in the figure at the right DC = 20 cm and AB =36 cm . what is FE? a.16cm b.56cm c.28cm d.46cm​

Answer:

51.63 ft

Step-by-step explanation:

Tangent 25 = opposite / adjacent

tan 25 = height/100

Height = 100 tan 25 = 46.63 feet ABOVE the head of the victim

victim head height = 5 ft

46.63 + 5 = 51.63 ft

The system of equations that models the given situation is given as follows:

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

He had 25 customers, hence:

x + y = 25.

He charges $15 for a single lawn and $25 for a front and back lawn, and made a total of $475, hence:

15x + 25y = 475

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Answer:

16 square units

Step-by-step explanation:

16 square units

Hey there!

4 3/5 - 2 5/6

= 23/5 - 17/6

= 53/30

≈ 1 23/30

Therefore, the answer should be:

53/30

OR

1 23/30

(Either should work because they are equivalent to each other)

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Value of the given mixed fraction [tex]4\frac{3}{5} -2\frac{5}{6}[/tex] is equals to [tex]1\frac{23}{30}[/tex] .

" Mixed fraction is defined as the fraction representing whole fraction along   with the quotient and remainder."

Convert mixed fraction into improper fraction

[tex]m\frac{p}{q} = \frac{q*m+p}{q}[/tex]

According to the question,

Given mixed fraction,

   [tex]4\frac{3}{5} -2\frac{5}{6}[/tex]

Convert mixed fraction into improper fraction we get,

[tex]=\frac{23}{5} -\frac{17}{6} \\\\=\frac{138-85}{30} \\\\=\frac{53}{30}\\ \\= 1\frac{23}{30}[/tex]

Hence, value of the given mixed fraction [tex]4\frac{3}{5} -2\frac{5}{6}[/tex] is equals to [tex]1\frac{23}{30}[/tex] .

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Answer:

150

Step-by-step explanation:

Let :

⇒ The numbers can be denoted as x, 3x, and 5x

=============================================================

Solving :

⇒ It mentions their sum is 270

⇒ x + 3x + 5x = 270

⇒ 9x = 270

⇒ x = 30

=============================================================

Largest number :

⇒ 5x

⇒ 5(30)

⇒ 150

Answer :

Step by step explaination :

Here we have been given with the ratio of three numbers that is 1 : 3 : 5. So let us assume a common factor for them , we are assuming it as y.

Therefore,

Sum of them is 270 :

>> 1y + 3y + 5y = 270

>> 4y + 5y = 270

>> 9y = 270

>> y = 270 / 9

>> y = 90 / 3

>> y = 30

Henceforth, value of y is 30.

★ Finding out first number :-

>> First number = 1y

>> First number = 1 × 30

>> First number = 30

★ Finding out second number :-

>> Second number = 3y

>> Second number = 3 × 30

>> Second number = 90

★ Finding out third number :-

>> Third number = 5y

>> Third number = 5 × 30

>> Third number = 150

area of square = s×s

9×9

81cm²

hope it helps...!!!

Answer:

81 cm^2

Step-by-step explanation:

A square is a 2d shape with side lengths all the same.

To find the area, all you need is one side length, which is 9cm in this case.

Then you just square the number (9 x 9) to get 81 cm^2 (centimetre squared).

Answer:

90

Step-by-step explanation:

The angles are on either side of the line are in proportion.

Hence,

⇒ [tex]\frac{10}{8} = \frac{x}{72}[/tex]

⇒ [tex]\frac{5}{4} = \frac{x}{72}[/tex]

⇒ [tex]x = \frac{5 \times 72}{4}[/tex]

⇒ [tex]x = 5 \times 18[/tex]

⇒ x = 90

Let's see

[tex]\\ \rm\Rrightarrow \dfrac{8}{10}=\dfrac{72}{x}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{4}{5}=\dfrac{72}{x}[/tex]

[tex]\\ \rm\Rrightarrow 4x=360[/tex]

[tex]\\ \rm\Rrightarrow x=90[/tex]

Answer:

A. Half of

B. Twice

C. greater than

Step-by-step explanation:

The median of the box plot is the middle line of the box, so for set a it is approximately ten and for set b it is approximately 20. 10 is half of 20 and 20 is twice as much as 10.

Hope this helps

Simplification form of the provided expression is -x⁴-2x³+2x+5 option (B) is correct.

It is defined as the combination of constants and variables with mathematical operators.

