If {x) = 3x + 2, what is (5)?​

Answer:

8.no answer A. x=8

Step-by-step explanation:

10.no answer B. x= -3

Answer:

8. (A) x = 8 , 10. (C.) x = 3

Step-by-step explanation:

Number 8 you could do 75 - 35 = 40

so what can you multiply 5 by (x) to get 40? you would multiply 5 by 8 or (x) and get 40

then add 35 + 40 to get 75 degrees which is the parallel angle to the other 75 degrees.

Number 10 you just want to get them to the same number.

so you would do ( 97 - 3 ) to get the ANSWER 87.

so x = 3

Answer:

12 Notebooks And 16 Erasers

Step-by-step explanation:

Let x represent the number of notebooks and y represent the number of erasers. (x+y=28) Then, input the cent numbers into the equation. (90x+45y=1800) The 1800 represents the amount of dollars spent. Then simplfy the equation, which gives you 12 notebooks and 16 erasers.

Answer:

diameter ÷ 2 = 8 ÷ 2 = 4

Step-by-step explanation:

Answer:

A.true)

Step-by-step explanation:

Hope this helps!

Answer:

She got 63 chocolates.

Step-by-step explanation:

Answer:

9. -3/4

10. -5/1

11. UNDEFINED

12. 2/3

Answer:

9. -3/4

10. -5

11. undefined

12. 2/3

Step-by-step explanation:

Answer:

2.94 in

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Since Riley has already saved 80 dollars and she needs to save 150 dollars.

150-80=70

She earns 14 dollars per week:

70/14=5

I also wrote a equation:

(150-80)/14=x

Hope this was helpful!

Answer:

She will pay $2.

Step-by-step explanation:

Answer:

Mrs Barnes has the highest

Answer:

Option C. 2(x + 8)

Step-by-step explanation:

To know which option is the correct answer, let us simplify each expression given in the options to know which will not result to 2x² – 16. This is illustrated below:

For Option A:

2x² + 4x – 4x – 16

= 2x² – 16

For Option B:

2(x² – 8)

Clear bracket

2x² – 16

For Option C:

2(x + 8)

Clear bracket

2x + 8

For Option D:

(4x² – 32) /2

4x²/2 – 32/2

2x² – 16

From the above illustration, option C did not result to 2x² – 16.

Therefore, option C is the answer to the question.

The answer is A

Hope this helps!

Answer:

The correct answer is B. The rate of 7% compounded quarterly is better.

Step-by-step explanation:

In the case of investment at 7% compounded quarterly, the final result after 4 years of investment arises from the following calculation:

X = 7000 x (1 + 0.7 / 3) 4x3

X = 9,232.16

Therefore, after 4 years of investment, the amount in the account would be $ 9,232.16.

In turn, in the case of the investment at 6.85% compounded monthly, the final result after the same investment period arises from the following calculation:

X = 7000 x (1 + 0.685 / 12) 4x12

X = 9,199.33

Thus, in this case, the amount in the account after 4 years of investment would be $ 9,199.33.

Answer:

Yes, because the plot shows no apparent pattern.

Step-by-step explanation:

Yes, because the plot is a residual plot from a regression of a variable with the independent variable x.

Therefore, the correct option is 1.)Yes, because the plot shows no apparent pattern.

To learn more about regression refer to:

brainly.com/question/26755306

#SPJ2

Answer:  

470

Step-by-step explanation:

Replace x with 10:  470

5(10)(10 - 3( = 500 - 30 = 470

470

Answer:

Standard Deviation and Below are, in fact, the right answer.

Step-by-step explanation:

Edge. :)

Answer:

The person above is right, they deserve brainliest.

-standard deviations

-below

ED2021

Answer:

3

Step-by-step explanation:

cause its a pretty simple question

Answer: The unit price is $6.59 per pair of socks

Step-by-step explanation: 26.36. divided by 4 = 6.59

Answer:

Yes it is

Step-by-step explanation:

Because

2) x (sqrt 3) times (sqrt 12)

Two is also equivalent to sqrt of 4. The operation may be expressed as,

                                  (sqrt 4) x (sqrt 3) x sqrt (12)

The product is sqrt (144). This gives an answer of 12 and it is rational.

So, the answer is Yes!

Hope this helped! :)

May i have brainliest!

Answer:

Yes it is

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

12 is the answer and 12 is a rational number

Radicand = The number under the inclusion bar of the radical sign.

Product = The result of two numbers being multiplied together.

Factor = One of two or more expressions that are multiplied together to get a product.

Answer:

2) 9/4

Step-by-step explanation:

12/5 in decimal form is 2.4. As a mixed number, 12/5 is 2 2/5. And, 12/5 is just a reduced form of 36/15. So, the only answer it can be is answer 2: 9/4

Answer:

A=-4/3

B=1/5

C=-5/4

Step-by-step explanation:

Answer: 24

Step-by-step explanation: negative multiples by a negative is a positive

The opposite of -(-24) is -24.

