I don’t know what to put as the answer for this question

The maximum possible cost in dollars is $226.76 (approx).

Standard deviation = $88

Let X be the cost of the automobile repair, then X ~ N(367, 88^2) (normal distribution)

Now, we need to find the following probabilities:

(a) P(X > 480)(b) P(X < 240)(c) P(240 < X < 480)(d)

Find X such that P(X < X1) = 0.05, where X1 is the lower 5% point of X(a) P(X > 480)

We need to find P(X > 480)P(X > 480) = P(Z > (480 - 367)/88) [Standardizing the random variable X]P(X > 480) = P(Z > 1.2955)

Using the standard normal table, the value of P(Z > 1.2955) = 0.0983 (approx)

Hence, the required probability is 0.0983 (approx)(b) P(X < 240)

We need to find P(X < 240)P(X < 240) = P(Z < (240 - 367)/88) [Standardizing the random variable X]P(X < 240) = P(Z < -1.4432)

Using the standard normal table, the value of P(Z < -1.4432) = 0.0749 (approx)

Hence, the required probability is 0.0749 (approx)(c) P(240 < X < 480)

We need to find P(240 < X < 480)P(240 < X < 480) = P(Z < (480 - 367)/88) - P(Z < (240 - 367)/88) [Standardizing the random variable X]P(240 < X < 480) = P(Z < 1.2955) - P(Z < -1.4432)

Using the standard normal table, the value of P(Z < 1.2955) = 0.9017 (approx)and the value of P(Z < -1.4432) = 0.0749 (approx)

Hence, the required probability is 0.9017 - 0.0749 = 0.8268 (approx)(d)

Find the maximum possible cost in dollars, if the cost for your car repair is in the lower 5% of automobile repair charges.

This is nothing but finding the lower 5% point of X.We need to find X1 such that P(X < X1) = 0.05.P(X < X1) = P(Z < (X1 - 367)/88) [Standardizing the random variable X]0.05 = P(Z < (X1 - 367)/88)

Using the standard normal table, the value of Z such that P(Z < Z0) = 0.05 is -1.645 (approx)

Hence, we get,-1.645 = (X1 - 367)/88

Solving for X1, we get: X1 = 88*(-1.645) + 367 = $226.76 (approx)

Therefore, the maximum possible cost in dollars is $226.76 (approx).

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During an experiment of acceleration changes, the value that must stay constant during these trials is d. Mass

Inertia, a basic characteristic of all matter, may be measured quantitatively using mass. When a force is applied, an item effectively provides resistance to changes in velocity or position. The change brought about by an applied force is less the more mass an item has. According to Newton's second law of motion an object's acceleration is inversely proportional to its mass and directly proportional to the net force that has been applied to it. It may be expressed mathematically as F = ma.

The goal of this experiment is to see how variations in force impact acceleration. It is crucial to maintain the mass constant throughout the trials in order to isolate the impact of force on acceleration. Any observable variations in acceleration may be entirely attributable to variations in the applied force by maintaining the mass constant.

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In the context of analyzing the relationship between studying time and test grades, the domain of the scatterplot would be the number of minutes the students studied (option D).

The domain refers to the set of possible inputs or variables in a given context. In this case, the scatterplot is being created based on the relationship between the time students spent studying and their corresponding test grades. Therefore, the domain in this context would be the number of minutes the students studied (option D).

The domain represents the independent variable, which is the variable that is controlled or manipulated in the analysis. In this scenario, the math teacher wants to analyze the relationship between studying time and test grades, so the number of minutes studied would be the independent variable. The teacher surveys the students to collect data on the time spent studying, and this variable becomes the domain of the scatterplot.

The range, on the other hand, represents the dependent variable, which is the variable that is measured or observed as an outcome or response. In this case, the dependent variable would be the students' test grades. The scatterplot will show how the test grades correspond to the amount of time students studied.

To summarize, in the context of analyzing the relationship between studying time and test grades, the domain of the scatterplot would be the number of minutes the students studied (option D).

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a) The volume of the solid E in rectangular coordinate system is given by: [tex]$$\iiint_{E}[/tex] dx dy dz = [tex]\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} \int_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dx dy dz$$[/tex]

b) The volume of the solid E in cylindrical coordinate system is given by:  [tex]$$\iiint_{E} \rho d\rho d\theta dz = \int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \int_{0}^{\sqrt{4 - z^2}} \rho d\rho d\theta dz$$[/tex]

c) The volume of the solid E is 11π/3.

a) The solid E that lies between the cone z² = x² + y² and the sphere x² + y² + (z + 2)² = 2.