The options are:

A) -x⁴ - 2x - x + 2

B) -x⁴ - 2x³ + 2x + 5

C) -2x³ + 1

D) -x - 2x² + 2x + 5

We have an expression:

= (x + 3) - [(x + 2)(x³ - 1)]

[tex]\rm =x+3-\left(x+2\right)\left(x^3-1\right)[/tex]

[tex]\rm =x+3-x^4+x-2x^3+2[/tex]

[tex]\rm =-x^4-2x^3+2x+3+2[/tex]

[tex]\rm =-x^4-2x^3+2x+5[/tex]

Thus, simplification form of the provided expression is -x⁴-2x³+2x+5 option (B) is correct.

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Answer:

ok soo

Step-by-step explanation:

45, 56, 61, 75

middle of 56 and 61 add them so 117 then half 117 which is 58.5-

Step-by-step explanation:

volume of a sphere is given by 4/3 × pi × r³

hence, the answer is 523.33

comment if you have any doubts

Work Shown:

[tex]V = (4/3)*\pi*r^3\\\\V \approx (4/3)*3.14*5^3\\\\V \approx 523.33\\\\[/tex]

Step-by-step explanation:

please mark me as brainlest

How you do it is add the 44% of 132 to 132 (132 + (132×44%))

First you have to find out how much 44% is. Change it into decimal form (0.44) and then multiply the two together. 132 × 0.44 is 58.08 miles. Then you add that to the rest of the trip, 132 miles. (132 + 58/08 is 190.08)

Answer: y = 60

the value of y will be 60 when the value of x is 1.

Solution set = (1 , 60)

hope that helps...

Question 1

Question 2

The volume of the given cylinders.

[tex]\huge\boxed{Formula: V=\pi{r}^{2}h}[/tex]

[tex]\huge\boxed{\red \pi \red = \red 3 \red . \red 1 \red 4}[/tex]

Let's solve!

Substitute the values according to the formula.

[tex]V=3.14×{3}^{2}×9[/tex]

[tex]\large\boxed{V= 254.34 \: {ft}^{3}}[/tex]

Let's work on question 2

Substitute the values according to the formula.

[tex]V=3.14×{13}^{2}×8[/tex]

[tex]\large\boxed{V= 4245.28 \: {yd}^{3}}[/tex]

[tex]~~~\left(\sqrt 2 + \sqrt 8 \right)^2\\\\=\left(\sqrt 2 \right)^2 + \left(\sqrt 8 \right)^2 +2 \sqrt 2 \sqrt 8\\\\=2+8+2\sqrt{2 \cdot 8}\\\\=10+2\sqrt{16}\\\\=10+2(4)\\\\=10+8\\\\=18[/tex]

Answer:

x=1 y=1

Step-by-step explanation:

Let's use the elimination method.
3x+4y=7
2x-y = 1 (multiply both sides by 4)
8x-4y=4
3x+4y=7

(add both equations together)
11x=11
x=1
Plug x=1 into either of the equations
2(1) - y=1
2-y=1
2=1+y
y=1

The equation is y = 27x. The amount she pays for an 8-day rental will be $ 216. Then the domain and range will be (0, ∞) and (0, ∞).

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

Connie Nardelli rents a car for $27 per day.

The total cost is a function of the number of days she rents the car.

Let x be the number of days ad y be the total rent cost.

Then the equation will be

y = 27x

The amount she pays for an 8-day rental will be

y = 27 × 8

y = 216

The domain and range will be (0, ∞) and (0, ∞).

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Answer:

-2.6

Step-by-step explanation:

-1.4+(-1.2)

-1.4-1.2=-2.6

Hope this helps!

If not, I am sorry.

The range of a function is the set of all output values.

A function is a relation where each input value is assigned to only one output value.

The domain of a function is the set of all input values, or x-values, for which the function is defined.

The range of a function is the set of all output values, or y-values, for which the function is defined.

To write the equation y = ax + b in function notation, substitute f(x) for y.

