I really need help lol so please do me a favor

I Really Need Help Lol So Please Do Me A Favor

Answers

Answer 1

Answer:

the answer should be 5/8.

Step-by-step explanation:

look at number of x.

Answer 2

Answer:

3/4

Step-by-step explanation:

When you simplify 6/8 (you get this by subtracting 1/8 from 7/8) , you get 3/4.


Related Questions

11/3 as a decimal pls help

Answers

Answer:

3.7 rounded

Step-by-step explanation:

Just divide 11/3

write an equation with a slope of -1/2 in each form.
point-slope form
slope-intercept form.

Answers

For the case of a line through

(

2

,

7

)

and

(

1

,

4

)

we have

slope

m

=

Δ

y

Δ

x

=

4

7

1

2

=

11

1

=

11

Using the point

(

2

,

7

)

we can write the equation of the line in point slope form as:

y

7

=

m

(

x

2

)

where the slope

m

=

11

.

That is:

y

7

=

11

(

x

2

)

To get point intercept form, first expand the right hand side so...

y

7

=

11

x

(

11

2

)

=

11

x

22

Then add

7

to both sides to get:

y

=

11

x

15

=

11

x

+

(

15

)

This is point intercept (

y

=

m

x

+

c

) form with slope

m

=

11

and intercept

c

=

15

.

What is the average rate of change of h over the interval −6 ≤ x ≤ 3? Give an exact number.

Answers

The answer will be to the pier if

Answer:

-1/9

Step-by-step explanation:

Help If you know the answer plz!

Answers

Answer:

2

Step-by-step explanation:

Answer:

2t

Step-by-step explanation:

3t-t is the same as 3-1, so it equals 2t

If the interest of a sum at 7.5% p.a in 4 years is Rs. 1050, find the sum​

Answers

~Refer to the attachment for the solution.

[tex] \to \bf { Sum = 3500 } [/tex]

Which of the following inequalities are true

Answers

Answer: The answer is E: |-4|<|-7| and C: |-7|>|4|

Find the measure of angle C

Answers

Answer:

ajnasnnanananandbabbabbansbansbz svabsvsb

Stanley attempted to simplify the expression below.

−4●(2.5x−1.25)−3x

His work, step by step, is shown below.

Step 1: −4●{(2.5x+(−1.25)}−3x

Step 2:−10x+(−5)−3x

Step 3:−10x−3x+(−5)

Step 4: −13x−5

In which step did he make his first error simplifying the expression?

Answers

Brainlessly please yes no please maybe so

Expand and combine like terms.
(4m^5) – 5m^6) (4m^5 + 5m^6) =

Answers

Answer:

[tex]16m^{10} -25m^{12}[/tex]

Step-by-step explanation:

hope this helps :)

The expand and combination like terms (4m^5) – 5m^6) (4m^5 + 5m^6) is -9m^12 + (16)m^10.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

A mathematical equation is a statement with two equal sides and an equal sign in between. An equation is, for instance, 4 + 6 = 10. Both 4 + 6 and 10 can be seen on the left and right sides of the equal sign, respectively.

We are given that;

The equation=(4m^5) – 5m^6) (4m^5 + 5m^6)

Now,

To expand the expression, we need to multiply each term inside the first parentheses by each term inside the second parentheses. This gives us:

(4m^5 - 5m^6) (4m^5 + 5m^6) = 4m^5 * 4m^5 + 4m^5 * 5m^6 - 5m^6 * 4m^5 - 5m^6 * 5m^6

To simplify the expression, we need to use the exponent rule that a^b * a^c = a^(b + c) and combine the terms that have the same base and exponent. This gives us:

4m^5 * 4m^5 + 4m^5 * 5m^6 - 5m^6 * 4m^5 - 5m^6 * 5m^6 = 16m^(5 + 5) + 20m^(5 + 6) - 20m^(6 + 5) - 25m^(6 + 6)

To further simplify the expression, we need to add the exponents and simplify the coefficients. This gives us:

16m^(5 + 5) + 20m^(5 + 6) - 20m^(6 + 5) - 25m^(6 + 6) = 16m^10 + 20m^11 - 20m^11 - 25m^12

To combine like terms, we need to add or subtract the coefficients of the terms that have the same base and exponent. This gives us:

16m^10 + 20m^11 - 20m^11 - 25m^12 = (16 - 25)m^12 + (20 - 20)m^11 + (16)m^10

= -9m^12 + (0)m^11 + (16)m^10

= -9m^12 + (16)m^10

Therefore, the equation will be equal to -9m^12 + (16)m^10.

