Example reuikfur2skied
Miles and Allison are conducting a science experiment on bacteria and
they have a different hypothesis about what is going to happen. After
repeating their experiment several times, they realize that the results of
the experiment do not clearly support either hypothesis. What should
Miles and Allison do next?
O A. assume Miles hypothesis is correct
O B. revise their hypotheses and do another test
C. change their results to match one of their hypotheses
O D. repeat the experiment until it supports one of their hypotheses
A biology student views several different prokaryotic and eukaryotic cells under a microscope. How do the prokaryotic cells appear different from the eukaryotic cells? Choose 1 answer: (Choice A) A The prokaryotic cells have mitochondria. (Choice B) B The eukaryotic cells have cytosol. (Choice C) C Eukaryotic cells have ribosomes and prokaryotic cells do not. (Choice D) D The prokaryotic cells are smaller than the eukaryotic cells.
Answer:
The prokaryotic cells are smaller than the eukaryotic cells.
Explanation:
Its just the simple process of elimination. Prokaryotic cells lack of a lot of things, including mitochondria, so it couldn't be option C. BOTH prokaryotic and eukaryotic cells have cytosol AND ribosomes, so the answer couldn't be D or A, and you're left with option B. Meaning option B is the correct choice.
what is kinetic energy
Answer:
Kinetic energy is the energy possessed in a body in motion
Answer:
wind energy is also called kinetic energy
If the toy helicopter weighs 115N and its hovering motionless in the air. What is the force that the helicopters propeller must exert?
You drive for 5 hours at a speed of 70 km/hr. How far did you go?
Answer:
350 miles
Explanation:
because multiply 70 times 5 and you will get 350
Identify the subatomic particle that is NOT contained in the nucleus. A) electron B) neutron C) nucleus D) proton
Answer:
The answer is A.
Explanation:
Electrons are found outside of a nucleus.
two decimals that are the same as 7.7
Answer:
7.70
7.700
Explanation:
We can simply add zeros behind the significant figures and they would still be equivalent to 7.7
What are the characteristics of high energy waves?
Answer:
High energy waves are louderHave a higher amplitudePeaks are higher and the valleys are lowerExplanation:
*Hope this helps*
Which statement describes the energy involved in diffusion?
O Diffusion requires energy in all cases.
O Diffusion requires energy only to move material in through the cell membrane.
O Diffusion does not require energy in any situation.
O Diffusion requires energy only to move material out through the cell membrane.
Answer:
So B
Explanation:
The statement that the energy involved in diffusion is as follows:
Diffusion does not require energy in any situation.Thus, the correct option is C.
What is Diffusion?Diffusion may be defined as the process of migration of substances or molecules through a semipermeable membrane from an area of higher concentration to an area of lower concentration.
Diffusion does not require energy because it is classified under the passive transport of materials. Diffusion always works towards the concentration gradient.
Energy is typically involved when the movement occurs against the concentration gradient like active transport.
Therefore, the correct option for this question is C.
To learn more about Diffusion, refer to the link;
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how much time will it take for the sound of thunder to travel 1,550 meters if sound travels at a speed of 340 m/s
Answer:
4.55 seconds
Explanation:
Speed=distance / Time
So Time = Distance /speed
=1550/340
Which situation shows potential energy transforming into kinetic energy 1.A car stopped at a stoplight 2.A flowerpot falling from a balcony 3.A cow standing in a field 4.A bicycle slowing down
Answer:
2.A flowerpot falling from a balcony
Explanation:
Potential energy is the internal energy within a body at rest or at a height above the ground. In this case of the falling flowerpot, the flowerpot initially has a potential energy due to its position on the balcony above the surface of the earth. As the flowerpot falls, the work done against gravity in taking the flowerpot to this height on the balcony (equivalent to the potential energy) is transformed into the kinetic energy of motion as the flowerpot falls down through the height.
A moon rock is dropped from a cliff and it takes 2 seconds for the rock to fall 6.6 meters. What is the moon rock’s average speed?
Average speed = (total distance) / (time to cover the distance)
Speed = (6.6 meters) / (2 seconds)
Speed = 3.3 m/s
1. How do energy and matter recycle in a closed-loop system?
Answer:
In a closed-loop system, matter is used to generate energy, and the energy generated is used to produce matter, and the cycle goes on without end.
