Answers
The magnitud of an electric field is given as:
[tex]E=\frac{1}{4\pi\epsilon_0}\frac{\lvert q\rvert}{r^2}[/tex]For the charge 1 the magnitude is:
[tex]\begin{gathered} E_1=\frac{1}{4\pi\epsilon_0}\frac{\lvert-6.39\times10^{-9}\rvert}{(0.424)^2} \\ E_1=319.543 \end{gathered}[/tex]Now, since charge 1 is negative this means that this field points towards the charge, in this case to the left, then the electric field for charge one is:
[tex]\vec{E_1}=-319.543[/tex]For the charge 2 the magnitude is:
[tex]\begin{gathered} E_2=\frac{1}{4\pi\epsilon_0}\frac{\lvert3.22\times10^{-9}\rvert}{(0.636)^2} \\ E_2=71.565 \end{gathered}[/tex]Now, since charge 2 is positive this means that this field points away from the charge, in this case to the left, then the electric field for charge two is:
[tex]\vec{E_2}=-71.565[/tex]Now, the total field on point P is the sum of both electric fields, then the total electri field on this point is:
[tex]E=-391.108[/tex]Related Questions
A pilot wishes to fly 2500km due South. The air speed of the plane is 300km/h and there is a wind of 50km/h from the West. What heading should the pilot take and what is the time required to complete the flight?
Answers
Since there is a wind speed of 50 km/h to the west, this speed needs to be compensated by the heading of the plane.
If we decompose the plane speed, one component will be used to cancel out the wind speed:
To find the orientation theta, we can calculate the east component of the plane speed and equate it to the wind speed:
[tex]\begin{gathered} V_{\text{east}}=V_{\text{wind}} \\ V\cdot\sin (\theta)=50 \\ 300\cdot\sin (\theta)=50 \\ \sin (\theta)=\frac{50}{300}=\frac{1}{6} \\ \theta=\sin ^{-1}(\frac{1}{6}) \\ \theta=9.59\degree \end{gathered}[/tex]Now, let's calculate the south component:
[tex]\begin{gathered} V_{\text{south}}=V\cdot\cos (9.59\degree) \\ V_{\text{south}}=300\cdot0.986 \\ V_{\text{south}}=295.8\text{ km/h} \end{gathered}[/tex]Calculating the required time of flight, we have:
[tex]\begin{gathered} \text{distance}=\text{speed}\cdot\text{time} \\ 2500=295.8\cdot t \\ t=\frac{2500}{295.8} \\ t=8.45\text{ hours} \end{gathered}[/tex]Therefore the orientation is 9.59° east of south and the time required is 8.45 hours.
When a force is exerted on a box, an equal and opposite force is exertedby the box. These forces are calledforces.O action-reactionO frictionalO centripetalO gravitational
Answers
Explanation
Newton's third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction.
let's check a box on a table
A wagon weighing 1000kg moves 50km/h on smooth rails. Later, a mass of 250 kg is placed in the wagon what is the velocity with which it moves?
Answers
The final velocity V is 40 km/h.
The final velocity V.
Mass of wagon m = 1000 kg
Initial velocity of wagon v = 50 km/h
Mass dropped velocity M = 250 kg
The final velocity =V
Initial system linear momentum [tex]P_{i}[/tex] = mv
=1000*50
=5*[tex]10^{4}[/tex] kg km/h
The system with the final velocity (wagon + mass dropped) be V .
Final system linear momentum [tex]P_{f}[/tex] = (m + M) V
=(1000+250)V
=1250 V
Basic principle of conservation of linear momentum,
[tex]P_{f}[/tex] = [tex]P_{i}[/tex]
1250V=5*[tex]10^{4}[/tex]
V=[tex]\frac{5*10^{4} }{1250}[/tex]
V= 40 km/h
So, the final velocity V is 40 km/h.
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A rifle is aimed horizontally at a target 35.0 m away. The bullet hits the target hits the
target 2.10 cm below the aiming point. a) What is the bullet's time of flight? b) What is
its muzzle velocity?
Answers
If the displacement, velocity and acceleration at an instant of a particledescribing S.H.M are respectively 7.5m, 7.5m/s, 7.5m/s?. Calculate themaximum velocity of the particle.