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Classify this expression

Answers

Answer:

8.

[tex]8. - 1. - 44 [/tex]

9

Simplify.
Rewrite the expression in the form z”. Z5 • Z6

Answers

Answer:

Simplify.

Rewrite the expression in the form z”. Z5 • Z6Simplify.

Rewrite the expression in the form z”. Z5 • Z6

Answer:

Simplify.

Rewrite the expression in the form z”. Z5 • Z6Simplify.

Rewrite the expression in the form z”. Z5 • Z6

The diagram shows a campground in the shape of a right triangle. You walk along a path from the camp office
at point c to your campsite at point D on a path that bisects the right angle C. Determine how far you are from
the picnic area at Point A to the nearest tenth of a meter.

Answers

The diagrams is 18 ethicbsudndosnskdkd

Name the side that’s opposite to angle A. (Geometry)

1.) AB
2.) AC
3.) BC

Answers

Answer:

The answer gonna be A and C because their both is the same length

Answer:

BC

Step-by-step explanation:

The side opposite the right angle is called the hypotenuse. It is the largest side right angled triangle.If you stand at A in the triangle ABC, the side BC is opposite to you and the side BC is next to you. We therefore say that BC is the opposite side to angle A and AB is the adjacent side ti angle A.

What is the quotient of 1.728 x 109 and 4.8 x 106 expressed in scientific
notation?

Answers

Answer:

3.7018867924 × [tex]10^{-1}[/tex]

Step-by-step explanation:

First you want to find what these two numbers are, then you divide, then you put that answer in scientific notation.

1.728(109) = 188.352

4.8(106) = 508.80

Now we divide :

188.352 ÷ 508.80 = 0.37018867924

That's a crazy decimal, but luckily because of scientific notation we can make it look a lot simpler.

0.37018867924 =  3.7018867924 × [tex]10^{-1}[/tex]

This should be right. Please comment if you are confused and want more detail.

What is the quotient of [tex]1.728*10^9 and, 4.8*10^6[/tex] expressed in scientific notation?

[tex]\frac{1.728*10^9}{4.8*10^6}[/tex]  Divide

[tex]\frac{1.728}{4.8} * \frac{10^9}{10^6}[/tex] Divide numbers and 10's separately.

[tex]0.36*10^3[/tex] Subtract exponents.

[tex](3.6*10^-^1 )*10^3[/tex] Rewrite as a number bigger than 1

[tex]3.6*(10^-^1*10^3)[/tex] Associate

       The answer is

[tex]3.6*10^2[/tex] Add exponents

The Box-and-Whisker Plot represents the ages of 40 people who responded to a telephone survey.

Which statement is true about this data set?

A. About 50% of the respondents were at or between 40 and 67.5 years old.
B. The range of the data is 84 years.
C. The outlier is 28 years.
D. The mean is 51 years.

Answers

Answer:

'A' is true; theoretically, 50% of the data items reside between the first and third quartiles (40 and 67.5)

Step-by-step explanation:

Range is 84-28 which is 56

Median is 51

1.5 x Interquartile Range (IQR) = 1.5(67.5-40) which equals 41.25

Q1 is 40

Q1 - IQR = -1.25

Low outliers are below -1.25 - 41.25; there are not data items below -42

Answer:

'A' is true; theoretically, 50% of the data items reside between the first and third quartiles (40 and 67.5)

Step-by-step explanation:

Range is 84-28 which is 56

Median is 51

1.5 x Interquartile Range (IQR) = 1.5(67.5-40) which equals 41.25

Q1 is 40

Q1 - IQR = -1.25

Low outliers are below -1.25 - 41.25; there are not data items below -42

You take a bus from your neighborhood to your school. The express bus arrives at your neighborhood at a random time between 7:30 and 7:36 a.m. The local bus arrives at your neighborhood at a random time between 7:30 and 7:40 a.m. You arrive at the bus stop at 7:33 a.m. Find the probability that you missed both the express bus and the local bus. Express your answer as a fraction in simplest form.

Answers

Answer:

[tex]\frac{3}{20}[/tex] probability that you missed both the express bus and the local bus.

