k5500 is invested for a period of 4 years in a savings account. for the first year , the investment grows at a simple interest rate of 11% per annum and then at a rate of 12.5% per annum compound and quarterly for the rest of the period. Determine the value of the investment at the end of the 4 years​

Answer:

X=-1

Y=1

Step-by-step explanation:

6x-12y

-18

) 6x + 4y

-

-2

Subtract the two equations

6x - 12y - (6x + 4y) = -18 - (-2)

Determine the sign

6x- 12y - 6x- 4y

=-18 + 2

Simplify

-12y

- Ay

=-18 + 2

Solve the equation

Substitute

6×+4

-2

Solve the equation

X=

Answer:

⇒8(x−1)=5x

⇒8x−x=5x

⇒8x−5x=8

⇒3x=8

⇒x=

3

8

The cost of packaging the box of chocolates per weight unit is;  ¹/₄x²/(x + 2)

We are given the cost of packing the box as;

C(x) = ¹/₄x²

where;

x is the number of chocolates

We are told that a box can never have fewer than 3 chocolates.

Now, the weight of a box of chocolates is given by; W(x) = x + 2

Thus, cost per unit weight is;

C(x)/W(x) = ¹/₄x²/(x + 2)

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Answer:

Option D graph

Step-by-step explanation:

x - 4 ≥ - 1

add 4 to both sides, x - 4 + 4 ≥ - 1 + 4

x ≥ 3

so x is greater than or equal to 3

- equal to means closed dot at 3

- greater than means arrow to the right of 3

Answer:

f(x) = -1/2x + 1

Step-by-step explanation:

y intercept is +1

For slope, used points on the graph (2,0) and (0,1)

m= y2-y1/x2-x1

= (1-0)/(0-2)

= -1/2

The graphed cosine function can either be:

cos(x + pi) or cos(x - pi).

We know that this function is a cosine function with a phase shift, so the general form is:

f(x) = cos(x + P).

Where P is the phase shift.

In the graph we can see that when x = 0, f(0) = -1

And we know that cos(pi) = -1 = cos(-pi)

Then we must have that:

f(0) = cos(P) = -1

By what we wrote above, we know that P can be either -pi or pi (because of the parity of the cosine). Let's say that P = pi, then the cosine function is:

f(x) = cos(x + pi).

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△STU is mapped to △PQR with center of dilation (-1.5, -1.5) and a scale factor of 2 and reflected about the x-axis.

From the given graph, we can see that;

SU is 1.5 units and the corresponding side of the dilated figure is 3 units. Thus, the scale factor of dilation is; 3/1.5 = 2

Now, we can see clearly that it is reflected about the x-axis as the x-values remain negative in △STU while the y-values are now positive in △PQR.

Lastly, we can see the dilation was with center (-1.5, -1.5)

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Answer:

-50

Step-by-step explanation:

1 - 2 + 3 - 4 + 5 - 6 + 7 - 8...99 - 100

just means,

1 - 2 = -1

3 - 4 = -1

5 - 6 = - 1

7 - 8 = - 1

99 - 100 = -1

basically, -1 + -1 + -1 + -1 + ....+ -1 or -1 - 1 - 1 - 1 - ... - 1

[tex](-1)^{n}[/tex]

Treating Grandi's series as a divergent geometric series we may use the same algebraic methods that evaluate convergent geometric series to obtain a third value:

S = 1 − 1 − 1 + ..., so

1 − S = 1 − (1 − 1 − 1 ...) = 1 − 1 − 1 ... = S

1 - S = S

1 = 2*S

resulting in S = 1/2. The same conclusion results from calculating −S, subtracting the result from S, and solving 2S = 1

1/2 of the last term is 100 x 1/2 = 50

This because you are using 2 numbers per -1

example: 1 - 2 = -1 or 3 - 4 = -1 resulting in 50 of the -1 being subtracted

Answer:

  (1/4, 5 7/8)

Step-by-step explanation:

The vertex is the extreme point of the graph. Here, it is a minimum.

For this quadratic function, a graphing calculator can tell you exactly what the vertex is. (No approximation is required.)

__

The graphing calculator in the attachment shows the vertex is ...

  (0.25, 5.875) = (1/4, 5 7/8)

Answer:

230 degrees

Step-by-step explanation:

draw a horizontal line from x and use congruent rule to have a full 360 degree circle. You can now subtract 60 and 70 from 360 degrees leaving you with 230 degrees as x

Answer:

The answer is origin

Answer: orgin

Step-by-step explanation:  orgin

Answer:

The 6 names to circle are:

The underlined letters from those circled names are:

The letters form the phrase [tex]\underline{\text{WR}}\ \underline{\text{ON}} \ \underline{\text{G}} \ \ \ \ \ \ \underline{\text{TU}} \ \underline{\text{RN}}[/tex]  or "wrong turn". The spacing is done like that in the first version to show the various subgroups of letters.