Let the limits of x, y, z be X, Y, Z respectively.

The limits of X:

From the equation, z² = x² + y²

Z² = X² + Y²

X² = Z² - Y²

Let Z = 0, then X² = - Y² which is impossible. Therefore, Y can take any value such that Y < Z.

The limits of Y:

From the equation, z² = x² + y²

Z² = X² + Y²

Y² = Z² - X²

Let Z = 0, then Y² = - X² which is impossible. Therefore, X can take any value such that X < Z.

Limits of Z:

From the equation x² + y² + (z + 2)² = 2z² + 4z + 8 = 2(Z + 1)² + 6

The limits of z are Z < 2 and Z > - 2.

Volume in rectangular coordinate system:

[tex]$$\iiint_{E}[/tex] dx dy dz = [tex]\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} \int_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dx dy dz$$[/tex]

b) Volume of solid E in cylindrical coordinate system

Let the limits of ρ, θ, z be R, Θ, Z respectively.

The limits of R:

From the equation, z² = ρ² cos²θ + ρ² sin²θ

Z² = ρ²

Rho² = Z²/ cos²θ + sin²θ

Rho = Z/ cosθ

Let Z = 0, then Rho = 0. Therefore, R can take any value such that 0 ≤ R < 2.

Limits of Θ:

From the equation, z² = ρ² cos²θ + ρ² sin²θ

Z² = ρ² sin²θ

Theta² = tan⁻²(Z²/ ρ²)

Let Z = 0, then Θ = 0. Therefore, Θ can take any value such that 0 ≤ Θ ≤ π/2.

Limits of Z:

From the equation x² + y² + (z + 2)² = 2z² + 4z + 8 = 2(Z + 1)² + 6

The limits of Z are -2 ≤ Z < 2.

Volume in cylindrical coordinate system:

[tex]$$\iiint_{E} \rho d\rho d\theta dz = \int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \int_{0}^{\sqrt{4 - z^2}} \rho d\rho d\theta dz$$[/tex]

c) Evaluation of the volume of solid E:

Using rectangular coordinate system, the volume of solid E is

[tex]$$\iiint_{E} dx dy dz[/tex] = [tex]\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} \int_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dx dy dz$$$$[/tex]

[tex]=\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} [x]_{-\sqrt{z^2 - y^2}}^{\sqrt{z^2 - y^2}} dy dz$$$$=\int_{-2}^{2} \int_{0}^{\sqrt{z^2}} 2\sqrt{z^2 - y^2} dy dz$$$$=\int_{-2}^{2} \left[-\frac{1}{2}(z^2 - y^2)^{3/2}\right]_{y=0}^{y=\sqrt{z^2}} dz$$$$=\int_{-2}^{2} \frac{1}{2}z^3 dz = 0$$[/tex]

Therefore, the volume of solid E using rectangular coordinate system is 0.

Using cylindrical coordinate system, the volume of solid E is

[tex]$$\iiint_{E} \rho d\rho d\theta dz = \int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \int_{0}^{\sqrt{4 - z^2}} \rho d\rho d\theta dz$$$$=\int_{0}^{2} \int_{0}^{\frac{\pi}{2}} \left[\frac{\rho^2}{2}\right]_{0}^{\sqrt{4 - z^2}} d\theta dz$$$$=\int_{0}^{2} \int_{0}^{\frac{\pi}{2}} 2 - \frac{z^2}{2} d\theta dz$$$$=\int_{0}^{2} \left[2\theta - \frac{\theta z^2}{2}\right]_{\theta = 0}^{\theta = \frac{\pi}{2}} dz$$$$=\int_{0}^{2} \pi - \frac{\pi z^2}{4} dz = \frac{11\pi}{3}$$[/tex]

Therefore, the volume of solid E using cylindrical coordinate system is 11π/3.

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Answer:

8/7

Step-by-step explanation:

12*2=24.

7*3=21

24/21 is divisible by 3

=8/7

Answer:

C is the answer also can I have brian list

Step-by-step explanation:

Answer:

Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored. Equation at the end of step 2 : 2n2 - 7n - 5 = 0. Step 3 : Parabola ...

Step-by-step explanation:

Answer: B)

Step-by-step explanation:

By checking which graph is satisfied, we choose points that the function has pass through.

First, we know that y = mx + b, where m is the slope, how the line change; and b is the y-intercept. In this equation, the slope is 24 which the line is increased. So we can eliminate the choice D, the line in D decreased.

Then we find where the first point and second point this graph will be.

