How much work can a motor with a power output of 0.70 hp do in 2 s?

Answer:

.....where's the model-

Answer:

Less

Explanation:

Weight is a force measurement. The object's mass is 5kg not its weight. To find its weight you have to take the mass of an object and multiply it by the acceleration of gravity. The acceleration of gravity is greater on earth than on the moon so therefore the object will weigh less on the moon.

Answer:

Temperature is a measure of the average kinetic energy of the particles in an object. So, the answer will be B.

This question is incomplete, the complete question is;

In a softball windmill pitch, the pitcher rotates her arm through just over half a circle, bringing the ball from a point above her shoulder and slightly forward to a release point below her shoulder and slightly forward. (Figure 1) shows smoothed data for the angular velocity of the upper arm of a college softball pitcher doing a windmill pitch; at time t = 0 her arm is vertical and already in motion. For the first 0.15 s there is a steady increase in speed, leading to a final push with a greater acceleration during the final 0.05 s before the release. In each part of the problem, determine the corresponding quantity during the first 0.15 s of the pitch.

Angular Velocity at time 0s = 12 rad/s

Angular Velocity at time 0.15s = 24 rad/s

a) What is the angular acceleration?

b) If the ball is 0.60 m from her shoulder, what is the tangential acceleration of the ball? This is the key quantity here--it's a measure of how much the ball is speeding up. Express your answer in m/s2 and in units of g

Answer:

a) the angular acceleration is 80 rad/s²

b) the tangential acceleration of the ball is;

- a = 48 m/s²

- a = 4.9 g

Explanation:

Given the data in the question;

from the graph below;

Angular Velocity at time 0s [tex]w_o[/tex] = 12 rad/s

Angular Velocity at time 0.15s [tex]w_f[/tex] = 24 rad/s

a) What is the angular acceleration;

Angular acceleration ∝ = ( [tex]w_f[/tex] - [tex]w_o[/tex] ) / dt

we substitute

Angular acceleration ∝ = ( 24 - 12 ) / 0.15

Angular acceleration ∝ = 12 / 0.15

Angular acceleration ∝ = 80 rad/s²

Therefore, the angular acceleration is 80 rad/s²

b)

If the ball is 0.60 m from her shoulder, i.e s = 0.6 m

the tangential acceleration of the ball will be;

a = ∝ × s

we substitute

a = 80 × 0.6

a = 48 m/s²

a = ( 48 / 9.8 )g

a = 4.9 g

Therefore, the tangential acceleration of the ball is;

- a = 48 m/s²

- a = 4.9 g

[tex]\huge \mathscr\colorbox{yellow}{AnSwEr}[/tex]

[tex] \huge\bold{T}[/tex]he speed of sound is maximum in solids. The speed of sound depends on the density of the medium through which it travels.The higher the density of the medium, the faster the propagation of sound. Since the density of solids is greater than that of liquids and gases, sound travels faster in solids. Also, the molecules in the solid medium are closer together than in liquids or gases, which allows sound waves to travel faster through it.

[tex] \huge \fbox \red{Hope This Helps You ❤}[/tex]

Answer:

B

Explanation:

i took the test

The resulting wave has the largest possible amplitude when Wave-1 and Wave-2 are exactly in step ... their peaks both happen at the same time and their troughs both happen at the same time.

This means that Wave-1 and Wave-2 have the same frequency, and the phase shift from one wave to the other is zero.

When all of that happens, the amplitude of the resulting wave is the sum of the amplitudes of Wave-1 and Wave-2.  If Wave-1 and Wave-2 have the same amplitude, then the resulting wave will have double that amplitude.

Answer:

60 w

Explanation:

Given :

V= 120V

I=0.5 A

Now,

power can be calculated as :

P=VI

where,

V is voltage

I is current

Now,

P=(120)(0.5)

P=60 W

Therefore, 60w power is delivered to a light

Answer:

2

Explanation:

Answer:

Convex lens

Explanation:

hope this helps

Answer:

convex lens

Explanation:

A converging lens is also called a convex lens because it makes parallel light rays passing through it Bend Inward and meet at a spot just beyond the lens known as the focal point.

