Help For points
-100
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-140

Answer:

201.062in²

Step-by-step explanation:

area for formula of a circle

[tex] {r}^{2} \pi[/tex]

we can now plug in the radius to solve

[tex] {8}^{2} \pi \\ 64\pi \\ 201.062[/tex]

that is the answer

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Answer:

[tex]3*(2x+3)*(x+1)[/tex]

Step-by-step explanation:

pull like terms from the problem to re-arrange it into a product

[tex]\left(2x+3\right)\left(3x+3\right)\\3x + 3 = 3 \cdot (x + 1)\\3 \cdot (2x + 3) \cdot (x + 1)\\[/tex]

#Part A

Volume of rectanglular prism

Volume of one cube

Total cubes

#2

Volume=

No of cubes ×volume of 1 cube

Answer:

A)  84 cubes

B)  Volume = 4 x 3 x 7 = 84 small cubes

    [tex]\sf Volume=3 \frac{1}{9}\:\:ft^3[/tex]

Step-by-step explanation:

As the lengths of each side of the small cube are ¹/₃ ft each, to find the number cubes in the rectangular prism, first find how many thirds are in each dimension of the prism:

[tex]\sf Length=1 \frac{1}{3}\:ft=\dfrac{4}{3}\:ft=4\:thirds[/tex]

[tex]\sf Width=1 \:ft=\dfrac{3}{3}\:ft=3\:thirds[/tex]

[tex]\sf height=2 \frac{1}{3}\:ft=\dfrac{7}{3}\:ft=7\:thirds[/tex]

Now simply multiply the number of thirds:

Number of cubes in prism = 4 x 3 x 7 = 84

As we have already found the dimensions of the prism in terms of the number of cubes, the volume of the prism in terms of the small cube is:

⇒ Volume = 4 x 3 x 7 = 84 small cubes

To find the volume of the prism in ft³, calculate the actual volume of the small cube:

[tex]\textsf{Volume of small cube}=\sf \dfrac{1}{3} \times \dfrac{1}{3} \times \dfrac{1}{3}=\dfrac{1}{27}\:ft^3[/tex]

Now multiply the volume in terms of number of cubes by the actual volume of a cube:

[tex]\begin{aligned}\textsf{Volume} &= \sf \textsf{Volume in cubes} \times \textsf{Volume of cube in ft}^3\\\\& = \sf 84 \times \dfrac{1}{27}\:ft^3\\\\& =\sf \dfrac{84}{27}\:ft^3\\\\& =\sf 3\frac{1}{9}\:ft^3\end{aligned}[/tex]

Answer:

For the function f(x) = 3(x − 1)2 + 2, identify the vertex, domain, and range

Step-by-step explanation:

The vertex is (1, 2), the domain is all real numbers, and the range is y ≥ 2.

The vertex is (1, 2), the domain is all real numbers, and the range is y ≤ 2.

The vertex is (–1, 2), the domain is all real numbers, and the range is y ≥ 2.

Answer:

see explanation

Step-by-step explanation:

the equation of a parabola in vertex form is

f(x) = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

f(x) = 3(x - 1)² + 2 ← is in vertex form

with vertex = (1, 2 )

The domain of a parabola exists for all real values of x

domain : x ∈ R

the range of the parabola are the values of y from the y- coordinate of the vertex, upwards.

range : y ≥ 2

Answer:

20 inches

Step-by-step explanation:

there is only 12 inches in a foot

Answer:

[tex]\tan U = 1[/tex]

Step-by-step explanation:

[tex]\text{Apply Pythagorean theorem,}\\\\~~~~~~\text{Hypotenuse}^2 = \text{Base}^2 + \text{Perpendicular}^2\\\\\implies UT^2 = UV^2 +VT^2\\\\\implies UV^2 = UT^2 -VT^2\\\\\implies UV^2 = \left(7\sqrt 2 \right)^2 - 7^2\\\\\implies UV^2 = 49(2)-49\\\\\implies UV^2 = 49\\\\\implies UV = \sqrt{49} \\\\ \implies UV = 7[/tex]

[tex]\text{Now,}\\\\~~~~~~~~\tan \theta = \dfrac{\text{Perpendicular}}{\text{Base}}\\\\\\\implies \tan U = \dfrac{7}{7}\\\\\\\implies \tan U = 1[/tex]

Answer:

Below is an array showing the x values, and phase shifts that occur in the graph of the equation.

