Use the following information to answer questions 6 and 7:
A61.0 kg grocery cart is sitting at rest. In order to change the cart's state of motion, Xavier must apply 72.1
Newtons of force on the cart.
6. How much magnitude of force does the cart exert back on Xavier's hand?
A. 4400 N
B. 1.20 N
C. 72.1 N
D. 0.00 N
After 10 seconds, the dirt has achieved a velocity of +3.62 m/s. Xavier is still applying 72.1 Not force on the
cart.
7. Xavier's sister Maria claims that the cart is in dynamic equilibrium. Is Maria correct?
A Maria is correct because the cart is traveling at a constant velocity while experiencing balanced
forces.
B. Maria is correct because the cart's velocity has changed.
C. Maria is incorrect because the cart is traveling at a constant velocity while experiencing
unbalanced forces.
D. Maria is incorrect because the cart's velocity has changed
Question 6
C. 72.1 N
Its simply the newton Third law, whenever two objects interact, they exert equal and opposite forces on each other.
Question 7
D. Maria is incorrect because the cart's velocity has changed
The car is accelerating so, It is not in dynamic equilibrium. Remember that by the Newton Second Law:
F = ma
The cart is in dynamic equilibrium. The correct options for the two question are:
6. C
7. A
6.) Given that a 61.0 kg grocery cart is sitting at rest. And Xavier applied 72.1 Newtons of force on the cart.
According to Newton's third law of motion which state that, in every action, there will be equal and opposite reaction. The magnitude of force That the cart exert back on Xavier's hand will be opposite and equal to the force applied. which is negative 72.1 N
7.) If the grocery cart is moving in a constant velocity, then it will achieve a dynamic equilibrium. In this scenario, the air resistance force balances with the applied force.
Therefore, Maria is correct because the cart is traveling at a constant velocity while experiencing balanced forces.
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In a physics lab experiment for the determination of moment of inertia, a team weighs an object and finds a mass of 4.67 kg. They then hang the object on a pivot located 0.180 m from the object's center of mass and set it swinging at a small amplitude. As two of the team members carefully count 129 cycles of oscillation, the third member measures a duration of 249 s. What is the moment of inertia of the object with respect to its center of mass about an axis parallel to the pivot axis
Answer:
The value is [tex]I_o = 0.6257 \ kgm^2[/tex]
Explanation:
From the question we are told that
The mass of the object is [tex]m = 4.67 \ kg[/tex]
The position of the pivot from the center of the mass is [tex]a = 0.180 \ m[/tex]
The number of cycles of oscillation is [tex]n = 129 \ cycles[/tex]
The time taken for the total oscillation is t =249 s
Generally the period of the oscillation is mathematically represented as
[tex]T = \frac{t}{n}[/tex]
=> [tex]T = \frac{249}{129}[/tex]
=> [tex]T = 1.9302 \ s[/tex]
Generally the moment of inertia of the object about the end of the suspension is mathematically represented as
[tex]I =[ \frac{T}{2 \pi } ]^2 * [m* g * l ][/tex]
=> [tex]I =[ \frac{1.9302}{2 *3.142 } ]^2 * [4.67* 9.8 * 0.180 ][/tex]
=> [tex]I = 0.777 \ kg m^2[/tex]
Generally the moment of inertia of the object with respect to its center of mass about an axis parallel to the pivot axis is mathematically evaluated using the parallel axis theorem as
=> [tex]I_o = I- I_p[/tex]
Here [tex]I_p[/tex] is parallel axis contribution which is mathematically represented as
[tex]I_p = m * l^2[/tex]
=> [tex]I_p = 4.67 * 0.180^2[/tex]
=> [tex]I_p = 0.1513 \ kg m^2[/tex]
So
[tex]I_o = I- I_p[/tex]
=> [tex]I_o = 0.777 -0.1513[/tex]
=> [tex]I_o = 0.6257 \ kgm^2[/tex]
A fruit bat falls from the roof of a cave. We know that her potential energy was
600 J, and that the roof of the cave was 12.8 meters high. What is her velocity
when she hits the ground?
Answer:
v = 15.65 m/s
Explanation:
We use conservation of mechanical energy between initial (i) and final (f) states:
Pi + KEi = Pf + KEf
At the top of the cave at the instant the bat starts to fall, there is only potential energy since the bat's velocity is zero.
Pi = m g h = 600 J
and the KEi = 0 J (no velocity)
Knowing the height of the cave's roof (12.8 m) , we can find the mass of the bat:
m = 600 J / (g 12.5) = 4.9 kg
Using conservation of mechanical energy, the final state is:
Pf + KEf = 600 J
with Pf = 0 (just touching the ground)
KEf= 1/2 4.9 (v^2)
and we solve for the velocity:
600 J = 0 + 1/2 4.9 (v^2)
v^2 = 600 * 2 / 4.9 = 244.9
v = 15.65 m/s
The weight of the bricks is 5000N. Calculate the mass of the bricks.