Answers
We are given the displacement, velocity, and acceleration of a particle that describes Simple Harmonic Motion. We are asked to determine the maximum velocity of the particle. To do that we can use the following equation for the maximum velocity of a particle describing SHM:
[tex]v_{máx}=-A\omega[/tex]Where:
[tex]\begin{gathered} A=\text{ amplitude} \\ \omega=\text{ angular frequency} \end{gathered}[/tex]To determine the values of amplitude and angular frequency we can use the expressions for displacement, velocity, and acceleration. The expression for displacement is:
[tex]x=A\cos (\omega t)[/tex]The expression for the velocity is:
[tex]v=-A\omega\sin (\omega t)[/tex]And the expression for acceleration is:
[tex]a=-A\omega^2\cos (\omega t)[/tex]Now, from the expression for the displacement we can solve for the amplitude, like this:
[tex]\frac{x}{\cos(\omega t)}=A[/tex]Now we can replace this in the expression got eh acceleration:
[tex]a=-\frac{x}{\cos(\omega t)}\omega^2\cos (\omega t)[/tex]Simplifying:
[tex]a=-x\omega^2[/tex]Now we can solve for the angular frequency:
[tex]-\frac{a}{x}=\omega^2[/tex]Taking square root to both sides:
[tex]\sqrt[]{-\frac{a}{x}}=\omega[/tex]replacing the values:
[tex]\sqrt[]{-\frac{-7.5\frac{m}{s^2}}{7.5m}}=\omega[/tex]Solving the operations:
[tex]1s^{-1}=\omega[/tex]Now we divide the formula for the displacement and the formula for the velocity, we get:
[tex]\frac{v}{x}=\frac{-A\omega\sin (\omega t)}{A\cos (\omega t)}[/tex]Simplifying we get:
[tex]\frac{v}{x}=-\omega\tan (\omega t)[/tex]Replacing the known values:
[tex]\frac{-7.5\frac{m}{s}}{7.5m}=-(1s^{-1})\tan (t)[/tex]Simplifying:
[tex]-1=-\tan (t)[/tex]Solving for "t":
[tex]t=\arctan (1)=0.78[/tex]Now we can replace these values in the formula for displacement to get the value of the amplitude:
[tex]x=A\cos (\omega t)[/tex]Solving for the amplitude:
[tex]\frac{x}{\cos (\omega t)}=A[/tex]Replacing the known values:
[tex]\frac{7.5m}{\cos (0.78)}=A[/tex]Solving the operations:
[tex]10.6m=A[/tex]Now we replace the values in the formula for the maximum velocity:
[tex]v_{\text{max}}=A\omega[/tex]Replacing:
[tex]\begin{gathered} v_{\max }=(10.6m)(1s^{-1}) \\ v_{\max }=10.6\text{ m/s} \end{gathered}[/tex]Therefore, the maximum velocity is 10.6 meters per second.
Part 1 Assume that as a wave travels from one particular medium to another, its speed decreases. What happens to the wave's frequency?A. Its frequency increases.B. Its frequency decreases.C. Its frequency remains the same.D. It is impossible to determine without more data.Part 2Which best explains the correct answer to Part 1?A. A wave's frequency always remains the same. B. A wave's frequency is inversely proportional to its speed.C. Given that the wave's wavelength remains the same, if the wave's speed decreases, then the frequency must decrease.D. Given that a wave's speed is equal to the product of its wavelength and frequency, the wavelength must be known to determine the frequency.
Answers
Part 1
C. Its frequency remains the same.
Part 2
A. A wave's frequency always remains the same.
Explanation:The relationship between wavelength, frequency, and speed is given as:
[tex]v=\lambda f[/tex]When the frequency of a wave increases, its wavelength also increases.
The speed of a wave does not change as its frequency changes, and vice-versa.
Therefore, as the speed of the wave decreases, its frequency remains the same
A wave's frequency always remains the same regardless of the speed and wavelength
In the experiment, the pressure of the gas is 1.2 x10^5 Pa at a temperature of 25.0°C.
When the cylinder is heated, the pressure reaches 2.1x10 Pa. Calculate the
temperature of the gas (in "C) at this pressure.