Work is done when you lift an object to a certain height. If the force exerted is greater than the weight of the object, input work is greater than the output work. Then the extra energy goes in overcoming the gravitational acceleration and heating up of body etc

Answer:

efficiency of a machine is less than 100% because some part is energy is utilized to overcome some opposing forces like friction which is wasted as heat ,sound energy etc

Explanation:

Answer:

the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB

Explanation:

Given the data in the question;

sound intensity reduced by the factor, m = 305

the sound intensity level experienced by the crew members wearing protective earplugs, L = 79 dB

Now, using the expression of sound intensity level;

L = 10log( [tex]I_0[/tex] )

where  [tex]I_0[/tex] is the intensity at L level

so we substitute

79 = 10log( [tex]I_0[/tex] )

[tex]I_0[/tex] = [tex]10^{7.9[/tex]

Now, expression for actual intensity;

[tex]I[/tex] = m[tex]I_0[/tex]

where [tex]I[/tex] is the actual intensity

so we substitute

[tex]I[/tex] = 305 × [tex]10^{7.9[/tex]

Next, we write the expression of sound intensity level for reduced intensity;

L' = 10log( [tex]I[/tex] )

So we substitute

L' = 10log( 305 × [tex]10^{7.9[/tex] )

L' = 10log( 24227011159.09058 )

L' = 103.8 dB

Therefore, the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB

Explanation:

Since gravitational forces are inversely proportional to the square of their distances, tripling the distance means the reduction of the force by a factor of 9. That means the force experienced by the two objects will be 1/9 smaller than before.

Answer:

p = 6.64 cm

Explanation:

For this exercise we use the equation of the constructor

          [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]

where f is the focal length, p and q are the distance to the object and the image, respectively

They tell us the focal length f = 2.2 cm and that the image as far as it can go is q = 3.29 cm, let's find the position of the object that creates this image

          [tex]\frac{1}{p} = \frac{1}{f} - \frac{1}{q}[/tex]

          1 / p = 1 / 2.2 - 1/3.29

           1 / p = 0.15059

           p = 6.64 cm

therefore the farthest distance from the object is 6.64 c

Answer:

dino :)

Explanation:

Answer:

Explanation:

From the missing image attached below, it is obvious that there no external force. This implies that they cannot change their position by merely just pulling the ropes. As a result, there will be no movement and no net force will exist.

So, if there is no external force;

The center of mass of the two people is:

[tex]X_{cm}= \dfrac{m_1x_1+m_2x_2}{m_1+m_2} \\ \\ X_{cm}= \dfrac{m(-3m)+m(+3m)} {m+m}\\ \\ X_{cm}= \dfrac{0}{2m} \\ \\ X_{cm} =0[/tex]

Thus, In the system, no movement occurs and all forces remain the same.

Answer:

Distancia = 42.5 metros

Explanation:

Dados los siguientes datos;

Velocidad del sonido = 340 m/s

Tiempo = 8 segundos

Para encontrar la distancia desde la que se escuchó el sonido;

Distancia = velocidad/tiempo

Sustituyendo en la fórmula, tenemos;

Distancia = 340/8

Distancia = 42.5 metros

Answer:

Power = 24.41Watts

Explanation:

Find the diagram attached

Power output  = Force * distance/Time

Given

Force = 120lb

Distance = 9inches

Time = 5sec

Since

1lb = 4.4482216153 N

120lb  = 120 * 4.4482216153

120lb = 533.787N

9in to meters

9in = 0.0254*9

9in = 0.2286N

Power = 533.787*0.2286/5

Power = 24.41Watts

Answer:

F = 10.78 N

Hence q₂ will move away from the charge q₁ towards right side.

Explanation:

The force between two charged particles can be found by using Colomb's Law:

[tex]F = \frac{kq_1q_2}{r^2}[/tex]

where,

F = Force = ?

k = Colomb Constant = 8.99 x 10⁹ N.m²/C²

q₁ = charge on first particle = 6 μC = 6 x 10⁻⁶ C

q₂ = charge on second particle = 2 μC = 2 x 10⁻⁶ C

r = distance between particles = 0.1 m

Therefore,

[tex]F = \frac{(8.99\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)(2\ x\ 10^{-6}\ C)}{(0.1\ m)^2}[/tex]

F = 10.78 N

Since both particles have a positive charge. Therefore this force will be the force of repulsion.

Hence q₂ will move away from the charge q₁ towards right side.

Answer:

Explanation:

E2020

Answer:

The rotation rate is 15.3 rad/s.

Explanation:

maximum voltage, V = 120 V

Magnetic field, B = 1.5 T

length, L = 10.2 cm

width, W = 12.8 cm

Number of loops, N = 400

Let the rate of rotation is w.

The maximum voltage is given by

V = N B A w

120 = 400 x 1.5 x 0.102 x 0.128 x w

w = 15.3 rad/s

Answer:

Explanation:

The one above is incorrect, and I know this is late. Even if it doesn't help you I hope it helps people in the future! YES I AM TALKING ABOUT YOU FUTURE PEOPLE!! I know this is the answer because I have taken 5.11 Quiz: Uncrewed Spacecraft in K12. There will only be the questions and correct answers below.

