Mariah and Caitlyn are moving a sofa for their teacher. If the sofa weighs 350 kg, how fast did the sofa accelerate if a 48 N force was applied?

Answers

Answer 1

Answer:

[tex]7.291(6)\frac{m}{s^2}[/tex]

Step-by-step explanation:

Firstly, there's definitely large friction with a sofa, so we cannot answer.

Assming there is no friction:

The acceleration is directly proportional to force and inversely proportional to mass (makes sense, right?)

[tex]a = \frac{F}{m}\\a = \frac{350kg}{48N} = \frac{350kg}{48\frac{kg\cdot m}{s^2}} = \frac{350}{48}\frac{m}{s^2} = 7.29166666\ldots\frac{m}{s^2}[/tex]


Related Questions

Given that (-3,-1) is on the graph of f(x), find
the corresponding point for the function
f(x-3).
Enter the correct answer.
OOOO
DONE
Clear all
00
G2

Answers

I think it’s b and c

HELP PLEASE IT'S VERY IMPORTANT
Determine the area of the composite figure.
Determine the perimeter of the composite figure.​​​​​

Answers

Answer:

If I did this right the perimeter is 83.7 and the area is 257.1

Explanation:

the perimeter is all sides added so 15+8+8+6.7+20+26 = 83.7

To make adding the area easier, we would separate it into different shapes.

Area of a Triangle: (b x h)/2

(15x9)/2 = 45 since it's a triangle

8x9 = 72

20x6 = 120

(6x6.7)/2 = 20.1 since it's also a triangle

45 + 72 + 120 + 20.1 = 257.1

Order these numbers from least to greatest:
|-17|
|-18|
-18
|19|
20

Answers

Answer: -18, l-17l, l-18l, l19l, 20

Step-by-step explanation: You can just think of the ones in absolute value brackets as positive.

The logistics/operations manager of a mail order house purchases two products for resale: king beds (K) and queen beds (Q). Each king bed costs $500 and requires 100 cubic feet of storage space, and each queen bed costs $300 and requires 90 cubic feet of storage space. The manager has $75,000 to invest in beds this week, and her warehouse has 18,000 cubic feet available for storage. Profit for each king bed is $300 and for each queen bed is $150. Which of the following is not a feasible purchase combination?

a. 100K - 90Q <= 18,000
b. 90K + 100Q <= 18,000
c. 300K + 90Q <= 18,000
s. 500K + 100Q <= 18,000
e. 100K + 90Q <= 18,000

Answers

Answer:

500K + 100Q <= 18,000 ( D )

Step-by-step explanation:

king bed ( K ) requires = 100 cubic feet

Queen bed ( Q ) requires = 90 cubic feet

Total available space = 18,000 cubic feet

Revenue of king size bed = $300

Revenue of queen size bed = $150

Hence the NOT feasible purchase combination

= 500K + 100Q <= 18,000

because 500 of king size bed + 1000 of queen size is > 18,000

A company manufacturing computer chips finds that 8% of all chips manufactured are defective. In an effort to decrease the percentage of defective chips, management decides to provide additional training to those employees hired within the last year. After training was implemented, a sample of 450 chips revealed only 27 defects. A hypothesis test is performed to determine if the additional training was effective in lowering the defect rate. The correct value of the Z-statistic is

Answers

Answer:

The correct value of the Z-statistic is z = -1.56

Step-by-step explanation:

A company manufacturing computer chips finds that 8% of all chips manufactured are defective.

This means that the null hypothesis is:

[tex]H_{0}: p = 0.08[/tex]

A hypothesis test is performed to determine if the additional training was effective in lowering the defect rate.

This means that the alternate hypothesis is:

[tex]H_{a}: p < 0.08[/tex]

z-statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

0.08 is tested at the null hypothesis:

This means that [tex]\mu = 0.08, \sigma = \sqrt{0.08*0.92}[/tex]

After training was implemented, a sample of 450 chips revealed only 27 defects.

