Mom cuts the cheese by pressing the knife with a force of 50N. What is the pressure of the knife blade into the cheese if the blade is 12 cm long and 0.2 mm wide?

Answer:

A. like charges repel, unlike charges, attract

Explanation:

A charge can be positive or negative.

Like charges, example positive and positive or negative and negative, repel each other, while unlike charges, example positive and negative attract each other.

From the given options, the correct option is A.

A. like charges repel, unlike charges, attract

The statement which is true for the interaction of charges is the like charges repel, unlike charges, attract (A).

When the two charges or the charged bodies interact each other, the force of attraction or repulsion acts between them. This force of attraction or repulsion can be find out using the coulombs' law.

This force of attraction or repulsion is identified by the sign of the particular charge. According to the property of interacting charges-

Thus, the statement which is true for the interaction of charges is the like charges repel, unlike charges, attract (A).

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The wavelength of the electron microscope is 2.472*10⁻²⁰ m.

Calculation:

Provided, accelerating voltage = 2450 V

According to de Broglie's equation:

λ = h/p

where,λ = the wavelength of the particle that moves

P= momentum of moving particle

h= plank's constant = 6.63 x 10⁻³ Js

We know that,

P = √(2mk)

P = √(2mqV)

where P= momentum of moving particle

M= mass of the moving object

K= kinetic energy of the object

V= Electric potential of the object(accelerating voltage)

q= charge of the object(electron) = e=1.6 x 10⁻¹⁹C

∴λ = h/√(2meV) = [tex]\frac{6,63 *10^{-34} }{2*9.1*10^{-31}*1.6*10^{-19}*2450 }[/tex]

=2.472*10⁻²⁰ m

S0, the wavelength of an electron microscope is 2.472*10⁻²⁰ m. Think it matches option C.

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Answer:

density =mass

volume

x = 39.5 ÷ 5.0

x =7.9

Answer:

7.9 g/cm3

Explanation:

Density = mass / volume

Density = 39.5 / 5.0

Density = 7.9 g/cm^3

Therefore, density is [tex]7.9 g/cm^{3}[/tex]

Answer:

B

Explanation:

Answer:

B

Explanation:

Answer:

5.88 Nm

Explanation:

Applying,

Moment(M) = Force(F)×perpendicular distance(d)

M = F×d.................... Equation 1

But,

F = mg.................. Equation 2

Where m = mass, g = acceleration due to gravity.

Substitute equation 2 into equation 1

M = mgd................. Equation 3

From the question,

Given: m = 3 kg, d = 20 cm = 0.2 m

Constant: g = 9.8 m/s²

Substitute these values into equation 3

M = 3×0.2×9.8

M = 5.88 Nm

Answer:

u r right

Explanation:

it is A. DNA

i took that class.

:)

Answer:

I think it may be a brain?

Answer:

The depth of the diver is 28.01 m

Explanation:

Given;

density of the seawater, ρ = 1,015 kg/m³

standard sea level pressure, P₀ = 1.0 atm = 101,325 Pa

the final reading of her pressure, P₁ = 3.75 atm = 379968.75 Pa

acceleration due to gravity, g = 9.8 m/s²

Let the depth she was diving at the final pressure = h

This depth is calculated as;

P₁ = P₀  +  ρgh

P₁ - P₀ =  ρgh

[tex]h = \frac{ P_1 \ - \ P_o}{\rho g} = \frac{379968.75 \ - \ 101325}{1015 \ \times \ 9.8} = 28.01 \ m[/tex]

Therefore, the depth of the diver is 28.01 m

the answer for this question is c

Answer:

snell's law = sinI /sin r

refractive index = sinI /sin r

1.33= 30 /sinR

sinR= 1.33×30

sinR=39.9

The angle with the normal by which the fish appear to the fisherman is 41.68 degrees.

According to the Snell's law, the ratio of index of reflection of the different material is equal to the ratio of incident sine angle and reflective sine angle. It can be given as,

[tex]\dfrac{n_1}{n_2}=\dfrac{\sin\theta_2}{\sin\theta_1}[/tex]

Here (n₁ and n₂) are the index and reflective index and (θ₁ and θ₂) are the incident and reflected angle.

The index of refraction of air is 1. Thus, by the Snell's law,

[tex]\dfrac{1}{1.33}=\dfrac{\sin(30)}{\sin\theta_1}\\\theta_1=41.68^o[/tex]

Thus, the angle with the normal by which the fish appear to the fisherman is 41.68 degrees.

