Measure of the triangle

The middle is a square with side length of 12cm

Area of the square = 12 x 12 = 144 cm^2

There are 4 triangles with base of 13cm and height of 8 cm

Area of triangle = 1/2 x base x height

Area = 1/2 x 12 x 8 = 48cm^2 each

48 x 4 = 192 cm^2

Total area = 144 + 192 = 336 cm^2

Answer:

10 km/h

Step-by-step explanation:

I'm not really sure about this but no ones answering your question and I wanna help.

So basically to calculate the average speed you need to divide the distance travelled by time taken

But you do not have the distance traveled. But it is mentioned that it takes u 30 minutes to walk from home to school when walking at 5 km/h so to find the distance all you have to do is... 30 x 5 = 150 km

Now that we have the time and distance all we have to do is find the average speed.

Average Speed = distance ÷ time

So 150 ÷ 15 = 10 km/h

The proposition that is a tautology is d. (p ^ q) → p. In a tautology, the truth value of the proposition is always true, regardless of the truth values of its individual components.

To determine if a proposition is a tautology, we can construct a truth table and evaluate all possible combinations of truth values for its variables.

For option d, (p ^ q) → p, we have the following truth table:

p q (p ^ q) (p ^ q) → p

T T T T

T F F T

F T F T

F F F T

The proposition that is a tautology is d. (p ^ q) → p.

In a tautology, the truth value of the proposition is always true, regardless of the truth values of its individual components. To determine if a proposition is a tautology, we can construct a truth table and evaluate all possible combinations of truth values for its variables.

For option d, (p ^ q) → p, we have the following truth table:

p q (p ^ q) (p ^ q) → p

T T T T

T F F T

F T F T

F F F T

As we can see, regardless of the truth values of p and q, the proposition (p ^ q) → p always evaluates to true. Therefore, option d is a tautology.

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Answer:

4

Step-by-step explanation:

Answer:

16

Step-by-step explanation:

60-44

The inequality is $40 + 4x < $60 and she has to spend 5 gigabytes to stay within her budget

Note that:  

> means greater than

< means less than

≥ means greater than or equal to  

≤ less than or equal to  

The total amount Lily has to spend has to be less than $60

The total amount she can spend can be represented with this equation

Flat cost + variable cost < $60

Flat cost = $40

Variable cost = cost per gigabyte x gigabyte

$4 × x = $4x

$40 + 4x < $60

To solve for x, combine similar terms

$4x < $60 - $40

$4x < $20

x < 5

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Given:

Base dimensions of a rectangular prism = 15 cm × x cm

The height of the prism = 8 cm

Volume of the prism = 600 cm.

To find:

The value of x.

Solution:

Base area of the prism is:

[tex]B=length\times width[/tex]

[tex]B=15\times x[/tex]

[tex]B=15x[/tex]

Volume of the prism is:

[tex]V=Bh[/tex]

Where, B is the base area and h is the height of the prism.

Putting [tex]V=600,B=15x,h=8[/tex], we get

[tex]600=15x\times 8[/tex]

[tex]600=(8)(15)x[/tex]

[tex]\dfrac{600}{(8)(15)}=x[/tex]

Therefore, the correct option is C.

Answer: They need to complete 21 more jumps all together .

Step-by-step explanation: So 14+13=J

14+13=27

27=j

World record: 48; 48-27=21

They will have to jump 21 more times in a row .

Answer:

The First choice

Step-by-step explanation:

Answer:

91in^2

Step-by-step explanation:

First, add 11 and 15:   11 + 15 = 26

Second, divide it by 2: 26/2 = 13

Third, multiply it by the height: 13 * 7 = 91in^2

The general solution of the given differential equation 7dy/dx + 56y = 8 is y(x) = -x/8 + C e^(-8x/7), where C is a constant.