This means that [tex]n = 450, X = \frac{27}{450} = 0.06[/tex]

The correct value of the Z-statistic is

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.06 - 0.08}{\frac{\sqrt{0.08*0.92}}{\sqrt{450}}}[/tex]

[tex]z = -1.56[/tex]

Car A is traveling east at a steady speed of 40 miles per hour. After 2 hours, it is 95 miles easy of Jhonstown. Car B is traveling east on the same road. its distance of Jhonstown is represented by the graph.​

Answers

Answer:

B

Step-by-step explanation:

hope i helped

Which expression is equivalent to:

−6x+10−16





2(3x+10−8)






−2(3x−5+8)






−2x(3−5+8)






2x(−3−10−8)

Answers

Answer:

from the given equation

Step-by-step explanation:

eqn 1 = eqn 3= eqn 4

these all are equivalent

It’s the end of the year I’m really not trying so anybody just help really

Answers

Answer: its D

Step-by-step explanation: because a - x - is a positive so you add them

plese help me
21,382.62 ÷ 10,000

Answers

Answer:

2.138262

Please mark my answer as the brainliest for further answers :)

Answer:

2.138262

Step-by-step explanation:

21,382.62 ÷ 10,000

Find arc DC please help me

Answers

Answer:

arc ABC = 196°

arc DC = 360 - 196 - 70 = 94°  (which looks out of proportion, but so does angle D)

Step-by-step explanation:

arc ABC = 2(∠D) = 2(98°) = 196°

Dad spends $227.06 at the grocery store,$95.55 at the shoe store,and $35.16 at the dry cleaners how much did dad spend in all?

Answers

Answer:

$357.77

Step-by-step explanation:

Add all of the figures together to find the answer

227.06 + 95.55 + 35.16 = 357.77

What do you get when you round 2932.62 to the nearest hundredth please provide step by step explanation too.

Answers

30,000
Hope that helped :)

Answer:

you get 2932.6

Step-by-step explanation:

you basically just round it down because it isn't 5 or above.

please mark brainliest

i need help with this

Answers

9514 1404 393

Answer:

  26

Step-by-step explanation:

The question is asking the fraction equivalent of 0.26 (twenty-six hundredths).

That fraction is 26/100 (twenty-six hundredths). The missing number is 26.

2. How many radians are in a full circle? ?
ON

0 27

Answers

Answer:

1 radius in a full circle

Answer: 6.28 radians

Step-by-step explanation: I think pls BRAINLIEST

Hi! I was wondering if someone could explain how to find a percent of a large number. I think you're supposed to multiply a number by a decimal, but I don't remember. Please give an example and no links. Thanks so much!

Answers

Answer:

Yes, you're correct.

An example would be, say, 345. You want to find 60%. So you multiply 345 by 0.60.

Answer:

Give other answer brainliest!!!!

Step-by-step explanation:

Good work

13 points pls help me quick

Answers

Answer:

Right Angles: C, F

Obtuse Angles: E, B

Acute Angles: A, D

Step-by-step explanation:

Right Angles are angles that are exactly 90 degrees.

Obtuse Angles are angles that are bigger than 90 degrees.

Acute Angles are angles that are smaller than 90 degrees.

Answer:

a . C and F .

b. B and E .

c. A and D .

Step-by-step explanation:

Hope this helps .

A geologist examines 18 water samples for iron concentration. The mean iron concentration for the sample data is 0.272 cc/cubic meter with a standard deviation of 0.0851. Determine the 99% confidence interval for the population mean iron concentration. Assume the population is approximately normal. Step 1 of 2: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

Answers

Answer:

The critical value that should be used in constructing the confidence interval is T = 2.898.

The 99% confidence interval for the population mean iron concentration is between 0.214 cc/cubic meter and 0.33 cc/cubic meter.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 18 - 1 = 17

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 17 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.898.

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.898\frac{0.0851}{\sqrt{18}} = 0.058[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.272 - 0.058 = 0.214 cc/cubic meter.

The upper end of the interval is the sample mean added to M. So it is 0.272 + 0.058 = 0.33 cc/cubic meter.

