Answer:
Metabolism
Explanation:
metabolism is the sum of all chemical reactions that take place within an organism
Answer:
Metabolism
Explanation:
what is the total magnification of a microscope with an eyepiece magnification of 10x and an objective lens magnification of 50x quizziz
Answer:
500x
Explanation:
A microscope had an eyepiece magnification of 10x
The objective lens magnification is 50x
Therefore the total magnification can be calculated as follows
= 10 × 50
= 500x
Hence the total Magnificattion is 500x
When an object moves, where does the energy come from?
Answer:
Kinetic energy.
Explanation:
This is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy.
1. *A car is going over the top of a hill whose curvature approximates a circle of radius 200 m. At
what velocity will the occupants of the car appear to weigh 20% less than their normal weight (or
their normal weight times 0.8)?
Answer:
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s
Explanation:
The given parameters are;
The curvature of the hill, r = 200 m
Due to the velocity, v, the occupants weight = 20% less than the normal weight
The outward force of an object due to centripetal (motion) force is given by the following equation;
[tex]F_c = \dfrac{m \times v^2}{r}[/tex]
Where;
r = The radius of curvature of the hill = 200 m
Given that the weight of the occupants, W = m × g, we have;
[tex]F_c = 0.2 \times W = 0.2 \times m \times g[/tex]
[tex]\therefore 0.2 \times m \times g = \dfrac{m \times v^2}{r}[/tex]
v = √(0.2 × g × r)
By substitution, we have;
v = √(0.2 × 9.81 × 200) ≈ 19.81
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.
The velocity is 19.81 m/sec at which the occupants of the car appear to weigh 20% less than their normal weight and this can be determined by using the formula of centripetal force.
Given :
A car is going over the top of a hill whose curvature approximates a circle of radius 200 m.
The centripetal force acting on the car is given by the formula:
[tex]\rm F_c = \dfrac{mv^2}{r}[/tex] ---- (1)
where m is the mass of a car, v is the velocity of the car and r is the radius of curvature.
Now, it is given that the occupants of the car appear to weigh 20% less than their normal weight that means:
[tex]\rm F_c = 0.2\times W[/tex]
[tex]\rm F_c = 0.2 \times m \times g[/tex] --- (2)
Now, equate equation (1) with equation (2).
[tex]\rm \dfrac{mv^2}{r}=0.2\times m \times g}{}[/tex]
[tex]\rm v = \sqrt{0.2\times g \times r }[/tex]
[tex]\rm v = \sqrt{0.2\times 9.81 \times 200 }[/tex]
v = 19.81 m/sec
The velocity is 19.81 m/sec at which the occupants of the car appear to weigh 20% less than their normal weight.
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HELP ASAP!! WILL TRY TO GIVE BRAINLIESTT!!
Please define the prefixes hyper-, hypo-, & iso- AND describe a solution that is hypertonic, hypotonic, & isotonic as well as compare how a living cell reacts when placed in a solution of each of the 3 types.
Answer:
Hypertonic, isotonic, and hypotonic solutions and their effect on cells. ... There are some different explanations out there. ... Tonicity is a concern for all living things, particularly those that lack rigid cell walls and live in ...
At a sports event, the car starts from iosi, in 5.0 siis acceleration is 5.
Calculate the distance travelled by ban
100 m
25 m
63 m
O bag 6.
The Score Tower hingga laglomery 4
werissa 13
Question:
At a sports event, the car starts from rest. in 5.0 s its acceleration is 5.0 m/s2. Calculate the distance travelled by car.
Answer:
62.5 metres
Explanation:
Given
[tex]u = 0[/tex] -- Initial Velocity
[tex]a = 5.0m/s^2[/tex] --- acceleration
[tex]t =5.0s[/tex] -- time
Required
Calculate the distance
This question will be solved using the following equation of motion
[tex]S = ut + \frac{1}{2}at^2[/tex]
Where S represents the distance
Substitute values for u, t and a
[tex]S = 0 * 5.0 + \frac{1}{2} * 5.0 * 5.0^2[/tex]
[tex]S = 0 + \frac{1}{2} * 5.0 * 25.0[/tex]
[tex]S = \frac{1}{2} * 5.0 * 25.0[/tex]
[tex]S = \frac{1}{2} * 125.0[/tex]
[tex]S = 62.5m[/tex]
Hence, the distance travelled is 62.5m
12. A baseball player throws a ball. While the 700.0-g ball is in the pitcher’s hand, there is a force of 125 N on it. What is the acceleration of the ball?
