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consider the polynomial function q(x)=-2x^8+5x^6-3x^5+50

end behavior

Answer:

I think it's A

Step-by-step explanation:

The equations of values of x and y =0 that will maximize the revenue.

The marginal revenue equations, to calculate the partial derivatives of the revenue function with respect to each variable, x and y.

Given the revenue function:

t(x, y) = 110x + 180y + 3x² - 4y² - xy

The marginal revenue with respect to x, rx(x, y), the partial derivative of t(x, y) with respect to x, while treating y as a constant:

rx(x, y) = ∂t/∂x = 110 + 6x - y

Similarly, the marginal revenue with respect to y, ry(x, y),the partial derivative of t(x, y) with respect to y, while treating x as a constant:

ry(x, y) = ∂t/∂y = 180 - 8y - x

The production levels that will maximize revenue, both marginal revenue equations equal to zero and solve as a system of equations.

Setting rx(x, y) = 0:

110 + 6x - y = 0

Setting ry(x, y) = 0:

180 - 8y - x = 0

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Answer:

6x

Step-by-step explanation:

Answer:

answer in photo

The differential equation y'' - 12y' + 36y = 36[tex]x^4[/tex] is solved using the method of undetermined coefficients. The particular solution is found to be y_p = (1/72)[tex]x^6[/tex] - (1/12)[tex]x^4[/tex]+ (1/6)[tex]x^{2}[/tex].

To solve the given differential equation using the method of undetermined coefficients, we assume a particular solution of the form y_p = A[tex]x^6[/tex] + B[tex]x^4[/tex] + C[tex]x^{2}[/tex], where A, B, and C are constants to be determined. We differentiate y_p twice to find its derivatives: y_p' = 6A[tex]x^5[/tex] + 4B[tex]x^3[/tex]+ 2Cx and y_p'' = 30A[tex]x^4[/tex] + 12B[tex]x^{2}[/tex] + 2C.

Substituting these derivatives into the original differential equation, we have:

30A[tex]x^4[/tex] + 12B[tex]x^{2}[/tex] + 2C - 12(6A[tex]x^5[/tex] + 4B[tex]x^3[/tex] + 2Cx) + 36(A[tex]x^6[/tex] + B[tex]x^4[/tex] + C[tex]x^{2}[/tex]) = 36[tex]x^4[/tex].

Simplifying and equating the coefficients of like powers of x, we obtain the following equations:

36A = 0 (coefficient of x^6 term),

-72A + 36B = 0 (coefficient of x^4 term),

-36B + 36C = 36 (coefficient of x^2 term).

Solving these equations, we find A = 0, B = -1/12, and C = 1/6. Therefore, the particular solution is y_p = (1/72)[tex]x^6[/tex]- (1/12)[tex]x^4[/tex]+ (1/6)[tex]x^{2}[/tex].

The general solution of the given differential equation is the sum of the particular solution and the homogeneous solution. However, since the equation does not specify any initial conditions, we only provide the particular solution in this case.

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The function for this problem is given as follows:

y = 0.25(x + 5)²(x - 4)²

We are given the roots for each function, hence the factor theorem is used to define the functions.

The function is defined as a product of it's linear factors, if x = a is a root, then x - a is a linear factor of the function.

The roots of the function in this problem are given as follows:

Hence the linear factors are given as follows:

The function is:

y = a(x + 5)²(x - 4)²

In which a is the leading coefficient.

When x = 0, y = 100, hence the leading coefficient a is given as follows:

100 = a(5²)(-4)²

400a = 100

a = 0.25.

Hence the function is:

y = 0.25(x + 5)²(x - 4)²

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To compute the 95% confidence interval for the mean number of visits per week, a t-distribution is used. The confidence interval suggests that with 95% confidence, the population mean number of visits per week is between a lower bound and an upper bound.

(a) The t-distribution is used to compute the confidence interval for the mean number of visits per week. This is because the sample size (230) is relatively large, making the t-distribution appropriate for estimating the population mean.

(b) With 95% confidence, the population mean number of visits per week falls within the confidence interval. To calculate the interval, the sample mean (3.5) and the standard deviation (2.7) are used. The confidence interval will have a lower bound and an upper bound, which can be calculated using the formula: mean ± (t-value * standard error), where the t-value is obtained from the t-distribution table.

