how do i solve this

How Do I Solve This

Answers

Answer 1

Answer:

m <E = 134

Step-by-step explanation:

Triangle DEF looks like an isosceles triangle to the base angles are the same measure.

6x+11 = 10x+3

Subtract 11 from both sides

6x = 10x-8

Subtract 10x from both sides

-4x = -8

Divide -4 from both sides

x = 2

Substitute 2 into both equations to make sure it works

6 (2) + 11

12+11

23

10 (2) +3

20+3

23

Both angles equal 23 degrees.

Now subtract both angles from the total angle measure of 180.

180-23-23=134


Related Questions


What is the following expression?
3x2 + 5
1.monomial
2.binomial
3 neither

Answers

Answer:

Assuming the 2 in 3x2 is an exponent, then it is binomial.

Step-by-step explanation:

A binomial is an expression with two terms, in this case those two terms are 3x^2 and 5

Answer:

2.binomial

Step-by-step explanation:

3x2=1

5=2

so its a binomial

What is 16.281 rounded to the nearest whole number
and What is 16.281 rounded to the nearest tenth?

Answers

Answer:

16, and 16.3

Step-by-step explanation:

Answer:

1. 16     2.16.3

Step-by-step explanation:

2.16.281 is 16.28 which is near 16.3 so you round. Also anything above 5 you round and anything below 5 you round down.

f(a)=2a+5
g(a)=a2-4
what is f(g(a))

Answers

f(g(a)) = f(-2(7)) because f(a)=7 and f(g)=-2

help please RSM problem -need anwser please

Answers

Answer:

1/8 + 1/4 = 3/8

Step-by-step explanation:

A text font fits 12 characters per inch. Using the same font, how many characters can be expected per yard of text? 36 characters 144 characters 360 characters 432 characters.

Answers

Answer:

  432 characters

Step-by-step explanation:

There are 36 inches in a yard, so there will be 36 times 12 characters:

  (36 in/yd)(12 char/in) = 432 char/yd

432 characters can be expected per yard of text.

Marla was given the point (1, 3), (2, 1), and (-2, -15). She was asked to find a quadratic function that fit these 3 given points. Marla created a system of three equations with three variables to solve the problem and then used the matrix functions on her graphing calculator to find the equation. Which equation can be written given these 3 points?

Answers

The quadratic equation is given by y = -2x² + 4x + 1

The standard form of a quadratic equation is given by:

y = ax² + bx + c

At point (1, 3):

3 = a(1)² + b(1) + c

a + b + c = 3      (1)

At point (2, 1):

1 = a(2)² + b(2) + c

4a + 2b + c = 1      (2)

At point (-2, -15):

-15 = a(-2)² + b(-2) + c

4a - 2b + c = -15      (3)

Solving equations 1, 2 and 3 simultaneously gives:

a = -2, b = 4, c = 1

The quadratic equation is given by y = -2x² + 4x + 1

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Hi! Please help me!

Lightbulbs act as resistors. Janine is building a circuit that contains two lightbulbs in parallel. One of the lightbulbs has a
resistance of 120 ohms, but the resistance of the second lightbulb is unknown. She models the total
resistance in the
circuit, t, with this equation, in which r represents the resistance of the second lightbulb.
t =
1207
+ 120
Find the inverse of Janine's equation.

Look at photo below

Thank you have a nice day:)

Answers

Answer:

The answer is t^-1 (r)=120r/120-r

i hope this is right sry if im wrong have a good day :)

The inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .

What is resistance?

Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω).

According to the question

Janine is building a circuit that contains two lightbulbs in parallel.

One of the lightbulbs has a resistance of 120 ohms.

R = 120ohms

r = resistance of the second lightbulb

t = total resistance in the circuit  

[tex]t = \frac{120r}{r+120}[/tex]

Now,

The inverse of Janine's equation in which we will make r independent

[tex]t = \frac{120r}{r+120}[/tex]

[tex]t(r+120) = 120r[/tex]

[tex]tr + 120t = 120r[/tex]

[tex]120t = 120r - tr[/tex]

[tex]120t = r(120-t)[/tex]

[tex]r = \frac{120t}{120-t}[/tex]

Hence, the inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .

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Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 68 km/h faster than the other. If the two planes are 5052 kilometers apart after 3 hours, what is the rate of each plane?

Answers

Step-by-step explanation:

the slower plane travels x km in 3 hours.

the faster plane travels x + 3×68 = x + 204 km in 3 hours.

x + x + 204 = 5052 km

2x = 4848 km

x = 2424 km (in 3 hours).

so, the slower plane's speed is 808 km/h.

the faster plane's speed is 808 + 68 = 876 km/h.

5w+4w=18 simplify

how do you do this??

Answers

Answer:

Solved: w = 2  

Step-by-step explanation:

Combine like terms

5w+4w = 9w

Isolate or make w alone

9w= 18 so divide both sides by 9 to make w alone

9w ÷ 9 = w

18 ÷ 9 = 2

w = 2

Answer:

you just add 5w and 4w and taht is 9w

[tex]9x = 18 \\ w = 18 \div 9 \\ w = 2[/tex]

helpppppppppppppppppp​

Answers

Answer:

IP information is attached to each packet, and this information helps routers to send packets to the right place. Every device or domain that connects to the Internet is assigned an IP address, and as packets are directed to the IP address attached to them, data arrives where it is needed.

Step-by-step explanation:

hope i helped!

What are the answers to these?

Answers

A) -3

B) 5

C) -2

D)-6

i have to write 20 characters so sisiasskklsa

Answer:

a) -3

b)5

c)-2

d)-6

Step-by-step explanation:

4 - 7 =-3

4 is positive and 7 is negative

a positive minus a negative is equal to a negative

3 is negative and 8 is positive, but 8 is bigger than 3, so take the sign of the bigger number which is 8.

c) is the same as question b

same signs rule

a negative + a negative is = to negative

positive and a positive is = to a positive

a negative +/_ a positive = a negative

What is 7x(-4) ? Please

Answers

[tex]\mathfrak{7x(-4)} [/tex]

[tex]\mathfrak{=7x*-4} [/tex]

[tex]\boxed{\mathfrak{=-28x}} [/tex]

[tex]\mathbb{MIREU} [/tex]

The product of a binomial and a trinomial is x 3 3 x 2 âÂ’ x 2 x 2 6 x âÂ’ 2. Which expression is equivalent to this product after it has been fully simplified? x3 5x2 5x â€"" 2 x3 2x2 8x â€"" 2 x3 11x2 â€"" 2 x3 10x2 â€"" 2.

Answers

The product of given binomial and trinomial is given by below polynomial:

[tex]x^5 + 9x^4 + 15x^3 -10x^2 + 14x - 4[/tex]

Given polynomials:Trinomial : [tex]x^3+3x^2-x+2[/tex]Binomial: [tex]x^2+6x-2[/tex]

Explanation:

The expression formed by the sum of sub expressions which are product of constant integers with variables raised to some exponent is called polynomial.

Their product is given by:

[tex](x^3 + 3x^2 - x + 2) \times (x^2 + 6x -2)\\= x^5 + 6x^4 - 2x^3 + 3x^4 + 18x^3 - 6x^2 -x^3 -6x^2 + 2x +2x^2 + 12x - 4\\= x^5 + 9x^4 + 15x^3 -10x^2 + 14x - 4[/tex]

Thus the product of given binomial and trinomial is given by below polynomial:

[tex]x^5 + 9x^4 + 15x^3 -10x^2 + 14x - 4[/tex]

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Find the equation of a line perpendicular to y - 1= -x that passes through the
point (-4,-8).
1.) y = x - 4
2.) y = -x - 4
3.) y = -x - 1
4.) y = x - 1

Answers

Answer:

4

Step-by-step explanation:

firstly you separate y

y=-x-1

which means that the slope is equal to -1

then you flip the slope so -1 over -1 which is equal 1

Sean is drinking a slushy as fast as he can. The amount of slushy left in the cup (in milliliters) as a function of time (in seconds) is graphed. How long did it take Sean to finish the slushy?

