Is lotion pure or impure?

Answer:

Because metal can not decompose!

Answer:

[tex]Kc\frac{(Ba3N2)(H2O)^6}{(Ba(OH)2)^3(NH3)^2}[/tex]

Explanation:

Because kc equals products/reactants hope this helps :)

put the glass lid on and turn or turn down the heat

Answer:

In chemistry, neutralization or neutralisation is a chemical reaction in which acid and a base react quantitatively with each other. In a reaction in water, neutralization results in there being no excess of hydrogen or hydroxide ions present in the solution.Neutralization reactions are the reaction between acid and base. The products formed are water and salt. It is called so because the acid and base neutralize each other to form water and salt.Hint: The neutralization reaction is the one in which an acid reacts with an equimolar amount of base to give salt and water. The example could be a reaction between any strong acid and a base. The sodium chloride formed is a result of neutralization reaction.

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Answer:

Zinc, Cerio, Talio, Cloro y Criptón.

Explicación:

El zinc es el elemento que tiene el número atómico 30 y su símbolo es Zn. Se encuentra en el grupo 2B de la tabla periódica. El cerio es el elemento que tiene el número atómico 58 y su símbolo es Ce. Se encuentra en el grupo de lantánidos de la tabla periódica. El talio es el elemento que tiene el número atómico 81 y su símbolo es Tl. Se encuentra en el tercer grupo de la tabla periódica. El cloro es el elemento que tiene el número atómico 17 y su símbolo es Cl. Se encuentra en el séptimo grupo de la tabla periódica. El criptón es el elemento que tiene el número atómico 36 y su símbolo es Kr. Se encuentra en el grupo de gases nobles, es decir, en la tabla periódica del octavo grupo.

Answer:

BaBr2 (aq) + H2SO4 (aq) → BaSO4 (s) + 2 HBr (aq)

Explanation:

This is a precipitation reaction: BaSO4 is the formed precipitate.

Answer:

75.9 grams of salt

Explanation:

The reaction is the following:  

2Na(s) + Cl₂(g) → 2NaCl(s)   (1)

We have:

m(Na): the mass of sodium = 30 g

V(Cl₂): the volume of the chlorine gas at STP = 60 L

So, to find the mass of NaCl we need to calculate the number of moles of Na and Cl₂.

[tex] n_{Na} = \frac{m}{A_{r}} = \frac{30 g}{22.99 g/mol} = 1.30 moles [/tex]

The number of moles of Cl₂ can be found by the Ideal gas law equation:

[tex] PV = n_{Cl_{2}}RT [/tex]

Where:

P: is the pressure = 1 atm (at STP)

R: is the gas constant = 0.082 L*atm/(K*mol)

T: is the temperature = 273 K (at STP)

[tex] n_{Cl_{2}} = \frac{PV}{RT} = \frac{1 atm*60 L}{0.082 L*atm/(K*mol)*273 K} = 2.68 moles [/tex]

Now we need to find the limiting reactant. From the stoichiometric relation between Na and Cl₂ (equation 1), we have that 2 moles of Na react with 1 mol of Cl₂, so:

[tex] n_{Na} = \frac{2 moles Na}{1 mol Cl_{2}}*2.68 moles Cl_{2} = 5.36 moles [/tex]

Since we have 1.30 moles of Na, the limiting reactant is Na.  

Finally, we can find the number of moles of NaCl and its mass.

[tex] n_{NaCl} = n_{Na} = 1.30 moles [/tex]

[tex] m_{NaCl} = n_{NaCl}*M = 1.30 moles*58.44 g/mol = 75.9 g [/tex]

Therefore, would be formed 75.9 grams of salt.

I hope it helps you!                

Answer:

the anwser is; B: increasing its speed

Answer:

I'm terribly sorry but the download is not working for me! All it says is Download pdf, and when I click it, It does nothing except for refreshing the page!

Explanation:

Answer:

sry, dk

Explanation:

Answer:

fractional distillation since ot depends on the different liquids to have different boiling points

Answer:

1.89 nol Cu(NO3)2

Explanation:

if you calculate it it will be 1.89

Fluorine has the highest electronegativity in comparison to other elements therefore, the F atom attracts electrons most strongly.

The electronegativity of an atom measures the tendency of an element to attract the bonded electrons pairs towards itself. The electronegativity of an atom is determined with respect to another bonded atom.

Electronegativity can be described as a chemical property of an atom or a functional group to attract electrons toward itself. The electronegativity of an atom depends on the atomic number and the distance of valence electrons from the charged nuclei.

When two different atoms are bonded through a bond. More electronegative will attract the electron density of the bond towards itself.

As we know, the electronegativity decreases as we move down the group in the periodic table. Fluorine is the most electronegative element in the periodic table therefore, Fluorine (F) will attract the electrons toward it most strongly.

Learn more about electronegativity, here:

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Answer: A

Explanation:

the melting point or boiling point of a substance at a specific pressure

Answer:

Bueno al principio pero empeorando con el paso del tiempo.

Explicación:

La calidad del aire es buena al inicio de la pandemia y hay menos infección en el aire pero con el paso del tiempo la infección se propaga a un ritmo más rápido y la calidad del aire se contamina con la infección que infecta a más personas. La pandemia reduce su intensidad cuando la gente sigue las reglas saludables que previenen la propagación de la pandemia en esa localidad por lo que podemos decir que la última semana de pandemia tiene menor número de pacientes.

