How does a balanced chemical equation show the conservation of mass?
O A. It shows that the total number of moles of substances stays the
same.
B. It shows that the mass of the products is greater than the mass of
the reactants when a reaction increases the moles of substances.
O C. It shows that the mass of the reactants is greater than the mass
of the products when gases are produced by the reaction.
O D. It shows that the number of each type of atom stays the same.

Answers

Answer 1

Explanation:

Every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. When an equal number of atoms of an element is present on both sides of a chemical equation, the equation is balanced.


Related Questions

WHAT DO THESE DIAGRAMS MEAN PLS HELP

Answers

Answer:

(I). Evaporation

(ii). Sublimation

30. A5.30 g of Na2CO3 is dissolved in a 400.0 mL solution. What is the molarity for this solution?
A. 0.0133 M
B. 0.0500 M
C. 0.125 M
D. 13.3 M

Answers

We first compute for the moles, n, of the solute sodium carbonate,
N
a
2
C
O
3
, by converting the given 5.30 g of the solute using its molar mass, 105.99 g/mol:

n
=
5.30

g

N
a
2
C
O
3
×
1

m
o
l

N
a
2
C
O
3
105.99

g

N
a
2
C
O
3
=
0.0500

m
o
l

N
a
2
C
O
3



Guys pls HELP ME PLS I WOLL GIVE BRAINLIEST PLS

Answers

The energy decreases

6NaBr+1AlO3=3Na2O+2AlBr3 How many grams of NaBr would be needed in order to make 23.5 grams of AlBr3

Answers

Answer:

23.5 grams of AlBr3 will be produced by 27.20 grams of NaBr

Explanation:

The balanced equation here is

6NaBr + 1AlO3 = 3Na2O + 2AlBr3

6 moles of NaBr are required to produce 2 moles of AlBr3

Mass of one mole of NaBr = 102.894 g/mol

Mass of one mole of AlBr3 = 266.69 g/mol

Mass of 6 moles of NaBr = 6*102.894 g/mol

Mass of two moles of AlBr3 = 2*266.69 g/mol

6*102.894 g  NaBr produces 2*266.69 g of AlBr3

23.5 grams of AlBr3 will be produced by (6*102.894)/(2*266.69 )*23.5 = 27.20 grams of NaBr

if 22.1g of CH4 reacts with 31.9g of O2 what is the limiting reactant?
timed test! will mark brainliest please help!!!

Answers

Answer:

CH4

Explanation:

because it CH4 have lesa mass than that of O2

my chem test is tomorrow!! please help

Answers

Answer:

The pH of the pure water is not always neutral but actually sometimes it can be slightly acidic but not of the same extent or value as HCl obviously. However ,it is enough to result to a color change in the presence of phenolphthalein.

Explanation:

I will try to be brief and spare the boring details .Basically ,this is caused by the reaction of water and CO2 that is naturally present in the atmosphere to produce a weak acid known as carbonic acid.

~Hope this helps:)

Identify the correct formula for each of the following acids. Click here to use the common polyatomic ion sheet if needed.

Hydrochloric acid

HClO2

HClO3

HCl

Answers

Answer:

HCl

H3PO4

Explanation:

The formula of hydrochloric acid is HCl. It contains one hydrogen and one chlorine atom. And thus all other options with O is wrong and option C is correct.

What is hydrochloric acid?

Hydrochloric acid is a strong acid having the formula HCl. Thus one mole of hydrochloric acid contains one hydrogen atom and one chlorine atom. No other elements such as oxygen is present in it.

The electronegativity of chlorine is very higher compared to hydrogen  and they attracts by hydrogen bond. Each atom shares one electron with the other atom and thus it can also said as they are covalently bonded.

Hydrochloric acid is used in many industrial uses and it is present even in our stomach to aid digestion. Since it is very strong acid it may cause sever damages to skin if and its vapor causes respiratory issues when comes in contact.

Therefore, the correct formula of hydrochloric acid is HCl, option C is correct.

To find more about HCl, refer the link below:

https://brainly.com/question/24177034

#SPJ5

Can someone help me with this?
How many grams of AlCl3 are needed to completely react with 2.25 of NaOH?

