\$3 + \$4 + \$5 + \$5 + \$6 + \$7}{6} = \$5\][/tex]
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Given y varies directly as x, find the constant of variation k.
Answer:
y=k×x
so k =-1/2
ie: -1=-1/2(2)
-1=-1
hope this helps hshshsjjss
Suppose you expect to receive the following cashflows: $14,000 today followed by $6,000 each year for the next 11 years (so the last cash flow is at year 11). How much is this cashflow stream worth to you today if the appropriate discount rate is 7.1%? Round to the nearest dollar.
The cash flow stream consisting of $14,000 today followed by $6,000 each year for the next 11 years, discounted at a rate of 7.1%, is worth approximately $52,743 to you today.
To determine the present value of the cash flow stream, we need to discount each cash flow back to the present using the appropriate discount rate.
The present value (PV) of each cashflow can be calculated using the formula:
[tex]PV = CF / (1 + r)^n[/tex]
where PV is the present value, CF is the cash flow, r is the discount rate, and n is the number of periods.
Calculating the present value of each cash flow and summing them up, we get:
[tex]PV = \$14,000 + \$6,000 / (1 + 7.1\% / 100)^1 + \$6,000 / (1 + 7.1\% / 100)^2 + ... + \$6,000 / (1 + 7.1\% / 100)^11[/tex]
Evaluating the expression, we find that the present value of the cash flow stream is approximately $52,743 when rounded to the nearest dollar.
This means that if you discount the future cash flows at a rate of 7.1%, the combined value of all the cashflows today would be approximately $52,743.
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HELP!!!!! Question in picture!!!!
Answer:
x = 29
Step-by-step explanation:
We know that those two angles equal 180° so we combine those two equations and set them equal to 180°:
6x + 6 = 180°
Subtract 6 from both sides:
6x = 174°
Divide by 6:
x = 29