Gustavo is the league's home run leader. The probabilities for his total number of home runs for the season are as follows:
\text{P(0-19 home runs}) = \dfrac14P(0-19 home runs)=
4
1
​
start text, P, left parenthesis, 0, negative, 19, space, h, o, m, e, space, r, u, n, s, end text, right parenthesis, equals, start fraction, 1, divided by, 4, end fraction
\text{P(20-39 home runs}) = 45\%P(20-39 home runs)=45%start text, P, left parenthesis, 20, negative, 39, space, h, o, m, e, space, r, u, n, s, end text, right parenthesis, equals, 45, percent
\text{P(40+ home runs}) = 0.3P(40+ home runs)=0.3start text, P, left parenthesis, 40, plus, space, h, o, m, e, space, r, u, n, s, end text, right parenthesis, equals, 0, point, 3
Put the following events in order from least to most likely.

Answer:

dont copy and paste i cant read the question

Step-by-step explanation:

The events in order from least to most likely are:

P(0-19 home runs) < P(40+ home runs) < P(20-39 home runs)

To put the events in order from least to most likely, we need to compare their probabilities:

Let's reorder the events based on their probabilities:

P(40+ home runs) = 0.3 (30%)

P(20-39 home runs) = 45% (0.45)

P(0-19 home runs) = 1/4 = 0.25 (25%)

So, the correct order from least to most likely is:

P(0-19 home runs) < P(40+ home runs) < P(20-39 home runs)

P(40+ home runs) = 0.3 (30%)

P(20-39 home runs) = 45% (0.45)

P(0-19 home runs) = 1/4 = 0.25 (25%)

So, the events in order from least to most likely are:

P(0-19 home runs) < P(40+ home runs) < P(20-39 home runs)

To know more about probabilities   here

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