Answers

Answer:

omg my friends name is Noah

Explanation:

Select all examples that apply as a physical changes in properties (please help)

Answers

All except burning gasoline

please look at the attached photo

Answers

Answer a: alkali

Pls why do i need to write 20
a. Alkali
b. Chemical
c. Reactants
d. Neutralized ,acid
e. Neutralization
f. Products

HELP ME PLEASE!! Which of the following is NOT an example of a chemical change ?

A. Mixing baking soda and vinegar together causing bubbles and foam.

B. A glass cup falling to the floor and breaking.

C. Lighting a piece of paper on fire.

D. Baking a birthday cake

Answers

B that’s is not a chemical change because I took the test

A 2.0 mL sample of air in a syringe exerts a pressure of 1.02 atm at 22 C. If that syringe is placed into boiling water at 100 C and the pressure in the syringe increases to 1.27 atm, what is the new volume of the air in the syringe?

Answers

Answer: The new volume of the air in the syringe is 7.3 mL.

Explanation:

Given: [tex]V_{1}[/tex] = 2.0 mL,     [tex]P_{1}[/tex] = 1.02 atm,          [tex]T_{1} = 22^{o}C[/tex]

[tex]V_{2}[/tex] = ?,               [tex]P_{2}[/tex] = 1.27 atm,               [tex]T_{2} = 100^{o}C[/tex]

Formula used to calculate the new volume in syringe is as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1.02 atm \times 2.0 mL}{22^{o}C} = \frac{1.27 atm \times V_{1}}{100^{o}C}\\V_{1} = 7.3 mL[/tex]

Thus, we can conclude that the new volume of the air in the syringe is 7.3 mL.

Sound is created through vibrations in the air which causes the auditory sensation in your ear – making you able to hear the noises that we do. Sound produced by different sources have different characteristics like amplitude , wavelength and frequency. Analyze the diagrams to answer the following questions with suitable reasons. (A)Which represents the highest pitched sound?. Give reason.

Answers

Answer:

The answer is A

Explanation:

A had higher frequency and higher the frequency of an object the higher its pitch still be

Need help ASAP ( will give 50 points)
Select the correct answer. Which galaxies have light smoothly spread across the
galaxy? A. spiral galaxy B. irregular galaxy C. lenticular galaxy D. elliptical galaxy

Answers

Answer:

Your answer would be D, Hope this helps.

which type of star will have the longest lifespan​

Answers

Answer:

Red dwarfs

Explanation:

Hope it helps!

PLS HELP NO LINKS PLS
What is the pH of normal rainfall?

Answers

Answer:

between 5 and 5.5

Explanation:

Answer:

between 5.0 and 5.5

Explanation:

between 5.0 and 5.5


Lee and some other students working with Dr. Yung were conducting an experiment and ended up with some confusing results. In the experiment, each student combined sodium and hydrogen chloride, but, as shown in the table below, each student ended up with different results. Lee is trying to determine what happened.

In a few minutes, you will see a video of what happened when Lee combined two substances. Before you watch the video, see if you can predict why each student ended up with different results.

Student's name Starting substances Ending substances
Lee sodium and hydrogen chloride hydrogen and sodium chloride
Vera sodium and hydrogen chloride hydrogen, sodium chloride, and sodium
Domingo sodium and hydrogen chloride hydrogen, sodium chloride, and hydrogen chloride


Why do you think Vera and Domingo ended up with three substances after the chemical reaction while Lee only ended up with two?

Answers

Answer:

chung long

Explanation:

cause 3 plus 2 =9

definition of ​spirilla
don't write incorrect answer ​

Answers

Answer:

a bacterium with a rigid spiral structure,found in stagnant water and something causing disease

What is the volume of NaOH used in each Titration??​

Answers

Answer:

Titration 1=33.9ml

Titration 2=33.45ml

Titration 3=33.35ml

Explanation:

Volume of NaOH used =Final reading - Initial reading

Titration 1:

Final reading =35.5ml

Initial reading=0.6ml

Volume of NaOH used =34.5ml -0.6ml=33.9ml

Titration 2:

Final reading =34.3ml

Initial reading=0.85ml

Volume of NaOH used =34.3ml -0.85ml=33.45ml

Titration 3:

Final reading =33.8ml

Initial reading=0.45ml

Volume of NaOH used =33.8ml 0.45ml=33.35ml

Hope it helps:)

Suggest a substance that can be used to neutralise sulfuric acid.



answer this please​

Answers

Sodium Carbonate, Sodium Bicarbonate or Sodium Hydroxide.