______ seconds ​

Answers

Answer:

75 seconds

Step-by-step explanation:

The graph intersects the x axis at 75 seconds.  That means y = 0, and y is the amount remaining (in ml).

After 75 seconds the amount of slushy left in the cup becomes zero the answer is 75 seconds.

What is a line graph?

A line graph is a type of graph where the data points are connected by segments of straight lines.

We have a line graph shown in the picture.

Sean is drinking a slushy as fast as he can. The amount of slushy left in the cup (in milliliters) as a function of time (in seconds) is graphed.

As we can see the amount of slushy left in the cup is decreasing as the time increases.

At time = 75 seconds

The amount of slushy left in the cup = 0

Thus, after 75 seconds the amount of slushy left in the cup becomes zero the answer is 75 seconds.

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How do I find the percentage of two column data table?

Answers

Answer:

  a) 47.7%

  b) 87.2%

Step-by-step explanation:

Find the ratio of interest, and convert it to a percentage.

a)

  (messy right-handed writers)/(right-handed writers)

  = 31/65 = 31/65 × 100% ≈ 47.7%

__

b)

  (neat right-handed writers)/(neat writers)

  = 34/39 = 34/39 × 100% ≈ 87.2%

Question 1
Part a) 9 Athletes are running the 200M event. How many ways can the first three finishers be awarded medals? Show your work using the Permutation or Combination formula for full credit.




Part b) You have 10 photos to arrange in an art gallery, where there are 5 spaces to place them. How many ways can they be arranged? Show your work using the Permutation or Combination formula for full credit.





Part c) Write an original word problem of your own creation that uses a combination and the numbers 8 and 4. Also state the solution. You may not use a pizza-themed scenario.

Answers

Using the permutation and the combination formula, we have that:

a) The first three finishers can be awarded medals in 504 ways.

b) They can be arranged in 252 ways.

c) In how many ways can 4 students form a team from a set of 8.

If the order is important, the permutation formula is used.If the order is not important, the combination formula is used.

Combination formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

Permutation formula:

The number of possible permutations of x elements from a set of n elements is given by:

[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]

Item a:

Order is important, as the finishers are ranked, hence:

[tex]P_{(9,3)} = \frac{9!}{6!} = 504[/tex]

The first three finishers can be awarded medals in 504 ways.

Item b:

The order is not important, hence:

[tex]C_{10,5} = \frac{10!}{5!5!} = 252[/tex]

They can be arranged in 252 ways.

Item c:

Situation in which the order is not important, hence, for example, in how many ways can 4 students form a team from a set of 8.

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Someone please help me with this question And you can get 20 points

Answers

[tex]\text{Consider the slope - intercept form} ~y = mx +c,\\\\ \text{where m is the slope and and c is the y-intercept.}\\\\(a) \\\\y = -\dfrac 12 x +8 \\\\\text{This is in a form of y = mx +c, so}\\\\\text{Slope, m =}-\dfrac 12 ~ \text{and}~ \text{y - intercept , c =8}\\\\(b)\\\\y = 9x -2 \\\\\text{This is in a form of y = mx +c, so}\\\\\text{Slope, m =9}~ \text{and}~ \text{y - intercept ,}~ c =-2\\\\[/tex]

Which decimal is 5.764 round to the nearest hundredth

Answers

Answer: I think it's 6

Step-by-step explanation:

Sally's bank account has $650 in it. Every week, Sally withdraws $50 to pay for her dog sitter.

What is the maximum number of weeks that Sally can withdraw the money so there is at least $75

remaining in the account?

Write and solve an inequality to find the solution.

Answers

Answer:

11 weeks

Step-by-step explanation:

If we multiply 50 by 11 we get 550 with a remainder of 100, if we're to take out another 50 for another week we would have 50 dollars remanding but the question says that we need to have at least 75 remaining so this will not be possible. Therefor 11 weeks is our answer.

