Look at the pattern below.
step 1 step 2 step 3 step 4
How many squares will be in the pattern at the 8th step?
Choose 1 answer:
8 squares
12 squares
B

The value of the [tex]\rm 6x^5y^3[/tex] is 35 if the value of [tex]\rm 2x^2y = 5[/tex] and [tex]\rm 3x^3y^2 = 7[/tex]

It is defined as the combination of constants and variables with mathematical operators.

We have:

[tex]\rm 2x^2y = 5\\\\\rm 3x^3y^2 = 7[/tex]

We have to find the value of [tex]\rm 6x^5y^3[/tex]

[tex]=\rm 6x^5y^3\\\\= \rm 6(x^2y)(x^3)(y^2)[/tex]

=6(5/2)(7/3)

= (5)(7)

= 35

Thus, the value of the [tex]\rm 6x^5y^3[/tex] is 35 if the value of [tex]\rm 2x^2y = 5[/tex] and [tex]\rm 3x^3y^2 = 7[/tex]

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Answer:

neither can be factored any further but if it is (9x^4) - (16y^4) it can be factored down to ((3x^2)+(4y^2)) ((3x^2)+(4y^2))

Step-by-step explanation:

Answer:

You should raise one side 14 inches

Step-by-step explanation:

I used a right angle triangle calculater at this sight

https://www.calculator.net/right-triangle-calculator.html

Based on the quadrilaterals given, the types of angles that we see are Acute and Obtuse.

Acute angles are those that are less than 90° and these are shown in the trapezium quadrilateral.

Obtuse angles are higher than 90° and so are drawn outwards as seen in the parallelogram.

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Sorry don't no the answer

sorry if I kwon the answer

I telling u the answer

Answer:

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Step-by-step explanation:

Using the combination formula, it is found that 35 different combination of teams can make it to the playoffs.

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem, 4 students are taken from a set of 7, hence the number of combinations is given by:

[tex]C_{7,4} = \frac{7!}{4!3!} = 35[/tex]

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The average rate of a function is 81 if a quadratic function with a vertex at (6, 8).

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

Quadratic function with a vertex at (6, 8).

It is required to find the average rate of the function:

Here the data table is not given, so we are assuming the value of a function:

At x = 13 is 196

f(13) = 144

At x = 14 is 225

f(14) = 225

The average rate of a function:

= [f(14) - f(13)]/(14 - 13)

= [225 - 144]/(1)

= 81

Thus, the average rate of a function is 81 if a quadratic function with a vertex at (6, 8).

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Answer: C. [tex]p = 2^{d}[/tex]

Step-by-step explanation:

The population rises exponentially, so the graph will have to go up. It also means the population is doubled directly in relation to days

We will get the areas of each one of the given triangles:

7) A = 12.69 mm²

8) A = 19.21 in²

9) A = 16.81 yd²

7) First, we have an equilateral triangle, where all the sides measure 5.4mm

For an equilateral triangle of side length S, the area is:

[tex]A = \frac{\sqrt{3} }{4}S^2[/tex]

In this case, S = 5.4 mm, replacing we get:

[tex]A = \frac{\sqrt{3} }{4}(5.4mm)^2 = 12.62 mm^2[/tex]

8) Now we have two equal sides and one different. The general area of a triangle of base B and height H is:

A = B*H/2.

In this case, the base measures 3.4 in.

To get the height, let's divide the triangle into two right triangles, such that one cathetus is 3.4in/2 = 1.7 in.

The hypotenuse measures 5.9 in

And the other cathetus is the height of the triangle.

Then, by using the Pythagorean theorem, we see that the height is:

[tex]H = \sqrt{(5.9 in)^2 - (1.7in)^2} = 5.65 in[/tex]

Then the area of this triangle is:

[tex]A = (3.4 in)*(5.65 in)/2 = 19.21 in^2[/tex]

9) Here the base measures 8.2 yds, and the height 4.1 yds, so the area is just:

[tex]A = (4.1 yd)*(8.2 yd)/2 = 16.81 yd^2[/tex]

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Answer:

The answer is the third bullet. (number 3)

The median of the data is 5 if the all class widths are 1, option (C) is correct.

A median is a middle number in a series of numbers that have been arranged to lift, and it might be more informative of the set of data than the average. When there are extremes in the sequences that might affect the average of the numbers, the median is sometimes employed instead of the mean.

In the histogram, 15 data values are given:

1, 2, 2, 3, 3, 3, 4, 5, 6, 6, 7, 7, 7, 8, 9

The mid-value is 5 which is on the 8th place

Thus, the median of the data is 5 if the all class widths are 1, option (C) is correct.

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Answer:

135°

Step-by-step explanation:

That triangle in the corner is an right angle isosceles triangle as that line the midpoint of both sides :

the base angle of this triangle (x) will be :

180 = 90 + 2x

90 = 2x

x= 45

Angles on a straight line add up to 180. So to work out a :

180 = 45 + a

135 = a

Hope this helped and brainliest please

Answer:

y = - 2 | x - 2 | + 4

Step-by-step explanation:

the general equation of an absolute value function is

y = a|x - h| + k

where (h, k ) are the coordinates of the vertex and a is the stretch factor

here (h, k ) = (2, 4 ) , then

y = - 2|x - 2| + 4

Answer:

See below ~

Step-by-step explanation:

Formula for absolute value function :

y = a |x - h| + k

==============================================================

Given :

⇒ a = -2

⇒ Vertex = (h, k) = (2, 4) [based on graph]

=============================================================

Solving by substitution :

⇒ y = -2|x - 2| + 4

Answer:

y = (-1/4)x + (13/4)

Step-by-step explanation:

The general structure of an equation in slope-intercept form is:

y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept.

