mostly located on the bottom of the leaf, open close the stomata
Answer:
Guard cells. The guard cells also contain chloroplast.
After the student closes the cooler, there NOT any inputs or outputs from this system because ________. a. no energy is being transferred into or out of the cooler b. there is no flow of energy across the system boundary c. there is no matter flowing into or out of the system d. all of the above
Answer:
d. All of the above
Explanation:
d. All of the above
A 66.4 gram sample of Ba(ClO4)2 3 H2O was heated thoroughly in a porcelain crucible, until its weight remained constant. After heating, how many grams of the anhydrous compound remained?
Answer:
57.2 g
Explanation:
First we convert 66.4 grams of Ba(ClO₄)₂·3H₂O into moles, using its molar mass:
Molar mass of Ba(ClO₄)₂·3H₂O = Molar mass of Ba(ClO₄)₂ + (Molar Mass of H₂O)*3Molar mass of Ba(ClO₄)₂·3H₂O = 390.23 g/mol66.4 g ÷ 390.23 g/mol = 0.170 mol Ba(ClO₄)₂·3H₂O0.170 moles of Ba(ClO₄)₂·3H₂O would produce 0.170 moles of 0.170 moles of Ba(ClO₄)₂. Meaning we now convert 0.170 moles of Ba(ClO₄)₂ into grams, using the molar mass of Ba(ClO₄)₂:
0.170 mol * 336.23 g/mol = 57.2 gTrue or false? All producers are at the top of the food web
Answer:
false all producers are at the top of food web
If 4.00 moles of O2 occupies a volume of 5.0 L at a particular temperature and pressure, what volume will 3.00 moles of oxygen gas occupy under the same condition?
Answer: Volume occupied by 3.00 moles of oxygen gas under the same condition is 3.75 L.
Explanation:
Given: [tex]n_{1}[/tex] = 4.00 moles, [tex]V_{1}[/tex] = 5.0 L
[tex]n_{2}[/tex] = 3.00 moles, [tex]V_{2}[/tex] = ?
Formula used is as follows.
[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{5.0 L}{4.00 mol} = \frac{V_{2}}{3.00 mol}\\V_{2} = 3.75 L[/tex]
Thus, we can conclude that volume occupied by 3.00 moles of oxygen gas under the same condition is 3.75 L.
which of these molecules is nonpolar?
Answer:
option b is your right answer
Sodium reacts vigorously with water while potassium, the next element down in Group I, has a faster reaction rate. What would you expect of the rate of reaction of elements further down in Group I when exposed to water?
a. They would react with the same rate as potassium.
b. They would react much faster than sodium or potasssium.
c. They would react more slowly than potassium.
d. The rate of reaction would be unpredictable
Answer:
c. They would react more slowly than potassium. It's because sodium reacts slowly with water!
Explanation:
i am giving you the answer according to the doubtnut channel!
c. They would react more slowly than potassium.
Because their ability to displace hydrogen will be less.
H2C=CH2 + H2 решение?
Answer:
[tex]CH _{3}CH _{3}[/tex]
Ethane
Drag the tiles to the correct boxes. Not all tiles will be used.
Match each Sl unit to the quantity it measures.
Answer:
1) Length - Meter
2) Mass - Pound
3) Time - Minute
Please Mark This As Brainliest!
*
The crystal structure of salt is
quimica espero que si sea corecta
What the correct answer
Answer:
[Ar] 4s²3d³
Explanation:
Vanadium has atomic number of 23. The electronic configuration of vanadium can be written as:
V (23) => 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d³
NOTE: After the 18th electron, 4s will be filled before 3d.
We can also write the electronic configuration of an element in its condensed form by writing the symbol of the noble before the desired element in a squared bracket followed by the remaining electrons to complete the electronic configuration of the element.
The electronic configuration of vanadium in its condensed form is given below:
The noble gas before vanadium is Argon (Ar) with atomic number of 18. Thus, the electronic configuration of vanadium becomes:
V (23) => [Ar] 4s²3d³
Draw the curved arrows showing a proton transfer reaction, and draw the products of that proton transfer. Do not include the Li counterion, and lone pairs are not required in the products.
Answer:
Draw the curved arrows showing a proton transfer reaction, and draw the products of that proton transfer. Do not include the Li counterion, and lone pairs are not required in the products and the question is hsown below:
Explanation:
The proton from water is abstracted by butyl carbanion and hydroxide ion is formed from water.
The reaction is shown below in the attachment.
28) Which of the following is true about the modern model of the atom?
A) Electrons orbit the nucleus in shells at fixed distances
B) Protons, neutrons, and electrons are located in the nucleus.