Step-by-step explanation:

Uniform distribution:

An uniform distribution has two bounds, a and b.

The probability of getting a value lower than x is:

[tex]P(X < x) = \frac{x - a}{x - b}[/tex]

The express bus arrives at your neighborhood at a random time between 7:30 and 7:36 a.m.

6 minutes, so [tex]a = 0, b = 6[/tex]

You arrive at 7:33, so if x < 3, you lose the express bus:

[tex]P_E = P(X < 3) = \frac{3 - 0}{6 - 0} = \frac{3}{6} = \frac{1}{2}[/tex]

The local bus arrives at your neighborhood at a random time between 7:30 and 7:40 a.m.

10 minutes, so [tex]a = 0, b = 10[/tex]

[tex]P_B = P(X < 3) = \frac{3 - 0}{10 - 0} = \frac{3}{10}[/tex]

Find the probability that you missed both the express bus and the local bus.

[tex]p = P_E*P_B = \frac{1}{2}*\frac{3}{10} = \frac{3}{20}[/tex]

[tex]\frac{3}{20}[/tex] probability that you missed both the express bus and the local bus.

The probability that you missed both the express bus and the local bus is 3/20

The individual probability of a uniform distribution is calculated as:

[tex]P(X < x) = \frac{x - a}{b - a}[/tex]

For the express bus

At 7:30 am, a = 0

At 7:36 am, b = 6

You arrived at 7:33 am; this means that:

x = 3

For you to miss the express bus, it means that the express bus left before 7:33 am.

i.e. x < 3

So, the probability that you miss the express bus is:

[tex]P(X < 3) = \frac{3 - 0}{6 - 0}[/tex]

[tex]P(X < 3) = \frac{3}{6}[/tex]

[tex]P(X_E < 3) = \frac{1}{2}[/tex]

For the local bus

At 7:30 am, a = 0

At 7:40 am, b = 10

You arrived at 7:33 am; this means that:

x = 3

For you to miss the local bus, it means that the local bus left before 7:33 am.

i.e. x < 3

So, the probability that you miss the local bus is:

[tex]P(X < 3) = \frac{3 - 0}{10 - 0}[/tex]

[tex]P(X_L < 3) = \frac{3}{10}[/tex]

So, the probability that you miss both bus is:

[tex]P(Both) = P(X_E < 3) * P(X_L < 3)[/tex]

This gives

[tex]P(Both) = \frac 12 * \frac 3{10}[/tex]

[tex]P(Both) = \frac 3{20}[/tex]

Hence, the probability that you missed both the express bus and the local bus is 3/20

Read more about probability at:

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3(2^2x+3)-5(2^x+2)-156=0

Answers

Answer: [tex]x=3.0206[/tex]

Step-by-step explanation:

Given

[tex]3(2^{2x}+3)-5(2^x+2)-156=0[/tex]

Replace [tex]2^x[/tex] by [tex]y[/tex]

We can write

[tex]\Rightarrow 3(y^2+3)-5(y+2)-156=0\\\Rightarrow 3y^2+9-5y-10-156=0\\\Rightarrow 3y^2-5y-157=0\\\\\Rightarrow y=\dfrac{5\pm \sqrt{25-4(3)(-157)}}{2\times 3}\\\\\Rightarrow y=\dfrac{5+43.69}{6}\\\\\Rightarrow y=8.115\\\Rightarrow 2^x=8.115\\\therefore \quad x=3.0206[/tex]

Suppose f(x) = x^3 +3. Find the graph of f(2/3x)

Answers

Answer:

First, when we have a function f(x), an horizontal dilation of scale factor k, is written as:

g(x) = f(x/k)

Then f((2/3)*x) is an horizontal dilation of scale factor 3/2 of the function f(x).

(The graph will be a little bit wider than the graph of f(x))

Also, knowing that f(x) = x^3 + 3

Then:

f((2/3)*x) = ( (2/3)*x)^3 + 3

              = (8/27)*x^3 + 3

And the graph of this function is shown below:

Bacteria are taking over the kitchen sink. Right now, there are 375 microbes of bacteria. They double every hour.
Is the function describe above a growth or decay function?

Answers

Answer: The function described in this scenario above is a “Growth Function”

Have a nice day!