Answer:
F=ma
125N=.7*a solve for a.
Explanation:
FAST ANSWERS PLS ! **
Describe a time when you took a big risk. Tell why it was risky and what you learned about yourself.
Answer:
You have to answer this in your opinion!
Anyways, A time I took a big risk was when I decided to talk to strangers online. It was risky because the stranger was harrasing me and doing bad stuff to me online. I learned about online safety and I learned to be careful who I talk to online! :)
Explanation:
You will get the most accurate resting heart rate if you take your pulse for ___ consecutive mornings and average the number
A: 3
B: 4
C: 5
PLEASE ANSWER QUICK I WILL DO BRAINLIEST.
The four objects are dropped from a balcony at the same time in a vacuum. (image)
amount of force: (f=ma)
feather: 0.006*9.8 = 0.0598 N
frisbee: 0.15*9.8 = 1.47 N
bowling ball: 5*9.8 = 49 N
golf ball: 0.04*9.8 = 0.392 N
Using Newton’s second law, explain which object will hit the ground with the most force? Use the calculations above to support your response.
Answer:
the bowling ball or the frisbee
Explanation:
I think it's the bowling ball or the frisbee. I am not really sure, so if you get it wrong I am extremely sorry!!
What travels by vibrating particles? Mechincal Waves or ElecrtoMagnetic Waves.
Answer:mechanical waves.
Explanation:
Mechanical waves require the particles of the medium to vibrate in order for energy to be transferred. For example, water waves, earthquake/seismic waves, sound waves, and the waves that travel down a rope or spring are also mechanical waves.
A ball is thrown up into the air. Ignore air resistance. When it is rising and reaches half of its maximum height,the net force acting on it is
Answer:
The net and only force acting on the ball thrown up into the air at half of its maximum height is the weight of the ball
Explanation:
When the ball is rising in the air, the force, F, acting on it is given by the product of the mass, m × acceleration, a
The acceleration of a body thrown in the air = Gravitational acceleration = g = Constant
Therefore;
The force acting on the body thrown in the air F = Constant = m × g (downwards)
The force acting on the ball thrown up into the air at half of its maximum height = The mass of the ball × The acceleration due to gravity = The weight of the ball.
If you run North for 5 meters and then East for 15 meters and then
South for 2 meters all in 22 seconds. What was your speed?
0 points
Answer:
1m/s
Explanation:
D = 22m
T = 22s
S = 22÷22
= 1 m/s
A 81.9 kg person stands on her toes. The surface area of her toes in contact with the ground is only .002^ - m ^2. How much pressure is exerted between her toes and the ground, IN ATMOSPHERES ?
Answer:
3.77202
Explanation:81.9 kg×9.8N/kg÷0.0021 Pa ×(1atm/101325)=3.77202
The pressure exerted between her toes and the ground is 3.77 atm.
What is pressure?The stress at a location within a confined fluid or the perpendicular force per unit area are the two definitions of pressure used in the physical sciences. A 42-pound box with an area of 84 square inches at the bottom will apply pressure on a surface equal to the force divided by the surface area.
Given:
An 81.9 kg person stands on her toes. The surface area of her toes in contact with the ground is only 0.00210 m²,
Calculate the pressure on the toe as shown below,
The pressure on the toe = Force of man / area of toe
The pressure on the toe = mass of man × 9.8 / 0.00210
The pressure on the toe = 81.9 × 9.8 / 0.00210
The pressure on the toe = 802.62 / 0.00210
The pressure on the toe = 382200 N/m²
The pressure on the toe = 382200 / 101325 (1 atm = 101325 N / m²)
The pressure on the toe = 3.77 atm,
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What would the mechanical advantage of a ramp be if the length is 25 feet and the height is 5 feet?