Explanation:
A closed-loop system is one in which materials or energy is recycled without end through a production cycle. This means that a raw material is used to produce a finished product, and the finished product at the end of its use cycle is converted back and used as a raw material to produce more of it again. Energy and matter can also be cycled in the same way in an energy and matter closed-loop system, converting matter to energy, and the energy is put back into the production of more of the matter.
In a closed system loop, the matter has been recycled to provide raw material and form new products. The energy formed by the product has been recycled by being used by the raw materials for the formation of new products.
The closed system loop can be defined as the system in which the products and energy has been recycled continuously to form more products. The energy has been formed in the closed system loop, that can be utilized by the raw materials for the production of energy.
The products formed after reaching the equilibrium of the formation, and dissociation reaches the point, and starts to dissociate to provide the raw material to the system.
Thus, in a closed system loop, the matter has been recycled to provide raw material and form new products. The energy formed by the product has been recycled by being used by the raw materials for the formation of new products.
For more information about a closed system loop, refer to the link:
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A cliff jumper jumps off a cliff with an initial horizontal velocity of 10 m/s. The cliff is 10 meters high. How far from the base of the cliff does the diamond fall?
Answer:
The distance reached is 14.3 m.
Explanation:
To find the distance reached by the diamond first we need to find the flight time:
[tex] t_{v} = \sqrt{\frac{2h}{g}} [/tex]
Where:
h: is the height = 10m
g: si the gravity = 9.81 m/s²
[tex] t_{v} = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2*10 m}{9.81 m/s^{2}}} = 1.43 s [/tex]
Now, we can find the distance reached:
[tex] x = V_{0_{x}}*t_{v} [/tex]
Where:
[tex]V_{0_{x}}[/tex] is the initial horizontal velocity = 10 m/s
[tex] x = V_{0_{x}}*t_{v} = 10 m/s*1.43 s = 14.3 m [/tex]
Therefore, the distance reached is 14.3 m.
I hope it helps you!
what is the nature of image of Sun obtained on a paper with the help of concave mirror
Answer:
Because concave mirror focus the sunlight at one particular point . At that particular point , amount of sunlight is converged and heat is trapped at that point . This is because , it burn the paper on which the image is focussed .
ball is dropped from the height H the total distance covered in last second of its motion is equal to distance covered in first 3 second. find the height.
pls answer this question correctly and don't give any irrelevant or else I will report the answer....
[tex]\rm{\gray{\underline{\underline{\blue{GIVEN:-}}}}}[/tex]
A ball is dropped from a height = HThe total distance covered in last second of its motion is equal to the distance covered in first 3 second .[tex]\rm{\gray{\underline{\underline{\blue{TO\:FIND:-}}}}}[/tex]
The height of the journey .[tex]\rm{\gray{\underline{\underline{\blue{SOLUTION:-}}}}}[/tex]
We have know that,
[tex]\green\bigstar\:\rm{\gray{\overbrace{\underbrace{\red{S\:=\:ut\:+\:\dfrac{1}{2}\:at^2\:}}}}}[/tex]
Where,
S = Distance .u = initial velocity = 0m/st = time = 3sa = acceleration[Note :- Here, acceleration is ‛acceleration due to gravity’ .]
a = 10m/s^2=> S = 1/2 × 10 × (3)^2
=> S = 5 × 9
=> S = 45m -----(1)
✒ If the ball takes ‛n’ second to fall the ground, then distance covered in nth second is,
[tex]\green\bigstar\:\rm{\gray{\overbrace{\underbrace{\red{S_n\:=\:u\:+\:\dfrac{g}{2}\:(2n\:-\:1)\:}}}}}[/tex]
=> Sn = 0 + 10/2 (2 × n - 1)
=> Sn = 5 (2n - 1)
=> Sn = 10n - 5 -----(2)
Therefore,
10n - 5 = 45=> 10n = 45 + 5
=> n = 50/10
=> n = 5
Now put the value of ‛n = 5’ in equation(2), we get
=> Sn = 10 × 5 - 5
=> Sn = 50 - 5
=> Sn = 45m
[tex]\rm{\pink{\therefore}}[/tex] The height of the journey is “ 45m ” .