A number is additive inverse of a given number when sum of the two number is zero and a number is a multiplicative inverse of a given number when product of two number is 1.

According to the given question statement we have to determine what is opposite of -(-24).

We know opposite of two numbers sums to zero.

Given -(-24).              ( negative signs will distribute and it'll become 24).

Let the opposite number be x.

∴ 24 + x = 0

x = -24.

So the opposite of -(-24) is - 24.

learn more about additive and multiplicative inverse here :

https://brainly.com/question/13715269

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Answer:

Option (4) and Option (6)

Step-by-step explanation:

By the zero product property,

If (x - a)(x - b) = 0

Then, (x - a) = 0 ⇒ x = a

(x - b) = 0 ⇒ x = b

By following the zero product property,

From the given equation,

3(x - 4)(2x - 3) = 0

x - 4 = 0 ⇒ x = 4

2x - 3 = 0 ⇒ x = [tex]\frac{3}{2}[/tex]

Therefore, options (4) and (6) will be the correct options.

Answer:

4 and 6 :)

Step-by-step explanation:

edge

Answer:

p=2 (l+w)

Step-by-step explanation:

Answer:

See explanation

Step-by-step explanation:

Solving (a):

[tex]a_n = 6a_{n-1}[/tex] where [tex]a_0 = 2[/tex]

n = 1

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_1 = 6a_{1-1}[/tex]

[tex]a_1 = 6a_{0}[/tex]

Substitute 2 for [tex]a_0[/tex]

[tex]a_1= 6 * 2[/tex]

[tex]a_1= 12[/tex]

n = 2

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_2 = 6a_{2-1}[/tex]

[tex]a_2 = 6a_{1}[/tex]

Substitute 12 for [tex]a_1[/tex]

[tex]a_2= 6 * 12[/tex]

[tex]a_2= 72[/tex]

n = 3

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_3 = 6a_{3-1}[/tex]

[tex]a_3 = 6a_2[/tex]

Substitute 72 for [tex]a_2[/tex]

[tex]a_3= 6 * 72[/tex]

[tex]a_3= 432[/tex]

n = 4

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_4 = 6a_{4-1}[/tex]

[tex]a_4 = 6a_{3}[/tex]

Substitute 432 for [tex]a_3[/tex]

[tex]a_4 = 6 * 432[/tex]

[tex]a_4 = 2592[/tex]

n = 5

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_5 = 6a_{5-1}[/tex]

[tex]a_5 = 6a_4[/tex]

Substitute 2592 for [tex]a_4[/tex]

[tex]a_5 = 6 * 2592[/tex]

[tex]a_5 = 15552[/tex]

n = 6

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_6 = 6a_{6-1}[/tex]

[tex]a_6 = 6a_{5}[/tex]

Substitute 15552 for [tex]a_5[/tex]

[tex]a_6 = 6 * 15552[/tex]

[tex]a_6 = 93312[/tex]

[tex]a_1= 12[/tex]   [tex]a_2= 72[/tex]   [tex]a_3= 432[/tex]   [tex]a_4 = 2592[/tex]   [tex]a_5 = 15552[/tex]   [tex]a_6 = 93312[/tex]

Solving (b):

[tex]a_n = a^2_{n - 1[/tex] where [tex]a_1 = 2[/tex]

We have

[tex]a_1 = 2[/tex] which serves as the first term

n =2

[tex]a_n = a^2_{n - 1[/tex]

[tex]a_2 = a^2_{2-1}[/tex]

[tex]a_2 = a^2_{1}[/tex]

Substitute 2 for [tex]a_1[/tex]

[tex]a_2 = 2^2[/tex]

[tex]a_2 = 4[/tex]

n = 3

[tex]a_3 = a^2_{3-1}[/tex]

[tex]a_3 = a^2_{2}[/tex]

[tex]a_3 = 4^2[/tex]

[tex]a_3 = 16[/tex]

n = 4

[tex]a_4 = a^2_{4-1}[/tex]

[tex]a_4 = a^2_3[/tex]

[tex]a_4 = 16^2[/tex]

[tex]a_4 = 256[/tex]

n =5

[tex]a_5 = a^2_{5-1[/tex]

[tex]a_5 = a^2_4[/tex]

[tex]a_5 = 256^2[/tex]

[tex]a_5 = 65536[/tex]

n = 6

[tex]a_6 = a^2_{6-1[/tex]

[tex]a_6 = a^2_{5[/tex]

[tex]a_6 = 65536^2[/tex]

[tex]a_6 = 4294967296[/tex]

[tex]a_1 = 2[/tex]   [tex]a_2 = 4[/tex]   [tex]a_3 = 16[/tex]   [tex]a_4 = 256[/tex]   [tex]a_5 = 65536[/tex]   [tex]a_6 = 4294967296[/tex]

Solving (c):

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] [tex]a_0=1[/tex]  ; ;  [tex]a_1=2[/tex]

[tex]a_1=2[/tex] ---- First term

n = 2

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_2=a_{2-1}+3a_{2-2}[/tex]