(1 kg weighs 10N)
Answer:
500kg
Explanation:
....................
Answer:
500Kg
Explanation:
1 kg = 10N
? =5000N
5000N÷10N * 1Kg = 500Kg
Why when i take "The FitnessGram Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. A single lap should be completed each time you hear this sound. Remember to run in a straight line, and run as long as possible." i don't fall flat on my face?
Answer:
NOOOOOOO NOT THE PACER TEST!!
Explanation:
MEMORIES OF MIDDLE SCHOOL I'D LIKE TO FORGET
also. LOL "Remember to run in a straight line" BRUH WE KNOW XDXD
The skateboarder weighs 75 kilogram. Calculate the potential energy of the skateboarder sliding on the track when his height above the ground is 5 meters. (Assume that acceleration due to gravity is 9.81m/s2.)
Answer:F(of gravity) = MA
F(normal force) = MA * cos(angle)
F = 72 * 9.81 * cos28
Don't have a calculator, so can't really do all the math right there. So just plug that in
Explanation:
i dont really know
Potential energy of a body is the product of its mass, height and acceleration due to gravity. The potential energy of 75 Kg skateboard sitting at 5 meter high is 3675 J.
What is potential energy?
Potential energy of a body is generated by virtue of the position of the body. It is dependent on the mass of the body and the height at which it is placed and the acceleration due to gravity.
Whereas kinetic energy of an object is a form of energy generated by virtue of the motion of the object. Kinetic energy is dependent on the mass and velocity of the body.
It is given that the mass of the object is 75 Kg and the height from the surface is 5 m. Acceleration due to gravity on earth is 9.8 m/s².Thus, the potential energy is calculated as follows:
p = m g h
= 75 Kg × 9.8 m/s² × 5 m
= 3675 J.
Therefore, the potential energy of the skateboard is 3675 J.
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if u want to play among us have fun the code is UQEZFF
Answer:
ight bet
Explanation:
A solid disk rotates in the horizontal plane at an angular velocity of 0.649 rpm with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.101 kg m2. From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.415 m from the axis. The sand in the ring has a mass of 0.499 kg. After all the sand is in place, what is the angular velocity of the disk
Answer:
The angular velocity of the disk is 0.0369 rad/sec.
Explanation:
Convert 0.649 rpm to rad/s
0.649 rpm = 0.649 * (2π/60) = 0.0679rad/sec
From the question,
Summation of final angular momentum equals summation of initial angular momentum
I*w = Io*wo
w = wo (lo/I)
But I = Isand + Io
and Isand = Msand * R²sand
Therefore, w = wo (lo/I) = wo (Io/Msand * R²sand + Io)
Where,
wo = 0.0679rad/sec
Io = 0.101 kg m2
Msand = 0.499 kg
Rsand = 0.415 m
Hence,
w = 0.0679 {0.101/(0.499*(0.415)²+0.101)}
w = 0.0679 (0.101/0.1869)
w = 0.0679*0.544 = 0.0369 rad/sec
The angular velocity of the disk is 0.0369 rad/sec.
10. A 90 kg box is sliding across a surface at a constant velocity while experiencing a rightward applied
force of 40 N. Calculate the force of friction acting on the box.
A. -40N
B. +40N
C.-2.5 N
D. 0 N
If the box is moving at constant velocity, net force must be zero, so:
F + fr = 0
fr = -F
fr = -40 N
.
Calculate the potential energy of a 6 kg bowling ball suspended 3 m above the surface of the Earth.
Answer: 176.4 J
Explanation:
A ball weighing 60 N is swinging like a pendulum at the end of a 6.0 m rope. As the ball swings through its lowest point, its speed is measured at 5.0 m/s. What is the tension in the rope at this point?
A. 58.6 N
B. 85.4 N
C. 90.2 N
D. 97.3 N
Answer:
B. 85.4 N
Explanation:
The tension in the rope at the lowest point of the motion of the ball is antiparallel to the weight of the ball. By Newton's laws we construct the following equation of equilibrium:
[tex]\Sigma F = T - W = \left(\frac{W}{g} \right)\cdot \frac{v^{2}}{L}[/tex] (1)
Where:
[tex]T[/tex] - Tension in the rope, measured in newtons.
[tex]W[/tex] - Weight, measured in newtons.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]v[/tex] - Speed of the ball, measured in meters per second.
