<6 and <7 can be classified as:
A. alternate exterior angles
B. same-side interior angles
c. alternate interior angles
D. vertical angles

Answer:

c

Step-by-step explanation:

6x2=12

3x6=18

18+12= 30

Answer:

B. 24 in ^2

Step-by-step explanation:

To find this follow these steps:

1. find the area of the first square: 6 inches times 3 inches so you get 18 inches squared

2. Find the area of the second square : 3 inches times 2 inches you get 6 inches squared

Have a wonderful day!

This may help

https://youtu.be/xxAFh-qHPPA

Answer:

P(A or B) = 39%

Step-by-step explanation:

If A and B are mutually exclusive, they cannot occur at the same time, therefore their probabilities are added. This means P(A or B) = P(A) + P(B) = 23% + 16% = 39%

Answer:

-log(2)

Step-by-step explanation:

Answer:

16

Step-by-step explanation:

8/ 2*(2+2) = 4*(2+2) = 4*4 = 16

Answer:

C - Triangle, Pentagon, Hexagon, Decagon

Step-by-step explanation:

Triangle - 3 sides

Pentagon - 5 sides

Hexagon - 6 sides

Decagon - 10 sides

From Least to greatest!

:)

Answer:

15x15x15

Step-by-step explanation:

13x13x13= 2197

15x15x15= 3375

Answer:

length is 17

width is 14

Step-by-step explanation:

Answer:

RN ≈ 4.2

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos65° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{RN}{PR}[/tex] = [tex]\frac{RN}{10}[/tex] ( multiply both sides by 10 )

10 × cos65° = RN , then

RN ≈ 4.2 ( to 1 dec. place )

Answer:

B

Step-by-step explanation:

Answer:

y = 20.

Step-by-step explanation:

Multiply 5 by 12.

Divide both 3y and 60 by 3.

Remove 3 from 3y.

Divide 60 by 3.

The value of y from the given equation when x=12 is 20.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

The given equation is 3y=5x.

The value of y when x= 12​ is

3y=5×12

y=5×4

y=20

Therefore, the value of y is 20.

To learn more about an equation visit:

https://brainly.com/question/14686792.

#SPJ2

Answer:

first statement

Step-by-step explanation:

The absolute value of - 6 is | - 6 | = | 6 | = 6

The absolute value is always positive as it is a measure of the distance from the origin to - 6 and distance is always positive.

It is not the distance between 6 and - 6 on the number line.

Answer:

1.

For triangle 1

[tex]a = 3\sqrt{5}[/tex]

For triangle 2

[tex]x = 2\sqrt{2}[/tex]

2.

Way 1

By reducing  the length of the side 4 to 3.60

Way 2

By increasing the length of side 7 to 7.21

Step-by-step explanation:

The complete question is attached in the image

Solution

1.

Both the triangles are right angled triangle

For triangle 1

[tex]7^2 = 2^2 + a^2\\49 = 4 + a^2\\a^2 = 45\\a = 3\sqrt{5}[/tex]

For triangle 2

[tex]4^2 = x^2+x^2\\2x^2 = 4*4\\x^2 = 8\\x = 2\sqrt{2}[/tex]

2.

Way 1

By reducing  the length of the side 4 to 3.60

Way 2

By increasing the length of side 7 to 7.21

Answer:

according to the question

y=x

p(x,y) reflection p'(y,x)

Answer:

with T = 50⁰C, we have:

50 = 200 - 5x - x²

<=> x² + 5x = 150

<=> x² + 5x - 150 = 0

=> x = 10

Answer:

12.5

Step-by-step explanation:

50÷4=12.5

Answer:

≈ 7.07m

Step-by-step explanation:

Let the length of a side of a square

= a metre

a² = 50 m²

[tex] \sf{a = \sqrt{50m {}^{2} }}[/tex]

[tex] \sf{ = \sqrt{2 \times 5 \times 5m {}^{2} }}[/tex]

[tex] \sf{ = 5 \sqrt{2m} }[/tex]

≈ 5x 1.414

≈ 7.07 m

therefore

side of triangle

[tex] \sf \: = 5 \sqrt{2m} [/tex]

Answer:

C. 0.025 < p < 0.05

Step-by-step explanation:

The [tex]\chi^2[/tex] goodness-of-fit test parameters are presented here as follows;

The number of Skittles in the bag = 30 Skittles

The different flavors in the bag of Skittles = Strawberry, orange, lemon, lime, and grape

The number of different flavors, n = 5 flavors

The [tex]\chi^2[/tex] statistic = 10.20

Therefore, the degrees of freedom, d.f. = n - 1 = 5 - 1 = 4

Using the chi-square ([tex]\chi^2[/tex]) distribution table,  we have;

The probability at 4 degrees of freedom for a [tex]\chi^2[/tex] statistic of 10.20 is between 0.025 and 0.05

Therefore, we get;

The probability (P > 10.20) = 0.025 < p < 0.05.

Answer:

your answer is 628.32cm :)

Answer:  I think it is 628.32

Step-by-step explanation: You have to multiply the radius by two to get the diameter and then multiply that by 3.14(PI)

100 x 2=200    

3.14 x 200=628.32

Answer:

Approximately 3 times, Jake will be able to hit the ball in a game of 10 balls

Step-by-step explanation:

Batting average determine the % share of time the bat hit the ball.

Jake's probability of hitting a ball = 0.34

Jake plays 10 games.

Probability of hitting a ball in a game is

10 * 0.34 = 3.4

Approximately 3 times, Jake will be able to hit the ball in a game of 10 balls

Answer:

Fixed Deposits have a fixed lock-in period, which limits the unnecessary withdrawal of your money until maturity. A savings account, on the other hand, enables you to withdraw any amount at any time, which proves detrimental to your goal of wealth appreciation.

:)

Answer:

p = 10

Step-by-step explanation:

3p + 10 + 5p = 90

8p + 10 = 90

90 - 10 = 80

80 / 8 = 10

Answer:

4

Step-by-step explanation:

(1,2) (0,-2)

y2 - y1 / x2 - x1

-2 - 2 / 0 - 1

-4 / -1

4

Answer:

B: 25

Give me Brainliest lol-

Answer:

25

Step-by-step explanation:

d1 x d2 divide by 2

10 x 5 = 50/2 =25

Answer:

0.8

Step-by-step explanation:

80 percent is 80/100. Decimal point 100 would be just 1. Hence 80 percent would be 0.8/

Answer:

Using Sine Rule

w= 19.8

Answer: A. 75

Step-by-step explanation: Hope this help :D

Evaluate for x=10

(4)(10)+5(10−3)

(4)(10)+5(10−3)

=75

Answer:

Centre is [tex](7,11)[/tex]

Radius is [tex]6[/tex]

Step-by-step explanation:

The general equation for a circle is written in the form [tex](x-a)^2+(y-b)^2=r^2[/tex] , where [tex](a,b)[/tex] is the centre of the circle, and [tex]r[/tex] is the radius.

For your circle, [tex](x-7)^2+(y-11)=36[/tex], we can compare it with the general equation to find the centre and radius.

[tex]-a = -7[/tex]

[tex]-b = -11[/tex]

[tex]r^2 = 36[/tex]

Therefore, [tex]a=7[/tex], [tex]b=11[/tex] and [tex]r=6[/tex].

Centre at [tex](a,b)[/tex] which is [tex](7,11)[/tex] .