Answers
Answer:
2411.52 mm²
Step-by-step explanation:
[tex]40^{2} =32^2+d^2[/tex]
→ [tex]d^2= 1600-1024[/tex]
→[tex]= 576[/tex]
→ [tex]d= 24[/tex] [tex]so, (radius=12[/tex]
[tex]Total~ surface ~ area= (2\pi r)*height[/tex]
→ [tex](2*3.14*12*82)[/tex]
[tex]= 2411.52 mm^2[/tex]
-------------------------------
hope it helps...
have a great day!!
Answer:
2411.52 mm²
Step-by-step explanation:
hope its helpful
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Answer:
-6(x-8)=60x-8= -10x= -10+8x= -2hope it helps...
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Step-by-step explanation:
-6 ( x - 8) = 60
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Step-by-step explaining.
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2-(x+1)/(x-2)-(x-4)/(x+2)can be written as a single fraction in the form (ax+b)/(x^(2)-4) where a and b are intergers
Answers
Answer:
a = 3, b = -18
Step-by-step explanation:
You can start by getting a common denominator in the fractions [tex]\frac{x+1}{x-2}[/tex] and [tex]\frac{x-4}{x+2}[/tex]. You can multiply the first one by [tex]\frac{x+2}{x+2}[/tex] to get [tex]\frac{(x+2)(x+1)}{x^2-4}[/tex]and you can multiply the second by [tex]\frac{x-2}{x-2}[/tex] to get [tex]\frac{(x-4)(x-2)}{x^2-4}[/tex]. You can simplify the fractions:
[tex]\frac{(x+2)(x+1)}{x^2-4}[/tex] - [tex]\frac{x^2+3x+2}{x^4-4}[/tex]
[tex]\frac{(x-4)(x-2)}{x^2-4}[/tex] - [tex]\frac{x^2-6x+8}{x^2-4}[/tex]
Now we can rewrite the equation:
[tex]2-\frac{x^2+3x+2}{x^2-4} -\frac{x^2-6x+8}{x^2-4}[/tex]
and combine the terms with the same denominator:
[tex]2+\frac{-x^2-3x-2-x^2+6x-8}{x^2-4}[/tex]
[tex]2+\frac{-2x^2+3x-10}{x^2-4}[/tex]
Now, to add the two into the fraction, we multiply it by [tex]x^2-4[/tex] to get [tex]2x^2 - 8[/tex].
[tex]\frac{2x^2-8-2x^2+3x-10}{x^2-4}[/tex]
And simplify:
[tex]\frac{3x-18}{x^2-4}[/tex]
a = 3, b = -18
The value of the integers a and b are 3 and - 18 respectively.
What do you mean by algebraic expressions ?
Algebraic expression is an equation which consists of variables and the arithmetic operations such as division , multiplication , etc.
Firstly , let's find out a common denominator in the fractions , [tex]\frac{x+1}{x-2}[/tex] and [tex]\frac{x-4}{x+2}[/tex] .
The first one can be written as :
= [tex]\frac{x+1}{x-2}[/tex] × [tex]\frac{x+2}{x+2}[/tex]
= [tex]\frac{(x+1)(x+2)}{x^{2} - 4}[/tex]
and the second one can be written as :
= [tex]\frac{x-4}{x+2}[/tex] × [tex]\frac{x-2}{x-2}[/tex]
= [tex]\frac{(x-4)(x-2)}{x^{2} - 4}[/tex]
The expression will be :
= 2 - [tex]\frac{x+1}{x-2}[/tex] - [tex]\frac{x-4}{x+2}[/tex]
= 2 - [tex]\frac{(x+1)(x+2)}{x^{2} - 4}[/tex] - [tex]\frac{(x-4)(x-2)}{x^{2} - 4}[/tex]
= [ 2 (x²- 4) - (x+1) (x+2) - (x-4) (x-2)]/ [(x²- 4)]
= [2x² - 8 - x² - 3x - 2 - x² + 6x - 8] / [(x²- 4)]
By simplifying it , we get :
= [tex]\frac{3x-18}{x^{2} - 4}[/tex]
If we compare it with the given form which is [tex]\frac{ax + b}{x^{2} -4}[/tex] we get :
[tex]\frac{3x-18}{x^{2} - 4}[/tex] = [tex]\frac{ax + b}{x^{2} -4}[/tex]
or
3x - 18 = ax + b
or
The values of a and b are :
a = 3 and b = -18.
Therefore , the value of the integers a and b are 3 and - 18 respectively.
Learn more about algebraic expressions here :
https://brainly.com/question/1382660
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