Unfortunately the mentioned riddle at the bottom is cut off, so I don't know what the riddle is.

======================================================

Explanation:

Here's a summary table:

[tex]\begin{array}{|c|c|} \cline{1-2}\text{Student} & \text{Are They Correct?}\\\cline{1-2}\text{Laverna} & \textbf{Yes}\\\cline{1-2}\text{Alfonso} & \textbf{Yes}\\\cline{1-2}\text{Autumn} & \textbf{Yes}\\\cline{1-2}\text{Willa} & \text{No}\\\cline{1-2}\text{Ignacio} & \textbf{Yes}\\\cline{1-2}\text{Napoleon} & \text{No}\\\cline{1-2}\text{Kathyrn} & \textbf{Yes}\\\cline{1-2}\text{Titus} & \text{No}\\\cline{1-2}\text{Lawrence} & \textbf{Yes}\\\cline{1-2}\end{array}[/tex]

Put another way, here are the people to circle (i.e. the people who made true statements):

In the order presented above, the letters underlined are:

Through a bit of trial and error, the letters make the phrase of:

[tex]\underline{\text{WR}}\ \underline{\text{ON}} \ \underline{\text{G}} \ \ \ \ \ \ \underline{\text{TU}} \ \underline{\text{RN}}[/tex]

I'm not sure what to do with the extra "RN". It might be a typo, or it might be the case your teacher wants you to ignore repeats like this.

The quantity of pure antifreeze that must be added to 2 quarts of a 20% antifreeze solution to obtain a 60% antifreeze solution 2 quarts

How to solve equation?

You have 2 quarts of 20% antifreeze.

(100%)x + (20%)2 = 60%(x + 2)

100x + 40 = 60(x + 2)

100x + 40 = 60x + 120

100x - 60x = 120 - 40

40x = 80

x = 80/40

x = 2 quarts

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The sequence is an arithmetic sequence and the expression used to find the nth term would be 3n option fourth I and II is correct.

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

We have a sequence:

3, 6, 9, 12…

First term a  = 3

Common difference d = 6 - 3 = 3

This is an arithmetic sequence.

nth term of the arithmetic sequence:

a(n) = 3 + (n-1)(3)

a(n) = 3n

Plug n = 5

a(5) = 3(5) = 15

Thus, the sequence is an arithmetic sequence and the expression used to find the nth term would be 3n option fourth I and II is correct.

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Answer:

y-intercept = 1, x-intercept= -1/4

Step-by-step explanation:

Default equation of line:

y = mx+c , where m is the slope and c is the y-intercept.

So first we will find the slope from the values given in the table.

slope of line  [tex]\frac{y1-y2}{x1-x2}\\= \frac{9-5}{2-1} \\= \frac{4}{1}\\ =4[/tex]

So take 1 random value of x and y from the table,

x =1 , y=5

5 = 4(1)+c

c = 5-4 = 1

so equation of line is y = 4x+1

and y intercept = 1

x intercept is the value of x when y = 0.

so given

y = 4x+1

0 = 4x+1

4x = -1

x = [tex]-\frac{1}{4}[/tex]

therefore x intercept = -1/4

Answer:

The bottom right line plot.

Step-by-step explanation:

In the table, 9 1/4 shows up twice. This can be represented in the line plot by putting 2 x's over the 9 1/4 point.

Answer:

Step-by-step explanation:

there is a 50/50 chance of getting a chocolate cupcake. :P

Because x is the number of boxes in the shipment, we conclude that the correct option is "the maximum weight allowed in a shipment"

Remember that for a function f(x), the y-intercept is given by f(0).

In this case, the graph represents the amount of allowed weight remaining in a shipment depending on the number of boxes of screws included.

Then the variable x represents "the number of boxes of screws in the shipment".

So when x = 0, there are no boxes.

Then the y-intercepts represents the remaining weight when there are no boxes of screws, which would be all the allowed weight on the shipment.

The correct option is:

"the maximum weight allowed in a shipment"

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Answer:

A

Step-by-step explanation:

the maximum weight allowed in a shipment

Answer:

radius = √13

Step-by-step explanation:

Forming the equation :

(x - h)² + (y - k)² = r²

Solving :

The quotient of 552/58 is 276/29.