10
125
5
30
Answer:
5.
Explanation:
From the question given above, the following data were obtained:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =?
Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:
Mechanical advantage = length /height
MA = L/H
With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =.?
MA = 25 / 5
MA = 5
The, the mechanical advantage of the ramp is 5.
Answer:
5.
Explanation:
From the question given above, the following data were obtained:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =?
Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:
Mechanical advantage = length /height
MA = L/H
With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =.?
MA = 25 / 5
MA = 5
The, the mechanical advantage of the ramp is 5.
PLSS HELPPP Which is a better deal: a 2 terabyte external hard drive for $100, or a
400-gigabyte hard drive for $50?
Answer:two terabyte external hard drive for $100
Explanation:
A heat lamp produces 32.8 watts of power at a wavelength of 6.5 mm. How many photons are emitted per second
Answer: 1.1x10^21 photons / sec
Explanation:energy per photon
.. E / photon = hc / L = (6.626x10^-34 J x sec) x (3.00x10^8 m/sec) / (6.5x10^-6m)
.. E / photon = 3.06x10^-20 J / photon
then
.. (32.7 watts) x (1 J/sec / 1watt) x (1 photon / 3.06x10^-20J) = 1.1x10^21 photons / sec
The number of photons are emitted per second will be "1.07".
According to the question,
Power,
P = 32.8 watts= 32.8 J/s
Wave length,
λ = 6.5 μm= [tex]6.5\times 10^{-6}[/tex]
As we know,
→ [tex]E = \frac{hc}{\lambda}[/tex]
By substituting the values, we get
[tex]= \frac{32.8}{\frac{(4.42\times 10^{-34})(3\times 10^{-4})}{4.5\times 10^{-6}} }[/tex]
[tex]= \frac{32.8}{3.055e}[/tex]
[tex]= 1.07[/tex]
Thus the above answer is correct.
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9. A student notices that wearing darker colors in sunlight makes him feel warmer, so he decides to conduct an experiment. He takes five pieces of different
colored cloth and wraps
each one around a water bottle. He then places all five bottles in direct sunlight and measures the temperature of the water in each bottle an hour later
What is the dependent variable in this experiment?
O the time he leaves it in the sunlight
O the amount of water in each bottle
O the color of the cloth
O the temperature of the water
Answer: 4
Explanation:
The dependent variable is the temperature of the water.
how to create or build a homemade golf club. is this possible? If so, what suggestion did you find? Do you have an original idea on how to build a homemade golf club? what types of materials and tools would you need? what skills are necessary to construct the club?
Answer:
All you need is golfing equipment make a small hole in the ground and have like something to cover the sun off of you and boom you got a golfing spot and a golf club no skills needed. Oh and you need a small flag for your gold hole but then your good and you can have fun
Explanation:
An atom of lithium (Li) forms an ionic bond with an atom of chlorine (Cl) to form lithium chloride. How are the valence electrons of these atoms rearranged to form this bond?
A few valence electrons are shared between the atoms.
Many valence electrons are shared between the atoms.
Electrons are transferred from the chlorine atom to the lithium atom.
Electrons are transferred from the lithium atom to the chlorine atom.
Answer:
electrons are transferred from the lithium atom to the chlorine atom
Answer:
D
Explanation:
I just took the test :)
What the distance between 2 particles is doubled and the force between them is quartered, what is that called
Answer:
Coulomb's law.
Explanation:
If the distance between two particles is doubled and the force between them is quartered, this is known as Coulomb's law. Coulomb presented a law in which he states that when there is increase occur in distance between two objects, the force between them is decreases so if the distance between two particles or objects is doubled so the force between them is also quartered.
A car slows from 22 m/s to 3.0 m/s at a constant rate of 2.1 m/s2. How many seconds are required before the car is traveling at a forward velocity of 3.0 m/s?
