hi besties help me

2- y= -5

3-  y= 2x

4- y= -4

5- y= 6x,,, 60

6-   -4,,,,,,,,,   36

Answer:

The value of g(-6) will be "-9".

Step-by-step explanation:

The given function is:

⇒  [tex]g(x)=x-3[/tex]

then,

⇒  [tex]g(-f)=?[/tex]

On putting the value "-6" at the place of "x", then we get

⇒  [tex]g(-6) = (-6)-3[/tex]

⇒            [tex]=-6-3[/tex]

⇒            [tex]=-9[/tex]

Thus the above is the correct solution.

There are 210 ways to choose a president, vice president, and treasurer for a 7-member club, with no person holding more than one office. Each position can be filled by a different member, resulting in 210 unique combinations.

To determine the number of ways to choose the three positions, we can use the concept of permutations. The president can be selected from the 7 members in 7 different ways. Once the president is chosen, there are 6 remaining members to choose from for the position of vice president. Therefore, there are 6 choices for the vice president. Finally, the treasurer can be chosen from the remaining 5 members.

To calculate the total number of ways, we multiply the number of choices for each position:

7 * 6 * 5 = 210.

Hence, there are 210 ways to choose a president, vice president, and treasurer from a 7-member club, with the condition that no person can hold more than one office.

In summary, the answer is that there are 210 ways to select the president, vice president, and treasurer for the 7-member club, with each member occupying only one position.

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The given confidence interval is 0.14 < p < 0.342, where p represents the proportion of students who take notes. To interpret this interval correctly, we can say:  We are 99% confident that the true proportion of students who take notes lies between 0.14 and 0.342.

In other words, based on the data from the random sample of size 83, we estimate that the proportion of students who take notes falls within this range with a 99% level of confidence. This means that if we were to take multiple random samples of the same size and calculate confidence intervals, approximately 99% of those intervals would contain the true proportion of students who take notes.

Furthermore, the interval does not include the value of 0.5, which represents no preference or a 50% proportion. Since both 0.14 and 0.342 are less than 0.5, we can infer that the data suggests that a substantial proportion of students take notes, but we cannot conclude with certainty whether the majority or minority take notes without further information.

It's important to note that the interpretation assumes the random sampling method was appropriate and the sample is representative of the population of interest.

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Answer: 34.5

Step-by-step explanation:

(Base · Height) ÷ 2 → (2 · 4.5) ÷ 2 = 5.5

5.5 · 5 = 27.5

27.5 + 7 = 34.5

Answer:

the sequence is geometric sequence with common ratio (-2).

Option : D is correct.

Step-by-step explanation:

In this question table is given as

n          1          2         3           4            5

f(n)     48       -96      192      -385       768

We have to find out if the sequence is arithmetic or geometric.

For Arithmetic sequence :

Difference should be common in each term of fees.

common difference  = f(2) - f(1)

= -96 -48 = -144

similarly  = f(3) - f (2) = 192 + 96 = 288

Here,  ≠  so the sequence is not an arithmetic sequence.

For Geometric sequence :

Ratio  should be common in each term of f(n)

Common ratio  =

Therefore, the sequence is geometric sequence with common ratio (-2).

Option : D is correct.

Answer:

750 equals to 1081 after that divide 1081 by 750 then you will get an answer.

Answer:

x = 19.48 or 19 12/25

Step-by-step explanation:

cos 41° = 14.7/x

x = 19.48 or 19 12/25

Answer:

I think you are I'm not 100%

Answer:

13qt

Step-by-step explanation:

your totally correct.

To determine whether set H is a subspace of R², we need to check if H satisfies the three requirements for a subspace: closure under addition, closure under scalar multiplication, and contains the zero vector.

To determine if set H is a subspace of R², we need to check if it satisfies the three properties of a subspace.

Closure under addition: For any two vectors u and v in H, their sum u + v should also be in H. If the lines forming the boundary of H extend infinitely, then any two vectors u and v in H can be added to form a vector that lies within H. Thus, H is closed under addition.

Closure under scalar multiplication: For any vector u in H and any scalar c, the scalar multiple cu should also be in H. Similarly to the closure under addition, if the lines forming the boundary of H extend infinitely, then any vector u in H can be multiplied by a scalar to obtain a vector that lies within H. Hence, H is closed under scalar multiplication.

Contains the zero vector: The zero vector (0, 0) is part of R² and is also part of H since it lies within the boundary of H.

Since H satisfies all three requirements, it is a subspace of R².

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Answer:

28

Step-by-step explanation:

if (AB and DC) parallels lines than the equation is alternate interior and therefore congruent to each other

Answer: 1,145,375cm^3

Step-by-step explanation:

The quadratic least squares approximation to f(x) = eˣ on the interval [0,2] is g(x) = (e - 1)x + 1.