To neutralize sulfuric acid we can use sodium bicarbonate (NaH2CO3) or Sodium hydroxide (NaOH).

HI! I REALLY NEED HELP, THANK YOU!!

Answers

Answer:

Nuclear fusion is a reaction in which two or more atomic nuclei are combined to form one or more different atomic nuclei and subatomic particles. The difference in mass between the reactants and products is manifested as either the release or the absorption of energy. 

Explanation: Read this and you might be able to figure it out for yourself ☺️☺️☺️

PlEASE HELP ME QUICK PLEASE!!!

Answers

Answer:

first is c and second is a

PLEASE HELP DUE IN 20 MINUTES NO LINKS PLEASE ​

Answers

Answer:

A

Explanation:

Electrolysis has to do with the decomposition of a solution by the passage of direct current through it. Current enters and leaves the electrolyte via electrodes.

The positive electrode is called the anode while the negative electrode is called the cathode. Positive ions move towards the cathode while negative ions move towards the anode.

Cu^2+ moves towards the cathode and accepts two electrons to be deposited on the cathode as metallic copper. Also, Cl^- ions move towards the anode and gives up electrons to become oxidized to chlorine gas.

Hence in the electrolysis of CuCl2, copper is obtained at the cathode while chlorine gas is obtained at the anode. Hence 1 and 3 are correct statements.

Is this an alpha or beta decay?

Answers

alpha

when radon decays it releases a splash particle to become polonium

What is Radical. Write it types also.​

Answers

1212121212121212121212121212

Answer:

Radical is a charged ion

the types are cation and anion.

cation is positively charged and anions are negatively charged

Explanation:

Il give brainliest question in the picture

Answers

Answer:

Nitrogen and Argon

Explanation:

These gases are part of a class of "noble" gases because they don't react with anything.

CO2 and n2 because they are in the air most the time so nothing bothers them other than oxygen

when chlorine gas is passed through potassium Bromide solution Potassium Chloride and bromine are formed which is a more reactive non metal bromine or chlorine ​

Answers

[tex] \boxed{\boxed{\huge{ \mathbf{  \underline{ Answer} \:  \:  ✓ }}}}[/tex]

In a displacement reaction, more reactive element displaces less reactive element from its compound and from the above reaction we observed that, Chlorine displaces bromine from its compound (KBr) to form Potassium chloride (KCl), therefore Chlorine is more reactive non - metal.

The equation for above reaction is :

[tex] \large\boxed {\mathrm{2KBr + Cl_2 \rightarrow 2KCl + Br_2}}[/tex]

_____________________________

[tex]\mathrm{ ☠ \: TeeNForeveR \:☠ }[/tex]

Can the excess reactant control the percentage yield?

Please answer

Answers

Answer:

Yes, it can.

Explanation:

The percentage yield is decreased if the reactants do not completely form the products. To make a given mass of product, a process with a low percentage yield requires more of the reactants than a process with high percentage yield.

The answer is yes it can! let me know if it works!

LINO3 +
CaBr2 → ____ Ca(NO3)2 +
LiBr

Answers

Answer:

2LiNO3 + CaBr2 → Ca(NO3)2 + 2LiBr (balanced equation)

Answer:

2LiNO3 + CaBr2 → Ca(NO3)2 + 2LiBr

Explanation:

The half-life of iodine-131 is 8 days. How many milligrams of iodine-131
remain after 24 days if the original amount was 4.00 mg?
A. 1.33 mg
B. 0.667 mg
C. 0.500 mg
D. 0.444 mg

Answers

Answer:

The correct answer is - C. 0.500 mg.

Explanation:

In this case, the half-life of the iodine-131 is 8 days and the initial amount is given 4 mg. According to this after every 8 days, half of the initial value of the iodine-131 remains only.

8 days or 1st half-life = A(i)* 1/2

16 days or two half-life = A(i)* 1/4

24 days or three half-life = A(i)* 1/8

and the remaining amount A would be

= A(i)*1/2^n

= 4 * 1/2^3

= 4 *1/8

= 0.500 mg

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