Marcus has a bag of 10
red chips, 15 blue chips,
and 5 black chips. How
many times would he
expect to pick a red chip if
he did the experiment 60
times?
A) 10
B) 20
C) 30
D) 45

PLEASE HELP THIS IS DUE TODAY

Answers

Answer 1

Answer:

B

Step-by-step explanation:

Answer 2

Marcus can expect to have red chip 20 times.

What is probability?

Probability denotes the possibility of the outcome of any random event. The meaning of this term is to check the extent to which any event is likely to happen.

Given that, Marcus has a bag of 10 red chips, 15 blue chips, and 5 black chips.

He did an experiment 60 times and we need to find that how many times would he expect to pick a red chip,

So,

Here the favorable outcomes = red chips (10)

Total outcomes = all the chips = 15+5+10 = 20

So, the probability of finding a red chips for the 60 times = 10/20 x 60

= 30

Hence, Marcus can expect to have red chip 20 times.

Learn more about probability, click;

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Related Questions

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Answer:

height = 5+2xbase

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69 = 2xbase

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34.5mm = base length

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Step-by-step explanation:

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Doors for the small cabinets are 11.5 inches long. Doors for the large cabinets are 2.7 times as long as the doors for the small cabinets. How many large doors can be cut from a board that is 10 feet long?

Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

You need to think about how the original price (578) is 100% of the price and that the sale price (78) is just a percentage of that. To discover how much of that 100% the price 78 is, you can write the formula:

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Answers

Step-by-step explanation:

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1 Krista has 10 cups of gelatin. If each bowl holds 3 cup, how many bowls can she fill?​

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Answers

Answer:

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Step-by-step explanation:

By Length · Width · Height

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For part B, the length and width are the same, but the depth (height) of the water is only one foot, so we can replace the height value from the first equation with 1.

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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therefore, BC has the same length as QR

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Answer:

Reflected OVER Y makes A

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Step-by-step explanation:

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Step-by-step explanation:

Answer:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

A field researcher is gathering data on the trunk diameters of mature pine and spruce trees in a certain area. The following are the results of his random sampling: Pine Trees Spruce Trees Sample Size 40 80 Mean trunk diameter (cm) 35 30 Population variance 160 160 Using a .10 significance level, can he conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree

Answers

Answer:

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

Step-by-step explanation:

Using a .10 significance level, can he conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree

The null hypothesis is that they are equal(that is, subtraction between the means is 0), while the alternate hypothesis is that they are greater(that is, subtraction between the means is larger than 0). So

[tex]H_0: \mu_1 - \mu_2 = 0[/tex]

[tex]H_a: \mu_1 - \mu_2 > 0[/tex]

In which [tex]\mu_1[/tex] is the mean pine trees height while [tex]\mu_2[/tex] is the mean spruce trees height.

The test statistic is:

[tex]z = \frac{X - \mu}{s}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that [tex]\mu = 0[/tex]

Mean trunk diameter (cm) 35 30:

Pine trees - 35

Spruce trees - 30

The sample mean is given by the subtraction of the means. So

[tex]X = 35 - 30 = 5[/tex]

Sample Size 40 80

Population variance 160 160

This means that the standard error for each sample is given by:

[tex]s_1 = \frac{\sqrt{160}}{\sqrt{40}} = 2[/tex]

[tex]s_1 = \frac{\sqrt{160}}{\sqrt{80}} = \sqrt{2}[/tex]

The standard error of the difference is the square root of the sum squared of the standard error of each sample.

[tex]s = \sqrt{2^2 + (\sqrt{2})^2} = \sqrt{6} = 2.4495[/tex]

Test statistic:

[tex]z = \frac{X - \mu}{s}[/tex]

[tex]z = \frac{5 - 0}{2.4495}[/tex]

[tex]z = 2.04[/tex]

Pvalue of the test:

Probability of a sample mean larger than 5, which is 1 subtracted by the pvalue of Z when X = 5.

Looking at the z-table, z = 2.04 has a pvalue of 0.9793.

1 - 0.9793 = 0.0207

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

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