4. Tyquan had his car towed by Lakeview's Towing Service. It cost him $3.00 per mile to have it towed
plus a flat fee of $70.00. The function for his cost is represented by the function C(m) = 3m + 70. What
does C(22) represent in this situation?
a. Tyquan had hisbear towed for 136 mile and it cost $22.00
b. Tyquan had his car towed for 22 miles and it cost him $136.00
c. Tyquan had his car towed for 3 miles at $70.00
d. Tyquan had his car towed 22 miles for $70.00

Answers

The answer is b. because the other ones don't charge money according to the number of miles.

Answer:

The structure that you used in your research paper can also be used for your presentation. For example, just like how your

Step-by-step explanation:


Rob's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 3 adult tickets and 1 student ticket
for a total of $15. The school took in $69 on the second day by selling 9 adult tickets and 7 student tickets. What is the price each
of one adult ticket and one student ticket?

Answers

Answer:

Adult Tickets =$3

Student Tickets =$6

Step-by-step explanation:

3=9 9+6=15

9×3=27

6=42

27+42=67

Find the area of a triangle with a height of 5 ft and a base of 4 ft.

Answers

Answer:

5 x 4 = 20, 20 divided by 2 ( x 1/2 ) = 10

Step-by-step explanation:

Formula area of a Triangle:

B(base) x H(height) x 1/2(basically just dividing by 2)

Find the measure of the arc indicated. Assume that lines which appear tangent are tangent.

Answers

Answer:

Minor Arc AC = 360 - 235 = 125°

[tex]mABC = \frac{Major \ arc - Minor \ arc}{2} = \frac{235 - 125}{2} = \frac{110}{2} = 55[/tex]

Write the expression using exponents.

43 . 43 . 43 . 43 . 43

Answers

Answer:

43⁵

Step-by-step explanation:

43 · 43 · 43 · 43 · 43 = 43⁵

I NEED THIS QUICK no links !!!!! (math)

Answers

answer: the answer is c

PLEASE HELP IF POSSIBLE :)

Answers

Answer:

Step-by-step explanation:

Please help. Image up top.

Answers

Answer:

6/5t + 4/15s - 3

Step-by-step explanation:

(-4/5t + 5/3s) + (-3 -7/5s + 2t)

You can only add like terms together so convert like terms to have the same denominator:

(-4/5t + 25/15s) + (-3 - 21/15s + 10/5t)

Get rid of the parentheses:

-4/5t + 25/15s - 3 - 21/15s + 10/5t

Combine like terms:

6/5t + 4/15s - 3

What is the area, in square units, of trapezoid AEDC shown below?

Answers

20 • 12 is 240
1/2 • 12 • 4 is 24
so 264

Area of this trapezoid is 264 unit²

What is the area of a trapezoid?

Area: ½ x (sum of the lengths of the parallel sides) x perpendicular distance between parallel sides.

Given perpendicular distance as 12 and parallel sides as 20,24 units respectively.

Thus Area is (20+24 /2) ×12=264 units²

Hence, the Area of trapezoid is 264 unit²

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Find the measure of the missing angle
128°
Help plz

Answers

Answer:

52 degrees

Step-by-step explanation:

a line is 180 degrees so just subtract 128 from 180 which is 52

Solve using the Quadratic Formula
5x2-3x-7=0
A)
B)
C)
D)

Answers

Answer:

C) [tex]\displaystyle x=\frac{3 \pm \sqrt{149}}{10}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Standard Form: ax² + bx + c = 0Quadratic Formula: [tex]\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

5x² - 3x - 7 = 0

a = 5, b = -3, c = -7

Step 2: Solve for x

Substitute in variables [Quadratic Formula]:                                                  [tex]\displaystyle x=\frac{3 \pm \sqrt{(-3)^2-4(5)(-7)}}{2(5)}[/tex][√Radical] Evaluate exponents:                                                                       [tex]\displaystyle x=\frac{3 \pm \sqrt{9-4(5)(-7)}}{2(5)}[/tex][√Radical] Multiply:                                                                                           [tex]\displaystyle x=\frac{3 \pm \sqrt{9+140}}{2(5)}[/tex][√Radical] Add:                                                                                                 [tex]\displaystyle x=\frac{3 \pm \sqrt{149}}{2(5)}[/tex][Fraction] Multiply:                                                                                            [tex]\displaystyle x=\frac{3 \pm \sqrt{149}}{10}[/tex]
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