Answer:

Gold and pyrite both have a brilliant metallic luster, but are different tones of yellow. Gold is golden to silvery yellow, whereas pyrite is a pale to medium brassy yellow that sometimes tarnishes.

Explanation:

Answer: 0.0016 moles of copper are present in copper gluconate

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of copper = 0.1 g

Molar mass of copper = 63.55 g/mol

Plugging values in equation 1:

[tex]\text{Moles of copper}=\frac{0.1g}{63.55g/mol}=0.0016 mol[/tex]

Hence, 0.0016 moles of copper are present in copper gluconate

Answer:

Explanation:

a ) If N₂(g) and 3H₂(g) is added to the system , 2 moles of additional  ammonia will be produced .

b ) If pressure is decreased , less amount of ammonia will be formed, because forward reaction reduces the pressure. So, reaction will take place in reverse direction.

c ) Keq = [ NH₃ ] ² / [ N₂ ] [ H₂]³

d ) Substituting the given values in the equation ,

Keq = [ 6M ] ² / [ 3M] [ 4M]³

= 36 / 3 x 64 M⁻²

= 18.75 x 10⁻² M⁻² .

Answer:

Explanation:

Down a group, the number of energy levels (n) increases, so there is a greater distance between the nucleus and the outermost orbital. This results in a larger atomic radius.

Answer:

Tussar silk

Charmeuse

Explanation:

Hope this helps! :)

Answer:

4000mL

Explanation:

Using the combined gas law equation as follows:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (mL)

V2 = final volume (mL)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information given in this question:

V1 = 1000mL

T1 = 20K

P1 = 1.0atm

V2 = ?

P2 = 0.5atm

T2 = 40K

Using P1V1/T1 = P2V2/T2

1 × 1000/20 = 0.5 × V2/40

1000/20 = 0.5V2/40

50 = 0.5V2/40

50 × 40 = 0.5V2

2000 = 0.5V2

V2 = 2000/0.5

V2 = 4000mL

Answer: The mass of lead (II) nitrate required is 74.52 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of lead (II) chloride = 62.6 g

Molar mass of lead (II) chloride = 278.1 g/mol

Plugging values in equation 1:

[tex]\text{Moles of lead (II) chloride}=\frac{62.6g}{278.1g/mol}=0.225 mol[/tex]

The chemical equation for the reaction of lead (II) chloride and sodium nitrate follows:

[tex]Pb(NO_3)_2+2NaCl\rightarrow PbCl_2+2NaNO_3[/tex]

By the stoichiometry of the reaction:

1 mole of lead (II) chloride is produced from 1 mole of lead (II) nitrate

Then, 0.225 moles of lead (II) chloride will react with = [tex]\frac{1}{1}\times 0.225=0.225mol[/tex] of lead(II) nitrate

Molar mass of lead (II) nitrate = 331.2 g/mol

Plugging values in equation 1:

[tex]\text{Mass of lead (II) nitrate}=(0.225mol\times 331.2g/mol)=74.52g[/tex]

Hence, the mass of lead (II) nitrate required is 74.52 g

Taking into account the molar mass of each elemente and ammonia, the correct answer is the first option: the percentage composition of each element in ammonia, NH₃ is 82.35% N; 17.65% H

First of all, molar mass is the mass of one mole of a substance, which can be an element or a compound. In the case of a compound, it is calculated by adding the atomic masses of the atoms that make up the molecule.

In this case, being the atomic mass of N equal to 14 and the atomic mass of H equal to 1, the molar mass of NH₃ is calculated as:

NH₃= 14 + 3* 1= 17

Now, to obtain the percentage composition of each element, you must divide each individual atom with the mass of ammonia and multiply by 100 to obtain the percentage:

N: [tex]\frac{14}{17} x100[/tex]

H: [tex]\frac{1x3}{17} x100[/tex] In this case, the atomic mass of hydrogen H is multiplied by 3 because 3 hydrogens are present in ammonia.

Solving:

N: [tex]\frac{14}{17} x100[/tex]= 0.8235×100= 82.35 %

H: [tex]\frac{3}{17} x100[/tex]= 0.1765×100= 17.65 %

Finally, the correct answer is the first option: the percentage composition of each element in ammonia, NH₃ is 82.35% N; 17.65% H

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Answer:

A

Explanation:

Opposite charges attract therefore the electrons of one atom would be attracted by the nucleus (which contains protons). This heavily relies on a property called electronegativity. Which deals with the level of attraction a nucleus (the protons in the nucleus) have for electrons of other atoms.

Answer:

your simpal answer is 177.32

Answer:

potential and chemical

Explanation:

Answer:

The energy absorbed in the first move is greater than the energy released in the second move

Explanation:

Electrons require (absorb) energy to move to a higher energy level when there is a large external heat source, the presence of an electric field or by colliding with other electrons

And the amount of energy absorbed by the electron is exactly equal to the change in the energy state between the initial energy level of the electron and the destination energy level

Therefore, given that the energy level of the electron at level 2 is higher than the energy level of the electron when at level 1, we have;

The difference in the energy level between level 4 and level 1 is greater than the difference in the energy level between level 4 and level 2 and more energy is absorbed and therefore, released when the electron moves from level 1 to level 4 than when the electron drops from level 4 to level 2.

The most likely result is that 'the energy absorbed in the first move is greater than the energy released in the second move'.