Remember that in a point (-3,4) you have an "x" and "y" value. As such, you have been given values for the "x", "y", and "m" variables. Therefore, you can plug these values into the general structure to find the value of "b".

y = mx + b                              <---- General structure

y = (-1/4)x + b                         <---- Plug (-1/4) in "m"

4 = (-1/4)(-3) + b                      <---- Plug in values from point

4 = (13/4) + b                          <---- Multiply (-1/4) and -3

(13/4) = b                               <---- Subtract (13/4) from both sides

Now that you know the value of "m" and "b", you can determine the formula.

y = (-1/4)x + (13/4)

Horizontal shift of 1 unit to the left and a vertical shift downward of 2 units.

Transformation technique is a way of changing the position of an object on an xy-plane.

Given the parent function of a modulus function f(x) = |x|, the graph of the function g(x) = |x| - 2 shows a vertical translation of the parent function down by 2 units.

The resulting graph of the translated function is as shown below

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The response that represents the 86th percentile is 7.884

The response that represents the 55th percentile is 5.69

The response that represents the first percentile 3.85

mean = 5.4

sd = 2.3

p(X>x) = 0.86

find the value of z using the NORMSINV function in excel with a probability of 0.86

z = 1.080

x = mean + sd*z

= 5.4 + 2.3 * 1.080

= 7.88

mean = 5.4

sd = 2.3

p(X>x) = 0.55

find the value of z using the NORMSINV function in excel with a probability of 0.55

z = 0.1257

x = mean + sd*z

= 5.4 + 2.3 * 0.1257

= 5.69

c. The first quartile is 25%

z = -0.6745

5.4 + 2.3 * -0.6745

= 5.4-1.551

= 3.85

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Answer:

The other length is 60m.

Step-by-step explanation:

If you look at the shape of a parallelogram, you will see that a parallelogram has two parallel sides. So, if the total perimeter is 220m, then 50m and 50m together would be 100m, so 220- 100= 120m left to fill in both sides left. so, 120÷2= 60m. 60m is the other length.

Answer:

21.25=4.25

Ms. Diaz buys 5 pounds of strawberrys

Step-by-step explanation:

Answer:

  3103 calories

Step-by-step explanation:

We presume the number of calories is proportional to the area of the pizza. The ratio of areas is the square of the ratio of the linear dimensions, so the number calories in the larger pizza is ...

  (14/6)² × 570 calories = 3103 1/3 calories

There are about 3103 calories in the 14-inch pizza.

The number of lines of symmetry for the given figure will be 4.

Symmetry is described in geometry as a balanced and proportionate likeness between two halves of an object.

As we know that similarity is defined as when the image is divided into two halves and one portion is completely overlapped by the other.

So in the given figure, the figure can be divided into two halves by drawing four lines along with the arrows and along with the corners. In all cases, the two halves overlap with the other.

Therefore the number of lines of symmetry for the given figure will be 4.

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Answer:

5) 22.95

6) 21.93

Step-by-step explanation:

Area of Triangle = BxH/2

= CxH/2

Answer:

yes there is a correlation

Step-by-step explanation:

here's how I found this by looking up all key words.

Answer:

C (3,6)

Step-by-step explanation:

So the zeroes are the points that the loop goes through on the x-axis

so three and six

Using it's concept, it is found that the percent increase in the amount of iron per serving was of 50%.

It is given by the increase divided by the initial value, and subtracted by 100%.

In this problem:

Hence the percent increase is given by:

P = 0.6/1.2 x 100% = 50%.

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Step-by-step explanation:

5(x+2)
1. Distributive property
2. Multiply
(5*x) + (5*2)
(5x)+(10)
Remove parenthesis

5x+10 ;

Therefore, 5(x+2) = 5x+10

Hopefully this helps! :3

Recall that the derivative of a function f(x) at a point x = c is given by

[tex]\displaystyle f'(c) = \lim_{x\to c} \frac{f(x) - f(c)}{x - c}[/tex]

By substituting h = x - c, we have the equivalent expression

[tex]\displaystyle f'(c) = \lim_{h\to0} \frac{f(c+h) - f(c)}h[/tex]

since if x approaches c, then h = x - c approaches c - c = 0.

The two given limits strongly resemble what we have here, so it's just a matter of identifying the f(x) and c.

For the first limit,

[tex]\displaystyle \lim_{h\to0} \frac{\sin\left(\frac\pi3 + h\right) - \frac{\sqrt3}2}h[/tex]

recall that sin(π/3) = √3/2. Then c = π/3 and f(x) = sin(x), and the limit is equal to the derivative of sin(x) at x = π/3. We have

[tex](\sin(x))' = \cos(x)[/tex]

and cos(π/3) = 1/2.

For the second limit,

[tex]\displaystyle \lim_{a\to0} \frac{e^{2a} - 1}a[/tex]

we observe that e²ˣ = 1 if x = 0. So this limit is the derivative of e²ˣ at x = 0. We have

[tex]\left(e^{2x}\right)' = e^{2x} (2x)' = 2e^{2x}[/tex]

and 2e⁰ = 2.