Answers
The temperature of the gas (in °C) at this pressure is 248.5 °C
Temperature is a bodily quantity that expresses the hotness of count or radiation. There are 3 kinds of temperature scales. Temperature is the degree of hotness or coldness of an item.
Temperature is a degree of the common kinetic energy of the debris in an object. whilst the temperature increases, the motion of those particles also increases. Temperature is measured with a thermometer or calorimeter.
Given;
P₁ = 1.2 x10⁵ Pa = 1.18430792
T₁ = 25.0°C = 298 K
P₂ = 2.1x10 Pa = 0.000207253886
T₂ = ?
using ideal gas equaion:-
PV = nRT
P₁/T₁ = P₂/T₂
T₂ = P₂T₁ /P₁
= 2.1x10⁵ x 298 / 1.2 x10⁵
= 521.5 K
= 248.5 °C
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Which ideas describe the big crunch? (1 point)
O After the universe reaches its expansion limit, gravity will pull it all back together.
O The big bang actually never occurred, and the universe must have a different origin.
O The universe goes through infinite cycles of expansion and contraction.
O The universe is not only composed of the objects that we can see.
Answers
Answer:
a
Explanation:
after the universe reach the limit, gravity does its thing
P and Q are points within a uniform electric field that are separated by a distance of 0.2 m as shown. The potential difference between P and Q is 75 V.How much work is required to move a +150 μC point charge from P to Q?0.023 J140 J0.011 J2800 J75 J
Answers
ANSWER:
0.011 J
STEP-BY-STEP EXPLANATION:
Given:
q = 150 μC
v = 75 V
r = 0.2
We calculate the work as the product between the charge and the potential difference, just like this:
[tex]\begin{gathered} W=q\cdot v \\ W=150\cdot10^{-6}\cdot75 \\ W=0.01125\text{ J} \\ W\cong0.011\text{ J} \end{gathered}[/tex]The work required is 0.011 J
Set the cannon to have an initial speed of 15 m/s. For which situation do you think the cannon ball will go the highest: if it is set at a 25-degree angle, or if it is set at a 35-degree angle?
Question 3 options:
25 degrees
35 degrees
Answers
The cannon ball will travel the highest distance when the angle of projection is 35 degrees.
What is the maximum height of a projectile?The maximum height reached by a projectile is calculated using the following formula.
H = u²sin²θ/2g
where;
u is the initial velocity of the projectile θ is the angle of pojectiong is acceleration due to gravitywhen the angle of projection is 25 degrees;
H = (15² (sin 25)²) / (2 x 9.8)
H = 2.05 m
when the angle of projection is 35 degrees;
H = (15² (sin 35)²) / (2 x 9.8)
H = 3.78 m
Thus, the cannon ball will travel the highest distance when the angle of projection is 35 degrees.
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The proper time between two events is measured by clocks at rest in a reference frame in which the two events: The proper time between two events is measured by clocks at rest in a reference frame in which the two events: a. are separated by the distance a light signal can travel during the time interval
b. occur at the same time
c. satisfy none of the above
d. occur in Nashville occur at the same coordinates
Answers
The correct option is option (D) occur in Nashville occur at the same coordinates.
In general proper time is the time interval between two events as measured by an observer who sees the event occur at the same position.
In geometry, a coordinate system is a device that makes use of one or more numbers, or coordinates, to uniquely determine the location of the points or different geometric factors on a manifold which includes Euclidean area.
Math coordinates discover the vicinity of a factor on a graph or map. The ordered pair, (x, y) is the cope with of the factor. The Cartesian coordinate gadget is the graph used to locate the point. The graph is split up into four quadrants.
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Archaeological samples are often dated by radiocarbon dating. The half-life of carbon-14 is 5,700 years.
After how many half-lives will the sample have only 1/64 as much carbon-14 as it originally contained?
How much time will have passed?
If the daughter product of carbon-14 is present in the sample when it forms (even before any radioactive decay happens), you cannot assume that every daughter you see is the result of carbon-14 decay. If you did make this assumption, would you overestimate or underestimate the age of the sample?