Let's choose x = 0, x = 1, and x = 2.

The corresponding y-values will be y = f(0) = e⁰ = 1,

y = f(1) = e¹ = e, and

y = f(2) = e².

Now, we can set up a system of equations using the chosen data points and solve for the coefficients a, b, and c:

For x = 0:

a(0)² + b(0) + c = 1

c = 1

For x = 1:

a(1)²+ b(1) + c = e

a + b + c = e

For x = 2:

a(2)² + b(2) + c = e²

4a + 2b + c = e²

Substituting c = 1 from equation 1 into equations 2 and 3, we have:

a + b + 1 = e

4a + 2b + 1 = e²

Now, we can solve this system of equations to find the values of a and b.

Subtracting equation 2 from equation 3, we get:

4a + 2b + 1 - (a + b + 1) = e² - e

3a + b = e² - e

Substituting b = e - a - 1 into equation 2, we have:

a + (e - a - 1) + 1 = e

e - a = e

a = 0

Substituting a = 0 into equation 2, we get:

b + 1 = e

b = e - 1

Therefore, the quadratic least squares approximation is given by:

g(x) = ax² + bx + c

= (0)x² + (e - 1)x + 1

= (e - 1)x + 1

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There exist no subspaces S, T, and U of R³ such that SIT, SIU, and T∩U.

In order to answer the given question, we first need to understand the definition of subspaces of a vector space.A subspace of a vector space is a subset that meets three requirements:

i) It includes the zero element of the vector space.

ii) It is closed under addition (if u and v belong to the subspace, then u + v is also in the subspace).

iii) It is closed under scalar multiplication (if u is in the subspace and k is a scalar, then ku is also in the subspace).

there exist no subspaces S, T, and U of R³ such that SIT, SIU, and T∩U.

The reason is simple because if T∩U = Ø, then either SIT or SIU will be the trivial subspace {0}.

However, this contradicts the fact that both SIT and SIU have to contain a non-zero vector as they are subspaces that are generated by S, T, and U.

Therefore, it is proven that there exist no subspaces S, T, and U of R³ such that SIT, SIU, and T∩U.

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Answer:

1. False

Sketch pads ordered: 10(90/3) = 10×30 = 300

2. True

Painting jars ordered: 8(90/5) = 8×18 = 144

3. True

(25×12)/(12×12) = 300/144

or

25/12 = 300/144 = 2.083..

4. False

Since the previous statement isn't 5:4 and it's true, then this statement is false.

Answer:

y=30x+25

Step-by-step explanation:

y=mx+b (slope-intercept formula)

y= amount of money per hour of labor

m= 30 (amount per hour, slope)

b= 25 (y-intercept, starting rate)

Answer:

fourth answer choice) 5

Step-by-step explanation:

2x + 9 = 4x - 1

9 = 2x - 1

10 = 2x

5 = x

x = 5

I would appreciate Brainliest, but no worries.

The value of x that would make ASUV = ATUN by HL is 4, the correct option is C.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

We are given that;

SUV congruent to TUV

Now,

To solve for x in the equation 2x+9=4x+1, we need to isolate x on one side of the equation.

First, we can simplify both sides by subtracting 2x from each side:

2x+9-2x=4x+1-2x

Simplifying this gives us:

9=2x+1

Next, we can subtract 1 from each side:

9-1=2x+1-1

Simplifying this gives us:

8=2x

Finally, we can divide both sides by 2:

8/2=2x/2

Simplifying this gives us:

4=x

Therefore, by the algebra the answer will be x=4.

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The justification for the proof based on the information will be:

lm = np (Given)

lp = mn (Given)

(1) lmn = lm * n

Justification: Associative property of multiplication

(2) lmn = np * n

Justification: Substitute lm = np

(3) lmn = n * np

Justification: Commutative property of multiplication

(4) lmn = npl

Justification: Substitute lp = mn

Therefore, lmn = npl.

The associative property of multiplication is one of the fundamental properties of arithmetic. It states that the grouping of factors does not affect the result of multiplication.

In other words, when you multiply three or more numbers, you can change the grouping of the factors without changing the product.

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Answer:

A=3^1/5

Step-by-step explanation:

3^x = 3 ^ 1/5*3^5x. Basically you need 3^x to equal A^x. A^x is equal to A^5x in this situration. So, multiply 5x to equal 1x. To make 1x you need to multiply the 5x by 1/5. So, the A value is 3, since the whole number in the 3^x has to be equal to the whole number in A^x. Knowing this, we can tell that A must be equal to 3^1/5.

Answer:

3^1/5

After considering the given data we conclude that value of monthly payments will achieve this is $25,000 over 17 years at a 7% annual interest rate under monthly compounding is $203.