[tex]~~~~~x~~~~f(x)\\\\\left[\begin{array}{cc}\pi &0 &\frac{9\pi }{8} &1\\\frac{5\pi }{4} &0&\frac{11\pi }{8} &-1&\frac{3\pi }{2}&0 \end{array}\right][/tex]

Answer:

Graph A

Step-by-step explanation:

Got 100% on edge

Answer:

a(y=-5x+2500) b(2,380) c(25months)

Step-by-step explanation:

someone point out if I'm wrong. I'm not so sure about "c".

(how I got b)

So 2 years=24 months

y=-5x+2500

So x would be 24.

-5(24)+2500

-120+2500

2,380

Answer:

D. 77º

Step-by-step explanation:

Because 3 and 7 are corresponding angles and 3 = 77º, 7 also is 77º.

The expression that is equivalent to 14xy – 28x – 36y + 48 is 2[7x(y-2)-6(3y-4)]

Factorization is a way of separating the equations into two separate factors.

Given the expression below;

14xy – 28x – 36y + 48

Group

(14xy – 28x) – (36y + 48)

14x(y - 2) - 12(3y-4)

Factor out the value of 2 from both terms

2[7x(y-2)-6(3y-4)]

Hence the expression that is equivalent to 14xy – 28x – 36y + 48 is 2[7x(y-2)-6(3y-4)]

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Answer:

2[7x(y – 2) – 6(3y – 4)]

Step-by-step explanation:

I got it right on the test.

Using proportions, it is found that the scale factor of the transformation is of 1/3.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, during the transformation, each coordinate was divided by 3, hence, applying the proportion, the scale factor of the transformation is of 1/3.

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Answer:

The area of the rectangle = 15√2 in²

Step-by-step explanation:

What is the area of a rectangle with a length of 3in

and a width of 5√2.

……………………………………………

FORMULA :

area of a rectangle = length × width

===============================

Then

The area of the rectangle = 3 × 5√2 = 15√2

The population of the town in 1955 was 12 thousand people, and the percent increase in population from year to year was 3%.

A function assigns the value of each element of one set to the other specific element of another set. The function that gives the population of the town is given.

Since the year 1955 the value of t=0. Therefore, The population of the town in 1955 was 12 thousand. The percentage increase in population from year to year is 3%.

Therefore, the population of the town in 1955 was 12 thousand people, and the percent increase in population from year to year was 3%.

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The graph for Suav's trip is attached along with the values derived from the information provided.

The key to understanding the graph is that every time spent while he was on the way to the back and back are all added cumulatively.

So when he stops at the store which is 8 blocks away from home, the time spent is recorded as 4 + 2 at location 8 blocks.

It is also to be noted that the time spent is plotted on the x-axis and the blocks away from home on the y-axis.

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Answer:

2

Step-by-step explanation:

because (x,y)=(1,2)

Therefore, domine(d)=(x)=1

And, range(r)=(y)=2

So the ans is 2

The error she made is Emi evaluated (46-78)² as - (32)² is wrong.

Variance is calculated as the average of squared differences of the data observations from the mean.

Given data: 87, 46, 90, 78, and 89.

Here, the first Emi find the difference of 89 - 78 correctly.

Now, Emi division is also correct.

Now, Emi evaluated (46 - 78)^2 as -(32)^2 is wrong.

(46-78)² = (-32)²

Here she used the negative sign outside.

Hence, Emi evaluated (46 - 78)^2 as -(32)^2 is wrong.

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Answer:

C.) Emi evaluated (46 - 78)2 as -(32)2.

Step-by-step explanation:

The dependent value for the graph given the independent value is 9.