Answers
There are six half lives that have passed within 34,200 years. When we assume that we have some of the products present initially, then we overestimate the age of the sample.
What is the half life?The half life is the time taken to obtain only half of the number of atoms that were originally present in the radioactive material. We know that living things do contain the carbon- 14 isotope together with the carbon - 12 isotope in the substance. When the organism dies, the carbon - 14 which is radioactive begins to decay and its half life could be used to estimate the age of the sample as we know.
Given that after each half life, we have only half of the original amount that remains. We would have 1/64 of the original amount left after six half lives and this means that 34,200 years have passed.
If we the daughter product of carbon-14 is present in the sample when it forms (even before any radioactive decay happens), then we would over estimate the age of the sample.
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If a piece of ribbon were tied to a stretched string carrying a transverse wave, then how is the ribbon observed to oscillate?a.)perpendicular to wave directionb.)both perpendicular to and parallel to wave direction
Answers
The ribbon was observed to oscillate perpendicular to the wave direction. Option A.
In transverse waves, particles move perpendicular to the direction of wave propagation. Examples of transverse waves are string vibrations and water waves. By moving the Slinky vertically up and down, you can create horizontal transverse waves. Her one type of mechanical wave is the transverse wave.
where the motion of the medium is perpendicular to the direction of energy propagation. A transverse wave is a wave whose vibration is perpendicular to the direction of wave propagation. This is in contrast to longitudinal waves, which propagate in the direction of oscillation. Water waves are an example of transverse waves.
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A projectile is fired horizontally at an angle of 70° with the speed of 0.11km/s. Find the range and height. The final answer should be in meters.
Answers
In the given question projectile is fired horizontally at an angle of 70° with the speed of 0.11km/s ,(=110m/s).
to find the range and height
height=544.66m
time= 10.54 second
range=793.63m
vy=0
h=v^2sin^2θ/ 2g
v=0.11km/s =110m/s
θ=70°
range=v^2sin2θ/ g
horizontal velocity,
vx= 110cos70=37.622 m/s
vertical velocity,
vy=110sin70=103.36 m/s
using the equation of motion
s=ut+1/2 at^2
range, s=0, t=total time taken
range= 110^2 sin 2*70/9.8
range=793.63m
t= vsinθ/ g
=110 sin 70/9.8
time= 10.54 second
s=(110sin 70)*10.54 +1/2(-9.8)* (10.54^2)
s=1089-544.34
height=544.66m
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The table below shows part of the operating budget of a small dairy farm for the last year. The only expense not listed is maintenance. LAST YEARS OPERATING BUDGETExpense Fraction of BudgetFood 1/3Housing 1/3 Medical Care 1/4This year the managers of the farm will change the fraction for the budget for housing to ⅛ but will leave the fraction of the budget for good and medical care the same. Again, the remaining portion of the budget will be before maintenance expenses. What is the difference between the fraction of the budget for maintenance this year and last year?Show your workAnswer
Answers
Explanation
Step 1
let the fractions
[tex]\begin{gathered} Food\text{ }\frac{\text{1}}{3} \\ \text{ Housing }\frac{\text{1}}{3} \\ \text{Medical care }\frac{1}{4} \\ \text{ maintenance= M ( unknown)} \end{gathered}[/tex]so
a)This year the managers of the farm will change the fraction for the budget for housing to 1/8
so
[tex]\begin{gathered} Food\text{ }\frac{\text{1}}{3} \\ \text{ Housing }\frac{\text{1}}{8} \\ \text{Medical care }\frac{1}{4} \\ \text{ maintenance= M ( unknown)} \end{gathered}[/tex]b) hence,the total budget is
[tex]\begin{gathered} \text{past year= Operatingbudget= food+housidn +Medical care+maintenance} \\ \text{replace} \\ past\text{ year= }\frac{1}{3}+\frac{1}{3}+\frac{1}{4}+m \\ past\text{ year=}\frac{11}{12}+m \end{gathered}[/tex]this year
[tex]\begin{gathered} \text{past year= Operatingbudget= food+housidn +Medical care+maintenance} \\ \text{replace} \\ thisyear\text{= }\frac{1}{3}+\frac{1}{8}+\frac{1}{4}+m \\ thisyear\text{=}\frac{17}{24}+m \end{gathered}[/tex]Step 2
