If log 7 =0.845, find log (7200).

Answer:it’s 1/4

Step-by-step explanation:

Answer:

$1.23

Step-by-step explanation:

9 binders for 11.07, where x = num of binders

9x = 11.07  [Divide both sides by 9]

x = $1.23

Answer:

each binder costs $1.23

Step-by-step explanation:

$11.07 divided by 9 equals $1.23

Answer:

it is the bottom answer or if it was labeled it would be D.

Answer:

B

Step-by-step explanation:

Period equals pi/2

Answer:

342 units squared

Step-by-step explanation:

since this is a rectangular prism, all we have to do is multiply the values by one of the other values once and multiply that by 2

Answer:

-5x=35            divide both sides by 5

-x=7                multiply both sides by -1

x=-7

Answer:

1:1 or 100% i don't know which you need

Step-by-step explanation:

Answer:

82.5

if its wrong sorry

hope this helps you ☺️☺️

6. = 0.0000004834

7. = 0.0000506

8. = 0.00098

9. = 64580000

10. = 1398600000

Answer:  The range of a set of data is the difference between the highest and lowest values in the set. To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

Answer:

3sqrt3 cm

Step-by-step explanation:

6^2-3^2

36-9=27

sqrt27 = 3sqrt3

Answer:

c. 3 square root ( 3 ) cm

Step-by-step explanation:

C^2 = A^2 + B^2

A^2 = C^2 - B^2

= 6^2 - 3^2

= 36 - 9

A^2 = 27

A = 3√3 cm

Answer:

A

Step-by-step explanation:

A. (g•f)(x)= log(5x) ( 5x + 4)=5x log(5x) + 4log(5x)

The function 5x log(5x) + 4log(5x) defines (g•f)

We have given that,

A. (g•f)(x)= 5x log(5x) + 4log(5x)

B. (g•f)(x) = 5x + 4 + log(5x)

C. (g•f)(x) = 5x – 4 – log(5x)

D. (g•f)(x) = 5x log(5x) + 4

We have to determine which function defines (g•f)

Where f(x)=log(5x) and g(x)=5x+5

A function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function. Functions were originally the idealization of how a varying quantity depends on another quantity.

A. (g•f)(x)= log(5x) ( 5x + 4)=5x log(5x) + 4log(5x)

(5x+4)(log(5x))=5x(log(5x))+4(log(5x))

Therefore the option A is correct.

To learn more about the function visit:

https://brainly.com/question/6561461

#SPJ5

Answer:

Im pretty sure you are correct

Step-by-step explanation:

Belive in urself m8

Answer:

no I don't think this is correct

Step-by-step explanation:

(no btw)

Answer:

A square unit is a small area of a square used to find a total.

Step-by-step explanation:

Answer:

k = (-1/4)

Step-by-step explanation:

Given that,

The point (-2, k) lies on the line 2x – 4y + 3 = 0.

We need to find the value of k.

Put x = -2 and y = k in the given equation.

2(-2) – 4k + 3 = 0

-4-4k = -3

-4+3 = 4k

-1 = 4k

k = (-1/4)

So, the value of k is equal to (-1/4).

Answer:

207,314

Step-by-step explanation:

V = πr2h =π  · 52·3 ≈ 235.61945 m^3

because 1m^3 = 1000 L, (27,535 / 1000) = the amount of added water in m^3. As this is equal to 27.535, we can substract this from 235.62.

235.62 - 27.535  is about 208.085, or 207.314 because of rounding. As this is in m^3, we multiply by liters to arrive at the answer of 207,314, or option D.

Answer:

RS=5.65

Step-by-step explanation:

Please gimme few minutes

Answer:

1, -4, -9, -14, -19, -24, -29, -34, -39, -44, -49, -54 = -318

Step-by-step explanation:

Answer:

The Answer is -318.

Step-by-step explanation:

1 + (-4) + (-9) + (-14) + (-19) + (-24) + (-29) + (-34) + (-39) + (-44) + (-49) + (-54)

Answer:

The value of log 8 is 0.9030

Step-by-step explanation:

To find:

Value of log 8

Solution:

Let we take,

x=log8

x=log (2)^3

x=3log2

x=3*0.3010

x=0.9030

Hence, the value of log 8 is 0.90.

