The velocity of the person as seen by someone not moving (watching the train going by) will be 55 m/s South. I can therefore conclude that none of the option given is correct.
Given that a train is moving south at 50 m/s and a person is running SOUTH on the train at 5 m/s.
That means the person is running relatively to the velocity of the train. Since the train and the person are moving in the same direction, the relative velocity seen by an observer watching the train going will be the addition of both the train and the person in the direction of the train.
That is,
Relative velocity = 50 + 5
Relative velocity = 55 m/s South.
Therefore, the velocity of the person as seen by someone not moving (watching the train going by) will be 55 m/s South.
I can therefore conclude that none of the option given is correct.
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Calculate the charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts.
The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb
Potential difference is the amount of work needed to move a unit charge from one point to another. It is given by:
V = E/Q
Where V is potential difference, E is energy and Q is charge. Given that:
V = 15 V, E = 5.25 kJ = 5.25 * 10³ J.
V = E/Q
15 = 5.25 * 10³ /Q
Q = 350 Coulomb
The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb
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A 2 kg object has a specific heat capacity of 1,700 J/(kg \cdot⋅oC)
To raise this object's temperature from 15 Celsius to 25 Celsius, the object must absorb _______ Joules of heat.
The amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.
HOW TO CALCULATE SPECIFIC HEAT CAPACITY:
The amount of heat absorbed by an object can be calculated by using the following expression:Q = m.c.∆TWhere;
Q = amount of heat absorbed or released (J)m = mass of objectc = specific heat capacity (J/g°C)∆T = change in temperature (°C)According to this question, 2 kg object has a specific heat capacity of 1,700J/kg°C and was raised from a temperature of 15 Celsius to 25 Celsius. The heat absorbed is calculated as follows:Q = 2 × 1700 × {25 - 15}Q = 3400 × 10Q = 34000JTherefore, the amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.Learn more about how to calculate heat absorbed at: https://brainly.com/question/11194034?referrer=searchResults
The person is in motion
relative to...
Answer:
muscular force in relative to this
Please help! Question is attached!
Answer:
1. -6m/s
2. 0m/s
3. 3m/s
4.14.38N
5. 25.9 J
Explanation:
1. point A and C same height means velocity will be the same just in opposite direction, = -6m/s
2. at max height vertical velocity is 0
3. same as point A
4. Weight is mg = 1.438*10 = 14.38N
5. total energy is KE+PE, which never changes
so TE = 32.4 and KE =6.5J then PE = 32.4-6.5 = 25.9 J
a person weighing 500 N climbs 3 m how much power. is needed to make the climb in 5 s?
Answer:
300watts
Explanation:
Answer:
300 watts
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What is the net force on a 4,000-kg car
that doubles its velocity from 15 m/s west
to 30 m/s west over 10 seconds?
Answer:
6000 N toward west
Explanation:
F = ma
a = 30-15/10 = 1.5 m/s^2 towards west
m = 4000 kg
F = 4000 x 1.5 = 6000 N towards west
Which of the following will require most developed countries to
decrease emissions of carbon dioxide and other greenhouse gases?
a. Montreal Protocol c. Emissions Reduction Act
b. Kyoto Protocol d. Reforestation Project
Answer:
Kyoto Protocol
Explanation:
When is there no atmospheric pressure pjysics.
If you double the pressure of a constant amount of gas at a constant temperature, what happens to the volume
Answer: if you double the pressure, you will halve the volume. If you increase the pressure 10 times, the volume will decrease 10 times.
Explanation:
how long does it take saturn to rotate on its axis
Answer:
Orbit and Rotation
One day on Saturn takes only 10.7 hours (the time it takes for Saturn to rotate or spin around once), and Saturn makes a complete orbit around the Sun (a year in Saturnian time) in about 29.4 Earth years (10,756 Earth days).
Explanation:
Waves can be refracted.
Explain this term.
HELP PLSSS
Answer: By "waves can be refracted" they mean that refraction can occur with waves. To better explain, refraction is the "change in direction of a wave passing from one medium to another or from a gradual change in the medium." You probably know this best when you put a pencil inside a glass of water where the pencil bends a bit. The same can happen with sound or water waves as well!
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An object of mass 10 kg is moving along positive x- axis with velocity 5 m/s. At some point it breaks into two parts of 6 kg and 4 kg. 6 kg moves making 600 with x –axis and 4 kg moves making -300 with axis. What is velocity of their centre of mass after breaking?
Explanation:
Correct option is
B
−3m/s
2
Given,
m=10kg
u=10m/s
v=−2m/s
t=4sec
The acceleration is rate of change of velocity,
a=
t
v−u
a=
4
−2−10
a=
4
−12
=−3m/s
2
The correct option is B.