Learn more about the Snell's law here;

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Answer:

B

Explanation:

Answer:

Explanation:

a

Answer:

[tex]428.75\ \text{Hz}[/tex]

Explanation:

[tex]\Delta y[/tex] = Change in water level = [tex]220-180=40\ \text{cm}[/tex]

[tex]\lambda[/tex] = Wavelength

[tex]v[/tex] = Speed of sound = 343 m/s

Between the points of resonance there exists [tex]\dfrac{1}{2}\lambda[/tex]

[tex]\dfrac{1}{2}\lambda=\Delta y\\\Rightarrow \lambda=2\Delta y\\\Rightarrow \lambda=2\times 40\\\Rightarrow \lambda=80\ \text{cm}[/tex]

Wavelength is given by

[tex]f=\dfrac{v}{\lambda}\\\Rightarrow f=\dfrac{343}{0.8}\\\Rightarrow f=428.75\ \text{Hz}[/tex]

The frequency of the tuning fork is [tex]428.75\ \text{Hz}[/tex].

Answer:

Explanation:

cross sectional area A = 40 cm² = 40 x 10⁻⁴ m² , n = 40 , Magnetic field B = 2 T . Current = I .

Maximum torque = 2 x 10⁻⁶ Nm

Value of maximum torque = n B A I .

n B A I = 2 x 10⁻⁶ Nm

40 x 2 x 40 x 10⁻⁴  I =  2 x 10⁻⁶ Nm

.32 I  = 2 x 10⁻⁶ Nm

I = 2  x 10⁻⁶ / 32 x 10⁻²

= .0625 x 10⁻⁴

= 6.25 x 10⁻⁶

= 6.25 μ A .

b )

Work done in rotating a coil = n B A I ( cos θ₂ - cosθ₁ )

= n B A I ( cos θ₂ - cosθ₁ )

= 2 x 10⁻⁶ ( cos 180 - cos θ )

= 2 x 10⁻⁶ ( -1  - cos θ )

= - 2 x 10⁻⁶ ( 1  + cos θ ) J .

The spinning would slow down. I've done this so many times and I know when you put your arms out you slow down. Half the time thats a good thing because if you go too fast you end up on the floor. I dont know the answer but id say its B or E

Tell me if I'm wrong

Answer:

the following variables

Answer:

HI THERE

Explanation:

MEIOSIS produces sperm and ova

thank you

I am also reading this chapter

it will come in my exams

Answer:

Explanation:

In equilibrium , weight of mug is equal to restoring force .

mg = kx where m is mass of mug , k is spring constant and x is extension .

k / m = g / x = 9.8 ms⁻² / .025 m

= 392

frequency of oscillation n = [tex]\frac{1}{2\pi}\sqrt{\frac{k}{m} }[/tex]

[tex]n=\frac{1}{2\pi}\sqrt{392 }[/tex]

= 4.46 per second.

Answer:

the force of the friction is A-0.52

The total momentum of the block and putty prior to their collision is

(0.454 kg) (0 m/s) + (5.70 × 10⁻² kg) (8.99 m/s) ≈ 0.512 kg•m/s

and the total momentum after the collision is

(0.454 kg) v + (5.70 × 10⁻² kg) (-8.99 m/s)

where v is the velocity of the block. Momentum is conserved, so

(0.454 kg) v + (5.70 × 10⁻² kg) (-8.99 m/s) = 0.512 kg•m/s

==>   v ≈ 2.26 m/s

The total work done on the block by the spring as it gets compressed by a distance x is equal to the change in the block's kinetic energy:

1/2 (25.0 N/m) x ² = 1/2 (0.454 kg) (2.26 m/s) - 0

==>   x ≈ 0.202 m ≈ 20.2 cm

Answer:

The answer is C.

Explanation:

If you have ever tried doing so, hair stick to the ballon. Opposites attract as well, so the answer is C.

Answer:

If it has more electrons than protons it has a net negative charge and is known as an anion.

Answer:

7 × 10^-1

Explanation:

Hope this helps :) mark branliest if you could!

Answer: Therefore, the scientific notation is [tex]7 *10 {}^{ - 1}[/tex]

To solve a scientific notation you must count how many zeros they have, this always starts from the first 0, in some cases you always start by putting any number but that is not 0 at the beginning, these exercises are no longer negative scientific notations, if not they are positive.

[tex]8840 = 8.84 \times 10 {}^{3} [/tex]

Always to write a positive exercise you should always take the following:

And finally, the leading and trailing zeros of the coefficient are eliminated.