The quotient of a number is the result or the outcome when you divide two numbers together.

From the given information, the quotient of [tex]\mathbf{\dfrac{552}{58}}[/tex] is can be determined by dividing both the numerator and the denominator by (2):

i.e.

[tex]\mathbf{=\dfrac{276}{29}}[/tex]

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a. A critical point at x = 25 would mean f'(25) = 0 or doesn't exist. We have derivative

[tex]f(x) = x - k \sqrt x \implies f'(x) = 1 - \dfrac k{2\sqrt x}[/tex]

so that

[tex]f'(25) = 1 - \dfrac k{2\sqrt{25}} = 1 - \dfrac k{10} = 0 \implies \boxed{k=10}[/tex]

b. Taking the second derivative, we get

[tex]f''(x) = \dfrac k{4 x^{3/2}} = \dfrac5{2 x^{3/2}}[/tex]

At x = 25, the second derivative has a positive sign,

[tex]f''(25) = \dfrac 5{2 \times 25^{3/2}} = \dfrac 5{2\times5^3} = \dfrac1{50} > 0[/tex]

which means f(x) is concave upward around x = 25, so this critical point is a local minimum.

Answer: not a triangle

Step-by-step explanation:

If this were to be a triangle, the shorter sides would be 11 and 4 and the longest side would be 16.

First, we should determine if it is a triangle.

The solution to the Raoul's equation x² - 6x - 27 = 0 is x = 9; or x = -3

An equation is an expression that shows the relationship between two or more numbers and variables.

Given the equation:

x² - 6x - 27 = 0

Adding 27 to both sides:

x² - 6x - 27 + 27 = 0 + 27

x² - 6x = 27

Adding to both sides the square of half the coefficient of x, that is 9:

x² - 6x + 9 = 27 + 9

(x - 3)² = 36

taking square root of both sides:

√(x - 3)² = √36

x - 3 = ±6

x = 3 ± 6

x = 3 + 6 or; x = 3 - 6

x = 9; or x = -3

The solution to the Raoul's equation x² - 6x - 27 = 0 is x = 9; or x = -3

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Answer:

4 radians

Step-by-step explanation:

[tex]s = \theta r[/tex]

[tex]20 = 5 \theta[/tex]

[tex] \theta = 4[/tex]

Answer:

[tex]\frac{1}{13}[/tex]

Step-by-step explanation:

Probability is the number of favorable outcomes divided by the number of total outcomes. The total outcomes are all the situations that could possibly happen. There are 52 cards in the deck, so there are 52 total outcomes. Next, the favorable outcomes are the outcomes we want. In this case it is drawing a 6. There are four 6's in a deck of cards: 6 of hearts, 6 of spades, 6 of diamonds, and 6 of clubs. This means there are 4 favorable outcomes.

We can write the probability as a fraction: [tex]\frac{favorable-outcomes}{total-outcomes}[/tex], so we can get [tex]\frac{4}{52}[/tex]. Since both 4 and 52 are divisible by 4, the fraction can be simplified to [tex]\frac{1}{13}[/tex].

Answer:

1/13

Step-by-step explanation:

that's the answer to the question

The simplified expression is [tex]\frac{-1}{9x} -9x - 10[/tex].

An algebraic expression in mathematics is an expression which is made up of variables and constants, along with algebraic operations (addition, subtraction, etc.).

Here, the given expression

           [tex]\frac{1}{x}+\frac{-10x/9}{x^2}-9x-10[/tex]

            [tex]\frac{1}{x}+\frac{-10}{9x}-9x-10[/tex]

             [tex]\frac{9-10}{9x} -9x -10[/tex]

                 [tex]\frac{-1}{9x} -9x - 10[/tex]

Thus, the simplified expression is [tex]\frac{-1}{9x} -9x - 10[/tex].

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Answer:

I think the letter B is a good idea for me to do the same as oneroure and I have a module that I can use to make sure that I have the right to use the periodic table to find the element name and its symbol then calculate the total amount of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between thank you

[tex]\begin{cases} u=6i-2j\\\\ v=-3i+7j \end{cases}\qquad \begin{cases} < 6~~,~~-2 > \\\\ < -3~~,~~7 > \end{cases} \\\\[-0.35em] ~\dotfill\\\\ u-v\implies < 6~~,~~-2 > ~~ - ~~ < -3~~,~~7 > \\\\\\ < 6-(-3)~~,~~-2-7 > \implies < 6+3,-9 > \implies < 9,-9 > \implies 9i-9j[/tex]

Answer:

q→p

Step-by-step explanation:

The converse of p→q is q→p.

which means If q ,then p.