I hope this helps have a great day :)

Make x the subject
5px+q^2=3c

Answers

Answer:

x=[tex]\frac{3c-q^2}{5p}[/tex]

Step-by-step explanation:

5px+q^2=3c

subtract q^2 from both sides

5px=(3c)-q^2

divide by 5p from both sides

x=[tex]\frac{3c-q^2}{5p}[/tex]

Paula caught a tarpon with a weight that was 10 times as great as the weight of a permit fish she caught. The total weight of the two fish was 154 pounds.

How much did each fish weigh?

The permit fish weighed _____ pounds.

The tarpon weighed ______ pounds.

Answers

Answer:

The weight of permit fish 140 pounds

The weight of Tarpon fish 14 pounds

Step-by-step explanation:

Let the weight of Tarpon fish ve 'x' Then by question weight of permit fish be '10x'

Now by question

x+10x=154 pounds

or,11x=154 pound

or,x=154pound/11

Therefore, x = 14 pounds

Again by question weight of permit fish

for 10x

by substituting value of x we have,

=10×14 pounds

=140 pounds

Kay is running a 13.5 km race. If she runs at a rate of 8 2/5 km/he for 1.5 hours, how many kilometers will she have left to run to finish the race?

Answers

The number of kilometers she will have left to run to finish the race is 0.9 km.

Given the following data:

Total distance = 13.5 kmSpeed = [tex]8\frac{2}{5} \;km/hr[/tex]Time = 1.5 hours

To determine the number of kilometers she will have left to run to finish the race:

First of all, we would calculate the distance she has covered by using this formula;

[tex]Distance = speed \times time\\\\Distance = 8\frac{2}{5} \times 1.5\\\\Distance = \frac{42}{5} \times \frac{3}{2} \\\\Distance = \frac{63}{5}[/tex]

Distance = 12.6 meters.

For the distance left:

[tex]Distance\;left = Total\;distance - Distance\;covered\\\\Distance\;left =13.5 -12.6[/tex]

Distance left = 0.9 km.

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Johnny kicks a ball into the air. Assume the path of the ball can be modeled with a quadratic function. The ball reaches a height of 10 feet and lands on the ground 3 seconds later. Draw and label a graph that models the path of the ball. Write an equation that models the path of Johnny’s ball.

Answers

An equation that models the path of Johnny’s ball is [tex]y = -\frac{40}9(x - 1.5)^2 + 10[/tex]

The maximum height is given as:

[tex]h_{max}= 10ft[/tex]

And the time spent is:

[tex]t = 3s[/tex]

So, the vertex of the ball would be:

[tex]Vertex = (t/2,h_{max})[/tex]

This gives

[tex]Vertex = (3/2,10)[/tex]

[tex]Vertex = (1.5,10)[/tex]

Rewrite properly as:

[tex](h,k) = (1.5,10)[/tex]

The ball is on the floor after 3 seconds.

So, another point on the graph is:

[tex](x,y) = (3,0)[/tex]

A quadratic equation is represented as:

[tex]y=a(x - h)^2 + k[/tex]

Substitute [tex](x,y) = (3,0)[/tex] and [tex](h,k) = (1.5,10)[/tex] in [tex]y=a(x - h)^2 + k[/tex]

[tex]0=a(3 - 1.5)^2 + 10[/tex]

[tex]0=a(1.5)^2 + 10[/tex]

Evaluate the exponent

[tex]0=2.25a + 10[/tex]

Subtract 10 from both sides

[tex]2.25a =- 10[/tex]

Divide both sides by 2.25

[tex]a = -\frac{10}{2.25}[/tex]

Multiply by 4/4

[tex]a = -\frac{40}{9}[/tex]

Substitute [tex]a = -\frac{40}{9}[/tex] and [tex](h,k) = (1.5,10)[/tex] in [tex]y=a(x - h)^2 + k[/tex]

[tex]y = -\frac{40}9(x - 1.5)^2 + 10[/tex]

See attachment for the graph that models the path

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d20) A department store buys 200 shirts at
of $2,400 and sells them at a selling price of $20
each. Find the percent markup.
Pls answer now I need it pls

Answers

This is the answer you’re welcome

19. The passing marks in an examination is 40%. If Seema gets 130 marks, she fails by ups 2 marks. Find the total marks.​

Answers

Given :-

Passing marks in an exam is 40% .Seema gets 130 marks and fails by 2 marks.