(c) If multiple groups of 230 randomly selected members are studied, each group will produce a different confidence interval. Approximately a certain percentage of these intervals will contain the true population mean number of visits per week, reflecting the level of confidence (95% in this case). The remaining percentage of intervals will not contain the true population mean. The actual percentage depends on factors such as the sample variability and the sample size.

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Given: A team of 3 employees is preparing 20 reports. Mary takes 30 minutes to complete a report. Matt takes 45 minutes to complete a report.

All reports are completed in 4 1/2 hours. To Find: How long does it take the third team member to complete a report?Solution: Let the third employee takes x minutes to complete a report work done by Mary in 1 minute = 1/30Work done by Matt in 1 minute = 1/45Work done by the third employee in 1 minute = 1/x Total work done by all three in 1 minute = 1/30 + 1/45 + 1/x (As all are working together) a Total number of reports to be prepared = 20Therefore, total work = 20Now,

we know that all reports are completed in 4 1/2 hours = 9/2 hours∴ Total time = 9/2 x 60 = 270 minutes according to the problem statement, Total work = Total time x Total work done by all three in 1 minute20 = 270 (1/30 + 1/45 + 1/x)Solving the above equation for x, we get :x = 90 minutes therefore, it takes the third team member 90 minutes to complete a report.

Answer: 90 minutes.

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Let's represent the third team member as t. Mary takes 30 minutes to complete a report, while Matt takes 45 minutes to complete a report.

Thus, it takes the third team member 3 hours to complete a report.

Therefore, we can use the information given to form an equation. We are given that the team is preparing 20 reports, so:

30 minutes/report × M reports + 45 minutes/report × N reports + T minutes/report × O reports = 4.5 hours

To make the equation simpler, let the unit conversion 4.5 hours to minutes:

4.5 hours × 60 minutes/hour = 270 minutes

Thus:

30M + 45N + TO = 270

O= 20 - M - N

From the third team member: TO = T × 20

Therefore:

30M + 45N + T × 20 = 270

Solving for T:

30M + 45N + 20T = 270

T = (270 - 30M - 45N)/20

We know that there are only three members in the team, and that M and N have already been defined, so we can substitute these values:

T = (270 - 30(20) - 45(0))/20

T = 3

Thus, the time taken by the third team member is 3 hours to complete a report.

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Answer:

hi

Step-by-step explanation:

hi

For highway-mileages of 9 different models of car, the mode is 41, mid-range is 37.5, range is 25, and standard-deviation is 6.25.

⇒ To find the mode, we identify the value(s) that occur most frequently in the data set. In this case, the mode is 41, as it appears twice, more than any other value.

So, the mode is 41,

⇒ The midrange is calculated by finding the average of the maximum and minimum values in the data set. In this case, the maximum value is 50 and the minimum value is 25. So, the midrange is (50 + 25)/2 = 37.5,

⇒ The range is determined by subtracting the minimum value from the maximum value. In this case, the range is 50 - 25 = 25,

⇒ To calculate the standard-deviation using the range rule of thumb, we divide the range by 4. In this case, the range is 25, so the standard deviation would be 25/4 = 6.25.

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The given question is incomplete, the complete question is

The highway mileage (mpg) for a sample of 9 different models of a car company can be found below. 41, 50, 41, 25, 28, 27, 36, 47, 46.

Find the mode, midrange, range, and standard deviation.

Answer:

54

Step-by-step explanation:

First of all,

Cross multiplication

4 = 12

18 = x

Let the value of the number of eggs be represented by x

4x = 12×18

4x = 216

4. 4

(Same as 216÷4)

x = 54

Answer:

Step-by-step explanation:

Write the sum of the terms in descending order.

the average value of f(x) = x³ on the interval [-1, 2] is 5/4.

To find the average value of the function f(x) = x^3 on the interval [-1, 2], we need to calculate the definite integral of f(x) over that interval and divide it by the length of the interval.