The independent variable is the variable that explains the dependent variable. The dependent variable is the value that the independent variable determines.

The dependent variable is y and the independent variable is x.

y = 15 - 3(2)

y = 15 - 6

y = 9.

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Answer:

rawrrrrrrrrrrrrrrrrr

Step-by-step explanation:

Why is P(A) •P(B/A) = P(B) • P(A/B)

P/B + P = A

P/B/P

- A

Answer:

Step-by-step explanation:

Each grandchild will receive 655/13 = 50 with 5 coins left over. She can keep the 5 coins and start again.

Answer

Answer:

50 coins for each grandchild

5 left over.

Step-by-step explanation:

13x50=650

655-650=5

Answer:

[tex]\boxed{\sf x = 11.7}[/tex]

[tex]\boxed{\sf b = 9.4}[/tex]

Sine Rule states:

[tex]\sf sin(x) = \dfrac{opposite}{hypotenuse}[/tex]

[tex]\hookrightarrow \sf sin(51) = \dfrac{x}{15}[/tex]

[tex]\hookrightarrow \sf x = 15sin(51)[/tex]

[tex]\hookrightarrow \sf x = 11.657 \ \ \approx \quad 11.7[/tex]

Additional, cosine rule:

[tex]\sf cos(x) = \dfrac{adjacent}{hypotenuse}[/tex]

[tex]\hookrightarrow \sf cos(51) = \dfrac{b}{15}[/tex]

[tex]\hookrightarrow \sf b = 15cos(51)[/tex]

[tex]\hookrightarrow \sf b = 9.4398 \quad \approx \ \ 9.4[/tex]

The area of a 2D form is the amount of space within its perimeter. The area of the arrow is 11.25 in².

The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm2, m2, and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.

For the given problem, the image is given below.

The area of the arrow is,

Area =  Area of rectangle + Area of triangle

        = (1.5 in × 4.5 in) + (0.5×3×3)

        = 6.75 in² + 4.5 in²

        = 11.25 in²

Hence, the area of the arrow is 11.25 in².

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Answer:

add the size plus

Step-by-step explanation:

Sunday if you add sox

The regression equation of the data values is y = 0.3x^2 - 2.8x +4.2

Using a technology such as a graphing calculator, we simply input the data values in the graphing calculator and then wait for the result.

The x coordinates must be entered into the x values and the y coordinates must be entered into the y values

Using a graphing technology, the regression equation of the data values is y = 0.3x^2 - 2.8x +4.2

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Using the line of best fit, it is found that the projected time for a man who is 166 cm tall is of 7.966 minutes.

It gives the project time in minutes to run the 3000 meters for a men of a height of x centimeters, according to the following function:

y = -0.081x + 21.412.

Hence, for a men of 166 centimeters, x = 166 and the projected time in minutes is given as follows.

y = -0.081(166) + 21.412 = 7.966.

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Answer:

4w-v

Step-by-step explanation:

Let the number be w.

Multiplying by 4:

Subtracting v,

They want you to solve the iterative process to a point where the value of x is greater than or equal to 6 decimal places.

An iterative process is a mathematical approach that employs an initial value to build a series of improving estimated solutions for a problem, where the nth-term estimation is generated from the prior ones.

You're required to put the value of x₁ = -1 into the equation:

[tex]\mathbf{x_{n+1}= \dfrac{(x_n)^3-1}{4}}[/tex]

So;

[tex]\mathbf{x_{2}= \dfrac{(-1)^3-1}{4}}[/tex]

[tex]\mathbf{x_{2}=-0.5}[/tex]

[tex]\mathbf{x_{3}= \dfrac{(-0.5)^3-1}{4}}[/tex]

[tex]\mathbf{x_{3}=-0.28125}[/tex]

[tex]\mathbf{x_{4}=\dfrac{(-0.28125)^3-1}{4}}[/tex]

[tex]\mathbf{x_{4}=-0.2555618286}[/tex]

x₄ ≅ -0.255562  ( to 6 decimal places)

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