C)Atoms are hard, indivisible spheres.
D)A positive nucleus is surrounded by negative electrons.
Answer:
A) Electrons orbit the nucleus in shells at fixed distances
Answer:
the answer is A
Explanation:
all first level consumers are carnivore: True or false?
..........................
HELP PLEASE HURRY!!!
You have 12.51 grams of C2H6, how many moles do you have?
Answer:
How many grams C2H6 in 1 mol? The answer is 30.06904. We assume you are converting between grams C2H6 and mole. You can view more details on each measurement unit
The citric acid cycle has a catabolic role, oxidizing acetate into CO2 and generating energy, and an anabolic role.
a. True
b. False
PLEASE is possible to calculate the theoretical yield without a balanced equation?
No, you absolutely need a balanced equation because you need the coefficients to figure out the molar ratios plus you need the amount of one reactant or product to determine the theoretical yield.
No, it's not possible to calculate the theoretical yield without a balanced equation.
What is the theoretical yield?Theoretical yield is the yield that is calculated by the complete reaction of the limiting reagent. This is called expected or calculated amount of product.
[tex]\rm percent\; yield = \dfrac{(actual\; yield)}{(theoretical\; yield)} \times 100\\\\[/tex]
Thus, No, it's not possible to calculate the theoretical yield without a balanced equation.
Learn more about theoretical yield
https://brainly.com/question/14966377
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Calculate the amount of heat associated with cooling a 350.0 g aluminum bar from 70.0 oC to 25.0 oC. The specific heat of aluminum is 0.897 J/g oC. (–14,127.75 J)
Explanation:
[tex]q = 350 \times0.897 \times (70 - 25) \\ q = 14127.75[/tex]
True or false: this reaction is balanced.
2C2H6(g) + 70215)
True
4CO2(g) + 6H20(3)
False
Answer:
false
Explanation:
i did it
In which two ways does a balanced chemical equation model the law of
conservation of mass?
Answer:Matter cannot be created or destroyed in chemical reactions. This is the law of conservation of mass. In every chemical reaction, the same mass of matter must end up in the products as started in the reactants. Balanced chemical equations show that mass is conserved in chemical reactions
Explanation:
sorry it is late but hope it helps!(o゜▽゜)o☆
Which expression gives the standard enthalpy
change of formation for methanol?
Answer:
25
Explanation:
bec
how many molecules are there in 75.0 grams of phosphorus trichloride plzz helpp
Answer:
Explanation:
55
for each 20 grams of glucose made by the plant, calculate the mass of water used
Answer: 6
Explanation:
You would need 6
Energy is just like water, cycles through ecosystems.
True or false?
Answer:
true
Explanation:
I think
f(x) = -x2+x+6
x
-2
a
-1
4
0
b
1
6
2
c с
do
11 11 11
Cross primary components of vascular tissue are the xylem and phloem. These two tissues transport fluid and nutrients internally. There are also two meristems associated with vascular tissue: the vascular cambium and the cork cambium. All the vascular tissues within a particular plant together constitute the vascular tissue system of that plant.
How do scientists test their ideas
What is the pH of 0.6 M NaOH?
Answer:
pOH = - log[OH-]
[OH-] = 0.6M
[tex]pOH \: = - log(0.6) \\ = 0.2218487496 \\ pH \: + pOH \: = 14 \\ pH \: + 0.221848749 = 14 \\ pH = 14 - 0.221848749 \\ = 13.77815125 \\ 13.8[/tex]
Use the periodic table to identify the noble gas that would be included in the noble-gas notation for each of the following elements.
Answer:
Explanation:
Use the periodic table to identify the noble gas that would be included in the noble-gas notation for each of the following elements.
Si:
Fr:
Hg:
V:
Answer:
Si: Ne
Fr: Rn
Hg: Xe
V: Ar
Explanation: trust me bro
When using vacuum filtration to separate a dissolved solid from an undissolved solid, what techniques should you use to ensure a quantitative separation
Answer: See explanation
Explanation:
Vacuum filtration is referred to as a fast filtration technique that is used in the separation of solids from liquids. It is also used to collect a desired solid. It basically uses a side-arm flask and a Buchner funnel.
Based on the question, the techniques that should be used to ensure a quantitative separation goes thus:
• Wet the filter paper before the mixture is poured into the filter funnel.
• Then, carefully rinse the flask with a little amount of water into the filter funnel.
• After that, the solid on the filter paper should be washed the with a small amount of water.
• Finally, Dry the solid on the filter paper when the separation is done.