The average value (Avg) is given by the formula:

Avg = (1 / (b - a)) * ∫[a to b] f(x) dx

In this case, a = -1 and b = 2. Let's calculate the average value:

Avg = (1 / (2 - (-1))) * ∫[-1 to 2] x³ dx

   = (1 / 3) * ∫[-1 to 2] x³ dx

To integrate x³, we add 1 to the exponent and divide by the new exponent:

Avg = (1 / 3) * [x⁴ / 4] | from -1 to 2

   = (1 / 3) * [(2⁴ / 4) - (-1⁴ / 4)]

   = (1 / 3) * [(16 / 4) - (1 / 4)]

   = (1 / 3) * (15 / 4)

   = 5 / 4

Therefore, the average value of f(x) = x³ on the interval [-1, 2] is 5/4.

According to the Mean Value Theorem for Integrals, there exists a point c in the interval [-1, 2] such that the value of f(c) is equal to the average value of the function over that interval.

In this case, the average value is 5/4. Therefore, there exists a point c in the interval [-1, 2] such that f(c) = 5/4.

c³ = 5/4

c = ∛(5/4)

The value of c is ∛(5/4)

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Answer:

Answer is NOT 126 CORRECT answer is 628

Step-by-step explanation

First you divide 40 by 2 which equals 20 . Then you do pi which equals 3.14 and you multiply it by 20^(2) which equals 1256 . After that you take 1256 and divide it by 2 which equals 628 .

Answer:  -7

Step-by-step explanation:

In order to find rate of change, we use two points (0,70) and (3,49).

rate of change = (y2 - y1)/ (x2 - x1)

                         = (49 - 70) / (3 - 0)

                         = -21/3

                         = -7

The solution to the equation [x³ - 1] = 0 is x = 1

From the question, we have the following parameters that can be used in our computation:

[x³ - 1] = 0

Remove the square bracket in the equation

So, we have

x³ - 1 = 0

Add 1 to both sides

This gives

x³ = 1

Take the cube root of both sides

x = 1

Hence, the solution to the equation [x³ - 1] = 0 is x = 1

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Answer:

4x-5y=10

Step-by-step explanation:

Answer:

Is this for your homework

Step-by-step explanation:

Answer:

P" is then (-3, 2).

Step-by-step explanation:

If the point P(-6, 4) is translated 3 units to the right, the x-coordinate increases by 3 from -6 to -3 and the y-coordinate decreases 2 units from 4 to 2.

P" is then (-3, 2).

Answer:

Answer:

P" is then (-3, 2).

Step-by-step explanation:

Cov(X, Y) = -1/3 and ρ(X, Y) = -1/18.

Given data:X and Y are two random variables,

σ² of X=4,σ² of Y=9.Z=2X − Y and W = X + Y are independent

To find:

Cov(X, Y) and ρ(X, Y)

Solution:

We know that:

Cov(X, Y) = E(XY) - E(X)E(Y)ρ(X, Y) = Cov(X, Y) / σX σY

Let's find E(X), E(Y), E(XY)E(X) = E(W - Y) = E(W) - E(Y)E(W) = E(X + Y) = E(X) + E(Y)

From this equation, E(X) = E(W)/2 ------- (1)

Similarly, E(Y) = E(W)/2 ------- (2)

To find E(XY), we will use the following equation:

E(XY) = Cov(X, Y) + E(X)E(Y)Using equations (1) and (2) in the above equation:

E(XY) = Cov(X, Y) + E(W)²/4

Now, we will use the independence of Z and W to find Cov(X, Y).Cov(X, Y) = Cov((W - Z)/2, (W + Z)/3)= 1/6[Cov(W, W) - Cov(W, Z) + Cov(Z, W) - Cov(Z, Z)]= 1/6[Var(W) - Var(Z)]

Here,Var(W) = Var(X + Y) = Var(X) + Var(Y) [using independence]= 4 + 9 = 13Var(Z) = Var(2X - Y) = 4Var(X) + Var(Y) - 2 Cov(X, Y)= 4 + 9 - 2 Cov(X, Y)

Now, putting these values in Cov(X, Y),Cov(X, Y) = -1/3

Also,σX = 2 and σY = 3ρ(X, Y) = Cov(X, Y) / σX σY= -1/18

Hence, Cov(X, Y) = -1/3 and ρ(X, Y) = -1/18.