The 99% confidence interval for the population mean iron concentration is between 0.214 cc/cubic meter and 0.33 cc/cubic meter.

there are 10 students in miss mendoza's remedial class. how many ways can she choose 3 students to clean the room?​

Answers

Answer:

im pretty sure thats 30

Step-by-step explanation: 3*10=30

Which table values would use to graph y=x^2 + 3 (with work please)

Answers

For graph y=x^2+3 the table values that would be used is the last one

simplify 14x(7xy^14)(-9x^-7 y^-3)

Answers

Answer:

-882y^11/x^5

Step-by-step explanation:

Please help

I don't know how to salve it

Answers

Answer:

20

Step-by-step explanation:

trust me

Answer:

51.2

Step-by-step explanation:

Since it's a percentage all you have to do is multiply 32 by 1.6 because a 100 percent is equivalent to 1 so 160 percent is equivalent to 1.6.

PLEASE HELP I HAVE NO IDEA HOW TO DO SLOPES

Answers

Step-by-step explanation:

(0, 4) (4, 0)

(0-4)/(4-0) = -4/4= -1 is the slope

Please hurry and solve for 40 points

Answers

Answer:

x=3 y=-2

Step-by-step explanation:

Elimination would bring the equation to

3x=18

18/6 is 3

6-3y=12

-3y=6

y=-2

A vehicle purchased for $29,800 depreciates at a constant rate of 4%. Determine the approximate value of
the vehicle 10 years after purchase. Round to the nearest whole dollar.

Answers

Answer:

$44104

Step-by-step explanation:

Given data

Cost = $29800

Rate= 4%

Time= 10years

Applying the formula below, we can find the cost after 10 years as

A=P(1+r)^t

A= 29800(1+0.04)^10

A=29800(1.04)^10

A=29800*1.480

A=$44104

Hence the new cost is $44104

Find -3(6m-8)+(-4+2m).

Answers

Answer: − 16 m + 20

Step-by-step explanation:

Answer:

m = 5/4

Step-by-step explanation:

Which value of c completes the square in the expression x2 + 14x + c?
A.-49
B.-7
C.7
D.49

Answers

The answer is letter D

In semiconductor manufacturing, wet chemical etching is often used to remove silicon from the backs of wafers prior to metalization. The etch rate is an important characteristic in this process and known to follow a normal distribution. Two different etching solutions have been compared, using two random samples of 10 wafers for each solution. Assume the variances are equal. The etch rates are as follows (in mils per minute):

Solution 1 Solution 2
9.9 10.6 10.5 10.2
9.4 10.3 10.6 10.2
9.3 10.0 10.7 10.7
9.6 10.3 10.4 10.4
10.2 10.1 10.5 10.3

Required:
a. Construct normal probability plots for the two samples. Do these plots provide support for the assumptions of normality and equal variances? Write a practical interpretation for these plots.
b. Do the data support the claim that the mean etch rate is the same for both solutions? In reaching your conclusions, use α = 0.05 and assume that both population variances are equal. Calculate a P-value.
c. Find a 95% confidence interval on the difference in mean etch rates

Answers

im really smart (no im not thats why im here)

A simple random sample of 150 people who completed the ESPN 2019 Tournament Bracket was selected, and 81 out of the 150 people who completed the ESPN 2019 Tournament Bracket had their choice to become the national champion make the Final Four. If appropriate, use this information to calculate and interpret a 90% confidence interval for the proportion of all people who completed the ESPN 2019 Tournament Bracket whose choice to become the national champion made the Final Four.

Answers

Answer:

The answer is "0.54 and (0.4733, 0.6067)".

Step-by-step explanation:

Please find the complete question in the attachment file.

In question 1:

[tex]\to x=81\\\\ \to n=150\\\\ \to \hat{p}=\frac{x}{n}=\frac{81}{150}=0.54\\\\[/tex]

Hence the choice A is correct.

In point b:

Calculating Critical Value:

[tex]\to (Z_{\alpha/2})=1.64 \ \ \ \ \ \ \ \ \ \ (use \ \ z\ \ table)\\\\[/tex]

Calculating the Confidence intervals:

[tex]=\hat{p} \pm Z_{\alpha/2}\times \sqrt{\frac{\hat{p} \times (1-\hat{p}))}{n}}\\\\ =0.54 \pm 1.64\times \sqrt{\frac{0.0.54 \times (1-0.54)}{150}}\\\\ =0.54 \pm 0.0667\\\\ =(0.4733, 0.6067)\\\\[/tex]

Hence the choice a is correct.