find the fractions for maintenance on each year:
as we are using fraction of the total budget, we need to set the sum of the fractions equals 1, hence
a) past year
[tex]\begin{gathered} \text{total = 1, so} \\ past\text{ year=}\frac{11}{12}+m=1 \\ m=1-\frac{11}{12} \\ m=\text{ }\frac{1}{12} \end{gathered}[/tex]b) this year
[tex]\begin{gathered} \text{total = 1, so} \\ this\text{year=}\frac{17}{24}+m=1 \\ m=1-\frac{17}{24} \\ m=\text{ }\frac{7}{24} \end{gathered}[/tex]Step 3
now, find the difference
[tex]\begin{gathered} \text{difference =}\frac{7}{24}-\frac{1}{12} \\ \text{difference =}\frac{5}{24} \end{gathered}[/tex]therefore, the answer is 5/24
I hope this helps you
your pet hamster sits on a record player that has constant angular speed . if the hamster moves to a point twice as far from the center, then its linear speed
Answers
When you drop a 0.38 kg apple, Earth exerts a force on it that accelerates it at 9.8 m/s2 to- ward the earth’s surface. According to Newtons third law, the apple must exert an equal but opposite force on Earth. If the mass of the earth 5.98 x 10^24 kg, what is the magnitude of the Earth's acceleration toward the apple? Answer in units of m/s^2
Answers
The magnitude of the earth’s acceleration toward the apple with a mass of 0.38 kg is 6.2 × 10⁻²⁵ m/s².
What is gravity?Gravity is a fundamental force which is responsible for causing mutual attraction between all the things with mass or energy.
The gravitational force can be calculated by the formula:
F = m.a
where, F = force
m = mass of an object
a = acceleration of the object
Here, the mass of the apple, m = 0.34 kg
The acceleration of the apple towards the earth's surface (a) = 9.8 m/s²
The mass of the Earth, M = 5.98 × 10²⁴ kg
Now, by applying Newton's Law of the motion,
The magnitude of the force on the apple due to Earth is can be calculated as:
F = m × a
F = 0.34 × 9.8
F = 3.724 N
According to the Newton's third law of motion, the apple must exert an equal but opposite force on Earth.
So, the magnitude of the force on Earth due to the apple will be:
F = 3.724 N
Let the magnitude of the earth’s acceleration towards the apple be 'A' m/s².
Thus, the magnitude of the earth’s acceleration towards the apple will be given by:
F = MA
M = mass of the Earth
A = acceleration of the Earth
3.724 = [5.8 × 10²⁴] × A
A = 3.724 / [5.8 × 10²⁴]
A = 0.6227 × 10⁻²⁴
A = 6.2 × 10⁻²⁵ m/s²
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WHAT IS CHROMATOGRAPHY ?
Answers
Answer:
Chromatography is a process for separating components of a mixture. To get the process started, the mixture is dissolved in a substance called the mobile phase, which carries it through a second substance called the stationary phase.
Explanation:
hope it will be helpful
Answer:
Chromatography is a process for separating components of a mixture.
Explanation:
To get the process started, the mixture is dissolved in a substance called the mobile phase, which carries it through a second substance called the stationary phase.
Have a good day!
The object represented by line E does not stop. Is this true or false?
Answers
The given graph is about velocity and time, the dependent and independent variable, respectively. As we can observe, line E crosses the zero level to the negative zone, which means the object didn't stop but changed its direction.
Therefore, the statement is true.consider the graph. which would best represent wearing a helmet during a blow to the head in a crash, explain.
Answers
By wearing the helmet, the time isextended during which the change in momentum of the body takes place during the crash.
This increase in time for the force acting on the body will decrease the impact of force on the body.
In the given graph, the value of force on the head is less and time taken is more in the first graph.
Thus, the first graph (1) represent the wearing helmet case.
The force on the head is more and time is less in the second case.
Thus, the second graph (2) represents the without helmet case.
Consider a 1500kg rollercoaster moving at 4.5m/s at the top of a
30.0m hill. If instead, friction does 52kJ of work on the rollercoaster on its
trip down the hill, how fast will the rollercoaster be moving once it
reaches ground level?
