La promoción de 5to grado de secundaria "Jóvenes caminando hacia el éxito" han estado realizando actividades

para su viaje y fiesta de promoción, logrando hasta la fecha juntar la suma de S/. 24 000. Por ello, el comité de

padres de familia convocó una reunión general para decidir dónde depositar el dinero, presentando dos opciones

de ahorro:

Opción 1: Depósito por 2 años que paga el 10% trimestral en interés simple.

Opción 2: Depósito por 2 años en una cuenta que paga el 18% de semestral compuesto anual.

Ayuda a los padres de familia de la promoción a elegir la mejor opción.







ACTIVIDAD 2:
Carolina y Carla son dos hermanas gemelas quienes ganaron S/.3450 en el Bingo organizado por su parroquia,
decidiendo gastar S/. 1450 en un viaje a Cuzco y repartirse el resto en partes iguales. Cada hermana decidió
ahorra en su Banco de confianza. ¿Cu

Answers

Answer 1

Answer:

Los padres de la promoción deben elegir la Opción 1, porque da un mayor interés en la inversión.

Step-by-step explanation:

El monto recaudado por la escuela secundaria = S / 24,000

Las opciones que tienen los padres para depositar el dinero son;

Opción 1:

El interés simple del depósito = 10%

El número de veces que se aplica el interés anualmente = Trimestral

El número de años para el depósito = 2 años

opcion 2

La tasa de interés del depósito, r = 18% de interés simple.

El número de veces que se aplica el interés = Semestralmente

La cantidad de años que se ahorrará la cantidad = 2 años

Opción 1

Observamos que para el interés simple no hay interés ganado sobre el interés anterior.

Por lo tanto;

Una inversión que paga el 10% trimestralmente = (1/4) año pagará 4 × 10% = 40% en 4 × (1/4) año = 1 año

La cantidad de interés ganado en 2 años invirtiendo en la opción 1 se da como sigue;

Yo = P × R × T / (100)

∴ I₁ = 24.000 × 40 × 2/100 = 19.200

El interés después de 2 años en la opción 1, I₁ = S /. 19.200

opcion 2

Una inversión que paga 18% semestralmente = (1/2) año pagará 2 × 18% = 36% en 2 × (1/2) año = 1 año

La cantidad de interés ganado en 2 años invirtiendo en la opción 2 se da a continuación;

Yo = P × R × T / (100)

∴ I₂ = 24.000 × 36 × 2/100 = 17.280

El interés después de 2 años en la opción 2, I₂ = S /. 17.280

Dado que el interés dado por la opción 1, I₁ = S / .19,200 es mayor que el interés dado por la opción 2, I₂ = S /. 17.280, los padres de la promoción deben elegir la opción 1, que es depositar durante 2 años que paga un interés simple trimestral del 10%


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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

There are 2 ways you can solve this

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Step-by-step explanation:

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Step-by-step explanation:

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I think the answer is A

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Since ABC is a right triangle, we can use Pythagorean Theorem to solve for side AB.

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Hope this helps!! :)

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Step-by-step explanation:

Well the formula for this is [tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]

The sides given are called the opposite and the adjacent, which, in this formula correspond to a and b. What you are trying to find is called the hypotenuse, and in this formula, c.

First you need to square a and b, like in the formula:

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[tex]7^{2}[/tex] = 49

Now you add these together to find [tex]c^{2}[/tex]:

16 + 49 = 65

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let me know if you need the work!

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Answer:

4 minutes

Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Step-by-step explanation:

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Answer: K

Step-by-step explanation:

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Answers

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Given: cost of drums = $ 2000

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(-1,11) reflected over the y axis
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Answers

Answer:

See explanation

Step-by-step explanation:

Reflecting over the y axis does not change the Y value. It multiplies the x value by -1.