Angela and Blake are running toward each other from
15 m away. At time t = 0 s, Angela runs to the right at 5
m/s and Blake runs to the left at 3 m/s
Write an equation for Angela?
Answer:
Kindly check explanation
Explanation:
Given the following information :
Distance between Angela and Blake = 15m
Angela's speed = 5m/s at t = 0
Angela's direction = Right = positive
Blake's speed = 3m/s at t = 0
Blake's direction = left = negative
Position or distance = speed × time
Hence,
Combined speed = (3 + 5) = 8m/s
Distance = 15m
Time = distance / speed
Time = 15 / 8
Time they meet = 1.875 seconds
Distance covered by Angela :
Speed × time
= 5 × 1.875 = 9.375 meters
The equation for the distance traveled by Angela is 5t and the distance covered by Angela is 9.375 m.
The given parameter:
the distance between Angela and Blake = 15 mspeed of Angela, [tex]V_A[/tex] = 5 m/sspeed of Blake, [tex]V_B[/tex] = 3 m/slet the time at which Angela and Blake meet = t
The equation for the distance traveled by Angela = 5t
The time (t) at which Angela and Blake meet will be calculated using relative velocity concept:
since they are closing the distance together, we will add their velocities
(i.e they are working together and not against each other)
[tex](V_A +V_B) t = 15\\\\(5 + 3) t = 15\\\\8t = 15\\\\t = \frac{15}{8} \\\\t = 1.875 \ s[/tex]
The distance covered by Angela = 1.875 s x 5 m/s = 9.375 m
The distance covered by Blake = 1.875 x 3 m/s = 5.625 m
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Does a sled have inertia while sitting still
Answer:
Yes, a sled has inertia while sitting still.
Explanation:
From Newton's law of inertia, an object at rest will remain at rest unless it is acted upon by an external force. The reason the object will remain at rest unless an external force acts is because of inertia. Inertia means the resistance of an object to motion.
Thus, a sled hammer at rest will remain at rest unless it is acted upon by an external force. So we can conclude that it has Inertia.
how many nanometers is 0.0357 m?
Answer:
35700000
Explanation:
multiply the meter value by 1e+9
Answer:
35700000 nanometers
Explanation:
so i need help with waves what is a transverse wave
Answer:
A wave in which the medium vibrates at right angles to the direction of the propagation is called transverse wave.
Which of the following is the energy stored in an object as a result of its vertical position or height? Elastic potential energy Gravitational potential energy Kinetic energy Thermal energy
Answer:
Gravitational potential energy
Explanation:
Gravity would act upon it if it were not suspended.
Answer: Gravitational potential energy
Explanation: I did the quiz! Hope it helped!
How is it possible to charge electrical devices when the power is out?
what is the power in a circuit with a voltage of 120 V and a resistance of 50
Answer:
288W.
Explanation:
P = IV = V^2 / R = (120)^2 / 50 = 288W.
Need help in class right now
Answer:
2.05pm.
Explanation:
In the picture.
An object increases its speed from rest to 35 m/s while traveling over a distance of
400 meters. Determine the acceleration of the object.
Answer:
1.53 m/s²
Explanation:
Given:
Δx = 400 m
v₀ = 0 m/s
v = 35 m/s
Find: a
v² = v₀² + 2aΔx
(35 m/s)² = (0 m/s)² + 2a (400 m)
a = 1.53 m/s²
identify me iam a nutrient in food does not require chemical other than a paper to food.
Answer:
Fats can be identified with a paper without any chemical. Just the food sample in Fats should be placed on the first paper than the rest three papers should be placed on and if any marks are there that shows the quantity of presence in Fats.
Explanation:
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A light-rail train going from one station to the next on a straight section of track accelerates from rest at 1.1 m/s^2 for 20s. It then proceeds at constant speed for 1100m before slowing down at 2.2m/s^2 until it stops at the station. A) What is the distance between stations? B) How much time does it take the train to go between the stations?
Answer:
A) The distance between the stations is 1430m
B) The time it takes the train to go between the stations is 80s
Explanation:
First we will calculate the distance covered for the first 20s.