What is the mass of an object that weighs 20N on earth? Use g=9.8 N/kg
Answer: Therefore, the mass of the object is 2.222 kg on the Earth, Moon, Saturn, Mercury and everywhere else it goes.
Explanation:
Answer:
the mass is 2.04
Explanation:
The weight of an object is calculated by: W=Mg
Solving for M: M=W/9
M=20/9.8 = 2.04
Calculate torque using angular momentum
Answer:
The equation net τ=ΔLΔt net τ = Δ L Δ t gives the relationship between torque and the angular momentum produced.
A block of mass m is initially at rest on a rough horizontal surface when a constant force F is exerted on it, as shown. The block accelerates to the right and is moving with speed v once it has moved a distance d. Which of the following equations can be used to solve for the force of friction exerted on the block by the surface?
The equations that can be used to solve for the force of friction exerted on the block by the surface is F- f = mv² / d
The constant force F is exerted on the block of mass and it accelerates with a speed, v and covering a distance of d in the direction of the force. The force of friction is an opposing force to the applied force.
Therefore,
using Newtons third law
F - f = ma
a = v/t
t = d/v
F - f = m × v / t
F- f = m × [tex]\frac{v}{\frac{d}{v} }[/tex]
F- f = m × v²/d
Therefore,
F- f = mv² / d
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Is mixing mixing sugar and cinnamon a chemical or physical change?
Answer:
It is a physical
Explanation:
a stone is thrown vertically upward with an initial velocity of 25m/s , calculate time taken to return to the thrower
Answer:
can you give me abrainlest??
State the general purpose of an experiment, using the terms dependent and independent variable
Answer:
Image result for State the general purpose of an experiment, using the terms dependent and independent variable
You can think of independent and dependent variables in terms of cause and effect: an independent variable is the variable you think is the cause, while a dependent variable is the effect. In an experiment, you manipulate the independent variable and measure the outcome in the dependent variable
Mark me Brainliest
What symbols are these?
Answer:
the bottom one is wollsiegel
helpp I'll give brainliest smth
Why there has to be a driving force to keep the car moving at a constant speed?
Explanation:
For example, when a car travels at a constant speed, the driving force from the engine is balanced by resistive forces such as air resistance and friction in the car's moving parts. ... an object falling at terminal velocity experiences the same air resistance as its weight.
Which is larger, the sun's pull on earth or earth's pull on the sun?.
Answer:
the suns pull
Explanation:
The Sun's pull on Earth is twice as large as Earth's pull on the much larger Sun.
Suppose cars start at a car race. In how many ways can the top 3 cars finish the race?.
Answer:
there is six ways the top three cars can finish the race
we cannot see the milky way galaxy without binocular or telescopes. true or false?
Answer:
I'm pretty sure it's false
Explanation:
.
sports photographers often use large aperture, long focal length lenses. what limitations do these lenses impose on the photographs?
Answer:
The depth of focus achievable with those lenses is small.
Explanation:
A larger aperture makes it much harder to focus on more than one object. When using a telephoto lens (the ones the question is referring to), the depth of focus is very small. For example, using a telephoto lens to take a photo of a runner might get the runner in focus, but certainly not the track, or the audience behind them. If you look at photos, especially older photos, of Olympians in almost any sport you can see this.
Hope this helps!
When astronomers carefully examine the planets found by Kepler and draw conclusions from the Kepler sample, what do they conclude about planets the size (radius) of Earth
Given what we know about the Kepler space program, we know that the astronomers discovered that Earth-sized planets are more common than we imagined.
Kepler was launched with the intention of getting a closer look at other planets outside of our solar system using enhanced photometrics.
The idea behind this launch was to discover more Earth-sized planets, preferably within the habitable zone of their central star.
What this mission showed astronomers, is that Earth-sized planets are more common than we could have imagined, Kepler proved this by finding over 2,662 planets to date.
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If you drag a 50kg block across the floor which has a coefficient of friction of .30, what is
the force needed to accelerated it at 2.0m/s^2 ?
Answer:
750 Newton
Explanation:
force=mass(acceleration)
The Earth system is an example of a(n)
Question 1 of 11
The book has a mass of 2.5 kg.
What net force must act on the book to make it accelerate to the left at a rate
of 7.0 m/s2? (Hint: Use F = ma.)
O A. F = 17.5 N right
OB. F = 2.8 N right
O C. F = 2.8 N left
O D. F = 17.5 N left
Answer:
D. F= 17.5 N left
Explanation:
I just took the quiz and got it correct!
given a force of 88N and an acceleration of 4 m/s 2, what is the mass?
Answer:22kg
Explanation:
from F=ma, 88=4m, m=22kg
1. How much heat is released when a 25 g sample of water (c = 4.184) is cooled from 99 °C
to 75 °C?