The correct confidence interval is (0.4733, 0.6067).

What is the z critical value?

The z critical test is conducted when the population standard deviation on a normal distribution is known and the sample size is greater than or equal to 30.

x = 81

n = 150

p = x/n =81/ 150

p  = 0.54

So, the correct choice is A.

In point b

Critical Value:

[tex]Z_{\alpha /2} = 1.64[/tex]

the Confidence intervals:

= p±[tex]Z_{\alpha /2} \times \sqrt{\frac{p \times (1-p)}{n} }[/tex]

= 0.54 ± [tex]\\1.64 \times \sqrt{\frac{0.54 \times (1-0.54)}{150} }[/tex]

= 0.54 ± 0.0667

= (0.4733, 0.6067)

Hence, the choice A is correct.

Therefore, the correct confidence interval is (0.4733, 0.6067).

Learn more about critical value:

https://brainly.com/question/5425085

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 148 millimeters, and a standard deviation of 7 millimeters. If a random sample of 31 steel bolts is selected, what is the probability that the sample mean would differ from the population mean by more than 2.2 millimeters? Round your answer to four decimal places.

Answers

Answer:

0.0802 = 8.02% probability that the sample mean would differ from the population mean by more than 2.2 millimeters

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Their current steel bolts have a mean diameter of 148 millimeters, and a standard deviation of 7 millimeters.

This means that [tex]\mu = 148, \sigma = 7[/tex]

Sample of 31:

This means that [tex]n = 31, s = \frac{7}{\sqrt{31}}[/tex]

What is the probability that the sample mean would differ from the population mean by more than 2.2 millimeters?

Less than 148 - 2.2 = 145.8 or more than 148+2.2 = 150.2. Due to the simmetry of the normal distribution, these probabilities are the same, which means that we find one and multiply by 2.

Probability of being less than 145.8:

The pvalue of Z when X = 145.8. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{145.8 - 148}{\frac{7}{\sqrt{31}}}[/tex]

[tex]Z = -1.75[/tex]

[tex]Z = -1.75[/tex] has a pvalue of 0.0401

2*0.0401 = 0.0802

0.0802 = 8.02% probability that the sample mean would differ from the population mean by more than 2.2 millimeters

What is the answer please help if you put a link I will report

Answers

True
PLEASE MARK BRAINLIESTTT

Answer:

true.

Step-by-step explanation:

Other Questions
Which detail best characterizes the narrator's uncle in the excerpt?excerpt from A Journey to the Center of the Earthby Jules VerneBut my uncle was not a man to be kept waiting so adjourning therefore all minor questions, I presented myself before him.He was a very learned man. Now most persons in this category supply themselves with information, as peddlers do with goods, for the for benefit ofothers, and lay up stores in order to diffuse them abroad for the benefit of society in general. Not so my excellent uncle, Professor Hardwigg; hestudied, he consumed the midnight oil, he pored overheavy tomes, and digested huge quartos and folios in order to keep the knowledge acquired tohimself.There was a reason, and it may be regarded as a good one, why my uncle objected to display his learning more than was absolutely necessary: hestammered; and when intent upon explaining the phenomena of the heavens, was apt to find himself at fault, and allude in such a vague way to sun,moon, and stars that few were able to comprehend his meaning. To tell the honest truth, when the right word would not come, it was generallyreplaced by a very powerful adjective.As | said, my uncle, Professor Hardwigg, was a very learned man; and now add a most kind relative. was bound to him by the double ties ofaffection and interest. took deep interest in all his doings, and hoped some (O day to be almost as learned myself. It was rare thing for me to beabsent from his lectures. Like him, I preferred mineralogy to all the other sciences. all My anxiety was to gain real knowledge of the earth. Geology andmineralogy were to uS the sole objects of life, and in connection with these studies many a fair specimen of stone, chalk, or metal did we break withour hammers. As educators, it is important to remember that parents/guardians may not have prior knowledge about learning disabilities, their risk factors, or early intervention strategies for exceptionalities in children of various ages. Additionally, parents/guardians may not understand how specific learning disabilities affect students in educational settings as well as everyday life. As educators, we can communicate and collaborate with parents/guardians to provide information and resources that help them understand learning disabilities, define the roles of the state, school, and the parents/guardians in accessing and providing intervention services, and navigate the acquisition of information and support agencies and services provided to students with disabilities.Consider students in the grade level that is the focus of your field of study. Select a specific disability category (intellectual disability, specific learning disability, emotional behavior disorders, autism spectrum disorder, traumatic brain injury, or orthopedic impairment).Create a 250-500 word digital brochure that could be given to families and provide information about services and supports for individuals with disabilities.The brochure should include the following:Short rationale explaining how you will use the brochure to communicate with parents/guardians and establish mutual expectations to help you work collaboratively to support child development and achievement.Short definition and explanation of the disability category including the developmental and individual differences typically associated with the disability category.Three developmentally appropriate, specially designed instructional strategies that can be used to address the educational needs of students with this disability.Three intervention strategies families can implement at home to promote communication skills, social skills, and literacy skills in their children affected by the chosen disability.Three communication/collaboration strategies that can be employed by the state, school, service providers, and parents/guardians to implement intervention services to support student achievement and development.Recommend local organizations families could use to learn more about the disability and community services that might be available to them. Provide contact information for the organizations and services.Support the assignment with a minimum of three scholarly resources.While APA format is not required for the body of this assignment, solid academic writing is expected, and in-text citations and references should be presented using APA documentation guidelines, which can be found in the APA Style Guide, located in the Student Success Center. A grain stack sitting in a farm field, casting a shadow on the ground in front of it. trees and a farm are in the background. if a structuralist was to look at this painting, what would he/she observe? a. a grain stack in a natural landscape. b. the shadow cast by the grain stack, indicating the setting of the sun, as sign of hope. c. the symbolism presented by the colors and light used. d. a farm field, a hill in the background, and the misplacement of the grain stack. Which rhetorical device does lincoln use? alliteration, in the phrase "ballot to the bullet" antithesis, in suggesting one could both "lose" and "pay" metonymy, in the use of "ballot" to represent voting allusion, in the reference to "free men". at a cafeteria the price of a salad depend on it weight in ounces. the graph shows the relationship what is the slope of the line write the summary of the poem all the worlds a stage Why did the sinking of the Lusitania make the United States angry? lObjective 6-6) The following are various management assertions (a. through m.)related to sales and accounts receivable.Management Assertiona. Recorded sales transactions have occurred.b. There are no liens or other restrictions on accounts receivable.c. All sales transactions have been recorded.d. Receivables are appropriately classified as to trade and other receivables in the financial statements and are clearly described.e. Sales transactions have been recorded in the proper period.f. Accounts