So, Therefore, The result of the scientific notation of the problem is [tex]7 *10 {}^{ - 1}[/tex]

You can see more about scientific notation in: https://brainly.com/question/17947470

Explanation:

a) It will weigh less because of its distance from the block.

b) torque = W1×d1 = (10N)(0.25m) = 2.5 N-m

c) torque = W2×d2 = W2×(0.50m)

d) W2×d2 = W1×d1

W2 = (d1/d2)W1

= 5 N

first is gamma Ray's, last is d

Answer:

Frequency = 1,550Hz

Explanation:

To solve this we can use the equation: [tex]f=\frac{v}{\lambda}[/tex]

(frequency = velocity/wavelength).

We are given the information that the wavelength is 22cm and the speed is 340m/s. The first step is to make sure everything is in the correct units (SI units), and to convert them if needed. The SI Units for velocity and wavelength are m/s and m respectively. This means we need to convert 22cm into meters, which we can do by dividing by 100, (as there are 100cm in a meter). 22/100 = 0.22m

Now we can substitute these values into the formula and calculate to solve:

[tex]f=\frac{340}{0.22} \\\\f=1545.454...[/tex]

Simplify to 3 significant figures:

f = 1,550Hz

(Which I believe is just below a G6 if you were interested)

Hope this helped!

The probability that a student chosen at random will play the guitar is 0.23.

To find the probability of student will play the guitar, we need to know about how to calculate the probability.

What is the number of elements of the sample space?

Seventh grade students instrument

Eighth grade students instrument

What is the number of elements of the event?

What is the probability of student will play the guitar?

Thus, we can conclude that the probability of student will play the guitar is 0.23.

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Answer:

a. Red and Orange

b. Yes, they are

Explanation:

a. This is because, since the yellow light is reflected back into the water, it undergoes total internal reflection and its wavelength in water is not long enough to allow it penetrate the water surface. Since the wavelength decreases from left to right, both the green and blue light have shorter wavelength than the yellow light, so they get reflected back. The red and orange lights are more likely to penetrate since they have longer wavelengths than the yellow light.

b. This is because the red and orange light have longer wavelengths and are thus more likely to penetrate the water surface and not get reflected back.

Answer:

To determine the minimum blade length, add 1" to the workpiece thickness. One type of material, and some materials can be cut by more than one type of blade. No matter the material, there's likely a jigsaw blade designed specifically for. Armed with the right blade, follow these pointers to make your work go (and cut) .

Explanation:

Answer:

ΔT = 4.058 10²⁰ [tex]\frac{S_o^2}{r^2 \ c_e}[/tex]

Explanation:

In this experiment the system can be approximated as a tube with one end open and the other closed.

The open end is where the ultrasound emitter is and the closed end where the limit between the tissue and the bone is, the length of the tube is L = 0.55 cm = 5.5 10⁻³ m

a node is formed at the closed end and a belly at the open end, so the resonance has the form

             λ = 4L                    1st harmonic

             λ = 4/3 L                third harmonic

             λ = 4/5 L                fifth harmonic

             λ = 4L / (2n + 1)     n = 0, 1, 2, (2n + 1)

This wave is a standing wave therefore energy density remains in place

                P = 1/2 ρ v (w S₀)²

angular velocity is related to frequency

               w = 2π f

we substitute

                E = P = 2π² ρ v f² S₀²

if this energy per unit area is transformed into heat

                E = m c_e DT

let's use the concept of density

                ρ = m / V

                m = ρ V

if there are no losses in the system

       ½ π² ρ v f² S₀² = ρ V c_e ΔT

       ΔT = [tex]\frac{\pi ^2 \ v \f^2 S_o^2}{2V \ c_e}[/tex]

When analyzing this expression the temperature increase is

* quadratic at the frequency and maximum amplitude of the wave

* proportional to the speed of the wave in the tissue

* inversely proportional to tissue volume

we can approximate the volume of the tissue to the volume of a cylinder tube

            V = π r² L

           ΔT = [tex]\frac{\pi \ v \ f^2 S_o^2 }{r^2 \ L \ c_e}[/tex]

we calculate

            ΔT = π 1450 (0.7 10⁶)² S₀² /( r² 5.5 10-3 c_e)

            ΔT = 4.058 10²⁰ [tex]\frac{S_o^2}{r^2 \ c_e}[/tex]

Answer:

A quick return motion mechanism is used in the shaper and slotter machine in which the circular motion is converted into reciprocating motion so that the slider moves forward and backwards. In the forward direction, the cutting process occurs while in return there is no such cutting.