Answer: Options A, B and C.
Use feedstocks that convert most/all of the plant to energy, not just kernels, Change the public view on biofuels??,
Be able to scale production up in an economical way
Use microbes to make oil?
Explanation:
In order for biofuels to become viable option the industry need to Use feedstocks that convert most/all of the plant to energy, not just kernels, Change the public view on biofuels, Be able to scale production up in an economical way, and Use microbes to make oil because biofuels are fuels produced from organic matter or living matter such as plant material and animal wastes which is use for transportation majorly.
In order for biofuel to become viable options, there should be increase in production in a way that is affordable,cheap and safe, use feedstocks that convert plants and animals remains since plants and animal remains are used for it's production and also some microbes are of economic importance's that help to breakdown or decompose plants and animals remains to make oil which is called biodesel use for transportation.
Why is chalk used on blackboards?
which levels of protein structure are expected to be altered as a result of the amino acid substitutions?
1. primary structure
2. secondary structure
3. tertiary structure
4. quaternary structure
Answer:
secondary structure
Explanation:
primary structure
Question 1
Which structure is outside the nucleus of a cell and contains
DNA?
A
chromosome
mitochondrion
B
gene
D
vacuole
Answer:Chromosome
Explanation:
Mitochondria are basically power generators, thats it.
Vacuole acts as a sewage system, dumping excess water and material.
A chromosome is something that makes up a gene, so that cant possibly be right.
Answer:
mitochondrion
Explanation:
The mitochondrion contains mitochondrial DNA which goes back to the endosymbiotic theory if you remember that.
Select all that apply. Which of the following are characteristics of eukaryotes? single- or multi-celled structure no distinct nucleus membrane-bound organelles cell(s) larger than prokaryotes
Answer:
They can be single or multicellular and they are bigger than prokaryotes. They have a distinct nucleus and membrane-bound organelles, so that option would be incorrect. I hope this helped.
Explanation:
15. Preservation focuses mainly on preserving resources so that they can be used by people a. True b. False
Answer:
b. False
Explanation:
Preservation stands for preserving or sustaining what already exists. aimed at preserving natural resources in their original environment, free from human interference. It stands for securing an object from harm or decay while preserving its nature or state at the same time. Preservation of natural resources does not only benefit humans but also rejuvenates the wildlife and thus gave time for the Earth to breathe and regain its natural form.
3. In a field of sugar beets in Georgia the net primary productivity is 120 grams/m^2/day, and the
respiration loss is 25%. The insolation energy is 800 calories/cm^2/day, and one gram of beets is
equivalent to 2,000 calories.
a. Find the gross productivity of the sugar beets.
b. Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.
Answer and Explanation:
Available Data:
1 gr beets = 2,000 cal NPP = GPP – Respiration = 120 grams/m2/day NPP= Net primary productivity of a system GPP= Gross productivity of the producers Respiration loss 25% of NPP Insolation energy is 800 calories/cm2/day % Efficiency of Photosynthesis = (NPP/Insolation Energy) X 1001) Find the gross productivity of the sugar beets.
We need to calculate the GPP, which equals NPP - Respiration rate. The respiration loss is 25% of the NPP. This is:
100% NPP--------------- 120 g/m²/day
25% NPP ----------------X = (25 x 120)/100 = 30 g/m²/day
Now that we know the values of NPP and respiration rate, we can calculate the GPP.
GPP = NPP - Respiration
GPP = 120 (g/m²/day) - 30 (g/m²/day)
GPP = 90 g/m²/day
GPP = 0.009 g/cm²/day
2) Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.
% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100
We know the NPP, but this value is calculated in g/m²/day, while the Insolation energy is in g/cm²/day. We need to calculate the % Efficiency of Photosynthesis in cm. To do that, we must transform the information.
So if 1 m² = 10,000 cm², then:
10,000cm²----------120 grams/m²/day NPP
1 cm²---------------- (1 x 120) / 10,000 = 0.012 grams/cm²/day NPP
We also know that 1 gr beets = 2,000 cal, and that the Insolation energy is 800 calories/cm²/day
So we need to transform Insolation energy from calories/cm²/day to grams/cm²/day, so:
2,000 calories ----------------- 1 gr beet
800 calories/cm²/day---------X = 0.4 gr beet.
% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100
% Efficiency of Photosynthesis = (0.012 (gr/cm2/day) /0.4 (gr/cm2/day)) X 100
% Efficiency of Photosynthesis = 3 gr/cm2/day
i dont know what to in this question
Answer:
they said to think visually
Explanation:
I hope this helps
About _____ of people develop a serious condition in their phenotype as well as their genotype.
Answer:
the answer is 8%
3
A scientist mixes 2 grams of water and 6 grams of a powder. A new colored liquid is formed.
How many grams of the new colored liquid result?
(A)
(B)
2 grams
4 grams
6 grams
(C)
(D)
8 grams
Answer: 8 grams
Explanation: 2 grams of water added with 6 grams of powder equals 8 grams.