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Answer:

[tex](x+5)^2+y^2=117[/tex]

Step-by-step explanation:

Equation of a circle

[tex](x-a)^2+(y-b)^2=r^2[/tex]

(where (a, b) is the center and r is the radius)

Given:

[tex]\implies (x-(-5))^2+(y-0)^2=r^2[/tex]

[tex]\implies (x+5)^2+y^2=r^2[/tex]

To find r², input the coordinates of the given point (4, -6) into the equation:

[tex]\implies (4+5)^2+(-6)^2=r^2[/tex]

[tex]\implies 81+36=r^2[/tex]

[tex]\implies r^2=117[/tex]

Therefore, the equation of the circle is:

[tex]\implies (x+5)^2+y^2=117[/tex]

Answer:

Standard form = (x + 5)² + y² = 117

General Form = x² + 10x + y² - 92 = 0

Explanation:

(x - h)² + (y - k)² = r²

Find radius using:

[tex]\sf Distance \ between \ two \ points = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]

[tex]\rightarrow \sf radius : \sqrt{(-5-4)^+(0-(-6))^2} \ = \ 3\sqrt{13} \ \ units[/tex]

Find equation inserting values:   Given center: (-5, 0)

⇒ (x - (-5))² + (y - 0)² = (3√13)²

⇒ (x + 5)² + y² = 117

⇒ x² + 10x + 25 + y² - 117 = 0

⇒ x² + 10x + y² - 92 = 0

The true statement about the pumpkin include:

The median is a value or quantity lying at the midpoint of a frequency distribution of observed values or quantities.

Here, the median pumpkin weight is 35 lb and 75% of pumpkins in the sample have weights higher than the mean.

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Answer:

B

Step-by-step explanation:

When you have a double negative (ie. 5 -(-10)) they cancel eachother out and become a plus. If you have + and - together, its always a minus, if you have + and + or - and -, its always plus.

Since in 4-(-3), the two minuses cancel each other out and become a plus, you move 3 to the right, since right is the positive direction.

subtracting a negative number changes the equation to an addition.

4 -(-3) becomes 4 + 3 = 7

you would start at 4 and move 3 places to the right.

the answer is B.

Step-by-step explanation:

Here is the solution...hope it helps:)

Answer:

Yes

Step-by-step explanation:

1. Yes , the data franchise owner is collecting, will be helpful in order to counter the criticism from the critic. As he has a record for every delivery they are making on daily basis.

2. The scenario is that for every fifth customer , the owner cross the four lines he makes. Thus a pack of five and easy to remember. As the data on regular week days is less, As can do the same for the third customer. Crossing the 2 lines for 3rd customer.

3. With this provision of crossing the third customer, the owner can have a better check on the late delivery. As it will bring in his notice earlier as compared to fifth crossing.

4. With the data as provided in the table, we can come to the conclusion that on weekends , i.e. both on time delivery and late deliveries are high in numbers. It must be because of high demand on that days. So owner must make some provision like hiring some more delivery boys for weekend in order to reduce the late deliveries.

[tex]~~2^{-5} \cdot 2^8\\\\=2^{-5+8}~~~~~~~~~~~~~~~~~~~~~;[a^m \cdot a^n = a^{m+n}]\\\\=2^3[/tex]

The matched pair of rational numbers are as follows;

[tex]\frac{-2}{a^{2}b }+\frac{2}{ab^{2} } = \frac{2(a-b)}{a^{2}b^{2} }[/tex]

[tex]\frac{1}{2ab} +\frac{-1}{4a^{2} b^{2} } =\frac{2ab-1}{4a^{2}b^{2} }[/tex]

[tex]\frac{2}{a^{2} b^{3} } +\frac{-2}{ab} =\frac{2(1-ab^{2} )}{a^{2} b^{3} }[/tex]

[tex]\frac{1}{ab^{3} } +\frac{-1}{a^{2} b} =\frac{a-b^{2} }{a^{2}b^{3} }[/tex]

The matched pair of rational numbers are as follows:

[tex]\frac{-2}{a^{2}b }+\frac{2}{ab^{2} } = \frac{-2b+2a}{a^{2} b^{2} } = \frac{2(a-b)}{a^{2}b^{2} }[/tex]

[tex]\frac{1}{2ab} +\frac{-1}{4a^{2} b^{2} } =\frac{2ab-1}{4a^{2}b^{2} }[/tex]

[tex]\frac{2}{a^{2} b^{3} } +\frac{-2}{ab} =\frac{2 - 2ab^{2} }{a^{2}b^{3} } =\frac{2(1-ab^{2} )}{a^{2} b^{3} }[/tex]

[tex]\frac{1}{ab^{3} } +\frac{-1}{a^{2} b} =\frac{a-b^{2} }{a^{2}b^{3} }[/tex]

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