Answer: 9.05 s
Explanation: v = u +at
v = 3 m/s
u = 22 m/s
Deceleration = 2.1 m/s^2
∴ 3 = 22 - 2.1 ( t )
∴ t = 9 .05 s
help pls i need this right now
Answer:
C = - 1.625 i + 6.06 j
Explanation:
Positive angles are measured counterclockwise.
Positive angles are measured counterclockwise. To determine the component on the x axis we use the cosine of the angle while to determine the component on the y axis we use the sine of the angle.
[tex]C_{x}=6.28*cos(105)=-1.625\\C_{y}=6.28*sin(105)=6.06\\[/tex]
C = - 1.625 i + 6.06 j
Which of the technologies could mostly like be found in a wearhouse
A sign is attached to the side of a building as seen below. The sign is attached to a steel rod. A wire connects to the end of the rod for support. The mass of the sign is 50 kg. Determine the supporting force exerted by the cable
Answer:
500N
Explanation:
50kgx10N/kg
= 500N
For many years the posted highway speed limit was 88.5 km/h but in recent years some rural stretches of highway have increased their speed limit to 104.6 km/h. In Maine the distance from Portland to Bangor is 215 km. How much time can be saved in making this trip at the new speed limit?
Answer:
Time Saved = 0.374 h = 22.4 min
Explanation:
First we calculate the time required at old speed limit:
s = v₁t₁
where,
s = distance from Portland to Bangor = 215 km
v₁ = old speed limit = 88.5 km/h
t₁ = time taken with old speed limit = ?
Therefore,
215 km = 88.5 km/h (t₁)
t₁ = (215 km)/(88.5 km/h)
t₁ = 2.429 h
Now, we calculate the time taken at the new speed limit:
s = v₂t₂
where,
s = distance from Portland to Bangor = 215 km
v₂ = new speed limit = 104.6 km/h
t₂ = time taken with new speed limit = ?
Therefore,
215 km = 104.6 km/h (t₂)
t₂ = (215 km)/(104.6 km/h)
t₂ = 2.055 h
So, the time saved will be:
Time Saved = t₁ - t₂ = 2.429 h - 2.055 h
Time Saved = 0.374 h = 22.4 min
can somebody calculate the velocity of this? ill give 30 points
Answer:
2m/s
Explanation:
time is 5 seconds
distance is 10m
the formula for velocity is v=d/t
so, v=10/5
v=2 m/s
A child kicks a ball horizontally with a speed of 2.8 m/s from the end of a deck that is 8.5 m high.
a. How long will the ball take to hit the ground?
Answer:
Explanation:
time =d/s
therefore, t =8.5/2.8
t=3.02s
What is the momentum of a 70 kg man who is running with a velocity of 2.5 m/s?
Answer:
175kg.m/s
Explanation:
Momentum= mv 70kg*2.5m/s
a sports event, the car starts from rest, in 5.0 s its acceleration is 5.0 m/s2.
culate the distance travelled by car.
Answer:
62.5m
Explanation:
Given parameters:
Time = 5s
Acceleration = 5m/s²
Unknown:
Distance traveled by car = ?
Solution:
To solve this problem, we use one of the motion equations as given below:
S = ut + [tex]\frac{1}{2}[/tex] at²
S is the distance traveled
t is the time taken
u is the initial velocity = 0m/s
a is the acceleration
Now insert the parameters and solve;
S = (0 x 5) + ([tex]\frac{1}{2}[/tex] x 5 x 5²) = 62.5m
The flow of air caused by blend in the blank creates distant blank on earth surface
Question:
The flow of air caused by _____ and the Coriolis effect creates distinct _____ on Earth's surface.
Answer:
Differences in heatingWind patternsExplanation:
The flow of air caused by variations in the rate at which the different parts are heated up as well as the Coriolis effect combine to create distinct wind patterns on Earth's surface.
The Coriolis Effect is used to describe a "force" that causes things (like objects, planes, air currents) traveling long distances around the Earth to appear to bend as they move rather than in a straight line.
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