receivable are recorded at the correct amounts.g. Sales transactions have been recorded in the appropriate accounts.h. All required disclosures about sales and receivables have been made.i. All accounts receivable have been recorded.j. Disclosures related to receivables are at the correct amounts.k. Sales transactions have been recorded at the correct amounts.1. Recorded accounts receivable exist.m. Disclosures related to sales and receivables relate to the entity.a. Explain the differences among management assertions about classes of transactions and events, management assertions about account balances, and management assertions about presentation and disclosure.b. For each assertion, indicate whether it is an assertion about classes of transactions and events, an assertion about account balances, or an assertion about presentation and disclosure.c. Indicate the name of the assertion made by management. (Hint: See Table 6-2 What are the 4 types of local government unit and explained each? is marfan syndrome caused by a substitution, insertion, or deletion mutationin the fbn1 gene What are some things that easily distract us? The three clusters we considered in this unit covered so many different pathways! Can youmake sense of it all? Create a chart that shows each career cluster and its pathways. Forevery pathway, list an example of a job found under it. Then list a possible company or area inwhich the person who has that job would work. Which detail from the passage best support the idea that the farm is a symbol? What was a long-term impact of trade during the Vedic Age? The people declared war on neighboring civilizations. New kingdoms developed. Craft products increased in value. Diseases were introduced that led to decline. What is the nature of the roots of the quadratic equation if the value of its discriminant is negative? ANALYTICS EXERCISE: FORECASTING SUPPLY CHAIN DEMANDSTARBUCKS CORPORATION (LO32) As we discussed at the beginning of the chapter, Starbucks has a large, global supply chain that must efficiently supply over 17,000 stores. Although the stores might appear to be very similar, they are actually very different. Depending on the location of the store, its size, and the profile of the customers served, Starbucks management configures the store offerings to take maximum advantage of the space available and customer preferences. Starbucks' actual distribution system is much more complex, but for the purpose of our exercise let's focus on a single item that is currently distributed through five distribution centers in the United States. Our item is a logo-branded coffeemaker that is sold at some of the larger retail stores. The coffeemaker has been a steady seller over the years due to its reliability and rugged construction. Starbucks does not consider this a seasonal product, but there is some variability in demand. Demand for the product over the past 13 weeks is shown in the following table. The demand at the distribution centers (DCs) varies between about 40 units on average per week in Atlanta and 48 units in Dallas. The current quarter's data are pretty close to the demand shown in the table. Management would like you to experiment with some forecasting models to determine what should be used in a new system to be implemented. The new system is programmed to use one of two forecasting models: simple moving average or exponential smoothing. Page 90 WEEK 1 2 3 4 5 6 7 8 9 10 11 12 13 AVERAGE Atlanta 33 45 37 38 55 30 18 58 47 37 23 55 40 40 Boston 26 35 41 40 46 48 55 18 62 44 30 45 50 42 Chicago 44 34 22 55 48 72 62 28 27 95 35 45 47 47 Dallas 27 42 35 40 51 64 70 65 55 43 38 47 42 48 LA 32 43 54 40 46 74 40 35 45 38 48 56 50 46 Total 162 199 189 213 246 288 245 204 236 257 174 248 229 222 1. Consider using a simple moving average model. Experiment with models using five weeks' and three weeks' past data. The past data in each region are given below (week -1 is the week before week 1 in the table, -2 is two weeks before week 1, etc.). Evaluate the forecasts that would have been made over the 13 weeks using the overall (at the end of the 13 weeks) mean absolute deviation, mean absolute percent error, and tracking signal as criteria. WEEK -5 -4 -3 -2 -1 Atlanta 45 38 30 58 37 Boston 62 18 48 40 35 Chicago 62 22 72 44 48 Dallas 42 35 40 64 43 LA 43 40 54 46 35 Total 254 153 244 252 198 2. Next, consider using a simple exponential smoothing model. In your analysis, test two alpha values, 0.2 and 0.4. Use the same criteria for evaluating the model as in question 1. When using an alpha value of 0.2, assume that the forecast for week 1 is the past three-week average (the average demand for periods -3, -2, and -1). For the model using an alpha of 0.4, assume that the forecast for week 1 is the past five-week average. 3. Starbucks is considering simplifying the supply chain for their coffeemaker. Instead of stocking the coffeemaker in all five distribution centers, they are considering only supplying it from a single location. Evaluate this option by analyzing how accurate the forecast would be based on the demand aggregated across all regions. Use the model that you think is best from your analysis of questions 1 and 2. Evaluate your new forecast using mean absolute deviation, mean absolute percent error, and the tracking signal. 4. What are the advantages and disadvantages of aggregating demand from a forecasting view? Are there other things that should be considered when going from multiple DCs to a DC? What do the terms floor and ceiling mean? Why is the square root of 4 only 2 and not 2? What is the elicitation technique used for? Barbara has $70. 00 in her pocket and a $20 gift card. Which purchase will she be able to make without having to use her credit card?a portable radio for $65. 95 and speakers for $29. 99five books for $18. 95 eachheadphones for $25. 99 and eight cds for 8. 99 eachsix puzzles for $11. 99 each and a board game for $15. 89.