I need help with math help a sis out

Answer:

4/5

Step-by-step explanation:

Answer:

65 degrees

Step-by-step explanation:

90 - 25 = 65

Answer and Step-by-step explanation:

To find x, we need to subtract all of the other angles from 180.

180 - 25 = 155

155 - 90 (that's the right angle) = The answer is 65.

The other way to find x is be subtracting 25 from 90, since 25 and x, when added together, forms a right angle, which is 90.

#teamtrees #PAW (Plant And Water)

Answer:

y=−25x+300

Step-by-step explanation:

have a good day/night

may i please have a branlliest

Answer:

106°

Step-by-step explanation:

An isosceles triangle has 2 sides of the same length. All triangles add up to 180°

37 + 37 + x = 180

74 + x = 180

x = 106

Answer:

120 and 144

120÷24=5

144÷24=6

Answer:

- 10 degrees Fahrenheit at 9:00 PM

Step-by-step explanation:

35 - 45 = -10

Answer:

A. 36

Step-by-step explanation:

We are given a total of 176 interviewed by Oliver and a total of 140 interviewed by Jenny. To find how many more 10th graders than 9th graders were interviewed, subtract the totals given

176 - 140 = 36

This is how we came to the answer:

We are given 70% of the 10th-grade and 30% of the 9th-grade with a total of 176 for Oliver.

While we're given 75% of the 9th-grade class and 25% of the 10th-grade with a total of 140 interviewed by Jenny

Oliver's Interviewees

10-graders

Firstly, let's find what the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

70% of 176 =

Cross multiply

123.2 were 10-graders interviewed by Oliver

9th-graders

Now, to find the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

30% of 176 =

Cross multiply

52.8 were 9th-graders interviewed by Oliver

Jenny's Interviewees

9th-graders

Firstly, let's find what the number of 9th-graders was interviewed by Jenney; find the percentage of the 9th-graders by the total;

75% of 140 =

Cross multiply

105 students were 9th-graders interviewed by Jenney.

10th-graders

Now, to find the number of 10th-graders was interviewed by Jenney; find the percentage of the 10th-graders by the total;

25% of 140 =  

Cross multiply  

35 students were 10th-graders interviewed by Jenney.  

Total calculation

Use the results and sum them up by 9th-grade plus 9th-grade and 10th-grade plus 10-grade. Then subtract the amount gotten from 9th-grade away from the amount gotten from 10th-grade;

Oliver's 9th-grade = 52.8

Jenny's 9th-grade = 105

105 + 52.8 = 157.8

Oliver's 10th-grade = 123.2

Jenny's 10th-grade = 35

123.2 + 35 = 158.2

Total calculation: 158. 2 - 157.8 = 0.4

Therefore, there are 36 more 10th than 9th.

For more information, visit: https://brainly.com/question/23490909

Answer:

A. 320 cubic centimeters

Step-by-step explanation:

First, you want to multiply 4 by 4 to get 16. Then what you want to be is multiply 16 by 20 and you will get 320 cubic centimeters.

Answer: y=6

Step-by-step explanation:

Data: y=3 and x=12

y=? and x=18

12/3=4 and 18/3=6

y=6

I hope this helps

Answer:

x = 0.6

Step-by-step explanation:

We use tangent because the given numbers are opposite and adjacent from x

So, tangent (x) = opposite/adjacent

tan(x) = 8.78/12

[tex]tan^{-1}(\frac{8.78}{12}) = x[/tex]

x = 0.631664

Round to nearest tenth:

x ~ 0.6

Answer:

75.4yd

Step-by-step explanation:

Find the diagram attached

Perimeter of the figure = perimeter of the 4 semicircles

Perimeter of a semicircle = πd/2

d is the diameter of the semicircle = 12yd

Perimeter of a semicircle = 3.14(12)/2

Perimeter of a semicircle = 37.68/2

Perimeter of a semicircle = 18.94yd

Perimeter of the 4 semicircles = 4 * 18.94

Perimeter of the 4 semicircles = 75.36yd

Hence the perimeter of the swimming pool to nearest tenth is 75.4yd

Answer:

Its an Obtuse angles

Step-by-step explanation:

x+79=2x-37

(x+79)+(-79)=(2x-37)+(-79)

x+79-79=(2x-37)-79

x=2x-37-79

x=116

An obtuse angle has a measurement greater than 90 degrees but less than 180 degrees.