Answers
The rollercoaster be moving once it reaches ground level with a speed of 23.21 m/s.
Applying work-energy theorem,
Work done by conservative forces on the body + work done by none conservative forces on the body = Total change in Kinetic Energy of the body.
Here, conservative forces are gravitational force and non-conservative force is frictional force,
MgH - Fr = 1/2MV² - 1/2MU²
Where,
M is mass of roller coaster,
g is acceleration due to gravity,
H is the height of the roller coaster,
Fr is the frictional force,
V is the final velocity of roller coaster,
U is the initial velocity of the roller coaster,
1500(9.8)(30) - 52000 = 1/2(1500)(V²-20.25)
(441000 -52000)2/1500 = V² - 20.25
518.67 = V² - 20.25
V² = 538.9
V = 23.21 m/s.
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A bicycle wheel, of radius 0.300 m and mass 1.47 kg (concentrated on the rim), is rotating at 4.00 rev/s. After 56.4 s the wheel comes to a stop because of friction. What is the magnitude of the average torque due to frictional forces? Nm
Answers
Given,
The radius of the wheel, r=0.300 m
The mass of the wheel, m=1.47 kg
The initial angular frequency of the wheel, f=4.00 rev/s
The time it takes for the wheel to come to a stop, t=56.4 s
The final angular velocity of the wheel, ω=0 rad/s
The initial angular velocity of the wheel is
[tex]\begin{gathered} \omega_0=2\pi f \\ =2\pi\times4.00 \\ =25.13\text{ rad/s} \end{gathered}[/tex]From the equation of motion,
[tex]\omega=\omega_0+\alpha t[/tex]Where α is the angular acceleration of the wheel.
On substituting the known values,
[tex]\begin{gathered} 0=25.13+\alpha\times56.4 \\ \Rightarrow\alpha=\frac{-25.13}{56.4} \\ =-0.45\text{ rad/s}^2 \end{gathered}[/tex]The moment of inertia of the wheel whose mass is concentrated on the rim is given by,
[tex]I=mr^2^{}[/tex]The torque applied by the friction is given by,
[tex]\begin{gathered} \tau=I\alpha \\ =mr^2\alpha \end{gathered}[/tex]On substituting the known values,
[tex]\begin{gathered} \tau=1.47\times0.300^2\times-0.45 \\ =-0.06\text{ Nm} \end{gathered}[/tex]The negative sign of the torque indicates that the torque is applied to the wheel in the direction opposite to the direction of rotation of the wheel.
Thus the magnitude average torque due to frictional force is 0.06 Nm
Identify the different types of energy transformation in each1. windmill Energy Transformation:2. FlashlightEnergy Transformation:3. Firecracker Energy Transformation:4. Bicycle Energy Transformation:5.Microwave Energy Transformation:Nonsense answer-reportGreat answer-brainliest
Answers
We will have the following:
1. Windmill: From wnd energy to mechanical energy.
2. Flashlight: From chemical energy to ligth energy and thermal energy.
3. Firecracker: From chemical energy to thermal energy and kinetic energy.
4. Bycicle: From mechanical energy to kinetic energy.
5. Microwave: From electric energy to thermal energy,
A car starts from rest with constant acceleration achieves a velocity 15m/s when it travels a distance of 200m. Determine its acceleration and the time required.
Answers
3.7996 seconds are needed to accelerate it.
How does acceleration work?acceleration is the rate of change in both speed and direction of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. Because the direction is always shifting, motion on a circle accelerates even while the speed is constant.
So we have u= 0m/s, v=15m/s, s= 200m
So,2as= v^2-u^2
A= V^2 - U^2/2s
= 225/400
=0.5625 m/s^2
V=u + a*(t^2)
15=0+0.5625(t^2)
15-0.5625= t^2
=14.4375=t^2
root14.4375= root(t)
Time= 3.7996 seconds
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_______ is the study of the way all living things relate to each other in the world. The word comes from two Greek words which mean the study or science of the home.
Answers
Ecology is the study of the way all living things relate to each other in the world.
What is Ecology?This is referred to as the science which deals with the study of organisms and how they interact with their environment. It comprises of the study of the organisms present and their habitat.