To solve the differential equation, we first rearrange it to isolate dy/dx: dy/dx = (8 - 56y)/7. This is a first-order linear differential equation. The integrating factor is e^(∫(-56/7)dx) = e^(-8x/7). Multiplying both sides of the equation by this integrating factor, we obtain e^(-8x/7) dy/dx + 8e^(-8x/7)y = 8e^(-8x/7). The left-hand side can be written as the derivative of y multiplied by e^(-8x/7). Integrating both sides gives ∫d(y e^(-8x/7)) = ∫8e^(-8x/7) dx. Solving these integrals and rearranging, we find the general solution y(x) = -x/8 + C e^(-8x/7), where C is the constant of integration.

The largest interval I over which the general solution is defined is (-∞, ∞) since there are no singular points or restrictions mentioned in the differential equation. This means that the solution is valid for all real values of x.

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The given differential equation is shown to be homogeneous, and the solution to the equation with the initial condition y(1) = 4 is :

y = 6x^2 * e^(-x/2) - 2x.

i) To show that the differential equation is homogeneous, we need to verify that it is invariant under the transformation y = ux, where u is a function of x.

Let's substitute y = ux into the given differential equation:

dy/dx = 3xy + y^2 / x^2 + xy

Using the chain rule, we can express dy/dx in terms of u and x:

dy/dx = d(ux)/dx = u + x * du/dx

Substituting this into the differential equation:

u + x * du/dx = 3x(ux) + (ux)^2 / x^2 + x(ux)

Simplifying the equation:

u + x * du/dx = 3u + u^2 / x + u

The equation can be further simplified:

x * du/dx = 2u + u^2 / x

We can see that the resulting equation is independent of x. Hence, the original differential equation is homogeneous.

ii) To solve the homogeneous differential equation, let's substitute y = xv back into the equation:

x * du/dx = 2u + u^2 / x

Multiplying through by x:

x^2 * du/dx = 2xu + u^2

Rearranging the equation:

x^2 * du / (2u + u^2) = dx

We can now integrate both sides:

∫ x^2 * du / (2u + u^2) = ∫ dx

The left-hand side can be further simplified using partial fraction decomposition:

∫ (A/u + B/(u+2)) du = ∫ dx

Solving for A and B, we get:

A = -2, B = 1

Substituting back into the integral:

∫ (-2/u + 1/(u+2)) du = ∫ dx

Simplifying the integral:

-2ln|u| + ln|u+2| = x + C

Now substituting u = y/x:

-2ln|y/x| + ln|(y/x)+2| = x + C

Using properties of logarithms, we can simplify this equation further:

ln((y+2x)/x^2) = -x/2 + C

Taking the exponential of both sides:

(y+2x)/x^2 = e^(-x/2+C)

Simplifying the right-hand side by combining e^C into a constant A:

(y+2x)/x^2 = A * e^(-x/2)

Now, solving for y:

y + 2x = Ax^2 * e^(-x/2)

Finally, rearranging the equation to solve for y:

y = Ax^2 * e^(-x/2) - 2x

Given the initial condition y(1) = 4, we can substitute x = 1 and y = 4 into the equation:

4 = A * e^(-1/2) - 2

Solving for A:

A * e^(-1/2) = 6

A = 6 * e^(1/2)

Substituting the value of A back into the equation, we have:

y = 6x^2 * e^(-x/2) - 2x

So the solution to the differential equation with the initial condition y(1) = 4 is y = 6x^2 * e^(-x/2) - 2x.

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Answer:

.5428571 repeating

or 19/35

Answer:

Cost of 7 pound potato = $3.15

Step-by-step explanation:

Given:

Cost of 5 pound potato = $2.25

Find:

Cost of 7 pound potato

Computation:

Cost of 1 pound potato = 2.25 / 5

Cost of 1 pound potato = $0.45

Cost of 7 pound potato = 7 x Cost of 1 pound potato

Cost of 7 pound potato = 7 x 0.45

Cost of 7 pound potato = $3.15

Answer:

The format of this equation is wrong

Answer:

18 Skittles

6 M&Ms

Step-by-step explanation:

Set up an equation:

Variable x = number of skittles

Variable y = number of M&Ms

1.50x + 2y = 39

x + y = 24

In the second equation, isolate a variable:

x = 24 - y

Substitute the value of x for 24 - y in the first equation:

1.50(24 - y) + 2y = 39

Use distributive property

36 - 1.5y + 2y = 39

Combine like terms

36 + 0.5y = 39

Isolate variable y:

0.5y = 3

y = 6

Substitute the value of y for 6 in the second equation:

x + 6 = 24

Isolate variable x:

x = 18

Plug these values into any equation of your choice to see if these values are correct (I'll do both equations just to prove it):

1.50(18) + 2(6) = 39

27 + 12 = 39

39 = 39

Correct

x + y = 24

18 + 6 = 24

24 = 24

Correct

Using the MGF and its derivatives, we have shown that the mean and variance of the standard normal distribution are both 0.

The MGF for the standard normal distribution is given as:

M(t) = e^(t²/2)

To find the mean of the standard normal distribution, we take the first derivative of the MGF with respect to t and evaluate it at t = 0:

M'(t) = (1/2)e^(t²/2) × 2t

Evaluating at t = 0:

M'(0) = (1/2)e⁰ × 2(0) = 0

Since the first derivative of the MGF evaluated at t = 0 is 0, this implies that the mean of the standard normal distribution is 0.

To find the variance of the standard normal distribution, we take the second derivative of the MGF with respect to t and evaluate it at t = 0:

M''(t) = (1/2)e^(t²/2) × 2t² + (1/2)e^(t²/2)×2

Evaluating at t = 0:

M''(0) = (1/2)e⁰ × 2(0)² + (1/2)e⁰ × 2

= 0 + 1

= 1

Since the second derivative of the MGF evaluated at t = 0 is 1, this implies that the variance of the standard normal distribution is 1.

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Answer:

(240,20)

Step-by-step explanation:

The correct answer is, [–5, 3]. In the other words, the interval in which the function [tex]f(x) = \sqrt{x^2 + 2x - 15}[/tex] is increasing is [–5, 3].

To determine the interval in which the radical function [tex]f(x) = \sqrt{x^2 + 2x - 15}[/tex] is increasing, we need to find the interval(s) where the derivative of the function is positive.

Let's first find the derivative of f(x):

[tex]f'(x) = (1/2) * (x^2 + 2x - 15)^(-1/2) * (2x + 2)[/tex]

To find where f'(x) > 0, we set f'(x) = 0 and solve for x:

[tex](1/2) * (x^2 + 2x - 15)^(-1/2) * (2x + 2) = 0[/tex]

Since the derivative is never equal to zero (since the denominator (x^2 + 2x - 15)^(-1/2) is never equal to zero), there are no critical points.

To determine the intervals of increase, we can evaluate f'(x) at test points in each interval. We'll consider the intervals defined by the given answer choices:

[3, ∞):

Choose a test point x > 3, let's say x = 4.

Evaluate [tex]f'(4) = (1/2) * (4^2 + 24 - 15)^{(-1/2)} * (24 + 2)[/tex]

[tex]= (1/2) * (16 + 8 - 15)^{(-1/2)} * 10[/tex]

[tex]= (1/2) * (9)^{(-1/2)} * 10[/tex]

= (1/2) * (1/3) * 10

= 5/3

Since f'(4) > 0, the function is increasing in the interval [3, ∞).

(4, ∞):

Choose a test point x > 4, let's say x = 5.

Evaluate f'(5) = (1/2) * (5^2 + 25 - 15)^(-1/2) * (25 + 2)

= (1/2) * (25 + 10 - 15)^(-1/2) * 12

= (1/2) * (20)^(-1/2) * 12

Since f'(5) = 0, the function is not increasing in the interval (4, ∞).

[–5, 3]:

Choose a test point x in the interval, let's say x = 0.

Evaluate [tex]f'(0) = (1/2) * (0^2 + 20 - 15)^{(-1/2)} * (20 + 2)[/tex]

[tex]= (1/2) * (-15)^{-1/2} * 2[/tex]

[tex]= (1/2) * (1/\sqrt{15}) * 2[/tex]

[tex]= 1/\sqrt{15}[/tex]

Since f'(0) > 0, the function is increasing in the interval [–5, 3].