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Answer:

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Answer:

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Step-by-step explanation:

Here are the laws which would be used in this question:

Indices:

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• [tex] \frac{1}{a} = {a}^{ - 1} [/tex]

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PLS HELP
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Answers

The value of X would have to be A-42

Answer:

B

Step-by-step explanation:

x+x+94 = 180 (sum of angle of triangle)

2x+94 = 180

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2x = 86

x = 86÷2

Therefore x = 43

A basketball tosses a ball to a teammate. The ball reaches a maximum height of 11 feet 3 seconds after it was released. If the ball is thrown from a height of 6 feet, write a quadratic equation that represents the height of the ball as a function of time

Answers

Answer:

h = - 16t² + 49.67t + 6

Step-by-step explanation:

The expression for the height of the basketball, h at time, t is given by

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We need to find u₀ from u = u₀ -

So, h - h₀ = u₀t - 1/2gt²

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substituting the values of the variables into the equation, we have

u₀ = (h - h₀)/t + 1/2gt

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u₀ = 1.67 ft/s + 48 ft/s

u₀ = 49.67 ft/s

Using h - h₀ = u₀t - 1/2gt² where h is the height of the basketball at time, t

h = u₀t - 1/2gt² + h₀

substituting the values of the variables into the equation, we have

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h = (49.67ft/s)t - 1/2(32 ft/s²)t² + 6 ft

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Help ​

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Answer:

the variable

Step-by-step explanation:

m is the variable

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Answer:

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Step-by-step explanation:

$289 I think

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Answer:

Technically Andrew since his sum is technically "higher" than the rest of the negative numbers.

Answer:

Andrew

Step-by-step explanation:

Andrew since his sum is practically greater than the rest of the negative numbers.

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Step-by-step explanation:

9x-4+6x+4=180 ( being straight angle)

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I hope it help you

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Answers

Answer:

[tex]3\sqrt{3}x[/tex]

Step-by-step explanation:

Expand √27x² in such a way that it is the :-

Product of at either two or more perfect square numbers or,Product of two or more numbers out of which one (or more) is a perfect square number.

So ,

[tex]\sqrt{27x^2} = \sqrt{9 \times 3 \times x^2}= 3 \times \sqrt{3} \times x = 3\sqrt{3}x[/tex]

Find the side length x

Answers

Answer:

x = 10

Step-by-step explanation:

8² + 6² = x²

64 + 36 = x

64 + 36 = 100

√100 = 10

[tex]\huge\bold{To\:find:}[/tex]

The length of the hypotenuse ''[tex]x[/tex]".

[tex]\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}[/tex]

[tex]\sf\purple{The\:length\:of\:the\:hypotenuse \:"x"\:is\:10.}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

Using Pythagoras theorem, we have

[tex] ( {hypotenuse})^{2} = ( {perpendicular})^{2} + ( {base})^{2} \\ ⇢ {x}^{2} = {6}^{2} + {8}^{2} \\ ⇢ {x}^{2} = 36 + 64 \\ ⇢ {x}^{2} = 100 \\ ⇢ x = \sqrt{100} \\ ⇢x = \sqrt{10 \times 10} \\ ⇢x = \sqrt{ ({10})^{2} } \\ ⇢x = 10[/tex]

[tex]\sf\blue{Therefore,\:the\:length\:of\:the\:hypotenuse\:is\:10.}[/tex]

[tex]\huge\bold{To\:verify :}[/tex]

[tex] {x}^{2} = {6}^{2} + {8}^{2} \\⇝ ({10})^{2} = 36 + 64 \\ ⇝10 \times 10 = 100 \\ ⇝100 = 100 \\ ⇝L.H.S.=R. H. S[/tex]

Hence verified. ✔

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

simplify the question​

Answers

Answer:

[tex] \frac{2}{x - 3} - \frac{12}{ {x}^{2} - 9} \\ = \frac{2}{x - 3} - \frac{12}{(x - 3)(x + 3)} \\ = \frac{2(x + 3) - 12}{( {x}^{2} - 9)} \\ = \frac{2x - 6}{( {x}^{2} - 9)} \\ = \frac{2(x - 3)}{(x - 3)(x + 3)} \\ = \frac{2}{x + 3} [/tex]

Which of these is NOT an example of flood control?

Group of answer choices

Building your house next to a river

Building a dam

Having levees in the ocean

Creating storm drains on a street




What can humans do to help stop beach erosion?
Group of answer choices

Beach restoration by pumping sand from the ocean

Stop visiting the beach

Rinse off when leaving the beach

Not allow animals to live on the beach

Answers

Answer:

For number one the answer is A and the second answer is A too.

Step-by-step explanation:

Answer: Building your house next to a river and Beach restoration by pumping sand from the ocean (While this does not prevent erosion, it can reduce storm damage to coastal development & infrastructure.)

Step-by-step explanation:

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