To evaluate the monthly payments that will amortize a debt of $25,000 over 17 years at a 7% annual interest rate under monthly compounding, we could apply the following steps:
Alter the annual interest rate to a monthly interest rate by applying division of 12. The monthly interest rate is 7% / 12 = 0.5833%.
Alter the number of years to the number of months by multiplying by 12. The number of months is 17 × 12 = 204.
Apply the formula for the monthly payment on an amortized loan:
[tex]P = (r * PV) / (1 - (1 + r)^{(-n))}[/tex]
Here,
P = monthly payment,
r = monthly interest rate,
PV = present value of the loan (which is $25,000),
n = total number of payments (which is 204).
Placing in the values, we get:
[tex]P = (0.005833 * 25000) / (1 - (1 + 0.005833)^{(-204))} = $202.91[/tex]
Hence, the monthly payments that will amortize the debt of $25,000 over 17 years at a 7% annual interest rate under monthly compounding is $203 (rounded to the nearest dollar).
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Answer:

900

Step-by-step explanation:

Answer: x^2+5x-14

Step-by-step explanation:

2 and -7 are the roots of the polynomial then we have to write them as

 x=2 ,x=-7

To convert these as factors, we have to write them as

(  x-2) (x+7)

The product of those factors will give the polynomial. Because we have two factors, we will get a quadratic polynomial.

x^2+7x-2x-14

x^2+5x-14

Number of factors  =  Highest exponent of the polynomial

Answer:

y = x² + 5x - 14

Step-by-step explanation:

Given roots x = a, x = b, then the corresponding factors are

(x - a) and (x - b) and the polynomial is the product of the factors

y = (x - a)(x - b)

Here the roots are x = 2 and x = - 7, then the factors are

(x - 2) and (x - (- 7)) = (x + 7), so

y = (x - 2)(x + 7) ← expand using FOIL

y = x² + 5x - 14

P(x < 1) = 0.082085.

The given parameters are μ and x. The mean and variance of the Poisson distribution are μ and σ^2 = μ.The probability that the random variable X takes on the value x is given by P(x).P(x=1) when μ = 3.5

Here, x = 1 and μ = 3.5Plug in the given values in the Poisson distribution,

P(x = 1) = ((e^-3.5) (3.5^1))/1!P(x = 1) = ((0.0301974) (3.5))/1!P(x = 1) = 0.105691(1)P(x = 1) = 0.105691

Thus, P(x=1) = 0.105691.P(x ≤ 9)when μ = 6. The given parameters are μ and x. The mean and variance of the Poisson distribution are μ and σ^2 = μ.

P(x ≤ 9) when μ = 6. Here, x ≤ 9 and μ = 6

Using the Poisson formula:

P(x ≤ 9) = Σ P(x = i) for i = 0 to 9.P(x ≤ 9) = Σ P(x = i) for i = 0 to 9.P(x ≤ 9) = Σ ((e^-6)(6^i))/i! for i = 0 to 9P(x ≤ 9) = 0.091578So,

P(x ≤ 9) = 0.091578P(x > 2) when μ = 3.The mean and variance of the Poisson distribution are μ and σ^2 = μ.P(x > 2) when μ = 3:Here, x > 2 and μ = 3

Using the Poisson formula:

P(x > 2) = Σ P(x = i) for i = 3 to infinityP(x > 2) = Σ ((e^-3) (3^i))/i! for i = 3 to infinityP(x > 2) = 1 - P(x ≤ 2)P(x > 2) = 1 - ((e^-3)(3^0))/0! + ((e^-3) (3^1))/1! + ((e^-3) (3^2))/2!P(x > 2) = 1 - ((0.04978706836)(1))/1 + ((0.04978706836)(3))/1 + ((0.04978706836)(9))/2P(x > 2) = 1 - (0.04978706836 + 0.1493612051 + 0.2240418077)P(x > 2) = 0.5768099198So, P(x > 2) = 0.5768099198.P(x < 1) when μ = 2.5.

The given parameters are μ and x. The mean and variance of the Poisson distribution are μ and σ^2 = μ.P(x < 1) when μ = 2.5:Here, x < 1 and μ = 2.5

Using the Poisson formula:

P(x < 1) = P(x = 0)P(x < 1) = ((e^-2.5) (2.5^0))/0!P(x < 1) = 0.082085P(x < 1) = 0.082085Thus, P(x < 1) = 0.082085.

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Given that X is a random variable having a Poisson distribution, the probability mass function of X is [tex]P(x)=((e^{-\mu})(\mu^{x}))/x![/tex],

x=0,1,2,…

Here, μ is the mean or the expected value of the distribution.

a) P(x=1) when μ=3.5 is 0.1288 (approx.)

b) P(x≤9) when μ=6 is 0.99988 (approx.)

c) P(x>2) when μ=3 is 0.5766 (approx.)

d) P(x<1) when μ=2.5 is 0.0821 (approx.).