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Answer:

y = -1/4x + 16

Step-by-step explanation:

the slope is -1/4 and the y-intercept is 16

Answer:

30000 times

Step-by-step explanation:

3 x 10^3 x 30000 = 90000000

Answer:

30000

Step-by-step explanation:

9×10^7 =90000000

also

3×10^3 =3000

divide 90000000 by 3000

=30000

Answer:

-3a^2 - 6a - 10

Step-by-step explanation:

You are subtracting 10a^2 + 6a + 2 from 7a^2 - 8.

You can set it up like the problem shows you, and subtract each term in the second line form a like term in the top line.

         7a^2            -8

(-)      10a^2 + 6a + 2

-----------------------------

        -3a^2 - 6a - 10

Answer:  -3a^2 - 6a - 10

Answer:

I would need to see the attached lesson to answer this question.

Answer:

d. -2/3x+5

Step-by-step explanation:

Because the line is perpendicular, the slope must be the inverse of the original slope. The inverse of 3/2 is -2/3. To find the b value, you plug (6,1) into the equation y=-2/3x+b

1=-2/3(6)+b

1=-4+b

5=b

The final equation is y=-2/3x+5

Any line perpendicular to it would have an undefined slope and would not pass through point (f, g) where f and g could be any values. In this case, the statement is false.

The statement "Leo drew a line that is perpendicular to the line shown on the grid and passes through the point (f, g)" can be true or false.

It depends on the line shown on the grid and the coordinates of point (f, g).

Two lines are perpendicular if their slopes are opposite reciprocals of each other.

To find the slope of the line perpendicular to the line shown on the grid,

we can use the negative reciprocal of the slope of the given line.

If the line drawn by Leo has this slope and passes through point (f, g), then the statement is true.

If not, then the statement is false.

For example, if the line shown on the grid has a slope of 2/3 and passes through the point (0,0),

then the perpendicular line drawn by Leo would have a slope of -3/2 and pass through point (f, g) where f and g could be any values.

In this case, the statement is true.

However, if the line shown on the grid has a slope of 0 and passes through point (1,1), then any line perpendicular to it would have an undefined slope and would not pass through point (f, g) where f and g could be any values. In this case, the statement is false.

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Step-by-step explanation:

Storage Space of Shed = Volume of Shed.

Volume of Shed = Volume of Rectangular level

+ Volume of Triangular roof

Volume of Rectangular Level =

Length x Width x Height

=

[tex]12 \times 6 \times 8 \\ = 576 {ft}^{3} [/tex]

Volume of Triangular Roof =

Area of Triangular side x Length

=

[tex] \frac{1}{2} \times base \times height \times length \\ = \frac{1}{2} \times 6 \times 4 \times 12 \\ = \frac{1}{2} \times 288 \\ = 144 {ft}^{3} [/tex]

Volume of Shed = 576 + 144

=

[tex]720 {ft}^{3} [/tex]

In part (A) of the problem, it is required to prove that if the initial conditions f(x) and g(x) are even functions and the forcing function F(x, t) is even for every t > 0, then the solution u(x, t) is also even with respect to x for every t > 0. In part (B), the task is to prove that if f(x) and g(x) are periodic functions and the forcing function F(x, t) is periodic for every t ≥ 0, then the solution u(x, t) is also periodic for every t ≥ 0.

To prove part (A), we can use the principle of superposition, which states that if the initial conditions and forcing function are even, then the solution will also possess the property of evenness.

To prove part (B), we can use the fact that if the initial conditions and forcing function are periodic, the solution will be a linear combination of periodic functions. The sum of periodic functions is also periodic, thus making the solution u(x, t) periodic for every t ≥ 0.

By leveraging these principles and the given assumptions about the initial conditions and forcing function, it can be shown that the solutions u(x, t) will also possess the specified properties of evenness or periodicity, depending on the case.

Note: The explanation provided is a general overview of the approach without delving into the mathematical details and formal proofs.

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Answer:

2

Step-by-step explanation:

2+2 is 4 so therefore the answer is 2.00.