(–∞, –5] ∪ [3, ∞):

Since we have already determined the function is increasing in [–5, 3] and [3, ∞), this interval is valid.

Therefore, the correct answer is, [–5, 3]. In the other words, the interval in which the function [tex]f(x) = \sqrt{x^2 + 2x - 15}[/tex] is increasing is [–5, 3].

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Answer:

The sample is the amount of people because not everyone is getting chosen

Step-by-step explanation:

I also agree, the coach choose certain people to march cuz not everyone is gonna be able to get used.

Answer:

periodttt. get out ya bag n make det money up.

Step-by-step explanation:

brainliestt:)?

Answer: taake this link,  it has all the answers

Step-by-step explanation:                 https://quizlet.com/183183758/statistical-studies-scatterplots-practiceamdm-flash-cards/

The best option for the points on the graph is points are at (0.4, 7.8), (3.1, 6.0), and (9.8, 0.5).

In two-dimensional Cartesian geometry, two intersecting straight lines are used as reference lines. In three-dimensional Cartesian geometry, three straight lines with a common point are the intersections of the three coordinate reference planes.

From the attached file of scatter plot for the data, it is clear that the for every value of x there is a suitable value of y which was given in the question.

Considering x values and plot the y vale on the graph.

For x = 0.4; y = 7.8

For x = 3.1; y = 6.0

and for x = 9.8; y = 0.5

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The duration in minutes for 40 consecutive dormant periods are given in the following table:91 82 84 85 80 73 72 84 86 76 51 70 71 83 79 79 67 76 60 81 55 53 51 53 45 49 67 76 86 88 82 68 82 51 51 75 86 575 66.

Assuming that the waiting time follows an exponential distribution with mean parameter A, a uniformly most powerful test of size α = 0.01 for H o λ^2=80 vs H1 A<80 can be developed as follows: The null and alternative hypotheses are as follows:H0:λ^2=80, that is, the mean of the exponential distribution is 80 squared.H1:A<80, which implies that the mean waiting time between eruptions is less than 80 squared.α=0.01 is the level of significance.

The following test statistic T is used: T = [n(λ^2-80)] / 80^2where n is the sample size, and the critical region is the left-tail rejection area. The probability of observing the values in the given sample or a more extreme set of values is calculated as follows: Since we are performing a one-tailed test, we divide α by 2.α/2 = 0.005

The area in the left tail is 0.005, and the corresponding z-score is -2.33.The null hypothesis is rejected if the computed value of the test statistic falls in the critical region, which is in the left-tail rejection region. T < -2.33

Since the test statistic T = -1.91 falls in the non-critical region, we fail to reject the null hypothesis at the α=0.01 level of significance. Therefore, based on this test, we can conclude that there is insufficient evidence to suggest that the mean waiting time between eruptions is less than 80 squared.

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To generate a figure containing the curves y = 1.5*sin(x) and y = x in MATLAB using the linspace and plot commands, you can follow the steps below:

matlab

% Set the range of x values

x = linspace(0, 2.5, 100);

% Calculate y values for each curve

y1 = 1.5*sin(x);

y2 = x;

% Plot the curves

plot(x, y1, 'b', x, y2, 'r')

% Add labels and title

xlabel('x')

ylabel('y')

title('Curves: y = 1.5*sin(x) and y = x')

% Add a legend

legend('y = 1.5*sin(x)', 'y = x')

% Display the grid

grid on

In this code, we use linspace to create a range of x values from 0 to 2.5 with 100 points. Then, we calculate the corresponding y values for each curve using the equations y1 = 1.5*sin(x) and y2 = x. We use the plot command to plot the curves, with 'b' and 'r' specifying the colors of the curves. Next, we add labels, title, and a legend to the graph. Finally, we display the grid.