To find :-

The maximum marks for the exam .

Solution :-

According to the Question ,

[tex]\dashrightarrow[/tex] Passing marks = 40% .

[tex]\dashrightarrow[/tex] Seema's marks = 130 .

Let us take the maximum marks be x . Then ,

[tex]\dashrightarrow[/tex] Passing marks = 130 + 2

[tex]\dashrightarrow[/tex] Passing marks = 132

And , by question ,

[tex]\dashrightarrow[/tex] 40x/100 = 132

[tex]\dashrightarrow[/tex] x = 132 * 100/40

[tex]\dashrightarrow[/tex] x = 330

Hence the maximum marks for the exam is 330.

Given :

Passing marks in the examination = 40% .

Marks obtained by Seema = 130 .

So, Let us assume the maximum marks as x .

Also,

Passing marks = 132 [ ∵ Seema got 130 marks and she failed by 2 marks ]

According to the question :

[tex] \\ \tt : \implies\dfrac{40x}{100} = 132 \\ \\ \tt : \implies\dfrac{4 \cancel{0}x}{10 \cancel{0}} = 132 \\ \\ \: \: \: \tt \: : \implies 4x = 132 \times 10 \\ \\ \tt : \implies \: 4x = 1320 \\ \\ \tt : \implies \: x = \frac{1320}{4} \\ \\ \tt : \implies \: x = 330 \: \: \\ [/tex]

Hence, The total marks is 330 .

Find the greatest common factor and the least common multiple of 16 and 20. The prime factorizations of each number are given.
.

Answers

Answer:

GCF 4, LCM 80

Step-by-step explanation:

Since both 16 and 20 have two 2s as factor, their greatest common factor is 4.

The LCM is found by multiplying all of the remaining factors by the LCM:

16 still has (2 x 2), 20 still has (5), times the GCF (4)  so 2 x 2 x 5 x 4 = 80.

The linear parent function, f(x) = x, was transformed to create a graph g(x) = f(x + 4).
Which statement about the graphs is true?
O The graph of fis steeper than the graph of g.
O The graph of fis shifted 4 units left to create the graph of g.
O The graph of fis less steep than the graph of g.
O The graph of fis shifted 4 units right to create the graph of g.

Answers

Answer:

2nd option

Step-by-step explanation:

Given f(x) then the graph of f(x + a) is a horizontal translation of f(x)

• If a > 0 then a shift left of a units

• If a < 0 then a shift right of a units

g(x) = f(x + 4)

Is the graph of f(x) shifted 4 units to the left

The number of international tourist arrivals in Russia in 2012 was 13.5% greater than in 2011. The number of international tourist arrivals in Russia was k million more in 2012 than in 2011. What is the value of k to the nearest integer

Answers

The value of k to the nearest integer is 21

Let the number of international tourist arrivals in Russia in 2011 be k

If the number of international tourist arrivals in Russia in 2012 was 13.5% greater than in 2011 will be expressed as:

k = 24.7 - (13% of 24.7)

k = 24.7 - (0.135 * 24.7)

k = 24.7 - 3.3345

k = 21.3655

Hence the value of k to the nearest integer is 21

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a √(x^2-n/m)= a^2/b make x subject

Answers

[tex]\sqrt{x^2 -\dfrac nm} = \dfrac{a^2}b\\\\\implies x^2 - \dfrac nm = \dfrac{a^4}{b^2}\\\\\implies x^2 = \dfrac{a^4}{b^2} + \dfrac nm}\\\\\implies x = \pm \sqrt{ \dfrac{a^4}{b^2} + \dfrac nm}}[/tex]

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