When x = 0, y = 24x = 24(0) = 0, (0,24)

When x = 1, y = 24x = 24(1) = 24, (1,24)

1 package can have 24 cookies, only B have 24 cookies in 1 package.

Answer:

Therefore, after 12 years the car will value $6,765.35.

Step-by-step explanation:

The share of money Alan receives is $850. Therefore, option C is correct answer.

Given that, the total amount is $1190 and the ratio Alan: Beth = 5:2.

We need to find the how much money Alan gets.

The quantitative relation between two amounts shows the number of times one value contains or is contained within the other.

Now, 5+2=7

Money Alan receives=5/7×1190

=$850

The share of money Alan receives is $850. Therefore, option C is correct answer.

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Answer:

12

Step-by-step explanation:

Write down multiples of each number:

3, 6, 9, 12 . . .

4, 8, 12 . . .

6, 12 . . .

The first one they all have is the LCM.

Answer:

12

Step-by-step explanation:

Think of it this way. Simplifying 3, 4 and 6 into their simplest factors:

[tex]3=3[/tex]

[tex]4=2*2[/tex]

[tex]6=3*2[/tex]

6 is a multiple of both 3 and 2, which are both represented by the factors of 3 and 4. Thus, as it is doubled in these, it is not necessary to find the lowest common multiple of the numbers.

Now the LCM can be multiplied with the factors of the remaining numbers:

LCM[tex]=3*2*2[/tex]

Notice the first two numbers equal 6, the second and third equal 4, and the first only equals 3. This means the three numbers are represented in the LCM.

[tex]3*2*2=24[/tex]

And that is the LCM, so we are done. QED

Answer:

D 19,905

Step-by-step explanation:

19,905.22×25%=4976.31

19905.22-4976.31=14,928.91

14928.91×8%=1194.31

14928.91-1194.31=13734.6

Answer:

4[tex]\sqrt{3}[/tex]

Step-by-step explanation:

Using the rule of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex] , then

[tex]\sqrt{48}[/tex]

= [tex]\sqrt{16(3)}[/tex]

= [tex]\sqrt{16}[/tex] × [tex]\sqrt{3}[/tex]

= 4[tex]\sqrt{3}[/tex]

The solution to the differential equation 5y'' - 2y' = 2x + 5 - e^(-2x) using the method of undetermined coefficients is given by y = C1 + C2e^(2x) - (5/2)x + B, where C1, C2, and B are constants determined by the initial or boundary conditions.

To solve the differential equation 5y'' - 2y' = 2x + 5 - e^(-2x) using the method of undetermined coefficients, we assume a particular solution of the form:

y_p = Ax + B + Ce^(-2x)

where A, B, and C are undetermined coefficients to be determined.

Taking the derivatives:

y_p' = A - 2Ce^(-2x)

y_p'' = 4Ce^(-2x)

Substituting these derivatives into the original differential equation, we have:

5(4Ce^(-2x)) - 2(A - 2Ce^(-2x)) = 2x + 5 - e^(-2x)

Simplifying the equation:

20Ce^(-2x) - 2A + 4Ce^(-2x) = 2x + 5 - e^(-2x)

(24C)e^(-2x) - 2A = 2x + 5 - e^(-2x)

For the equation to hold for all x, the coefficients on both sides of the equation must be equal.

Matching the coefficients:

24C = 0 -> C = 0

-2A = 5 -> A = -5/2

Therefore, the particular solution is:

y_p = (-5/2)x + B

To find the value of B, we substitute the particular solution back into the original differential equation:

5(-5/2) - 2(0) = 2x + 5 - e^(-2x)

-25/2 = 2x + 5 - e^(-2x)

Solving for x and e^(-2x) in terms of B:

2x = -25/2 - 5 + e^(-2x)

2x = -35/2 + e^(-2x)

As the left side is a linear function of x and the right side is a constant plus an exponential function, there is no value of x that satisfies this equation for all x. Hence, the equation is inconsistent, and there is no particular solution in the form y_p = Ax + B.

Therefore, the solution to the given differential equation using the method of undetermined coefficients is the complementary function (homogeneous solution) plus the particular solution, which is:

y = y_c + y_p = C1 + C2e^(2x) + (-5/2)x + B

where C1 and C2 are constants determined by the initial or boundary conditions, and B is an arbitrary constant.

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Answer:

2cm

Step-by-step explanation:

Given data

Capacity/volume of liquid held=  6π cm^3

Height= 6cm

Required

The diameter d of the tube

let us apply the expression for the volume of cylinder

V=πr^2h

6π=πr^2*6

6=r^2*6

r^2= 6/6

r^2=1

r= √1

r=1cm

Hence the diameter d = 2r= 2*1= 2cm

Answer:

2 km < 4,000 m

Step-by-step explanation:

2 km = 2,000 m

Therefore, 2,000 m is less than 4,000 m.