From one the equations of kinematics for linear motion
[tex]S = ut + \frac{1}{2}at^{2} \\[/tex]
Where [tex]S[/tex] is distance traveled
[tex]u[/tex] is the initial velocity
[tex]t[/tex] is time
and [tex]a[/tex] is acceleration
Since the train starts from rest, [tex]u[/tex] = 0 m/s
Hence, for the first 20s
[tex]a =[/tex] 1.1 m/s²; [tex]t =[/tex] 20s, [tex]u[/tex] = 0 m/s
∴ [tex]S = ut + \frac{1}{2}at^{2} \\[/tex] gives
[tex]S = (0)(20) + \frac{1}{2}(1.1)(20)^{2}[/tex]
[tex]S = \frac{1}{2}(1.1)(20)^{2}[/tex]
[tex]S =[/tex] 220m
This is the distance covered in the first 20s.
The train then proceeds at constant speed for 1100m.Now, we will calculate the speed attained here
From
[tex]v = u +at[/tex]
Where [tex]v[/tex] is the final velocity
Hence,
[tex]v = 0 + 1.1(20)[/tex]
[tex]v = 1.1(20)[/tex]
[tex]v =[/tex] 22 m/s
This is the constant speed attained when it proceeds for 1100m
The train then slows down at a rate of 2.2 m/s² until it stopsWe can calculate the distance covered while slowing down from
[tex]v^{2} = u^{2} + 2as[/tex]
The initial velocity, [tex]u[/tex] here will be the final velocity before it started slowing down
∴[tex]u[/tex] = 22 m/s
The final velocity will be 0, since it came to a stop.
∴ [tex]v[/tex] = 0 m/s
[tex]a = -[/tex]2.2 m/s² ( - indicates deceleration)
Hence,
[tex]v^{2} = u^{2} + 2as[/tex] gives
[tex]0^{2} =22^{2} +2(-2.2)s[/tex]
[tex]0=22^{2} - (4.4)s\\4.4s = 484\\s = \frac{484}{4.4} \\s = 110m[/tex]
This is the distance traveled while slowing down.
A) The distance between the stations is
220m + 1100m + 110m
= 1430m
Hence, the distance between the stations is 1430m
B) The time it takes the train to go between the stations
The time spent while accelerating at 1.1 m/s² is 20s
We will calculate the time spent when it proceeds at a constant speed of 22 m/s for 1100m,
From,
[tex]Speed =\frac{Distance}{Time}\\[/tex]
Then,
[tex]Time = \frac{Distance}{Speed}[/tex]
[tex]Time = \frac{1100}{22}[/tex]
Time = 50 s
And then, the time spent while decelerating (that is, while slowing down)
From,
[tex]v = u + at\\0 = 22 +(-2.2)t\\2.2t = 22\\t = \frac{22}{2.2} \\t= 10 s[/tex]
This is the time spent while slowing down until it stops at the station.
Hence, The time it takes the train to go between the stations is
20s + 50s + 10s = 80s
The time it takes the train to go between the stations is 80s
If a resident accidentally causes a chunk of ice to fall from the roof, how fast would the ice be moving when it hits the ground? Neglect air resistance.
Answer:
v = √2gh
v = 7 m / s
Explanation:
For this exercise we can use the law of conservation of energy
starting point. In the roof
Em₀ = U = m g h
final point. On the floor
Em_f = K = ½ m v²
as there is no friction, the energy is conserved
Em₀ = Em_f
m g h = ½ m v²
v = √2gh
In the exercise the height of the ceiling is not indicated, but in general the height of the ceiling of a house is h = 2.5 m
v = √ (2 9.8 2.5)
v = 7 m / s
define aperture of a spherical mirror
The diameter of the reflecting surface of spherical mirror is called its aperture. Mirrors whose aperture is much smaller than its radius of curvature, we use R=2f.
A ball is dropped from the roof of the A200 building. How fast is a traveling 0.5 seconds later?
ANYTHING that's dropped near the Earth's surface and isn't affected by air resistance falls 9.8 m/s faster at any time than it did 1 second earlier.
0.5 second after it was dropped with zero speed, it's falling at
(0.5) x (9.8 m/s) = 4.9 m/s .
It makes no difference which building it was dropped from.