Compute the following:

a) P(x=1) when μ=3.5

Calculate probability for random variable by using the probability mass function of X as follows:

[tex]P(x=1)=((e^{-3.5})(3.5^{1}))/1![/tex]

=0.1288 (approx.)

b) P(x≤9) when μ=6

Calculate, [tex]P(x\leq9)= \sum P(x=k)[/tex] from

k=0 to

[tex]9= \sum ((e^{-6})(6^{k}))/k![/tex] from

k=0 to

9=0.99988 (approx.)

c) P(x>2) when μ=3

We are given μ=3. Then,

P(x>2)= 1- P(x≤2)

= 1- (P(x=0)+P(x=1)+P(x=2))

[tex]= 1- (((e^{-3})(3^{0}))/0!+((e^{-3})(3^{1}))/1!+((e^{-3})(3^{2}))/2!)[/tex]

= 0.5766 (approx.)

d) P(x<1) when μ=2.5

Then, P(x<1)=

P(x=0)

[tex]= ((e^{-2.5})(2.5^0))/0![/tex]

= 0.0821 (approx.)

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The number of ways seven books can be arranged on a shelf if there are no restrictions is 7! = 5040.Why? As there are no restrictions, any of the seven books can occupy any of the seven places on the shelf. Therefore, there are 7 ways to place the first book. After the first book has been placed, there are 6 ways to place the second book (as one place is now occupied).Then, after the first and second books have been placed, there are 5 ways to place the third book (since two places are now occupied). Similarly, there are 4 ways to place the fourth book after the first four have been placed. There are 3 ways to place the fifth book after the first five have been placed.

There are 2 ways to place the sixth book after the first six have been placed. There is only one way to place the last book after the first six have been placed.

So, using the Multiplication Principle, the number of ways 7 books can be arranged on a shelf is:7 × 6 × 5 × 4 × 3 × 2 × 1 = 5040.

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(a) The non-identity isometry given by a reflection followed by a glide reflection can be classified as a translation. In Euclidean geometry, any reflection followed by a glide reflection is equivalent to a translation in a specific direction.

(b) The non-identity isometry that fixes two points can be classified as a rotation. In Euclidean geometry, any isometry that fixes two distinct points is a rotation about the midpoint between those two points.

(a) Let's denote the reflection as R and the glide reflection as G. If G is applied after R, we have GR. Since the isometry does not have any fixed points, GR cannot be a reflection or a translation. Therefore, the only possibility left is that GR is a glide reflection. However, in Euclidean geometry, a glide reflection is equivalent to a translation. Hence, the non-identity isometry in this case is a translation.

(b) Since the isometry fixes two points P and Q, let's denote the isometry as F. Fixing two distinct points implies that the isometry must be a rotation about the midpoint between those two points. Therefore, the non-identity isometry in this case is a rotation.

In summary, the non-identity isometry in (a) is a translation, and the non-identity isometry in (b) is a rotation.

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Answer:

sheck wes, sam hunt, mainiac, petty level , lakeyah , doja cat, sawatiee

Step-by-step explanation:

Answer:

NF: Songs are kinda depressing sometimes but he is a really good rapper. Hear clouds

Kid Laroi: Listen to without you.

iann dior: rapper and really good

Mumford and sons: more of slow music but upbeat at the same time

Tracy chapman: She has really good music. Recommend listening to fast car

those are some of my favs

Step-by-step explanation:

The dimensions of the largest area that can be enclosed is 1590 × 795= 1264050 yd² when no fencing is required along the river.

Given the owner of the Rancho Los Feliz has 3180 yd of fencing to enclose a rectangular piece of grazing land along the straight portion of a river and then subdivide it by means of a fence running parallel to the sides. No fencing is required along the river.

We need to find the dimensions of the largest area that can be enclosed.

Therefore, the length of the land is the perimeter of the rectangle minus the river front.

We have; 2x + 3y = 3180 yd

Also, we can rewrite this equation in terms of x;

2x = 3180 - 3yy = (3180 - 2x) / 3

Substituting y in terms of x in the area equation;

Area A = x y= x(3180 - 2x) / 3

Taking the derivative of the area equation to find the maximum value of A;

A' = 1060 - 2x / 3 When A' = 0, x = 1590 / 2 = 795 yd.

Substitute x = 795 into the equation for y;

2(795) + 3y = 3180y = (3180 - 1590) / 3 = 530 yd

Therefore, the dimensions of the largest area that can be enclosed are; Length = 1590 yd Width = 795 yd

Hence, the area is given by; Area = Length × Width= 1590 × 795= 1264050 yd².

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