1. Which planetary body was Spirit designed to explore?

Mars.

2. What is the name of the most distant manmade object in space? (Credit: shathaadnan64/lak521)

Voyager 1.

3. Which group was designed to study Saturn? (Credit: Brainly User/snowballandtigoya1xa

Voyager 1, Huygens, and Cassini.

4. Why are scientists interested in exploring Mars?

Possible evidence of life.

5. What do interplanetary space missions study?

Planets in the solar system.

Have an amazing day!!

Answer:

We should not try to park the car because its rest length is greater than the space available.

The car seems to be approximately equal to the friend (L = 3.16 m). Due to this reason he is sure to park.

Explanation:

We should not try to park the car because its rest length is greater than the space available.

The friend is sure about parking because the car appears short in length to him. For this, we will solve Einstein's length contraction formula from theory of relativity:

[tex]L = L_o\sqrt{1-\frac{v^2}{c^2}}[/tex]

where,

L = Relative length observed by friend = ?

L₀ = rest length = 6 m

v = relative speed = 85% of speed of light = 0.85c

Therefore,

[tex]L = (6\ m)\sqrt{1-\frac{(0.85c)^2}{c^2}}[/tex]

L = 3.16 m

Hence, the car seems to be approximately equal to the friend. Due to this reason he is sure to park.

Answer:

100 A.

Explanation:

From the question given above, the following data were obtained:

Electrochemical equivalent (Z) = 0.0012 g/C

Mass (M) = 36 g

Time (t) = 5 mins

Current (I) =?

Next, we shall determine the charge. This can be obtained as follow:

Electrochemical equivalence (Z) = 0.0012 g/C

Mass (M) = 36 g

Charge (Q) =.?

M = ZQ

36 = 0.0012 × Q

Divide both side by 0.0012

Q = 36 / 0.0012

Q = 30000 C

Next, we shall convert 5 mins to s. This can be obtained as follow:

1 min = 60 s

Therefore,

5 mins = 5 × 60

5 mins = 300 s

Finally, we shall determine the current. This can be obtained as shown below:

Charge (Q) = 30000 C

Time (t) = 300 s

Current (I) =?

Q = It

30000 = I × 300

Divide both side by 300

I = 30000 / 300

I = 100 A

Therefore, the current is 100 A.

Answer:

Mater's Mass is the Answer

Answer:

Wavelength = [tex]\lambda_p = 3.986 * 10^{-6}[/tex] m

Explanation:

As we know

Fringe width (w) = [tex]\frac{D*\lambda}{d}[/tex]

where

[tex]\lambda[/tex] is the wavelength

D is distance between source and screen

d is the distance between two slits

[tex]\frac{D}{d} = \frac{y}{\lambda}[/tex]

[tex]\frac{D}{d} = \frac{y_r}{\lambda_r} = \frac{y_p}{\lambda_p}\\\frac{y_r}{\lambda_r} = \frac{y_p}{\lambda_p}\\\lambda_p = \frac{y_p* \lambda_r}{y_r} \\\lambda_p =\frac{6.30 * 10^{-3} * 632.8 * 10^{-9}}{6 *10^{-3}} \\\lambda_p = 3.986 * 10^{-6}[/tex]m

Answer:

Explanation:

The length of the string determines the frequency of the sound waves. Shorter length strings will cause the string to vibrate faster which causes faster frequency and a higher pitch. Longer length strings have the opposite effect, in which frequency is slowed down causing lower pitch. This higher pitch creates a perceived brightness of the sound which can be categorized as being a better sound quality than that of a lower-pitched message. Therefore, we can say that yes, it does affect the sound produced.

Answer:

4210 W

Explanation:

We'll begin by calculating the energy required in lifting the water from the depth. This can be obtained as follow:

Mass (m) = 1200 Kg

Height (h) = 10 m

Acceleration due to gravity (g) = 9.8 m/s²

Energy (E₁) =?

E₁ = mgh

E₁ = 1200 × 9.8 × 10

E₁ = 117600 J

Next, we shall determine the energy required to project the water at 15 m/s. This can be obtained as follow:

Mass (m) = 1200 Kg

Velocity (v) = 15 m/s

Energy (E₂) =?

E₂ = ½mv²

E₂ = ½ × 1200 × 15²

E₂ = 600 × 225

E₂ = 135000 J

Finally, we shall determine the power of the motor. This can be obtained as follow:

Total energy (E) = E₁ + E₂

= 117600 + 135000

= 252600 J

Time (t) = 1 min = 60 s

Power (P) =?

P = E/t

P = 252600 / 60

P = 4210 W

Therefore, the power of the motor is 4210 W.