[tex]L[/tex] - Length of the rope, measured in meters.
If we know that [tex]W = 60\,N[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]v = 5\,\frac{m}{s}[/tex] and [tex]L = 6\,m[/tex], then the tension in the rope at this point is:
[tex]T = W+\frac{W\cdot v^{2}}{g\cdot L}[/tex]
[tex]T = W\cdot \left(1+\frac{v^{2}}{g\cdot L} \right)[/tex]
[tex]T = (60\,N)\cdot \left[1+\frac{\left(5\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot (6\,m)} \right][/tex]
[tex]T = 85.492\,N[/tex]
Hence, the correct answer is B.
Question 10 of 10
In the photoelectric effect, an electric current forms when light strikes a metal
surface. Which statement explains what causes the current?
O A. Electrons flow from one atom to another because the light acts as
a wave.
O B. The light causes electrons to flow in different directions within an
atom because light acts as a wave.
O C. Electrons are destroyed when light strikes a surface because the
light acts as particles.
D. Electrons are knocked off the surface when light strikes it because
the light acts as particles.
Explanation:
D. I hope i helped it should be right but if it isn't my bad
In the photoelectric effect, an electric current forms when light strikes a metal surface because electrons are knocked off the surface when light strikes it because the light acts as particles, The correct option is D.
What is the photoelectric effect?
It is the process of emission of electrons from the material because of absorption of electromagnetic radiation in form of photons of light waves.
The photoelectric effect explains the particle behavior of the light waves.
The photoelectric effect is responsible when electrons are knocked off the surface when light strikes it because the light acts as particles.
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Can you help with this question please
Answer:
First answer to the first question is Two people pulling a rope with the same force in a opposite direction. The other one would be 2.72N
Explanation:
Hope this helps you :)
you are driving at 18m/s down Lyndale avenue. A car backs out a driveway 25 meters in front of you. You continue at that speed while your brain processes the danger which takes 0.25 seconds. You then slam on the brakes and your car has an acceleration of -5.4m/s^2. Do you stop before reaching the driveway(and hitting the car)? Show your work. This is a two-part problem with constant speed and braking.
Hello!
For this, first let's calculate time of stop:
t = (V - Vi) / a
Replacing:
t = (0 m/s - 18 m/s) / -5,4 m/s^2
Resolving:
t = -18 m/s / -5,4 m/s^2
t = 3,33 s + 0,25 s = 3,58 s
Now lets calculate distance traveled, with formula:
d = Vi*t + (a*t^2)/2
Replacing:
d = 18 m/s * 3,58 s + (-5,4 m/s^2 * (3,58 s)^2) /2
Resolving:
d = 64,44 m + (-34,604 m)
d = 29,83 m
Then, the vehicle will CRASH
1. express the following in proper SI form using the appropriate prefixes. a. 52500000 m b. 1000 g c. 2435200000
Answer:
a
[tex]L = 5.25*10^{7} \ m[/tex]
b
[tex]m = 1 \ kg[/tex]
c
[tex]t = 1.46112000000 *10^{11} \ s[/tex]
Explanation:
From the question we are told that
Length is L = 52500000 m
Mass is
Time is 2435200000 minutes
Generally the proper SI for length is meters ,
Now converting the given length to proper SI form using the appropriate prefixes we have that
[tex]L = 5.25*10^{7} \ m[/tex]
Generally the proper SI for mass is kilograms
converting grams to kilograms , we have
[tex]m =\frac{1000}{1000 }[/tex]
=> [tex]m = 1 \ kg[/tex]
Generally the proper SI for time is seconds
converting minutes to seconds , we have
[tex]t = 24352000000* 60[/tex]
=> [tex]t = 146112000000 \ s[/tex]
Now converting to the proper SI form using the appropriate prefixes
[tex]t = 1.46112000000 *10^{11} \ s[/tex]
Obesity and stress are confirmed risk factors for which of the following?
lost of nutrition in human
Answer:
True
Explanation:
Obesity and stress are confirmed risk factors for CHD
A 60-W light bulb radiates electromagnetic waves uniformly in all directions. At a distance of 1.0 mfrom the bulb, the light intensity is I0, the average energy density of the waves is u0, and the rms electric and magnetic field values are E0 and B0, respectively.
At 2.0 m from the bulb, what is the light intensity?
Answer:
I0/4
Explanation:
If the difference is increasedby a factor of two(i.e twice it's original value), then the light intensity happens to get reduced by one-fourth. This means that the light intensity would be:
I0/4
What energy transformation takes place in the
solar panel?
1. A 3.8 kg scooter moves with a constant acceleration of 2.5 m/s”. Determine the net
applied force responsible for the acceleration.
