Kamal said the distance from the top of the balloon to the ground in the Example is Ï···· 353 ft. What mistake might Kamal have made? 1 2
Answers
Complete question is;
Kamal said the distance from the top of the balloon to the ground in the Example image attached is √353 ft. What mistake might Kamal have made?
Answer:
the mistake Kamal made is that she probably used 17 ft as the perpendicular side of the triangle with b as the hypotenuse instead of using 17ft as the hypotenuse
Explanation:
From the image attached, we can see that the distance from the top of the balloon which is blue in color to the ground is denoted by "b".
Now the triangle is a right angle triangle with hypotenuse = 15ft + 2ft = 17 ft; the adjacent side = 8 ft, while the opposite side is "b".
Thus, we can use pythagoras theorem to solve this as;
b = √(17² - 8²)
b = √(289 - 64)
b = √225
b = 15ft
However,we are told Kamal got b as √353 ft.
From inspection of the calculations we just did, if we had used addition instead of subtraction, we would have gotten b = √353 ft.
Thus, we can under that the mistake Kamal made is that she probably used 17 ft as the perpendicular side of the triangle with b as the hypotenuse instead of using 17ft as the hypotenuse.
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Answer:
Part A
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Part B
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Explanation:
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Answers
Answer:
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Answers
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Answer:
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Answers
Answer:
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Explanation:
The capacitance on the parallel plate capacitor = C₀
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[tex]V = \dfrac{Q}{C}[/tex]
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∴ V = 2 × V₀
The new potential difference, V = 2·V₀
Therefore, after the plates are 2·d apart, the new capacitance and potential difference between the plates are;
1/2·C₀, 2·V₀.
At a distance of 2d, the potential difference will be twice the potential difference before while the capacitance will be half the value before.
Given to us
The capacitance on the parallel plate capacitor = C₀The area of the plate = AThe voltage on the battery = V₀The magnitude of the charge in the plate = Q₀The new distance between the plates = 2d What is Capacitance?We know capacitance can be written as,
[tex]C= \dfrac{\epsilon_0 A}{d}[/tex]
where C is the capacitance,
A is the area,
d is the distance and
ε₀ is the electrostatic constant,
Capacitance before,[tex]C= \dfrac{\epsilon_0 A}{d}[/tex]
Capacitance Afterwards,[tex]C= \dfrac{\epsilon_0 A}{2d}[/tex]
[tex]C=\dfrac{1}{2} \times \dfrac{\epsilon_0 A}{d}[/tex]
[tex]C=\dfrac{1}{2} \times C_0[/tex]
What is Voltage(Potential difference)?We know that for the voltage we can write,
[tex]\rm Voltage = \dfrac{Charge}{Capacitance}[/tex]
Voltage before[tex]V=\dfrac{Q_0}{C_0}[/tex]
Voltage Afterwards[tex]V_{new} = \dfrac{Q_0}{C_{new}}[/tex]
[tex]V_{new} = \dfrac{Q_0}{\dfrac{1}{2} \times C_0}[/tex]
[tex]V_{new} = 2 \times\dfrac{Q_0}{C_0}[/tex]
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Answers
Answer:
Momentum = 4455 Ns
Explanation:
Given the following data;
Force = 450 N
Time = 9.9 seconds
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According to Newton's second law of motion in terms of momentum states that the net force acting on an object is equal to change in momentum divided by time.
Mathematically, it is given by the formula;
Net Force = change in momentum/time
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Substituting into the formula, we have;
Momentum = 450 * 9.9
Momentum = 4455 Ns
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c
Explanation:
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C.
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Answers
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Answer: you ever get the awnser?
Explanation:
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What is the potential difference across a circuit that delivers 4.2A to a 500W motor?
Answers
Answer:
Thus, the potential difference is 119 V.
Explanation:
Current, I = 4.2 A
Power, P = 500 W
The rate of doing work is called power.
The SI unit of power is Watt.
The commercial unit of power is horse power.
1 horse power = 746 Watt
The formula of the electrical power is
P = V I
where, V is the voltage and I is the current.
Substitute the values in the formula
500 = 4.2 x V
V = 119 V