Their habitat is the area where they live which comprises of many resources such as food, water etc which are needed for their growth and survival. The living things interact with it for beneficial reasons and is the reason why Ecology was chosen as the correct choice.
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Set the cannon to have an initial speed of 25 m/s at an angle of 30-degrees. Find how long it takes to hit the ground. Will the time it takes to get to the highest point be less than ½ the time, more than ½ the time, or ½ the time?
Question 7 options:
1/2 the time
more than 1/2 the time
less than 1/2 the time
Answers
The time taken by the projectile to reach the highest point would be one half of the total time of the projectile , therefore the correct answer is option D .
What is a projectile motion ?It is the motion of any object or body when it is ejected off the surface of the earth and follows any curving path while being affected by the gravitational pull of the planet .
As given in the problem Set the cannon to have an initial speed of 25 m / s at an angle of 30 degrees .
Thus, the right response is option D because it would take the projectile half as long to reach the highest position.
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19, 20, and 21 are confusing
Answers
1) Solid ,whose molecules are compactly arranged . so ,letter N
2) liquid state -the state in which molecules are arranged neither too compact nor loose . SO, letter O is pure liquid
3) letter Q is a pure gas
What is heat of fusion?The quantity of heat energy needed to convert a substance from a solid to a liquid is known as the heat of fusion. Enthalpy of fusion is another name for it. Joules per gram (J/g) or calories per gram (Cal/g) are typically used as its units. The solution to this example problem shows how to determine how much energy is needed to melt a sample of water ice.
What are the points to remember?The quantity of heat energy required to convert solid stuff into liquid is known as the heat of fusion (melting.)
Q = mHf is the formula for calculating heat of fusion.
The temperature is not a factor in the equation or the computation because matter does not truly change temperature when it changes states.
Heat of fusion is usually a positive value, with the exception of when melting helium.
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A 0.35-kg tennis racquet moving to the right at 20 m/s hits a 0.06-kg tennis ball that is moving to the left at 30 m/s. After the collision, the racquet continues to the right, but at a reduced speed of 10 m/s. What is the ball's velocity after the collision?
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From conservation of momentum we have that:
[tex]0.35(20)-0.06(30)=0.35(10)+0.06v[/tex]Solving for v we have that:
[tex]\begin{gathered} 0.35(20)-0.06(30)=0.35(10)+0.06v \\ 7-1.8=3.5+0.06v \\ 0.06v=7-1.8-3.5 \\ 0.06v=1.7 \\ v=\frac{1.7}{0.06} \\ v=28.33 \end{gathered}[/tex]Therefore the velocity of the ball after the collision is 28.33 m/s
This is astronomy and give explanations
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The scientific study of all celestial objects is known as astronomy. Galaxies, planets, stars, comets, meteors, and other events affecting the celestial bodies are all observed and studied by astronomers.
The words "Astro," which means "star," and "nomos," which means "rule," are derived from ancient Greek. Astronomy, when combined, refers to "star law." The natural sciences are the ones that it is the oldest.
Since there are so many celestial objects to study, it is practical to divide astronomy into various branches.
Here are some of the more well-known astronomical fields-
1. Planetary Astronomy
2. Solar Astronomy
3. Stellar Astronomy
4. Galactic Astronomy
5. Observational Astronomy; etc.
Let's know more about its distinction with space exploration
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9.A stock car is moving at 25.0 m/s when the driverapplies the brakes. If it stops in 3.00 s, what is itsaverage acceleration?
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The average acceleration a of an object that changes its speed from v_0 to v_f during a time interval t is:
[tex]a=\frac{v_f-v_0}{t}[/tex]Since the car is initially moving at 25.0m/s and it stops in 3.00 seconds, then its final speed is 0m/s.
Replace v_f=0, v_0=25.0m/s and t=3.00s to find the average acceleration of the car:
[tex]a=\frac{0\frac{m}{s}-25.0\frac{m}{s}}{3.00s}=-8.333\ldots\frac{m}{s^2}[/tex]Therefore, the average acceleration of the car when it stops from 25.0m/s in 3.00 seconds, is -8.33m/s^2.