Answer:
9.5 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 3.8 × 2.5
We have the final answer as
9.5 NHope this helps you
Translatory motion and Circular motion difference between
Correct question is;
What is the difference between Translatory motion and Circular motion.
Answer:
Outlined below
Explanation:
Circular motion is the motion whereby all the particles of a body move along the circumference of a circle while Translatory motion is one in which all particles move in a straight line or a curved fixed part.
Another difference is that in circular motion, the distance moved by all particles vary based on the distance moved from the centre of the circle while in Translatory motion, the distance covered by all particles is equal.
If a neutral atom has 25 protons in its nucleus. What is the number of surrounding electrons? Explain your answer.
Answer:
25 electrons.
Explanation:
In a neutral atom, the number of protons is equal to the number of electrons, therefore there are 25 protons and 25 electrons.
Final Answer: 25 electrons
Explanation/Reasoning:
Hey there!
The number of protons in the nucleus of a neutral atom would have 25 protons. This is because it is equal to the atomic number.
The number of protons is equal to the number of electrons. So for our answer, the number of atoms in a neutral atom will be 25 electrons because the neutral atom had 25 protons.
~I hope I helped you :)~
Which is an example of a chemical change?
frying an egg
boiling water
melting butter
chopping onions
Answer:
Frying an Egg
Explanation:
When chemical bonds are broken or formed, new particles are created. Therefore, frying an egg is a chemical change because it results in the formation of new particles.
Frying an egg is an example of chemical change. Therefore, option (A) is correct.
What is the chemical change?A chemical change can be described as a change in which a chemical substance is converted into one or more new types of substances. Chemical changes occur through chemical reactions that result in substances with different properties.
Chemical changes are irreversible in nature and are also called permanent changes in which an entirely new substance is formed. We have three kinds of chemical change organic, biochemical and inorganic.
While frying an egg, the egg changes from a fluid to a strong one. The egg changes from a fluid protein into a strong mass. Actually, the strands of protein extend, permitting the protein to denature by breaking the chemical bonds and formation of a new product.
Therefore, Frying an egg is a chemical change while boiling water, melting butter, and chopping onions are physical changes.
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What is the slope of the line that passes through the points (-8, -3)(−8,−3) and (-12, -3) ?(−12,−3)? Write your answer in the simplest form.
single black dude
Notice that both of those points are 3 units below the x-axis. So the line is horizontal ... its slope is zero.
the surface of objects in contact are not completely smooth true or false
Answer:
true objects in contact are not completely smooth
2/3
If the crate has a mass of 80 kg, how much would it weigh?
A ray moving in water at 55.5 deg
enters plastic, where it bends to
48.7 deg. What is the index of
refraction for the plastic?
( water n = 1.33, Air n = 1.00 )
Answer:
Refractive index of the plastic = 1.46
Explanation:
By Snell's law,
[tex]\frac{\text{sin}\theta _{2} }{\text{sin}\theta _{1}}=\frac{n_1}{n_2}[/tex]
Here, [tex]\theta _1[/tex] = Angle of incidence in medium 1 (Plastic)
[tex]\theta_2[/tex] = Angle of refraction in medium 2 (Water)
[tex]n_1[/tex] = Refractive index of medium 1 (Plastic)
[tex]n_2[/tex] = Refractive index of medium 2 (Water)
By substituting values in the formula,
[tex]\frac{\text{sin}(48.7)}{\text{sin}(55.5)}=\frac{1.33}{n_2}[/tex]
[tex]n_2=\frac{1.33\times \text{sin}(55.5)}{\text{sin}(48.7)}[/tex]
= 1.46
Therefore, refractive index of the plastic = 1.46
A car of mass 1150 kg drives in a circle of radius 44 m. If the car has a speed of 13 m/s, what is the
centripetal force acting on the car?
Answer:
4417
i think because
mv^2/r is centripetal force
How does solar energy impact the environment? Use in your own words.
give an example of a normal force. type below.
Normal force is the force exerted when an object is on an surface. So an example could be a pile of books on top of a table.
A bowling ball weighing 71.2 N is swinging like a pendulum at the end of a 3.8 m rope. As the ball swings through its lowest point, its speed is measured at 4.2 m/s. What is the magnitude and direction of the acceleration of the ball at this point?
At its lowest point, the ball feels a downward force due to its weight of 71.2 N and an upward force of tension from the rope. Its motion is circular, so that the net radial acceleration is felt upward toward the center of the circle.
With a tangential speed of 4.2 m/s at the lowest point, its radial acceleration has magnitude
a = (4.2 m/s)² / (3.8 m) ≈ 4.6 m/s²