Making sure that all objectives are shared among team members and that all activities benefit the team's final objective means the team is
self-presentational
critical in their thinking
O goal-oriented
ineffective

The statement about the source term affecting all algebraic equations is; False

In the finite-element method of Analysis, we usually go from differential equations to a set of algebraic equations. Now, it is pertinent to note that each algebraic equation will tend to relate a nodal value with all other nodal values.

The assumed polynomial variation that will exist within each element is usually the basis for which we derive the algebraic equations. Thus, to derive the algebraic equations, we will have to assume a polynomial variation for the parameter values within each element.

The above can be done through interpolation of nodal parameter values in the post-processing stage. This is because the assumed polynomial variation within each element that is used for deriving the algebraic equations is also used for post-processing.

Finally, for each algebraic equation, the source term will tend to contribute to the coefficient that is taken to the right hand side of it and then entered into the corresponding row of the {f} vector.

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Complete Question is;

Select true or false.

The source term will affect all algebraic equations.

A.) True

B.) False

Answer:

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Explanation:

you have to do just opposite. is that clear?

Answer:

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Explanation:

What is this...

Answer:

let me know if this's helpful.

The load required to produce a change in diameter of 10 mm in a cylindrical brass rod is 1.57 N.

A tensile stress of 0.157 MPa is required to produce a change in diameter of 10 mm in a cylindrical brass rod. The deformation is entirely elastic, so the Poisson's ratio for brass is 0.34, and the modulus of elasticity is 97 GPa.

The load required to produce this tensile stress is 1.57 N.

To solve this problem, we can use the following equation:

Stress = (Change in diameter) * (π / (2 * Diameter))

Plugging in the values for the change in diameter, diameter, and Poisson's ratio, we get the following tensile stress:

Stress = (0.001) * (π / (2 * 0.010)) = 0.157 MPa

The load required to produce this tensile stress is then:

Load = Stress * Modulus of Elasticity

Plugging in the values for the tensile stress and modulus of elasticity, we get the following load:

Load = 0.157 MPa * 97 GPa = 1.57 N

Therefore, the load required to produce a change in diameter of 10 mm in a cylindrical brass rod is 1.57 N.

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let, A be the are of cross section of the electrodes.

The capacitance is C.

Let E represent the electric field between the electrodes.

Be the charge per square meter (sigma).

∉ be the permittivity of open space

and considering the fact that

Insulator's dielectric constant is K.

Between the electrodes is slid d/2.

between the electrodes is now an electric field.

E = sigma + sigma + sigma

E = sigma / ——1

we are aware,

E = V /(d/2)

V = E d/2

V=sigma /*d/2 ( from equation 1)

V = d/2 sigma ———2

once more, we are aware

C = Q/V

Sigma A/(sigma d/2) = C Using Q = sigma A and equation 2,

C = 2∉A/d

has a K-valued dielectric constant.

C = 2K∉A/d

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One similarity between the scientific method and the engineering design process is that "They are both iterative processes that begin with a problem."

The engineering design process is a set of processes that engineers use to solve an issue. Problem-solving techniques such as establishing your objectives and limitations, prototyping, testing, and assessment are among the phases.

It always serves a clear and well-defined goal. Experiments may be conducted to better understand the problem (or a potential solution), but the purpose of engineering design is always to solve a problem.

The engineering design approach enables students to learn from failure and stresses open-ended problem solutions. This technique develops students' capacity to devise creative answers to problems in any discipline.

The process involves:

The scientific method is an empirical way of collecting information that has been used in science since at least the 17th century. It entails thorough observation and applying severe skepticism to what is observed, given that cognitive preconceptions might alter how the observation is interpreted.

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Answer:

Insurance is an example of C. Risk Mitigation.

Explanation:

Insurance is used to manage (or mitigate) risk. Companies and individuals purchase insurance to protect themselves from financial stress. For example, car insurance insures your car up to a certain percentage or value amount if something were to happen to your car while driving.

This response is accompanied by the T-s or H-s graphic.

2. The steam extraction rate is 4.088 kg per second.

3. Steam leaving the boiler has a net power output of 1089.5 KJ/Kg.

4. The boiler's mass flow rate of steam is 16.352Kg/s.

5. The plant generates 11016.2KJ/s of net electricity.

6. 0.218 is the usage factor.

We must ascertain all of the system's thermodynamic coordinates in order to examine the issue. The optimal cogeneration steam plant technology can be seen in the second image that is attached to this response.

We may get the details for each point from a chart of the thermodynamic characteristics of water.

+ Steam from the boiler reaches the turbine at 7 MPa and 500 °C:

h₆=3410.56KJ/Kg

s₆=6.7993 KJ/Kg

As a result, this cogeneration steam system is suitable. s₆=s₇=s₈

At 600 kPa, one-fourth of the steam is removed from the turbine:

2773.74 KJ/Kg = h7(s7) (overheated steam)

+The remaining steam expands further and exhausts to the condenser at a pressure of 10 kPa.

(This is wet steam with title X=0.8198; h8(s8)=2153.58 KJ/Kg.)

s1=0.64925KJ/Kg and h1(P=10Kpa)=191.83 KJ/Kg (condensed water).

Pumping this flow to 600KPa results in:

s₂=s₁

h₂(s₂)=192.585KJ/Kg

+The heater condenses the steam that was taken for the process heater.

h₃(P=600KPa)=670.42KJ/Kg (condensed water) (condensed water).

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