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Answer:

i dont what an ellipse is but here's the answer:

8x + 32y = 121

Answer:

123‐10×40y=0

10×+40y=123

We cannot construct a square that equals the sum of the areas of two given squares. This statement contradicts the mathematical principles and properties of squares and the Pythagorean theorem.

The statement that given any two squares, we can construct a square that equals the sum of the two given squares is actually false. This statement goes against the well-known mathematical concept known as the Pythagorean theorem.

The Pythagorean theorem states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. This theorem holds true for right-angled triangles, but it does not hold true for squares.

In fact, if we take two squares and try to add their areas together, the result will not be a square with an area equal to the sum of the two given squares. The resulting shape will be a non-square rectangle or some other irregular shape.

Therefore, we cannot construct a square that equals the sum of the areas of two given squares. This statement contradicts the mathematical principles and properties of squares and the Pythagorean theorem.

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Answer: Randomization prevents the researchers from specifically assigning all adults who regularly stay up late to complete assigned tasks late at night.

-Randomization ensures each group will be similar in everything except the time of day they are assigned to work.

-Randomization prevents the adults from selecting their own group.

Step-by-step explanation:

The options include:

a. Randomization ensures each group will be similar in everything except the time of day they are assigned to work.

b. Randomization prevents the adults from selecting their own group.

c. Randomization eliminates lurking variable from the experiment.

d. Randomization prevents the researchers from specifically assigning all adults who regularly stay up late to complete assigned tasks late at night.

e. Randomization ensures that there'll be an equal number of adults in each group.

Randomization refers to a method that is based on chance alone whereby the participants in a particular study are assigned to treatment group. Based on the information given, it us important that the researchers use randomization to assign each of the adults to a group because:

• Randomization ensures each group will be similar in everything except the time of day they are assigned to work.

• Randomization prevents the researchers from specifically assigning all adults who regularly stay up late to complete assigned tasks late at night.

• Randomization prevents the adults from selecting their own group.

Answer:

The number will decrease in value

Step-by-step explanation: For example if we had 638.23 if I move the decimal to the left 3 times it would be .63823, and if we add zeros it would look like this, 0.63823 so the number would decrease in value

To best collect a sample of books from the 13,000 titles at the bookstore, Miguel should use a cluster sampling method.

The best sampling method Miguel should use is a cluster sample.

A cluster sample involves dividing the population into clusters or groups and randomly selecting entire clusters to include in the sample.

In this situation, Miguel could divide the bookstore's titles into clusters, such as by genre or shelf location, and randomly select clusters to sample books from.

his method would help ensure representation from different areas of the bookstore and provide a diverse sample of books.

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By classifying sets of three numbers from the interval [0...n] by their maximum element, we have provided a combinatorial proof of the identity 1, 2 + 2.3 + 3.4 + ... + (x - 1)^n = 2^(n+1).

The combinatorial proof of the identity 1, 2 + 2.3 + 3.4 + ... + (x - 1)^n = 2^(n+1) revolves around classifying sets of three numbers from the integer interval [0...n] by their maximum element.

Let's consider the right-hand side of the equation, which is 2^(n+1). This represents the number of subsets of an n-element set. We can think of each element in the set as having two choices: either it is included in a subset or not. Therefore, there are 2 choices for each element, resulting in a total of 2^(n+1) subsets.

Now, let's look at the left-hand side of the equation, which is the sum 1 + 2 + 2.3 + 3.4 + ... + (x - 1)^n. We can interpret each term as follows:

1: Represents the number of subsets with a maximum element of 0, which is only the empty set.

2: Represents the number of subsets with a maximum element of 1, which includes the subsets {0} and {1}.

2.3: Represents the number of subsets with a maximum element of 2, which includes the subsets {0, 1}, {0, 2}, and {1, 2}.

Similarly, for each subsequent term (x - 1)^n, it represents the number of subsets with a maximum element of x-1.

Now, if we add up all these terms, we are essentially counting the total number of subsets from the original set. This matches the right-hand side of the equation, which is 2^(n+1).

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