[tex]a_2=a_1+3a_0[/tex]

Substitute values for a1 and a0

[tex]a_2=2+3 * 1[/tex]

[tex]a_2=2+3[/tex]

[tex]a_2=5[/tex]

n = 3

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_3=a_{3-1}+3a_{3-2}[/tex]

[tex]a_3=a_{2}+3a_{1}[/tex]

[tex]a_3=5+3 * 2[/tex]

[tex]a_3=5+6[/tex]

[tex]a_3=11[/tex]

n = 4

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_4=a_{4-1}+3a_{4-2}[/tex]

[tex]a_4=a_{3}+3a_{2}[/tex]

[tex]a_4=11+3 * 5[/tex]

[tex]a_4=11+15[/tex]

[tex]a_4=26[/tex]

n = 5

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_5=a_{5-1}+3a_{5-2};[/tex]

[tex]a_5=a_{4}+3a_3[/tex]

[tex]a_5=26+3 * 11[/tex]

[tex]a_5=26+33[/tex]

[tex]a_5=59[/tex]

n = 6

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_6=a_{6-1}+3a_{6-2}[/tex]

[tex]a_6=a_{5}+3a_4[/tex]

[tex]a_6=59+3*26[/tex]

[tex]a_6=59+78[/tex]

[tex]a_6=137[/tex]

[tex]a_1=2[/tex]   [tex]a_2=5[/tex]   [tex]a_3=11[/tex]   [tex]a_4=26[/tex]   [tex]a_5=59[/tex]   [tex]a_6=137[/tex]

Solving (d):

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex];     [tex]a_0=1[/tex]; [tex]a_1=1[/tex]

[tex]a_1=1[/tex] --- First term

n = 2

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_2=2 * a_{2-1}+2^2a_{2-2}[/tex]

[tex]a_2=2 * a_1+4*a_0[/tex]

[tex]a_2=2 * 1+4*1[/tex]

[tex]a_2=2 +4[/tex]

[tex]a_2=6[/tex]

n = 3

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_3=3 * a_{3-1}+3^2 * a_{3-2}[/tex]

[tex]a_3=3 * a_{2}+9 * a_{1}[/tex]

[tex]a_3=3 * 6+9 * 1[/tex]

[tex]a_3=18+9[/tex]

[tex]a_3=27[/tex]

n = 4

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_4=4*a_{4-1}+4^2*a_{4-2}[/tex]

[tex]a_4=4*a_{3}+16*a_{2}[/tex]

[tex]a_4=4*27+16*6[/tex]

[tex]a_4=204[/tex]

n = 5

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_5=5 * a_{5-1}+5^2 * a_{5-2}[/tex]

[tex]a_5=5 * a_{4}+25 * a_{3}[/tex]

[tex]a_5=5 * 204+25 *27[/tex]

[tex]a_5=1695[/tex]

n = 6

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_6=6 * a_{6-1}+6^2*a_{6-2}[/tex]

[tex]a_6=6 * a_{5}+36*a_{4}[/tex]

[tex]a_6=6 * 1695+36*204[/tex]

[tex]a_6=17514[/tex]

[tex]a_1=1[/tex]   [tex]a_2=6[/tex]   [tex]a_3=27[/tex]   [tex]a_4=204[/tex]   [tex]a_5=1695[/tex]   [tex]a_6=17514[/tex]

Solving (e):

[tex]a_n= a_{n-1}+a_{n-3};\ a_0=1; a_1=2; a_2=0[/tex]

First term: [tex]a_1=2[/tex]

Second Term: [tex]a_2=0[/tex]

n = 3

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_3= a_{3-1}+a_{3-3}[/tex]

[tex]a_3= a_{2}+a_0[/tex]

[tex]a_3= 0+1[/tex]

[tex]a_3= 1[/tex]

n = 4

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_4= a_{4-1}+a_{4-3}[/tex]

[tex]a_4= a_{3}+a_{1}[/tex]

[tex]a_4= 1+2[/tex]

[tex]a_4=3[/tex]

n = 5

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_5= a_{5-1}+a_{5-3}[/tex]

[tex]a_5= a_{4}+a_{2}[/tex]

[tex]a_5= 3 + 0[/tex]

[tex]a_5= 3[/tex]

n = 6

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_6= a_{6-1}+a_{6-3}[/tex]

[tex]a_6= a_{5}+a_{3}[/tex]

[tex]a_6= 3 + 1[/tex]

[tex]a_6= 4[/tex]

[tex]a_1=2[/tex]   [tex]a_2=0[/tex]   [tex]a_3= 1[/tex]   [tex]a_4=3[/tex]   [tex]a_5= 3[/tex]   [tex]a_6= 4[/tex]

Explanation:

The slope of the line is found by the method: rise/run

You calculate how much the slope rises(goes up) and divide it by run(goes horizontal).

One more thing to note is that: the slope is negative BECAUSE ITS DECREASING.

Your answer:   -3/2