Answer:

The greatest common factor is 4

Step-by-step explanation:

1)     12x3+4x2-8x

2)    (12x3)+(4x2)-8x

3)     36+(4x2)-8x

4)     36+8-8x

5)     44-8x

6)     4(11-2x)

Answer:

[tex]y=6.391[/tex]

Step-by-step explanation:

Given

[tex]y=16.279 - 0.206x[/tex]

Required

Find y when [tex]x = 48[/tex]

Substitute [tex]48[/tex] for [tex]x[/tex] in [tex]y=16.279 - 0.206x[/tex]

[tex]y=16.279 - 0.206 * 48[/tex]

Multiply

[tex]y=16.279 - 9.888[/tex]

Subtract

[tex]y=6.391[/tex]

Answer:

x=-6, y=1

Step-by-step explanation:

Let's solve your system by substitution.

y=x+7;−2x−11=y

Step: Solve y=x+7 for y:

y=x+7

Step: Substitute x+7 for y in −2x−11=y:

−2x−11=y

−2x−11=x+7

−2x−11+−x=x+7+−x(Add -x to both sides)

−3x−11=7

−3x−11+11=7+11(Add 11 to both sides)

−3x=18

−3x/ −3 = 18/ −3  (Divide both sides by -3)

x=−6

Step: Substitute−6 for x in y=x+7:

y=x+7

y=−6+7

y=1  (Simplify both sides of the equation)

Answer:

x=−6 and y=1

Answer:

[tex]x = \frac{50 + 92}{2} = 71[/tex]

Step-by-step explanation:

question 1

[tex]6 {x}^{4} - 36 {x}^{3} \\ 6 {x}^{3} (x - 6)[/tex]

question 2

[tex]64 {x}^{2} + 48x + 9 \\ {(8x + 3)}^{2} [/tex]

Answer:

Solution given:

cotangent x=cot x=-1

now

x=cot -¹(-1)

x=180-45°

x=135°

So

ans is d. 135 degrees.

as cot is negative in 2nd quadrant.

Answer:

BOGO ko sa math

Step-by-step explanation:

hahaha sorryyyyy

Answer:

I belive the answer for the first box is 9.67

I belive the answer for the second box is 71.

I hope I helped

Answer:

I would say it's d (sorry if im wrong)

Answer:

.....Your answer is D

...

.

0.59 h + 0.98 b = 1041.37 - 79.37

h + b = 1300

Answer: 95%

Step-by-step explanation:

Answer:

x-intercept

Step-by-step explanation:

Answer:

56 rabbits

Step-by-step explanation:

Given that  t represents the time, and weeks, and P(t) is the population of the rabbits and that the population doubles every 6 weeks.

In 126 days, there are

= 126/7

= 18 weeks

It means that the rabbit population will double

= 18/6 times

= 3 times

Since there are currently 7 rabbits at the end of 6 week,

P(6) = 7 * 2

= 14

At the end of 12 weeks

P(12) = 14 * 2 = 28

At the end of 18 weeks

P(18) = 28 * 2 = 56

Hence there will be 56 rabbits at the end of 126 days

Answer:

Vector (ordered pair - rectangular form)

[tex]\vec F = (27.189,12.679)\,[lbf][/tex]

Vector (ordered pair - polar form)

[tex]\vec F = (30\,lbf, 25^{\circ})[/tex]

Sum of vectorial components (linear combination)

[tex]\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N][/tex]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ([tex]\vec F[/tex]), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

[tex]\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)[/tex] (1)

Vector (ordered pair - polar form)

[tex]\vec F = \left(\|\vec F\|, \theta\right)[/tex]

Sum of vectorial components (linear combination)

[tex]\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}[/tex] (2)

Where:

[tex]\|\vec F\|[/tex] - Norm of the vector force, in newtons.

[tex]\theta[/tex] - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

[tex]\hat{i}[/tex], [tex]\hat{j}[/tex] - Orthogonal axes, no unit.

If we know that [tex]\|\vec F\| = 30\,lbf[/tex] and [tex]\theta = 25^{\circ}[/tex], then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

[tex]\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf][/tex]

[tex]\vec F = (27.189,12.679)\,[lbf][/tex]

Vector (ordered pair - polar form)

[tex]\vec F = (30\,lbf, 25^{\circ})[/tex]

Sum of vectorial components (linear combination)

[tex]\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N][/tex]

[tex]\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N][/tex]