Answer:

Your answer would be D. I know this is kind of late, but maybe other people that come up here could get some help

Step-by-step explanation:

Answer:

x=-6, y=-7

Step-by-step explanation:

Answer:

x = -6, y = -7

Step-by-step explanation:

One way to solve for x and y is using the substitution method

(1) 3x + 4y = -46

(2) 6x + y = -43

Solve for y in equation (2)

6x + y =-43, so y = -43 - 6x

Substitute y = -43 -6x into equation (1)

3x + 4(-43 -6x) = -46

3x -172 -24x = -46

-21x -172 = -46

-21x = 126

x = -6

Find y by substituting x = -6 into equation (2)

6(-6) + y = -43

-36 + y = -43

y = -7

Answer:

A is the answer

Step-by-step explanation:

All you have to do is follow the order pair such as 2, 100 and see if that is a correct pair.

Hope that helps

Answer: A. (2, 100)

Step-by-step explanation:

Answer: Should be 7

Step-by-step explanation:

14/2 is 7

Answer:

n=2

Step-by-step explanation:

[tex]\frac{3.3.3.3.3.3}{3.3.3.3} = 3^{n}[/tex]

[tex]3^{2}[/tex]= [tex]3^{n}[/tex]

n=2

Answer:

[tex]3^1[/tex]

Step-by-step explanation:

[tex]\frac{3*3*3*3*3}{3*3*3*3} =3^1[/tex]

Answer:

Step-by-step explanation:

Based on the sample data, we can construct a 99% confidence interval estimate for the percentage of girls born as approximately 85.1% to 94.9%.

To construct a confidence interval estimate for the percentage of girls born, we can use the formula for estimating a proportion.

First, we calculate the sample proportion, which is the number of successes (girls) divided by the total number of trials (babies born):

Sample proportion (p-hat) = Number of girls / Total number of babies born

= 288 / 320

= 0.9

Next, we can construct the confidence interval using the sample proportion. Since we want a 99% confidence interval, we need to find the critical value corresponding to that level of confidence. For a two-tailed test, the critical value is obtained from the standard normal distribution (Z-distribution).

Using a Z-table or calculator, the critical value for a 99% confidence level is approximately 2.576.

The margin of error (E) can be calculated as:

Margin of error (E) = Critical value * Standard error

The standard error (SE) for estimating a proportion is given by:

Standard error (SE) = [tex]\sqrt {(p-hat * (1 - p-hat)) / n}[/tex]

where p-hat is the sample proportion and n is the sample size.

Using these values, we can calculate the margin of error:

Standard error (SE) = [tex]\sqrt {(0.9 * (1 - 0.9)) / 320}[/tex]

≈ 0.019

Margin of error (E) = 2.576 * 0.019

≈ 0.049

Finally, we can construct the confidence interval:

Confidence interval = Sample proportion ± Margin of error

= 0.9 ± 0.049

≈ (0.851, 0.949)

Therefore, based on the sample data, we can construct a 99% confidence interval estimate for the percentage of girls born as approximately 85.1% to 94.9%.

Since the interval includes the value of 0.5 (50%), which represents an equal chance of having a girl or a boy, it suggests that the method used in the clinical trial does not significantly increase the probability of conceiving a girl.

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Answer:

the answer is 14 I pinkie promise!

...............................................

The variance of the sampling distribution for the difference of the two means is 0.0147142857.

The correct option is D. 0.051.

The variance of the sampling distribution for the difference of two means of sample populations can be calculated using the formula given below:

[tex]\Large\frac{{{\sigma }_{1}}^{2}}{n_{1}}+\frac{{{\sigma }_{2}}^{2}}{n_{2}}[/tex]

Where,[tex]{{\sigma }_{1}}$ and ${{\sigma }_{2}}[/tex] are the standard deviations of the two populations respectively, and [tex]{{n}_{1}} and ${{n}_{2}}[/tex] are the sample sizes of the first and second populations respectively.

Substituting the given values, we get

[tex]\Large\frac{0.9^2}{25}+\frac{0.8^2}{35}=0.009+0.0057142857[/tex]

=0.0147142857

Therefore, the variance of the sampling distribution for the difference of the two means is 0.0147142857.

Sampling distribution approaches normal distribution:

True. Regardless of the shape of the population, the sampling distribution of the mean approaches a normal distribution as the sample size increases.

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