Answer:

x = -19

Step-by-step explanation:

first isolate x by subtracting 8 on both sides:

179 = -9x + 8

-8              -8

=> 171 = -9x

then divide -9 on both sides to solve for x:

=> x = 171 ÷ -9 = -19

hope it helps ;)

Answer:

5 units

Step-by-step explanation:

(4, -2 )  ;   [tex]x_{1}=4[/tex]  and [tex]y_{1} = -2[/tex]

(4 , 3) ;      [tex]x_{2} = 4[/tex]  and  [tex]y_{2}=3[/tex]

distance = [tex]\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\[/tex]

              [tex]= \sqrt{(4-4)^{2}+(3-[-2])^{2}}\\\\= \sqrt{0+(3+2)^{2}} \\\\=\sqrt{5^{2}}\\\\= 5 units[/tex]

Answer:

9.95 cm

Step-by-step explanation:

Volume of a cylinder = pi * r² * h

Volume = 500 cm³

Radius, r = 8cm / 2 = 4cm

500 = 3.14 * 4² * h

500 = 3.14 * 16 * h

500 = 50.24 * h

h = 500 / 50.24

h = 9.952229

Height, h = 9.95 cm

Answer: 0.09375

Step-by-step explanation: divid 3/8 and 1/4 together and you get 0.09375

Answer:

309

Step-by-step explanation:

To determine the estimated free-flow speed

[tex]FFS = 75.4 -f_{LW}-f_{LC} - 3.22 TRD^{0.84}[/tex]

From the table "Adjustment for lane width," which corresponds to a lane width of 12 feet. As a result, [tex]f_{LW}[/tex] equals 0 mi/h.

Take the meaning from the table "Adjustment for right-shoulder lateral clearance," which corresponds to 6 feet of right shoulder lateral clearance and two lanes in one direction.

The [tex]f_{LC} = 0 mi/h[/tex]

[tex]FFS = 75.4 -0-0-3.22 ( \dfrac{5}{6})^{0.84}[/tex]

[tex]= 72.64 \ mi/h[/tex]

[tex]\simeq 73 \ mi/h[/tex]

Determine the peak-hour factor

[tex]PHF = \dfrac{V}{V_{15}\times 4} \\ \\ =\dfrac{1800}{700\times 4}\\ \\ = 0.6429[/tex]

Now, Find the heavy-vehicle adjustment factor.

[tex]v_P = \dfrac{V}{PHF\times N \times f_{HV}\times f_P} --- (1)[/tex]

Take the value for the 15-minute passenger car equivalent flow rate from the table "LOS requirements for freeway segments" for the FFS and LOS C conditions. The free-flow speed is estimated to be 73 miles per hour

[tex]v_p = 1735+ \dfrac{73-70}{75-70}(1775-1735)[/tex]

[tex]v_p = 1759 \ pc/h/In[/tex]

Think about for familiar users the value of f_p = 1.00

Replace all of the values obtained in (1)

[tex]v_p = \dfrac{V}{PHF \times N\times f_{HV}\times f_p}[/tex]

[tex]1759 = \dfrac{1800}{0.6429\times 2 \times f_{HV}\times 1}[/tex]

[tex]f_{HV} = \dfrac{1800}{0.6429\times 2 }\times \dfrac{1}{1759}[/tex]

= 0.795

Calculate the percentage of trucks and buses in the flow of traffic stream.

[tex]f_{HV} = \dfrac{1}{1+P_{\tau}(E_{\tau}-1) + P_R(E_R-1)}[/tex]

Take the values from the table "Passenger car equivalent for extended highway segments" referring to trucks and buses and rolling terrains for passenger car equivalent for trucks and buses and recreational vehicles. As a result, [tex]E_T[/tex] has a value of 2.5 and [tex]E_R[/tex] has a value of 2.0.

Since [tex]P_R[/tex] is zero and there is no recreational vehicle.

Then;

[tex]0.759 = \dfrac{1}{1+ P_T(2.5 -1) +0}[/tex]

[tex]P_T = 0.1719[/tex]

Finally, to estimate the maximum number of large trucks and buses; we have:

[tex]= V\times P_T = 1800 \times 0.1719[/tex]

Maximum number of large trucks and buses = 309